I downloaded a file which has a space in the filename. I want to run a
shell unzip on it, but it fails in my current code:
syscmd = cd %s ; unzip %s % (self.storage.input,
file.basename())
os.system(syscmd)
because no escaping was done.
Is there a more principled way to
Metaperl wrote:
I downloaded a file which has a space in the filename. I want
to run a shell unzip on it, but it fails in my current code:
syscmd = cd %s ; unzip %s % (self.storage.input, file.basename())
os.system(syscmd)
because no escaping was done.
Using cd '%s' ;
metaperl wrote:
I downloaded a file which has a space in the filename. I want to run a
shell unzip on it, but it fails in my current code:
syscmd = cd %s ; unzip %s % (self.storage.input,
file.basename())
os.system(syscmd)
because no escaping was done.
Is there a more
Fredrik Lundh [EMAIL PROTECTED] wrote:
metaperl wrote:
I downloaded a file which has a space in the filename. I want to run a
shell unzip on it, but it fails in my current code:
syscmd = cd %s ; unzip %s % (self.storage.input, file.basename())
os.system(syscmd)
