Re: comprehension parsing

2022-11-06 Thread philippe descharmes
Hello, I‌ts probably a priority of avalauation in the chain of operators ans association of themselves. I'm not sure. Philippe.   De : "BlindAnagram" A : python-list@python.org Envoyé: dimanche 6 Novembre 2022 00:57 Objet : Re: comprehension parsing   On 05/11/2022 22:11, MRAB w

Re: comprehension parsing

2022-11-05 Thread BlindAnagram
On 05/11/2022 22:11, MRAB wrote: On 2022-11-05 18:52, cactus wrote: On Saturday, 5 November 2022 at 16:06:52 UTC, cactus wrote: I should have quoted the full comprehensions:   all((srt(m, n) in c_np) == (srt(a, b) in c_ap)  for (m, a), (n, b) in combinations(na8, 2))   all( srt(m, n) in c_np 

Re: comprehension parsing

2022-11-05 Thread MRAB
On 2022-11-05 18:52, cactus wrote: On Saturday, 5 November 2022 at 16:06:52 UTC, cactus wrote: I should have quoted the full comprehensions: all((srt(m, n) in c_np) == (srt(a, b) in c_ap) for (m, a), (n, b) in combinations(na8, 2)) all( srt(m, n) in c_np == srt(a, b) in c_ap) for (m, a

Re: comprehension parsing

2022-11-05 Thread cactus
On Saturday, 5 November 2022 at 16:06:52 UTC, cactus wrote: I should have quoted the full comprehensions: all((srt(m, n) in c_np) == (srt(a, b) in c_ap) for (m, a), (n, b) in combinations(na8, 2)) all( srt(m, n) in c_np == srt(a, b) in c_ap) for (m, a), (n, b) in combinations(na8, 2)) --

comprehension parsing

2022-11-05 Thread cactus
The two comprehensions: all((srt(n, m) in c_np) == (srt(a, b) in c_ap) for (m, b) in na) all( srt(n, m) in c_np == srt(a, b) in c_ap for (m, b) in na) parse differently but I am unclear what the second one produces since I thought it would be the same as the first. Any ideas how the second