> On Wednesday, June 2, 2021, 7:58:54 PM EDT, xiaoyan yu
> wrote:
>
> I am using gmail. Not sure of the configuration of plain text.
> The memory pointed by the char * as the output of Rf_translateChar() is
> actually the string "".
Hi Xiaoyan,
Unfortunately I'm not super familiar with R on W
I am using gmail. Not sure of the configuration of plain text.
The memory pointed by the char * as the output of Rf_translateChar() is
actually the string "".
On Wed, Jun 2, 2021 at 6:09 PM David Winsemius
wrote:
> First; you should configure yopu mail client to send plain text.
>
> Can you ex
Might the new UCRT build help?
https://developer.r-project.org/Blog/public/2021/03/12/windows/utf-8-toolchain-and-cran-package-checks/
On 6/2/21 5:36 PM, Ben Bolker wrote:
On 6/2/21 5:31 PM, Duncan Murdoch wrote:
On 02/06/2021 4:33 p.m., xiaoyan yu wrote:
I have a R Script Predict.R:
On Wed, 2 Jun 2021, 22:31 Duncan Murdoch, wrote:
> On 02/06/2021 4:33 p.m., xiaoyan yu wrote:
> > I have a R Script Predict.R:
> > set.seed(42)
> > C <- seq(1:1000)
> > A <- rep(seq(1:200),5)
> > E <- (seq(1:1000) * (0.8 + (0.4*runif(50, 0, 1
> > L <- ifelse(runif(100
First; you should configure yopu mail client to send plain text.
Can you explain what is meant by:
the characters are unicodes () instead of
utf8 encoding of the korean characters 부실.
As far as I can tell those two unicodes _are_ the utf8 encodings of 부실.
You may need to consult a couple of R
On 6/2/21 5:31 PM, Duncan Murdoch wrote:
On 02/06/2021 4:33 p.m., xiaoyan yu wrote:
I have a R Script Predict.R:
set.seed(42)
C <- seq(1:1000)
A <- rep(seq(1:200),5)
E <- (seq(1:1000) * (0.8 + (0.4*runif(50, 0, 1
L <- ifelse(runif(1000)>.5,1,0)
df <- data.fra
On 02/06/2021 4:33 p.m., xiaoyan yu wrote:
I have a R Script Predict.R:
set.seed(42)
C <- seq(1:1000)
A <- rep(seq(1:200),5)
E <- (seq(1:1000) * (0.8 + (0.4*runif(50, 0, 1
L <- ifelse(runif(1000)>.5,1,0)
df <- data.frame(cbind(C, A, E, L))
load("C:/Temp/tree.RDat
I have a R Script Predict.R:
set.seed(42)
C <- seq(1:1000)
A <- rep(seq(1:200),5)
E <- (seq(1:1000) * (0.8 + (0.4*runif(50, 0, 1
L <- ifelse(runif(1000)>.5,1,0)
df <- data.frame(cbind(C, A, E, L))
load("C:/Temp/tree.RData")# load the model for scoring
Problem:
When running the following commands:
x <- numeric(1e8)
format(object.size(x), units = "kB", standard = "SI")
#> [1] "8e+05 kB"
The object size is returned in scientific notation.
It is natural to assume we could use the argument 'scientific = FASLE'
to solve this.
format(object.size(x),
