On Wed, 19 Jun 2019 at 22:20, Richard Duivenvoorde wrote:
>
> Hi,
>
> got a question from somebody who needed to find the filename of an input
> param in a ProcessingAlgorithm
> (because he is going to read that file again or something like that).
Short answer -- it's not possible, and if you DO
Hi,
l.source() perhaps?
Cheers,
Benoit
On 2019-06-19 14:20, Richard Duivenvoorde wrote:
Hi,
got a question from somebody who needed to find the filename of an
input
param in a ProcessingAlgorithm
(because he is going to read that file again or something like that).
He adds the INPUT via t
Nope,
SOURCE =
which (I think) does not bring you any further:
https://qgis.org/api/classQgsProcessingFeatureSource.html
unless you 'materialize' it to a layer:
https://qgis.org/api/classQgsFeatureSource.html
which is what I actually do below
Regards,
Richard
On 19/06/2019 15.26, info w
Hi,
got a question from somebody who needed to find the filename of an input
param in a ProcessingAlgorithm
(because he is going to read that file again or something like that).
He adds the INPUT via the initAlgorithm function:
self.addParameter(
QgsProcessingParameterFeature
