Further to Duncan's comments, you can control factor codings via
options(contrasts=), by setting contrasts() on the factor and via C().
This does enable you to code an ordered factor as a linear term, for
example.
The only place I know that this is discussed in any detail is in Bill
Venables' a
errata: fcsPar[k+1]
On Jan 6, 2008, at 1:50 AM, Benilton Carvalho wrote:
make "k = 100", note that you're doing fcsPar[k]-fcsPar[k+10]
note fcsPar has length 100...
therefore valueDiff becomes NA.. and the if() statement fails.
b
On Jan 6, 2008, at 1:16 AM, Nicholas Crosbie wrote:
Can a
make "k = 100", note that you're doing fcsPar[k]-fcsPar[k+10]
note fcsPar has length 100...
therefore valueDiff becomes NA.. and the if() statement fails.
b
On Jan 6, 2008, at 1:16 AM, Nicholas Crosbie wrote:
Can any explain the following error:
Error in if ((seedCount <= seedNumber) && (
Can any explain the following error:
Error in if ((seedCount <= seedNumber) && (valueDiff >
sup)) { :
missing value where TRUE/FALSE needed
which I get upon running this script:
seedNumber <- 10
seeds <- array(dim = seedNumber)
seedCount <- 1
maxValue <- 100
sup <- maxValue / 2
fcsPar <- a
Can any explain the following error:
Error in if ((seedCount <= seedNumber) && (valueDiff >
sup)) { :
missing value where TRUE/FALSE needed
which I get upon running this script:
seedNumber <- 10
seeds <- array(dim = seedNumber)
seedCount <- 1
maxValue <- 100
sup <- maxValue / 2
fcsPar <-
Dear Prof. Vincent Goulet,
Vincent Goulet wrote:
>
> If there is any interest, I might prepare an English version of
> the document.
>
Maybe a little little late, but if by chance you happened to create the
English version of the document, I would also be interested in reading it.
Thank you
On 05/01/2008 7:16 PM, David Winsemius wrote:
> David Winsemius <[EMAIL PROTECTED]> wrote in
> news:[EMAIL PROTECTED]:
>
>> I have a variable which is roughly age categories in decades. In the
>> original data, it came in coded:
>>> str(xxx)
>> 'data.frame': 58271 obs. of 29 variables:
>> $ i
On Jan 5, 2008 7:45 PM, Milton Cezar Ribeiro <[EMAIL PROTECTED]> wrote:
> Dear all,
>
> I have a dataset which I need to estimate the regression model and plot the
> estimated curve two other curves with low and high confidence interval
> (CI=95%). How can I do that?
The easiest way is to use th
Dear all,
I have a dataset which I need to estimate the regression model and plot the
estimated curve two other curves with low and high confidence interval
(CI=95%). How can I do that?
x<-1:100
y<-x^0.2+rnorm(100,0.1,0.1)
mod<-glm(y~log(x))
plot(y~x)
lines(predict(mod)~x,col=2)
Kind regards,
Hi all,
A good new year for everybody.
Could somebody help me on a question?
The Singular Value Decomposition of a matrix A gives A = U * D * t(V)
I A is a M X N matrix, U is the left singular matrix (M X N), D is a
diagonal singular values matrix (N X N) and V is the transpose right
singular
David Winsemius <[EMAIL PROTECTED]> wrote in
news:[EMAIL PROTECTED]:
> I have a variable which is roughly age categories in decades. In the
> original data, it came in coded:
>> str(xxx)
> 'data.frame': 58271 obs. of 29 variables:
> $ issuecat : Factor w/ 5 levels "0 - 39","40 - 49",..: 1 1
I have a variable which is roughly age categories in decades. In the
original data, it came in coded:
> str(xxx)
'data.frame': 58271 obs. of 29 variables:
$ issuecat : Factor w/ 5 levels "0 - 39","40 - 49",..: 1 1 1 1...
snip
I then defined issuecat as ordered:
> xxx$issuecat<-as.ordered(x
This is really great. It will be very usefull. Thanks for that!
Fernando Mayer.
On Jan 5, 2008 12:10 PM, Tyler Smith <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I've added several pages of worked solutions for the book Ecological
> Detective by Hilborn and Mangel to the R-wiki. My hope is that this
> wi
You might want to descibe what uses you expect to have
for SAS and/or R. It might make it easier for people
to make specific recommendations.
Personally I like the graphics, ease of writing
functions, and general ease of data manipulation.
--- Alberto Monteiro <[EMAIL PROTECTED]> wrote:
> I nee
Gang Chen <[EMAIL PROTECTED]> wrote in
news:[EMAIL PROTECTED]:
> Suppose I have a two-way table of nominal category (party
> affiliation) X ordinal category (political ideology):
>
> party affiliation X (3 levels) - democratic, independent, and
> republic
> political ideology Y (3 levels) - l
Colin Robertson wrote:
> Dear List,
>
>
>
> I am trying to assess the prediction accuracy of an ordinal model fit with
> LRM in the Design package. I used predict.lrm to predict on an independent
> dataset and am now attempting to assess the accuracy of these predictions.
>>From what I have rea
Hi,
I've added several pages of worked solutions for the book Ecological
Detective by Hilborn and Mangel to the R-wiki. My hope is that this
will be of use to others working through this book without access to a
local expert. I am certainly not an expert, local or otherwise.
I have posted soluti
On Sat, 5 Jan 2008, xinyi lin wrote:
> Hi,
>
> I want to do a global likelihood ratio test for the proportional odds
> logistic regression model and am unsure how to go about it. I am using
> the polr() function in library(MASS).
>
> 1. Is the p-value from the likelihood ratio test obtained by
> a
csiro.au> writes:
...
> 1) I can't seem to send variables classed as factors (Month), is there a
> way do this?
You can not use factors per se in BUGS. You have to convert them to numeric
(integer) variables before.
> 2) Checking the Log in WinBUGS I can see that the model is Syntactically
> co
Hi,
I want to do a global likelihood ratio test for the proportional odds
logistic regression model and am unsure how to go about it. I am using
the polr() function in library(MASS).
1. Is the p-value from the likelihood ratio test obtained by
anova(fit1,fit2), where fit1 is the polr model with o
marcg said the following on 1/5/2008 3:48 AM:
> hello
>
> could anyone tell my, why I do not suceed with mfrow?
>
> par(mfrow=c(4,4))
>
> for (i in 5:17){
> levelplot(maxwater[,i]~maxwater$V1*maxwater$V2, col.regions=whiteblue(5),
> xlab="", cuts=4)
> }
>
> Thanks
>
> Marc
> --
>
Johannes Graumann wrote:
> Dear all,
>
> As you can see from the attachment I'm using R to automatically annotate
> peptide fragmentation mass spectra, which are represented by impulse plots.
> I'd like to poll you on approaches of how to deal as generally as possible
> with the two biggest annota
hello
could anyone tell my, why I do not suceed with mfrow?
par(mfrow=c(4,4))
for (i in 5:17){
levelplot(maxwater[,i]~maxwater$V1*maxwater$V2, col.regions=whiteblue(5),
xlab="", cuts=4)
}
Thanks
Marc
--
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Sorry, I realized that somehow the message got truncated. Here is the
remaining part of the SAS output:
Solutions for Fixed Effects:
Effect DIST DW ELI SEX SEAS Estimate Std. Error
DF t Value Pr > |t|
Intercept
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