Dirk Nachbar writes:
> I want to take a copy of a list a
>
> b=a
In addition to the other good replies you've received:
To take a copy of an object, the answer is never ‘b = a’. That binds a
reference ‘b’ to the same object referenced by ‘a’.
The assignment operator ‘=’ never copies; it binds
cassiope wrote:
Alternatively, you can write
import copy
a = [1,2,3]
b = a.copy()
JM
I'm not a pyguru, but... you didn't use copy quite right.
Try instead: b= copy.copy(a)
You're right, you're not a python guru so don't even try to contradict
me ever again.
...
:D of course I di
On Dec 10, 8:48 am, Dirk Nachbar wrote:
> I want to take a copy of a list a
>
> b=a
>
> and then do things with b which don't affect a.
>
> How can I do this?
>
> Dirk
Not knowing the particulars,
you may have to use:
import copy
b=copy.deepcopy(a)
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On Dec 10, 6:06 am, Jean-Michel Pichavant
wrote:
> Dirk Nachbar wrote:
> > I want to take a copy of a list a
>
> > b=a
>
> > and then do things with b which don't affect a.
>
> > How can I do this?
>
> > Dirk
>
> In [1]: a = [1,2,3]
>
> In [2]: b = a[:]
>
> In [3]: b[0] = 5
>
> In [4]: a
> Out[4]:
On Freitag 10 Dezember 2010, Dirk Nachbar wrote:
> > b=a[:]
> >
> > --
> > Wolfgang
>
> I did that but then some things I do with b happen to a as
> well.
as others said, this is no deep copy. So if you do something
to an element in b, and if the same element is in a, both
are changed as they ar
On Dec 10, 1:56 pm, Wolfgang Rohdewald wrote:
> On Freitag 10 Dezember 2010, Dirk Nachbar wrote:
>
> > I want to take a copy of a list a
>
> > b=a
>
> > and then do things with b which don't affect a.
>
> > How can I do this?
>
> > Dirk
>
> b=a[:]
>
> --
> Wolfgang
I did that but then some things
Dirk Nachbar wrote:
I want to take a copy of a list a
b=a
and then do things with b which don't affect a.
How can I do this?
Dirk
In [1]: a = [1,2,3]
In [2]: b = a[:]
In [3]: b[0] = 5
In [4]: a
Out[4]: [1, 2, 3]
In [5]: b
Out[5]: [5, 2, 3]
Alternatively, you can write
import copy
a
On Freitag 10 Dezember 2010, Dirk Nachbar wrote:
> I want to take a copy of a list a
>
> b=a
>
> and then do things with b which don't affect a.
>
> How can I do this?
>
> Dirk
b=a[:]
--
Wolfgang
--
http://mail.python.org/mailman/listinfo/python-list
b = list(a)
or
b = a[:]
--
http://mail.python.org/mailman/listinfo/python-list
On Fri, Dec 10, 2010 at 7:18 PM, Dirk Nachbar wrote:
> I want to take a copy of a list a
>
> b=a
>
> and then do things with b which don't affect a.
>
> How can I do this?
>
b = a[:] will create a copy of the list. If the elements of the list
are references to mutable objects (objects of your ow
I want to take a copy of a list a
b=a
and then do things with b which don't affect a.
How can I do this?
Dirk
--
http://mail.python.org/mailman/listinfo/python-list
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