I'm trying to compile Python 2.5 on a RHEL system, using "./
configure;make;make install". The build seems to go alright, but the
zlib module is missing.
I've tried the following:
1) Download and build the zlib libraries myself
2) Specify '--without-system-zlib' to ./configure
Neither seems to w
On Nov 19, 2:19 pm, "Martin v. Löwis" <[EMAIL PROTECTED]> wrote:
> > Neither seems to work. What am I missing here?
>
> You forgot to install the zlib header files, which come in
> an RPM provided by Redhat (probably called zlib-dev or some
> such).
>
> Regards,
> Martin
Those headers are already
On Nov 19, 8:22 pm, "Martin v. Löwis" <[EMAIL PROTECTED]> wrote:
> > Those headers are already installed, according to "up2date". Is there
> > a way to specify the header files used?
>
> It will automatically use them if they are good. What's the value of
> ZLIB_VERSION in /usr/include/zlib.h?
>
>
I can't seem to get the zlib module to build on an RHEL box.
I did the following:
1) Download zlib 1.2.3
2) configure;make;make install
3) Download python 2.5.2
4) configure;make;make install
5) >>> import zlib => "ImportError: No module named zlib"
In the make install step for python, I notice t
On Mar 18, 8:42 am, "mhearne808[insert-at-sign-here]gmail[insert-dot-
here]com" <[EMAIL PROTECTED]> wrote:
> I can't seem to get the zlib module to build on an RHEL box.
>
> I did the following:
> 1) Download zlib 1.2.3
> 2) configure;make;make install
>
I have an application where I would like to append to the python path
dynamically. Below is a test script I wrote. Here's what I thought
would happen:
1) I run this script in a folder that is NOT already in PYTHONPATH
2) The script creates a subfolder called foo.
3) The script creates a file cal
Here's a scenario:
import re
m = re.search('e','fredbarneybettywilma')
Now, here's a stupid question:
why doesn't m.groups() return ('e','e','e').
I'm trying to figure out how to match ALL of the instances of a
pattern in one call - the group() and groups() return subgroups... how
do I get my se
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