2009/5/5 Ricardo Aráoz :
> This seems to work for any length tuples :
>
a = [(1,2), (3,4, 'goes'), (5,None), (6,7, 8, 'as', None), (8, None),
(9, 0)]
[tup for tup in a if not [e for e in tup if e == None]]
> [(1, 2), (3, 4, 'goes'), (9, 0)]
Why that extra "for"? KISS
>>> a = [(1,2
namekuseijin wrote:
> On May 4, 9:15 am, David Robinow wrote:
>
>> On Mon, May 4, 2009 at 2:33 AM, namekuseijin
>>
>> wrote:
>>
>> ls = [(1,2), (3,4), (5, None), (6,7), (8, None)]
>> [(x,y) for (x,y) in ls if y]
>>
>>> [(1, 2), (3, 4), (6, 7)]
>>>
>> Nope.
On May 4, 9:15 am, David Robinow wrote:
> On Mon, May 4, 2009 at 2:33 AM, namekuseijin
>
> wrote:
> ls = [(1,2), (3,4), (5, None), (6,7), (8, None)]
> [(x,y) for (x,y) in ls if y]
> > [(1, 2), (3, 4), (6, 7)]
>
> Nope. That filters out 0 as well as None. Not what the OP asked for.
True
On Mon, May 4, 2009 at 2:33 AM, namekuseijin
wrote:
ls = [(1,2), (3,4), (5, None), (6,7), (8, None)]
[(x,y) for (x,y) in ls if y]
> [(1, 2), (3, 4), (6, 7)]
Nope. That filters out 0 as well as None. Not what the OP asked for.
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Snorri H writes:
> On May 3, 6:13 am, Ross wrote:
>> I'm trying to set up a simple filter using a list comprehension. If I
>> have a list of tuples, a = [(1,2), (3,4), (5,None), (6,7), (8, None)]
>> and I wanted to filter out all tuples containing None, I would like to
>> get the new list b = [(
On May 3, 6:13 am, Ross wrote:
> I'm trying to set up a simple filter using a list comprehension. If I
> have a list of tuples, a = [(1,2), (3,4), (5,None), (6,7), (8, None)]
> and I wanted to filter out all tuples containing None, I would like to
> get the new list b = [(1,2), (3,4),(6,7)].
>
> I
>>> ls = [(1,2), (3,4), (5, None), (6,7), (8, None)]
>>> [(x,y) for (x,y) in ls if y]
[(1, 2), (3, 4), (6, 7)]
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This isn't list comprehension, but it's something to keep in mind:
b = filter(lambda x: None not in x, input_list)
On Sat, May 2, 2009 at 10:25 PM, CTO wrote:
> On May 2, 10:13 pm, Ross wrote:
> > I'm trying to set up a simple filter using a list comprehension. If I
> > have a list of tuples,
On May 2, 10:13 pm, Ross wrote:
> I'm trying to set up a simple filter using a list comprehension. If I
> have a list of tuples, a = [(1,2), (3,4), (5,None), (6,7), (8, None)]
> and I wanted to filter out all tuples containing None, I would like to
> get the new list b = [(1,2), (3,4),(6,7)].
try
On May 2, 7:21 pm, Chris Rebert wrote:
> On Sat, May 2, 2009 at 7:13 PM, Ross wrote:
> > I'm trying to set up a simple filter using a list comprehension. If I
> > have a list of tuples, a = [(1,2), (3,4), (5,None), (6,7), (8, None)]
> > and I wanted to filter out all tuples containing None, I wou
On Sat, May 2, 2009 at 7:13 PM, Ross wrote:
> I'm trying to set up a simple filter using a list comprehension. If I
> have a list of tuples, a = [(1,2), (3,4), (5,None), (6,7), (8, None)]
> and I wanted to filter out all tuples containing None, I would like to
> get the new list b = [(1,2), (3,4),
I'm trying to set up a simple filter using a list comprehension. If I
have a list of tuples, a = [(1,2), (3,4), (5,None), (6,7), (8, None)]
and I wanted to filter out all tuples containing None, I would like to
get the new list b = [(1,2), (3,4),(6,7)].
I tried b = [i for i in a if t for t in i is
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