Re: user+foobar@domain.com

2001-02-02 Thread Charles Cazabon
Mike Jackson <[EMAIL PROTECTED]> wrote: > Charles Cazabon wrote: > > > > it might be "~vdomains/.qmail-foonet-default" > I understand what you are talking about. The .qmail-default works for > addresses containing minus signs, not plus signs. That's what I am talking > about :-)) You can cha

Re: user+foobar@domain.com

2001-02-02 Thread Mike Jackson
Charles Cazabon wrote: > > Mike Jackson <[EMAIL PROTECTED]> wrote: > > Thanks for the response. First, the users are all virtual so they can't > > create their own aliases. I could create aliases for them, but I would > > have to create one for each and every foobar style argument. > > Nope. `

Re: user+foobar@domain.com

2001-02-02 Thread Charles Cazabon
Mike Jackson <[EMAIL PROTECTED]> wrote: > Thanks for the response. First, the users are all virtual so they can't > create their own aliases. I could create aliases for them, but I would > have to create one for each and every foobar style argument. Nope. `man dot-qmail` for details. Hint: .q

Re: user+foobar@domain.com

2001-02-02 Thread Mike Jackson
Peter van Dijk wrote: > > On Thu, Feb 01, 2001 at 08:38:00PM +0200, [EMAIL PROTECTED] wrote: > > Hi, > > I have a user asking about the [EMAIL PROTECTED] addressing > > scheme. I guess this would allow the user to pass foobar as a argument > > to procmail, etc. It works in sendmail.. Is this imp

user+foobar@domain.com

2001-02-01 Thread jacksonm
Hi, I have a user asking about the [EMAIL PROTECTED] addressing scheme. I guess this would allow the user to pass foobar as a argument to procmail, etc. It works in sendmail.. Is this implemented in qmail-ldap? Regards, Mike

Re: user+foobar@domain.com

2001-02-01 Thread Peter van Dijk
On Thu, Feb 01, 2001 at 08:38:00PM +0200, [EMAIL PROTECTED] wrote: > Hi, > I have a user asking about the [EMAIL PROTECTED] addressing > scheme. I guess this would allow the user to pass foobar as a argument > to procmail, etc. It works in sendmail.. Is this implemented in > qmail-ldap? Yes, the