If the two multiply operands are int and uint types separately,
the int type will be transformed to uint firstly, which is not the
intent in our code piece. The fix is to add (int64_t) transform
for the uint type before the multiply.
Signed-off-by: Dongxiao Xu dongxiao...@intel.com
---
xen-all.c
On Wed, 22 Aug 2012, Dongxiao Xu wrote:
If the two multiply operands are int and uint types separately,
the int type will be transformed to uint firstly, which is not the
intent in our code piece. The fix is to add (int64_t) transform
for the uint type before the multiply.
Signed-off-by: