I create my extend type something like
http://www.python.org/doc/current/extending/newtypes.html.
And my type has a member which is a pointer point to my allocate
memory ( no ref count).
ex:
---
typedef struct {
PyObject_HEAD
/*
On Jul 2, 2009, at 2:11 AM, Shen, Yu-Teh wrote:
I create my extend type something like http://www.python.org/doc/current/extending/newtypes.html
.
And my type has a member which is a pointer point to my allocate
memory ( no ref count).
ex:
---
En Thu, 02 Jul 2009 14:22:53 -0300, Philip Semanchuk
phi...@semanchuk.com escribió:
On Jul 2, 2009, at 2:11 AM, Shen, Yu-Teh wrote:
I create my extend type something like
http://www.python.org/doc/current/extending/newtypes.html.
And my type has a member which is a pointer point to my
On Jul 2, 2009, at 9:28 PM, Gabriel Genellina wrote:
En Thu, 02 Jul 2009 14:22:53 -0300, Philip Semanchuk
phi...@semanchuk.com escribió:
Hi Shen,
I'm no expert on Python memory management, but since no once else
has answered your question I'll tell you what I *think* is happening.
Python
I have written a c++ extend module and I use distutils to build.
setup.py
from distutils.core import setup, Extension
setup(name=noddy, version=1.0,
ext_modules=[
Extension(noddy3, [noddy3.cpp, a.cpp])
])
I found it's quite strange when compiling. I
I have written a c++ extend module and I use distutils to build.
setup.py
from distutils.core import setup, Extension
setup(name=noddy, version=1.0,
ext_modules=[
Extension(noddy3, [noddy3.cpp, a.cpp])
])
I found it's quite strange when compiling. I
找尋自己的一片天 schrieb:
I found it's quite strange when compiling. I didn't use extern C at all
, how can python get the right c++ funciton name without any compile error??
I found that it first use gcc to compile noddy3.cpp and then link by g++.
Could anyone explain what it's all about?
The
