From: Eduardo Habkost <ehabk...@redhat.com>
The Memory Device size calculation logic is broken when the RAM size is
a multiple of 16GB, making the size of the last entry be 0 instead of
16GB. Fix the logic to handle that case correctly.
Signed-off-by: Eduardo Habkost <ehabk...@redhat.com>
Reviewed-by: Michael S. Tsirkin <m...@redhat.com>
Signed-off-by: Michael S. Tsirkin <m...@redhat.com>
Reviewed-by: Paolo Bonzini <pbonz...@redhat.com>
---
hw/i386/smbios.c | 3 ++-
1 file changed, 2 insertions(+), 1 deletion(-)
diff --git a/hw/i386/smbios.c b/hw/i386/smbios.c
index 024e594..ae7032a 100644
--- a/hw/i386/smbios.c
+++ b/hw/i386/smbios.c
@@ -850,7 +850,8 @@ void smbios_get_tables(uint8_t **tables, size_t *tables_len,
}
#define MAX_DIMM_SZ (16ll * ONE_GB)
-#define GET_DIMM_SZ ((i < dimm_cnt - 1) ? MAX_DIMM_SZ : ram_size % MAX_DIMM_SZ)
+#define GET_DIMM_SZ ((i < dimm_cnt - 1) ? MAX_DIMM_SZ \
+ : ((ram_size - 1) % MAX_DIMM_SZ) + 1)
dimm_cnt = QEMU_ALIGN_UP(ram_size, MAX_DIMM_SZ) / MAX_DIMM_SZ;
--
MST
