sharon kim wrote:
is there a way to sum up all the numbers in a list?
>>> help(sum)
sum(...)
sum(iterable[, start]) -> value
Returns the sum of an iterable of numbers (NOT strings) plus the value
of parameter 'start' (which defaults to 0). When the iterable is
empty, return
brilliant, thank you both of you, i will try that out later.
:)
On Wed, Aug 27, 2008 at 1:34 AM, c james <[EMAIL PROTECTED]> wrote:
> >>> L=['10','15','20']
> >>> sum(int(x) for x in L)
> 45
>
> or
> >>> sum(map(int,L))
> 45
>
>
> sharon kim wrote:
>
>> hi all,
>>
>> i have a list, for example;
>>> L=['10','15','20']
>>> sum(int(x) for x in L)
45
or
>>> sum(map(int,L))
45
sharon kim wrote:
hi all,
i have a list, for example;
>>> L=[]
>>> L.append('10')
>>> L.append('15')
>>> L.append('20')
>>> len(L)
3
>>> print L
['10', '15', '20']
is there a way to sum up all the numbers in
sharon kim wrote:
i have a list, for example;
>>> L=[]
>>> L.append('10')
>>> L.append('15')
>>> L.append('20')
>>> len(L)
3
>>> print L
['10', '15', '20']
is there a way to sum up all the numbers in a list? the number of
objects in the list is vary, around 50 to 60. all objects are 1
hi all,
i have a list, for example;
>>> L=[]
>>> L.append('10')
>>> L.append('15')
>>> L.append('20')
>>> len(L)
3
>>> print L
['10', '15', '20']
is there a way to sum up all the numbers in a list? the number of objects
in the list is vary, around 50 to 60. all objects are 1 to 3 digit positive
