On Thu, 13 Dec 2007 22:52:56 +0100, Bruno Desthuilliers wrote:
> flyfree a écrit :
[snip]
>> What is the difference between "y = [3,4]" and "y[0]=3 y[1] =4 "
>
> In the first case, you rebind the local name y to a new list object -
> and since the name is local, rebinding it only affects the loca
On Tue, 11 Dec 2007 12:51:52 -0800, Nishkar Grover wrote:
> I'm trying to replace a built-in exception type and here's a simplified
> example of what I was hoping to do...
>
>
> >>> import exceptions, __builtin__
> >>>
> >>> zeroDivisionError = exceptions.ZeroDivisionError
I don't know why y
On Mon, 07 Jan 2008 05:21:42 -0800, Mike wrote:
> I want to do something like the following (let's pretend that this is in
> file 'driver.py'):
>
> #!/bin/env python
>
> import sys
>
> def foo():
> print 'foo'
>
> def bar(arg):
> print 'bar with %r' % arg
>
> def main():
> getattr
On Thu, 31 Jan 2008 20:51:23 +0100, Helmut Jarausch wrote:
> Hi,
>
> the following code works fine
>
> def Helper(M) :
>return 'H>'+M
String concatenation is generally considered unpythonic, better use
string interpolation::
'H> %s' % (M,)
> class A(object):
>def __init__(self,Ms
On Thu, 31 Jan 2008 15:30:09 -0600, Terran Melconian wrote:
> * Is there a way to get headings in docstrings?
>
> I want to create my own sections, like "OVERVIEW", "EXAMPLES",
> "AUTHORS", "BUGS", etc. I can't figure out any way to do this. In
> perldoc, I can easily use =head1, but
On Sun, 10 Feb 2008 08:46:24 +0100, David Trémouilles wrote:
[snip]
> I tried:
> >>> map(not, boolean_list)
> but it seems that "not" is not a function.
`not` is not a function, indeed. It is a keyword, allowing you to write
``not x`` instead of ``not(x)``.
You can of course write a function t
On Wed, 12 Mar 2008 01:05:06 +0100, Igor V. Rafienko wrote:
> Hi,
>
>
> I was wondering if someone could help me explain this situation:
>
> h[1] >>> import inspect
> h[1] >>> inspect.getmro(ValueError)
> (, ,
> , , 'object'>)
> h[2] >>> try:
> raise ValueError("argh")
> except object:
>
ds of tracing (apart from debugging, which is rather
unpopular in Python) because you have one *extra* level (the interpreter)
between your machine and your code.
HTH,
Stargaming
--
http://mail.python.org/mailman/listinfo/python-list
On Mon, 17 Mar 2008 10:40:43 +, Duncan Booth wrote:
> Here's a puzzle for those who think they know Python:
>
> Given that I masked out part of the input, which version(s) of Python
> might give the following output, and what might I have replaced by
> asterisks?
>
a = 1
b =
>>
On Mon, 17 Mar 2008 16:03:19 +, Duncan Booth wrote:
> For the answer I actually want each asterisk substitutes for exactly one
> character.
Played around a bit and found that one:
Python 3.0a3+ (py3k:61352, Mar 12 2008, 12:58:20)
[GCC 4.2.3 20080114 (prerelease) (Debian 4.2.2-7)] on linux2
T
On Tue, 25 Mar 2008 05:42:03 -0700, hellt wrote:
[snip]
> usage = "usage: %prog [options]"
> parser = OptionParser(usage)
> parser.add_option("-f", "--file", dest="filename",
> help="executable filename",
> metavar="FILE")
> parser.add_option("-b"
101 - 111 of 111 matches
Mail list logo