no heart feelings. i was just throwing ideas. no time to testing it.
On Feb 9, 3:55 pm, "Tekkaman" <[EMAIL PROTECTED]> wrote:
> Thanks everybody!Azrael: your suggestions involve python-level membership
> testing and
> dummy list construction just like my uniter3 example, so I'm afraid
> they wou
Thanks everybody!
Azrael: your suggestions involve python-level membership testing and
dummy list construction just like my uniter3 example, so I'm afraid
they would not go any faster. There's no built-in sequence flattening
function that I know of btw.
bearophile: your implementation is very simil
Tekkaman:
If the sublists contain hashable elements you can use this:
def uniter(lists):
merge = set()
for sub in lists:
merge = merge.union(sub)
for el in merge:
yield el
data = [['a', 'b', 'd'], ['b', 'c'], ['a', 'c', 'd']]
print list(uniter(data))
But often this t
tra using the firs sublist (list[1]) as cell.then take zhe second
sublist and take a value from it at once and if the value from list[2]
doesnt exist in list[1] then insert it into list[1] at the correct
place. Something like the insertionsort.
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try something else. im posting the code from a kiosk which has no
python, sooo. no code. only explanation
if my memory works well there is a function in python that takes a
multidimensional list and returns its values as a one-dimension list.
def main():
list =unknownFunction([['a', 'b', '
Tekkaman wrote:
> I have a list of lists and I want to define an iterator (let's call
> that uniter) over all unique elements, in any order. For example,
> calling:
>
> sorted(uniter([['a', 'b', 'd'], ['b', 'c'], ['a', 'c', 'd']]))
>
> must return ['a', 'b', 'c', 'd']. I tried the following
> im
I have a list of lists and I want to define an iterator (let's call
that uniter) over all unique elements, in any order. For example,
calling:
sorted(uniter([['a', 'b', 'd'], ['b', 'c'], ['a', 'c', 'd']]))
must return ['a', 'b', 'c', 'd']. I tried the following
implementations:
from itertools im
