Joerg Schuster schrieb:
> Hello,
>
>
> I want to open the file 'configuration.smo' that is in directory dir.
> Yet, I don't know on which os my program is being run. On Unix I would
> say:
>
> f = open(dir + '/configuration.smo', 'r')
>
> What is the os-independent version of this line?
Did You c
Gerald Klix schrieb:
> Hi,
> it`s
>
> import os
> f = open( os.path.join( dir , 'configuration.smo' ), 'r' )
*nix-heads everywhere?
For a text file, I would prefer:
f = open( os.path.join( dir , 'configuration.smo' ), 'U' )
and for a binary file:
f = open( os.path.join( dir , 'configuration
Thanks, Andrew and Gerald.
Jörg
--
http://mail.python.org/mailman/listinfo/python-list
Hi,
it`s
import os
f = open( os.path.join( dir , 'configuration.smo' ), 'r' )
HTH,
Gerald
Joerg Schuster schrieb:
> Hello,
>
>
> I want to open the file 'configuration.smo' that is in directory dir.
> Yet, I don't know on which os my program is being run. On Unix I would
> say:
>
> f = open(d
I believe you want:
import os
f = open(os.path.join(dir, 'configuration.smo'), 'r')
...
Joerg Schuster wrote:
> Hello,
>
>
> I want to open the file 'configuration.smo' that is in directory dir.
> Yet, I don't know on which os my program is being run. On Unix I would
> say:
>
> f = open(dir
Hello,
I want to open the file 'configuration.smo' that is in directory dir.
Yet, I don't know on which os my program is being run. On Unix I would
say:
f = open(dir + '/configuration.smo', 'r')
What is the os-independent version of this line?
(I have read the manual of the module os, but I di
