Thank you very much Osin!
With the example that you kindly provided is more clear. I will try it and
again, thank you very much!
Regards.
El martes, 14 de mayo de 2024, 13:52:16 GMT-6, oisin.kelly.w...@gmail.com
escribió:
get_feature(layer, attribute, value)
This returns a feature. Y
get_feature(layer, attribute, value)
This returns a feature. You can then wrap this in attributes() to return a
dictionary of attribute names and values.
You then add ['attributename'] on end to return value.
So for each table
something like
attributes(get_feature('table1', 'common-id-name',
No it won't work. It's not SQL syntax, it's expression syntax. So you need to
use a function to get the corresponding feature from another layer. Hence
getfeature() or one of the overlay_ functions.
You will end up with a long expression.
Or, you could use sql in dB manager?
Oisin
07570 9774
Hello Oisin,
Thank you for your guidance regarding this topic, and I am sorry if I need
further assistance, but I'm kind of new to QGIS.
Regarding the need to define the layer for each attribute, will it work if I
stated like I had wroten before? i.e.:'Table1.H3centr_h9_cobcubierto' = 1 OR
'Tab
You definitely need to define the layer for each attribute (except the current
layer).
You also need a way to find the comparable record, e.g.
(i) with a common id (use getfeature() to access attribute) or
(ii) spatially use one of the overlay functions.
Oisin
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On 14
Hi,
I have several tables with the same fields, same grid information, but
different field data for each one (information from different providers, let's
say).
Particularly, I have a field with 0 and 1 which represent if each provider
have, or not have coverage in that area.
I want to compare th
