Re:
validate string is valid maths
28/01/2008 18:30
Steven D'Aprano wrote:
def rationalise_signs(s):
while ++ in s or +- in s or -+ in s or -- in s:
s = s.replace(++, +)
s = s.replace(--, +)
s = s.replace(+-, -)
s = s.replace(-+, -)
return s
I assume it's faster to check the length of the string s
Hi pythoners.
I am generating strings of length n, randomly from the symbols
+-/*0123456789
What would be the 'sensible' way of transforming the string, for example
changing '3++8' into 3+8
or '3++--*-9' into '3+-9' such that eval(string) will always return a
number?
in cases where
On Mon, 28 Jan 2008 15:10:54 +, Matthew_WARREN wrote:
Hi pythoners.
I am generating strings of length n, randomly from the symbols
+-/*0123456789
What would be the 'sensible' way of transforming the string, for example
changing '3++8' into 3+8
That's easy: replace pairs of +
Hi,
It seems that for every group of 2 or more +-/* signs, one of the following
holds:
- The group starts with '-', everything after it should be dropped,
otherwise
- The second character is '-', everything after it should be dropped,
otherwise
- Drop everything after the first.
That should
I decided to play with it a little bit, but take a different approach
than Steven. This seems actually one of the problems where regexp
might be a good solution.
import re
re_signednumber = r'([-+]?\d+)'
re_expression = '%s(?:([-+/*])[-+/*]*?%s)*' % (re_signednumber,
re_signednumber)
for
impor tOn 28 ene, 14:31, [EMAIL PROTECTED] wrote:
What would be the 'sensible' way of transforming the string, for example
changing '3++8' into 3+8
or '3++--*-9' into '3+-9' such that eval(string) will always return a
number?
'3++8' is already a valid expresion, like '3++---9'
in
Re:
validate string is valid maths
28/01/2008 15:43
