Hello,
I am wondering if it is possible to view what variables and vairable
values are stored in the R memory. This to enable debugging of R-scripts
I write.
Sumit
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
http
How do I use the Butterworth filter from the signal library to simulate
an antialias filter, that was analog? I know basically how to use the
butter() function, but am not sure how to apply it to the data. Does
the filter() function work. Can I use the plane='s', i.e. analog
version? Thanks for
Dear R-Users,
Have a question about reading in some data and manipulating dates. I
have a data set in excel which looks like this:
Date PEGETNHSPPTC
13/10/200441.9264.7529.869.27
14/10/200441.9361.79
hello list members,
I am wanting to write a label using the Hmisc package, but inside a
function. Normally I can do:
library(Hmisc)
M=2
label(M)="lab"
#But inside a function the "=" does not work:
Test=function(obj,labe)
{
label(obj)=labe
}
Test(M,"new label")
I usually use the "assign" functio
I'd like to create a small "local" repository that would be used to
install a package for a class of students at their home. I don't want
to upload it to CRAN, as I don't think it should be disseminated at
that level.
What I'd like to do is:
> where="http://mysite.com/";
> install.packages("mypa
Excellent. Thanks!
===
David Kaplan, Ph.D.
Professor
Department of Educational Psychology
University of Wisconsin - Madison
Educational Sciences, Room 1061
1025 W. Johnson Street
Madison, WI 53706
email: [EMAIL PROTECTED]
Web:
Paul,
On 9/11/07, JRG <[EMAIL PROTECTED]> wrote:
> On 11 Sep 2007 at 22:10, Robert A LaBudde wrote:
>
> > I think a ratio of two normals has a Cauchy distribution, which
> > doesn't have a variance (the singularity in the denominator), so the
> > Central Limit theorem does not apply.
> >
>
> The C
The mice package might also be useful, especially the md.pattern function:
http://finzi.psych.upenn.edu/R/library/mice/html/md.pattern.html
James
--
James Reilly
Department of Statistics, University of Auckland
Private Bag 92019, Auckland, New Zealand
On 12/9/07 1:33 PM, Bill Pikounis wrote:
> D
Hello!
I have a problem with integrate() in my function nctspa(). Integrate
produces an error message "evaluation of function gave a result of
wrong length". I don't know what that means. Could anyone suggest me
what is wrong with my function?
These are the examples of function calls that work OK
Hello!
I have a problem with integrate() in my function nctspa(). Integrate
produces an error message "evaluation of function gave a result of
wrong length". I don't know what that means. Could anyone suggest me
what is wrong with my function?
These are the examples of function calls that work OK
Hi All,
I installed R 2.5.1 recently on a PC (Windows XP Professional 2001) and tried
to install some R packages. It took several minutes and gave me the following
message.
> utils:::menuInstallPkgs()
--- Please select a CRAN mirror for use in this session ---
Error in open.connection(fil
On 11 Sep 2007 at 22:10, Robert A LaBudde wrote:
> I think a ratio of two normals has a Cauchy distribution, which
> doesn't have a variance (the singularity in the denominator), so the
> Central Limit theorem does not apply.
>
The Cauchy results if the denominator normal distribution has mean
It even does not have a mean, but this does not
matter: both the numerator and denominator are
asymptotically normal and so the ratio converges (in
distribution) to the ratio of two normals (which
indeed has a Cauchy distribution).
--- Robert A LaBudde <[EMAIL PROTECTED]> wrote:
> I think a ratio
> My question is what is the best OS on PC (laptop) for statistical
> computing and why.
A free/open source *nix operating system is the best you can have
todate, for almost everything, noticeably stability, security,
scalability, networking and development, given that your hardware is
supported a
I think a ratio of two normals has a Cauchy distribution, which
doesn't have a variance (the singularity in the denominator), so the
Central Limit theorem does not apply.
I would suggest using bootstrap resampling to make inferences.
At 08:10 PM 9/11/2007, Moshe wrote:
>For large samples you ha
David,
Frank Harrell's pair of packages Hmisc and Design has some functions
for tabulating, visualizing, and accounting for missing data. I
recommend them as one avenue to investigate. Frank's companion book
"Regression Modeling Strategies" covers their use in-depth.
Hope that helps,
Bill
__
Dear Nilsson,
Thank you very much for your reply which gave me much instruction!
I will have a try on the suggested way from you.
In fact, to get the value of MA is the most important thing for me
in the fitting by this model. And I have thought about the linear model
fitting at first
Dear Professor Lumley.
You are absolutely right! Please allow me to rephrase:
Assuming Professor Murdoch's explanation that theta=c(0.5,0.3,0.5) violate
the constrain while theta1=c(0.5,0.9,0.5) satisfies it.
I did the following
#
> theta=c(0.5,0.3,0.5)
> theta1=c(0.5,0.9,
For large samples you have asymptotic normality!
--- Paul Smith <[EMAIL PROTECTED]> wrote:
> Dear All,
>
> The package mratios can perform inferences for
> ratios of normal means.
> Is there some other package to do the same but with
> non-normal
> populations. Since I have got large samples, an
On 12/09/2007, at 11:33 AM, David Kaplan wrote:
> I did. If you don't want to answer, then your unhelpful suggestions to
> yourself.
This is uncalled for. Bert Gunter's response was perfectly reasonable.
Read the posting guide.
cheers,
I did. If you don't want to answer, then your unhelpful suggestions to
yourself.
===
David Kaplan, Ph.D.
Professor
Department of Educational Psychology
University of Wisconsin - Madison
Educational Sciences, Room 1061
1025 W. Jo
Please use R's existing search tools before posting:
RsiteSearch("imputation")
RsiteSearch("missing data imputation")
etc.
Bert Gunter
Genentech Nonclinical Statistics
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of David Kaplan
Sent: Tuesday, Septem
Hi all,
I'm looking for a contributed package that can provide a detailed
account of missing data patterns and perhaps also provide imputation
procedures, such as mean imputation or hot deck imputation and the like.
Is there anything out there?
Thanks in advance,
David
--
===
Dr. Paul Murrell will present his course "Introduction to R
- Data Handling" online at statistics.com Sept. 28 - Oct.
26. Participants can ask questions and exchange comments
with Dr. Murrell via a private discussion board throughout
the period.
This course will provide an easy introduction to R
What operating system are you running on? Do you know if you have run
out of physical memory? If on Windows, what do you have
'--max-mem-size' set to on the command line invoking the RGUI?
On 9/11/07, Sasse, Mark <[EMAIL PROTECTED]> wrote:
> I have been using R off an on for approximately 3 mont
This is what I might do:
> y <- rchisq( 1000, df=10, ncp=2 )
> library( stats4 )
> res <- mle( function(x,z) -sum( dchisq(y, x, z , log=TRUE ) ), start=list(
> x=5, z=5 ) )
> coef(res)
x z
10.355711 1.586123
>
> ## or just to keep clear of boundary constraints:
>
> res <- mle(
On my linux machine (Ubuntu Feisty on i-686) this works:
./configure --with-blas="lf77blas -latlas"
Yuelin.
-- K Vanw wrote --|Tue (Sep/11/2007)[03:56]|--:
I'd like to build R using my optimized blas and lapack libraries. It seems
know matter what I do, the configure script uses the b
Looks like the list-server didn't like whatever gmail does to the
formating. Sorry. So here's my post in plain text:
On 9/11/07, K Vanw <[EMAIL PROTECTED]> wrote:
> I'd like to build R using my optimized blas and lapack libraries. It seems
> know matter what I
> do, the configure script uses the
I'd like to build R using my optimized blas and lapack libraries. It seems
know matter what I do, the configure script uses the blas supplied with the
source. My blas and lapack libraries are in /usr/local/atlas/lib. How can I
get configure to use these?
[[alternative HTML version deleted]
Hi, I have written out the log-likelihood function to fit some data I have
(called ONES20) to the non-central chi-squared distribution.
>library(stats4)
>ll<-function(lambda,k){x<-ONES20;
25573*0.5*lambda-25573*log(2)-sum(-x/2)-log((x/lambda)^(0.25*k-0.5))-log(besselI(sqrt(lambda*x),0.5*
I have been using R off an on for approximately 3 months. As such, I am
not very knowledgeable about coding in R. Currently I am running into
the following problem. I'm using scan to make data available in R. The
data I'm loading consists of over 400,000 records with 5 data fields.
After runnin
Does anybody have any experience fitting data to the non-central chi-squared or
chi-squared distribution? I am trying to fit some data to this distribution but
there is error after error.
audaces fortuna iuvat
-
[[alternative HTML version deleted]
On 9/11/07, Leeds, Mark (IED) <[EMAIL PROTECTED]> wrote:
> Thanks Deepyan. I am doing it in source but I didn't realize that that
> was a function. Thanks so much.
You might try source(..., echo=TRUE) if you want to mimic console evaluation.
-Deepayan
Ok, of course you were right. As Stefan pointed out, it was a
problem of the type of the vector: it was a factor and hence the
quantile was not what expected. Thank you all!!
Jose Luis Aznarte M. escribió:
> Hi there! Still struggling to translate Matlab code into R's tsDyn package.
> Here i
Thanks Deepyan. I am doing it in source but I didn't realize that that
was a function. Thanks so much.
-Original Message-
From: Deepayan Sarkar [mailto:[EMAIL PROTECTED]
Sent: Tuesday, September 11, 2007 12:38 PM
To: Leeds, Mark (IED)
Cc: [EMAIL PROTECTED]
Subject: Re: [R] xyplot questio
On 9/10/07, jim holtman <[EMAIL PROTECTED]> wrote:
> I am using 'xyplot' in lattice to plot some data where the x-axis is a
> POSIXct date. I have data which spans a 6 month period, but when I
> plot it, only the last month is printed on the right hand side of the
> axis. I would have expected th
On Tue, Sep 11, 2007 at 07:09:24PM +0200, Jose Luis Aznarte M. wrote:
> Thank you all! But the problem is that quantile() returns "how many
> data" are greater than p percent, and not a value in the domain of the
> vector under scrutiny. For example, I have a vector
not quite, quantile retur
On 9/11/07, Leeds, Mark (IED) <[EMAIL PROTECTED]> wrote:
> I have the code below and it works fine if I print the xyplot but if I
> take the print out, then I just get a blank
> pdf. The same holds if I just send the plot to the console without the
> print ( I get nothing ). My question is whether
Try
quantile(x, .1, type=1)
or read
?quantile
for other options.
url:www.econ.uiuc.edu/~rogerRoger Koenker
email[EMAIL PROTECTED]Department of Economics
vox: 217-333-4558University of Illinois
fax: 217-244-6678
Original Message
Subject: Re: [R] Percentiles in R
From: Jose Luis Aznarte M. <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Date: 11.09.2007 19:09
> Thank you all! But the problem is that quantile() returns "how many
> data" are greater than p percent, and not a value in the dom
Hi
He is actually plotting DM matrix against default values [0,1]. So what he
needs to do is to change y to c(1,10) and x to seq(1,20,2) to enable his
code work. And even in that case there is not possible AFAIK to control
exact labeling of axes as they are internaly recalculated to [0,1] value
Thank you all! But the problem is that quantile() returns "how many
data" are greater than p percent, and not a value in the domain of the
vector under scrutiny. For example, I have a vector
> x
[1] "-0,39559" "1,1916""0,23214" "1,656" "-0,3439" "-0,50568"
[7] "0,52281" "0,
Hi
Gonçalo Ferraz <[EMAIL PROTECTED]> napsal dne 11.09.2007 16:35:57:
> Thanks! What is the easiest way of declaring an empty data frame. Is
there
> anything similar to:
> matrix(0,x,y)
> In the help files, I am only finding longer commands that ask me to
specify
> each individual column.
Yo
Original Message
Subject: [R] xyplot question
From: Leeds, Mark (IED) <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Date: 11.09.2007 18:00
>
> load("stocks.dat")
>
> pdf('temp.pdf', width=10, height=8)
>
does ist work with postscript?
something like:
postscript("temp.ps", width =
This email may be an advertisement or solicitation. If you do not want
to receive marketing messages from WebEx click here | view Privacy
Policy
-WEBEX:enUS:sdFj9CMZvQ8KWIBz21EK7I-
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listi
When using cl_medoid to create a consensus clustering I've noticed that the
list element in the resulting object containing the cluster assignments by case
will switch between the [1] and [3] positions. This has happened when
re-running the code without changes.
Has anyone else experienced this
I have the code below and it works fine if I print the xyplot but if I
take the print out, then I just get a blank
pdf. The same holds if I just send the plot to the console without the
print ( I get nothing ). My question is whether this is always
the case with xyplot or is there something wrong w
Hola Jose Luis,
Sure, you can use quantile(). Use the probs argument. For example, to
get the median do
quantile(X,probs=0.5).
Do ?quantile to learn about the different type of quantiles calculated
by the funcion.
Saludos,
Julian
Jose Luis Aznarte M. wrote:
> Hi there! Still struggling t
It looks like
prctile(X,p) is the same as quantile(X,p)
i.e
x<-0:100
quantile(x,0.5) is the median(x)
and
quantile(x,0.1)=10 is the value that is greater than 10% percent of the
values in X
"José Luis Aznarte M." wrote:
>
> Hi there! Still struggling to translate Matlab code into R's tsDyn
>
Fiona Callaghan wrote:
> Hi Chris. Thanks for replying. I want to take the pruned list of
> subtrees, and select the final tree from this list using a bootstrap
> technique (rather than cross validation). I think, and I could be wrong,
The result will be very poor predictive accuracy on new sa
There is an error in your code:
in persp(x , y , z) the length of x is the number of rows of z, the length
of y is the number of columns of z,
You should also name the rows and columns in z with x and y
Economics Guy wrote:
>
> I am having some trouble getting the persp() package to change th
Hi there! Still struggling to translate Matlab code into R's tsDyn package.
Here is my question: Is there in R an equivalent function to Matlab's
prctile()? To the moment I thought it was quantile(), but I just
realized I was wrong. The definition of the Matlab function:
prctile
Percentiles of a
Hi all,
Another good alternative is VIM www.vim.org, vim Rules :D
Too, check it in the historic list:
http://tolstoy.newcastle.edu.au/R/help/06/05/26548.html
cheerios
..-..
Josue
On 9/11/07, Stefan Grosse <[EMAIL PROTECTED]> wrote:
> I use emacs with the ess extension on Fedora 7. Emacs is
On Tue, 2007-09-11 at 08:36 -0500, [EMAIL PROTECTED] wrote:
> Hello everyone,
>
> I wanted to ask what will be a good editor to write R scripts in Fedora 7.
Emacs + ESS is my editor of choice. There is more info here:
http://ess.r-project.org/
and a list of editors and the like can be found he
I use emacs with the ess extension on Fedora 7. Emacs is easily
installable via yum and for ESS (emacs speaks statistics) you could use
the Moertel rpms: http://community.moertel.com/ss/space/RPMs
To edit: save a "buffer" as *.r, then some buttons appear which enable
you to start an R process and
Did you consider R GUI project?
http://www.sciviews.org/_rgui/
I used kate on Fedora, my general impression is not bad.
But one should be careful with running R session inside kate.
I killed it accidentally several times without saving of the state, when
exited the editor.
Antonio_Paredes wro
Fedora 7 is a linux distribution
On 9/11/07, Paul Smith <[EMAIL PROTECTED]> wrote:
> On 9/11/07, [EMAIL PROTECTED]
> <[EMAIL PROTECTED]> wrote:
> > I wanted to ask what will be a good editor to write R scripts in Fedora 7.
>
> Tell us first what is your operating system.
>
> Paul
>
> _
On 9/11/07, [EMAIL PROTECTED]
<[EMAIL PROTECTED]> wrote:
>
> Fedora 7
What about kate then?
Paul
> "Paul Smith" <[EMAIL PROTECTED]>
> Sent by: [EMAIL PROTECTED]
>
> 09/11/2007 09:25 AM
>
> To [EMAIL PROTECTED]
>
> cc
>
>
> Subject Re: [R] Editor for R under Fedora 7
>
>
>
>
>
>
>
>
> On 9/11/07
On Mon, 10 Sep 2007, Yuchen Luo wrote:
> Dear Professor Murdoch.
> Thank you for your help!
> 1. I believe c(0.5,0.3,0.5) satisfies the constrain because I did the
> following experiment
> ui=-1*ui
> ci=-1*ci
> constrOptim(c(0.5,0.3,0.5), f=fit.error, gr=fit.error.grr, ui=ui,ci=ci)
>
> The same er
On 9/11/07, [EMAIL PROTECTED]
<[EMAIL PROTECTED]> wrote:
> I wanted to ask what will be a good editor to write R scripts in Fedora 7.
Tell us first what is your operating system.
Paul
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/li
This is what I get:
> unclass(strptime("1970-01-01", "%Y-%m-%d", tz="GMT") + 0)
[1] 0
attr(,"tzone")
[1] "GMT"
> unclass(strptime("1970-01-01", "%Y-%m-%d", tz="EST5EDT") + 0)
[1] 18000
attr(,"tzone")
[1] "EST5EDT"
> R.version.string # Windows Vista
[1] "R version 2.6.0 alpha (2007-09-06 r42791)"
Hi all,
I tried to do this:
unclass(strptime("1970-01-01", "%Y-%m-%d", tz="") + 0)
[1] 18000
I thought the starting time is zero? Same result returns if I do:
unclass(strptime("1970-01-01", "%Y-%m-%d", tz="EDT") + 0)
unclass(strptime("1970-01-01", "%Y-%m-%d", tz="EST") + 0)
unclass(st
Hi
Although not specifically stated in help page, matrix is a vector with dim
attribute. Therefore it can have only one type of values either numeric or
character or logical or factor. So if you want textual and numeric values
you probably have to stick with data frames.
Regards
Petr
[EMAIL PR
Hi,
I would like to store some text and decimal values in the following
form:
namedec.val dec.val ... dec.val
namedec.val dec.val ... dec.val
...
namedec. valdec.val ... dec.val
To do so, I created a matrix of the necessary size (x row per y cols)
with the com
Hi Chris. Thanks for replying. I want to take the pruned list of
subtrees, and select the final tree from this list using a bootstrap
technique (rather than cross validation). I think, and I could be wrong,
that bagging takes a bunch of bootstrap samples, grows one tree per
boostrap sample and
Hello everyone,
I wanted to ask what will be a good editor to write R scripts in Fedora 7.
Tony
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
Dear R users,
Yesterday, I updated R 2.4.1 to R 2.5.1 on Unbuntu 7.0.4 successfully.
I also update the JGR to 1.5-6 according to
http://rosuda.org/JGR/linux.shtml (after "sudo update-java-alternatives
-s java-6-sun", I cannot do "sudo update-java-alternatives -s
java-1.6.0-sun"). I can use the
On 9/11/2007 8:54 AM, kevinchang wrote:
> I heard that if-loop may result in errors if we are going to loop for a lot
> of times.
I don't know what you mean by an "if-loop", but if doing it lots of
times caused an error, that would likely be a bug in R. And I know of
no such bug.
> And sum()
Hello Moshe,
Replication in this sense means that I want to use the parameters specified
in a1 b1, and c1 to produce a set of simulated responses, coded as a 0 or a
1, and do this many times. So a1, b1, and c1 do not change, and I would
like to produce 30 different sets of simulated responses, a
I heard that if-loop may result in errors if we are going to loop for a lot
of times. And sum() can be the alternative way to do this kind of hugbe
looping. But I haven't figure out how . Can someone please give me an
concrete example of using sum() for this purpose?
--
View this message in con
Hi, I would like to run an ANOVA with repeated measures with both a
between subjects variable and within subjects (repeated measures)
variables. I know how to do this when I have equal numbers of
subjects in both groups (i.e., balanced design). That has been very
well documented by Baron, for exa
Here is a solution using character manipulation. Noting that month.name
is built into R we paste together the character string:
"January Februrary ... December January ... December"
Then we use perl style ungreedy matching to get the shortest substring
matching the indicated expression then splitt
Download the multcomp package for multiple comparisons.
You might also want to use the MMC functions in the HH package
to display the contrasts.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
Hi Vladimir
You may well be right and it is better, or at least better practice. But
I have a feeling I tried it and it was not as successful, but I cannot
remember why. Perhaps it was because when installing new packages they
were not installed in that (USER) directory?
JS
-Original Mess
Ptit_Bleu wrote:
> Hi,
>
> just to say that I "solved" my problem. I wrote "solved" because all I did
> was to uninstall R and the DBI and RMySQL libraries and then install
> everything again.
> The only change is that I used another RMySQL.zip file found at this address
> :
> http://www.bioconduct
Duncan Murdoch-2 wrote:
>
> On 11/09/2007 6:36 AM, Arun Kumar Saha wrote:
>> Hi all,
>>
>> I am looking for a function for following calculation.
>>
>> start.month = "July"
>> end.month = "January"
>>
>> months = f(start.month, end.month, by=1)
>>
>> * f is the function that I am looking for
On 11/09/2007 6:36 AM, Arun Kumar Saha wrote:
> Hi all,
>
> I am looking for a function for following calculation.
>
> start.month = "July"
> end.month = "January"
>
> months = f(start.month, end.month, by=1)
>
> * f is the function that I am looking for.
>
> Actually I want to get months = c(
On Mon, 10-Sep-2007 at 07:26PM -0400, Gabor Grothendieck wrote:
|> My sense is that R users are even split between UNIX and Windows
|> users so either will do in terms of the larger community.
|>
|> Some R packages may not be avaliable on every platform or will
|> be available on one platform bef
On 9/11/07, Peter Dalgaard <[EMAIL PROTECTED]> wrote:
> Ptit_Bleu wrote:
> > Hi Peter,
> >
> > I really have no idea about your comment. I was so happy to be able to
> > connect to my database ...
> >
> > In fact I found the address in the following post :
> > https://stat.ethz.ch/pipermail/r-help/
Hi all,
I am looking for a function for following calculation.
start.month = "July"
end.month = "January"
months = f(start.month, end.month, by=1)
* f is the function that I am looking for.
Actually I want to get months = c("July", "August",.."January")
If start.month = 6 and end.
Dear Warren,
I had similar problems, this is (roughly) how I solved it translated to your
problem:
x <- c(-0.06,-0.04,-0.025,-0.015,-0.005,0.005,0.015,0.025,0.04,0.06)
y <- c(1866760,1457870,1314960,1250560,1184850,1144920,
1158850,1199910,1263850,1452520)
dafa<-data.frame(x,y)
plot(x,y)
Ptit_Bleu wrote:
> Hi Peter,
>
> I really have no idea about your comment. I was so happy to be able to
> connect to my database ...
>
> In fact I found the address in the following post :
> https://stat.ethz.ch/pipermail/r-help/2007-August/138142.html
>
> Do you think I can't use it freely ? :(
>
Dear All,
The package mratios can perform inferences for ratios of normal means.
Is there some other package to do the same but with non-normal
populations. Since I have got large samples, an asymptotic procedure
would be fine.
Thanks in advance,
Paul
___
Do you need precisely RMySQL and DBI?
RODBC can successfully replace this.
I used RMySQL some time ago, but then, after the next version upgrade it
stopped working.
Switching to RODBC was almost without pain, since function names were quite
similar.
I simply replaced dbGetQuery with sqlGetQuery
Hi Peter,
I really have no idea about your comment. I was so happy to be able to
connect to my database ...
In fact I found the address in the following post :
https://stat.ethz.ch/pipermail/r-help/2007-August/138142.html
Do you think I can't use it freely ? :(
Thanks for your comments,
Ptit
I think using R_LIBS_USER is better.
>From ?.libPaths:
The library search path is initialized at startup from the environment
variable R_LIBS (which
should be a semicolon-separated list of directories at which R library trees
are rooted) followed by those in environment variable R_LIBS_USER.
Hi,all guy,
I am doing ANOVA of some data with one factor,and the result
shows factor's effect is not significant,but through some plots ,I
know maybe some levels of the factor is significant,so I need to do
multiple contrast to tell me which levels ,What I can do?
thanks a lot!
Hi
I use the following method which works well for me.
I create a directory to hold the installed packages e.g. C:\Program
Files\R\mylibrary
Then in my C:\Program Files\R\R-2.5.1\.Renviron file I have a line as
follows:
R_LIBS=C:/PROGRA~1/R/mylibrary
(I think you have to use Windows short
min(x[x>0])
dxc13 wrote:
>
> useRs,
>
> I am looking to find the minimum positive value of some data I have.
> Currently, I am able to find the minimum of data after I apply some other
> functions to it:
>
>> x
> [1] 1 0 1 2 3 3 4 5 5 5 6 7 8 8 9 9 10 10
>
>> sort(x)
> [1]
Hi,
just to say that I "solved" my problem. I wrote "solved" because all I did
was to uninstall R and the DBI and RMySQL libraries and then install
everything again.
The only change is that I used another RMySQL.zip file found at this address
:
http://www.bioconductor.org/packages/2.0/extra/bin/w
Dear R-users,
I want to compose a new table (a presence/absence matrix of species in
regions) by matches between two data frames.
The first data frame has the species as header and the habitats in
which they occure as elements.
The second data frame has the regions as header and the occuring
habit
This was discussed here sometime ago.
Several variants are possible.
You can install the new version of R over the old one, in the same folder,
this preserves the installed packages. At least, this works fine for me on
Windows.
You can also store your list of packages in a simple R script and ex
92 matches
Mail list logo
