luofeiyu writes:
> s="Aug"
>
> how can i change it into 8 with some python time module?
months = (None, # dummy, to start month indices from 1
"Jan","Feb","Mar","Apr","May","Jun",
"Jul","Aug","Sep","Oct","Nov","Dec"
)
month_number = months.index(month_abbr) # month_abbr == "Aug
On Thu, 14 Aug 2014 14:52:17 +0800, luofeiyu wrote:
> in the manual https://docs.python.org/3.4/library/time.html
>
> %zTime zone offset indicating a positive or negative time difference
> from UTC/GMT of the form +HHMM or -HHMM, where H represents decimal hour
> digits and M represents deci
On Thu, 14 Aug 2014 09:46:20 +0800, luofeiyu wrote:
> s="Aug"
>
> how can i change it into 8 with some python time module?
You don't need a time module for this, just use a dictionary:
months = { "Jan" : 1, . , "Dec": 12 }
num = months[s]
print num
Fill in the rest of the months dictionary
Dennis Lee Bieber writes:
> "Android" /is/ the flavor
>
> Though Google has probably done some things to it that make it
> "not-Linux".
Android is definitely Linux, since that is the kernel Android runs.
Remember that Linux is not an operating system; it is one part, the
kernel.
Th
In article ,
Dennis Lee Bieber wrote:
> On Thu, 14 Aug 2014 17:47:00 +1000, Cameron Simpson
> declaimed the following:
>
> >
> >Your Android phone will be running some flavour of Linux I believe. Someone
> >who
> >has used one may correct me here.
> >
> "Android" /is/ the flavor
>
>
On 14/08/2014 02:46, luofeiyu wrote:
s="Aug"
how can i change it into 8 with some python time module?
If all else fails, read the instructions, so start here
https://docs.python.org/3/library/datetime.html#module-datetime
--
My fellow Pythonistas, ask not what our language can do for you, a
On 14Aug2014 14:52, luofeiyu wrote:
in the manual https://docs.python.org/3.4/library/time.html
┌──┬──┬─┐
│ │Time zone offset indicating a positive or negative time difference│ │
│%z│from UTC/GMT of the form +HHMM or -HHM
On 14Aug2014 15:30, luofeiyu wrote:
import sys
sys.version
'3.4.0 (v3.4.0:04f714765c13, Mar 16 2014, 19:25:23) [MSC v.1600 64 bit
(AMD64)]'
First, please post in an interleaved style so that we can see your responses
underneath the text to which they relate. Thanks.
Ok, you have Python 3.4
>>> import sys
>>> sys.version
'3.4.0 (v3.4.0:04f714765c13, Mar 16 2014, 19:25:23) [MSC v.1600 64 bit
(AMD64)]'
>>> import time
>>> time.tzname
('China Standard Time', 'China Daylight Time')
On 8/14/2014 3:25 PM, Cameron Simpson wrote:
On 14Aug2014 14:52, luofeiyu wrote:
in the manual http
Please don't top-post your response. Instead, interleave your response
and remove irrelevant quoted material. Use the Interleaved style
https://en.wikipedia.org/wiki/Posting_style#Interleaved_style>.
luofeiyu writes:
> in the manual https://docs.python.org/3.4/library/time.html
>
> %zTime z
in the manual https://docs.python.org/3.4/library/time.html
%z Time zone offset indicating a positive or negative time difference
from UTC/GMT of the form +HHMM or -HHMM, where H represents decimal hour
digits and M represents decimal minute digits [-23:59, +23:59].
%Z Time zone name
Tim Chase :
> Or, if you want a more convoluted way:
>
> >>> import calendar as c
> >>> [i for i, m in enumerate(c.month_abbr) if m == "Aug"].pop()
> 8
Let's not forget the much simpler solutions:
>>> def eight(x): return 8
...
>>> eight("Aug")
8
and:
>>> 8
8
BTW,
In article <53ec2453$0$2299$426a7...@news.free.fr>,
YBM wrote:
> Le 14/08/2014 04:16, Tim Chase a écrit :
> > On 2014-08-13 21:01, Tim Chase wrote:
> >> On 2014-08-14 09:46, luofeiyu wrote:
> >>> s="Aug"
> >>>
> >>> how can i change it into 8 with some python time module?
> >>
> >> >>> import
On Wed, Aug 13, 2014 at 8:51 PM, YBM wrote:
> BTW, why iterators does not have such an index method ?
Because iterators don't support indexing. In order to support such a thing,
it would have to exhaust the iterator.
>>> iter(range(5))[3]
Traceback (most recent call last):
File "", line 1, in
Le 14/08/2014 04:16, Tim Chase a écrit :
On 2014-08-13 21:01, Tim Chase wrote:
On 2014-08-14 09:46, luofeiyu wrote:
s="Aug"
how can i change it into 8 with some python time module?
>>> import time
>>> s = "Aug"
>>> time.strptime(s, "%b").tm_mon
8
works for me.
Or, if you want a mo
On 2014-08-13 21:01, Tim Chase wrote:
> On 2014-08-14 09:46, luofeiyu wrote:
> > s="Aug"
> >
> > how can i change it into 8 with some python time module?
>
> >>> import time
> >>> s = "Aug"
> >>> time.strptime(s, "%b").tm_mon
> 8
>
> works for me.
Or, if you want a more convoluted way:
>>
On 2014-08-14 09:46, luofeiyu wrote:
> s="Aug"
>
> how can i change it into 8 with some python time module?
>>> import time
>>> s = "Aug"
>>> time.strptime(s, "%b").tm_mon
8
works for me.
-tkc
--
https://mail.python.org/mailman/listinfo/python-list
luofeiyu writes:
> s="Aug"
>
> how can i change it into 8 with some python time module?
What is your purpose here? If you want to parse a text value into a
structured time object, don't do it piece by piece. Use the
‘time.strptime’ function.
>>> import time
>>> input_time_text = "14 Aug
On Thu, Aug 14, 2014 at 11:46 AM, luofeiyu wrote:
> s="Aug"
>
> how can i change it into 8 with some python time module?
Is this homework? If not, let me set you some homework.
Step 1: Read the docs for some Python time module.
Step 2: See if it lets you do what you want.
Step 3: Return to step
s="Aug"
how can i change it into 8 with some python time module?
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