On 01/04/06, John Salerno <[EMAIL PROTECTED]> wrote:
> I V wrote:
>
>
> > Note that print gets called after _each_ time that printBackward
> > returns. So, as the different calls to printBackward return, they print
> > whatever 'head' was set to in that invocation. Now, logically enough,
> > the la
I V wrote:
> Note that print gets called after _each_ time that printBackward
> returns. So, as the different calls to printBackward return, they print
> whatever 'head' was set to in that invocation. Now, logically enough,
> the last call to printBackward is the first to return, so the last
> va
John Salerno wrote:
> The printable value of node1 is 1, node2 is 2 and node 3 is 3.
>
> node1.next is node2, node2.next is node3 and node3.next is None.
>
> This might be painfully obvious, but I don't understand when the print
> statement is getting called. If you call printBackward with node1, t
Can someone explain to me how this works:
def printBackward(list):
if list == None: return
head = list
tail = list.next
printBackward(tail)
print head,
>>> printBackward(node1)
3 2 1
The printable value of node1 is 1, node2 is 2 and node 3 is 3.
node1.next is node2, node2.next
