On 01.07.2017 22:27, Richard Henderson wrote:
> On 06/25/2017 03:19 PM, Aurelien Jarno wrote:
>> On 2017-06-23 01:12, David Hildenbrand wrote:
>>> If we have for example: r3 contains 0x
>>> ec 33 3f bf 61 55 risbg %r3,%r3,63,191,97
>>>
>>> We want to rotate 33 to the le
On 06/25/2017 03:19 PM, Aurelien Jarno wrote:
On 2017-06-23 01:12, David Hildenbrand wrote:
If we have for example: r3 contains 0x
ec 33 3f bf 61 55 risbg %r3,%r3,63,191,97
We want to rotate 33 to the left and only keep MSB bit 63 of that. So the
result is then exac
On 2017-06-23 01:12, David Hildenbrand wrote:
> If we have for example: r3 contains 0x
> ec 33 3f bf 61 55 risbg %r3,%r3,63,191,97
>
> We want to rotate 33 to the left and only keep MSB bit 63 of that. So the
> result is then exactly 1 (we're reading the sign of the 32
If we have for example: r3 contains 0x
ec 33 3f bf 61 55 risbg %r3,%r3,63,191,97
We want to rotate 33 to the left and only keep MSB bit 63 of that. So the
result is then exactly 1 (we're reading the sign of the 32 bit value).
Current code assumes that we can do that vi
