Thanks to all
I settled with this:
def partial1(f,b):
return lambda a:f(a,b)
def partial2(f,a):
return lambda b:f(a,b)
Juan Pablo
2005/10/20, Mike Meyer [EMAIL PROTECTED]:
Robert Kern [EMAIL PROTECTED] writes:
Juan Pablo Romero wrote:
Hello!
given the definition
Hello!
given the definition
def f(a,b): return a+b
With this code:
fs = [ lambda x: f(x,o) for o in [0,1,2]]
or this
fs = []
for o in [0,1,2]:
fs.append( lambda x: f(x,o) )
I'd expect that fs contains partial evaluated functions, i.e.
fs[0](0) == 0
fs[1](0) == 1
fs[2](0) == 2
But this
Juan Pablo Romero wrote:
Hello!
given the definition
def f(a,b): return a+b
With this code:
fs = [ lambda x: f(x,o) for o in [0,1,2]]
or this
fs = []
for o in [0,1,2]:
fs.append( lambda x: f(x,o) )
I'd expect that fs contains partial evaluated functions, i.e.
You are asking it to return a list of lambda, not its evaluated value.
map(lambda x: f(x,0), [0,1,2]) works.
[ f(o) for o in [0,1,2] ] works too.
Juan Pablo Romero wrote:
Hello!
given the definition
def f(a,b): return a+b
With this code:
fs = [ lambda x: f(x,o) for o in [0,1,2]]
or
Robert Kern [EMAIL PROTECTED] writes:
Juan Pablo Romero wrote:
Hello!
given the definition
def f(a,b): return a+b
With this code:
fs = [ lambda x: f(x,o) for o in [0,1,2]]
or this
fs = []
for o in [0,1,2]:
fs.append( lambda x: f(x,o) )
I'd expect that fs contains
