On Thu, Aug 18, 2016 at 4:51 PM Christopher Crouzet <
christopher.crou...@gmail.com> wrote:
> Aren asked for “any number of resulting lists”, which I interpreted as him
> wanting one list of UVs per shell, whereas the sorted zip version returns a
> single list of ordered UVs with no way to figure
Aren asked for “any number of resulting lists”, which I interpreted as him
wanting one list of UVs per shell, whereas the sorted zip version returns a
single list of ordered UVs with no way to figure out from which shell they
belong to. But that wouldn't be the first time that I misunderstand
somet
On Thu, Aug 18, 2016 at 4:40 PM Justin Israel
wrote:
> On Thu, Aug 18, 2016 at 4:34 PM Christopher Crouzet <
> christopher.crou...@gmail.com> wrote:
>
>> If I'm understanding it right, try this:
>>
>> import itertools
>>
>> def sort_uvs_by_shells(uvs, shells):
>> groups = itertools.groupby(so
On Thu, Aug 18, 2016 at 4:34 PM Christopher Crouzet <
christopher.crou...@gmail.com> wrote:
> If I'm understanding it right, try this:
>
> import itertools
>
> def sort_uvs_by_shells(uvs, shells):
> groups = itertools.groupby(sorted(zip(shells, uvs)), key=lambda x:
> x[0])
> return ((group
If I'm understanding it right, try this:
import itertools
def sort_uvs_by_shells(uvs, shells):
groups = itertools.groupby(sorted(zip(shells, uvs)), key=lambda x: x[0])
return ((group[0], [x[1] for x in group[1]]) for group in groups)
# dictionary version:
# return {group[0]: [x[1]
I realized that subject doesn't sound like it makes any sense - but here is
what I'm trying to do: I am generating two lists...one looks something like
this -
[MeshUV(u'pCubeShape1.map[0]'), MeshUV(u'pCubeShape1.map[1]'),
MeshUV(u'pCubeShape1.map[2]'), MeshUV(u'pCubeShape1.map[3]'),
MeshUV(u'
