Re: how to extract a variable as parameter which has index using by a for loop?

meInvent bbird writes: > it is not convenient to disclose in detail > just expect to discuss from the view of programming It is not convenient to discuss programming without a good understanding of what the program is meant to do. (Also, please don't top-post, instead

Re: how to extract a variable as parameter which has index using by a for loop?

On 8 June 2016 at 12:20, meInvent bbird wrote: > just extract b[i][0:1] and b[i][1:2] out of for loop > > but i depend on for loop > > def node(mmm, A, B): > H2 = [MM[mmm][A+B] for i in range(len(b))] > return H2 > > node(5, b[i][0:1], b[i][1:2]) > > it is not convenient

Re: how to extract a variable as parameter which has index using by a for loop?

just extract b[i][0:1] and b[i][1:2] out of for loop but i depend on for loop def node(mmm, A, B): H2 = [MM[mmm][A+B] for i in range(len(b))] return H2 node(5, b[i][0:1], b[i][1:2]) it is not convenient to disclose in detail just expect to discuss from the view of programming On

Re: how to extract a variable as parameter which has index using by a for loop?

On Wednesday 08 June 2016 17:31, meInvent bbird wrote: > b = [str(i)+str(j)+str(k) for i in range(m) for j in range(m) for k in > range(m)] > b[21][0:1]+b[21][1:2] > b[21][1:2]+b[21][2:3] > b[21][0:1]+b[21][2:3] > > > originally, > > mmm = 5 > H2 = [MM[mmm][b[i][0:1]+b[i][1:2]] for i in

how to extract a variable as parameter which has index using by a for loop?

b = [str(i)+str(j)+str(k) for i in range(m) for j in range(m) for k in range(m)] b[21][0:1]+b[21][1:2] b[21][1:2]+b[21][2:3] b[21][0:1]+b[21][2:3] originally, mmm = 5 H2 = [MM[mmm][b[i][0:1]+b[i][1:2]] for i in range(len(b))] how to extract b[i][0:1] and b[i][1:2] as parameters? def node(mmm,