Hello R,
Is there a package to perform Polynomial goal programming in R?
BR, Shubha
Shubha Karanth | Amba Research
Ph +91 80 3980 8031 | Mob +91 94 4886 4510
Bangalore * Colombo * London * New York * San José * Singapore *
www.ambaresearch.com
This e-mail may contain confidential a
Thanks Chuck
With your help I managed to write the code as I wanted it.
The result looks like this:
dafSamp <-
data.frame(cbind(c(1972,1984,1969,1976,1999,1996,1976,1984,1976),c(117,7
3,92,113,80,78,98,106,99)))
dafSamp$Ay <- ave(dafSamp$X2, dafSamp$X1, FUN=mean)
dafSamp$AA <- dafSamp$X2 * (mean(
Hello to everyone,
I am trying to compute a mean and show it to the screen and then save to later
be used
as a boxplot.I have used the following code:
dat<-read.table(file="C:\\Documents and Settings\\Owner\\My
Documents\\Yeast\\Yeast.txt",header=T,row.names=1)
file.show(file="C:\\Documents and S
See the summary() method. It labels the weights for you.
On Tue, 10 Jun 2008, wmg wrote:
In MASS there is a nnet() function which returns, among other things, a wts[]
vector giving the weights in the neural network. However, in neither the book
nor in the online documentation for the routine
On Tue, 10 Jun 2008, Barry Rowlingson wrote:
Hua Li wrote:
Hi All,
I have a problem of putting long titles on a graph:
for example,
x= seq(1:100)
y=seq(1:100)
plot(x,y,main="p=0.05:A-B=3,C-D=10,D-E=100,A-F=2,AFR-E=3,ACE-D=1,ADEF-M=0,AED-E=10,DE-F=3,AB-J=4,AC-J=10,ED-F=1,ED-B=4,AF-B=10,CD-S=1
DrakeGis wrote:
WinBugs doesn't run in LINUX. Neither OpenBugs.
There is a long thread ending on
http://tolstoy.newcastle.edu.au/R/e2/devel/07/08/4121.html
which documents how many people helped me get
OpenBUGS running under Linux (embedded in an
R package, of course).
HTH,
Tobias
Drake
Hi everyone.
I want to solve the following problem. I have a data.frame and I
create a dotplot using lattice.
Then I want to use the grid-package to create a combined graphic which
contains the dotplot as well as a textplot() (using package gplots) of
the data.frame next to the dotplot.
Example
Hi!
Is there any possibilities to do multiple classification analysis (MCA)
in R? (MCA examines the relationships between several categorical
independent variables and a single dependent variable, and determines
the effects of each predictor before and after adjustment for its
inter-correlat
Hi,
I was wondering if someone could give a brief, big picture overview of the
difference between the two optimization functions nlm and nlminb. I'm not
familiar with PORT routines, so I was hoping someone could give an explanation.
Thanks,
Angelo
__
Hello,
I have consciously avoided using step() for model simplification in favour
of manually updating the model by removing non-significant terms one at a
time. I'm using The R Book by M.J. Crawley as a guide. It comes as no
surprise that my analysis does proceed as smoothly as does Crawley's a
Hi, All:
Is there a way to get random effects for ARMA parameters?
Consider the following example from the 'corARMA' help page:
fm1Ovar.lme <- lme(follicles ~ sin(2*pi*Time) + cos(2*pi*Time),
data = Ovary, random = pdDiag(~sin(2*pi*Time)))
fm5Ovar.lme <- update(fm
If you can define a distance between two vectors (where each one has some
numerical and some categorical coordinates) then you can proceed with any
clustering algorithm.
One possibility to get such a distance is to use RandomForest which can produce
a proximity matrix which can be turned into d
Try hclust with daisy in cluster package.
Cheers,
Jin
Jin Li, PhD
Spatial Modeller/
Computational Statistician
Marine & Coastal Environment
Geoscience Australia
Ph: 61 (02) 6249 9899
Fax: 61 (02) 6249 9956
email: [EMAIL PROTECTED]
---
Hi,
Are there any algorithms that handle numeric and factor variables
together in a cluster analysis?
Thank you,
Nagu
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-projec
Thanks to all for the advice. Took me a bit to get back to this, but
the following worked just fine for me with my 64-bit Ubuntu 8.04 OS:
R CMD INSTALL Rmpi_0.5-5.tar.gz --configure-args=--with-mpi=/usr/lib64/openmpi
On Thu, Jun 5, 2008 at 3:23 AM, Paul Hewson <[EMAIL PROTECTED]> wrote:
> Or (mor
Martin
I know you and Brian have been discussing this issue, and Brian
would officially declare it a 'buglet' if he used that word, but
for completeness (I should have done this anyway; my oversight):
> What are the exact platform details?
> sessionInfo()
R version 2.7.0 (2008-04-22)
i486-pc-l
I am using Sweave to generate a document in which ggplot2 figures are
embedded. I am using the following code in a particular plot within a
subfloat environment:
<>=
print(qplot(bosday2, Arday2, data= arbostimearonlyNArm,
colour=factor(bos2), shape=factor(bos2), size=factor(cumARscore),
position="
Hi
On 11/06/2008 at 10:56 a.m., "Ranney, Steven" <[EMAIL PROTECTED]>
wrote:
> I'm tyring to fit a relatively simple nls model to some data, but keep coming
> up against the same error (code follows):
>
> Oto=nls(Otolith ~ Linf*(1-exp(-k(AGE-to))),
> data = ages,
> start = list(Linf=100
On Tue, 2008-06-10 at 16:56 -0600, Ranney, Steven wrote:
> I'm tyring to fit a relatively simple nls model to some data, but keep coming
> up against the same error (code follows):
>
> Oto=nls(Otolith ~ Linf*(1-exp(-k(AGE-to))),
> data = ages,
> start = list(Linf=1000, k=0.1, to=0.1),
I'm tyring to fit a relatively simple nls model to some data, but keep coming
up against the same error (code follows):
Oto=nls(Otolith ~ Linf*(1-exp(-k(AGE-to))),
data = ages,
start = list(Linf=1000, k=0.1, to=0.1),
trace = TRUE)
The error message I keep getting is "Error in eva
I am using Sweave to generate a document in which ggplot2 figures are
embedded. I am using the following code in a particular plot within a
subfloat environment:
<>=
print(qplot(bosday2, Arday2, data= arbostimearonlyNArm,
colour=factor(bos2), shape=factor(bos2), size=factor(cumARscore),
position="
Try plotmeans in the gplots package.
On Tue, Jun 10, 2008 at 5:14 PM, stephen sefick <[EMAIL PROTECTED]> wrote:
> I can not seem to get a ylim argument into plotMeans() is there anyway to do
> this.
> thanks in advance
>
> Stephen
>
> --
> Let's not spend our time and resources thinking about thin
The reshape package will definitely do what you want. Cast will
automatically fill in an missing spots with NAs, and you'll just need
something like the following for your aggregation function:
last <- function(x) x[length(x)]
You can find out more about reshape at http://had.co.nz/reshape
Hadl
The reshape function and even more powerful reshape package will probably do
what you want.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801) 408-8111
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Be
I can not seem to get a ylim argument into plotMeans() is there anyway to do
this.
thanks in advance
Stephen
--
Let's not spend our time and resources thinking about things that are so
little or so large that all they really do for us is puff us up and make us
feel like gods. We are mammals, and
WinBugs doesn't run in LINUX. Neither OpenBugs.
>
> DrakeGis wrote:
>> Hi all,
>> I observed that the 'link' between R and BUGS (winBugs/linBugs) has
>> totally disappeared. I'm wondering what package can be use to run
>> bayesian models specified using the BUGS language in R (specifically
>> und
I have this frame in the long format which I want to convert to wide
format. There are three columns in the frame, the id for the rows in
the wide format, the name of the column where the final value (the third
column) is to be placed.
The complicating factor is that the long format is not co
Thanks,
This works fine.
-Original Message-
From: Erik Iverson [mailto:[EMAIL PROTECTED]
Sent: Tuesday, June 10, 2008 4:19 PM
To: Manisha Brahmachary
Cc: r-help@r-project.org
Subject: Re: [R] convert characters into integers in a matrix
Manisha -
Will this work instead?
if 'a' is your
?setdiff
Fra: [EMAIL PROTECTED] på vegne af [EMAIL PROTECTED]
Sendt: ti 10-06-2008 22:32
Til: r-help@r-project.org
Emne: [R] Really simple question
Hi,
I don't have too much programming experience - sorry in advance if this question
is very basic, and thanks f
Hi,
I don't have too much programming experience - sorry in advance if this question
is very basic, and thanks for the help.
I have a vector of numbers and another vector of a subset of those numbers. How
can I create a third vector with all the numbers in the original list that
aren't in the giv
Could you post your code so we can see what you are trying to do?
Thanks,
Patrick
From: [EMAIL PROTECTED] [EMAIL PROTECTED] On Behalf Of Eleni Christodoulou
[EMAIL PROTECTED]
Sent: Tuesday, June 10, 2008 11:20 AM
To: r-help@r-project.org
Subject: [R] sam
Try this:
x <- matrix(c("A", "P", "M", "A", "P", "M"), 2)
x[] <- as.numeric(as.character(factor(x, labels = c(0,1,1
x
On 6/10/08, Manisha Brahmachary <[EMAIL PROTECTED]> wrote:
>
> Hello,
>
>
>
> I will appreciate any suggestion for this simple problem. I have a matrix
> of
> characters "A"
If you make the x-values more dense, e.g. with x<-seq(0,20,0.1) then your
example works. Plotting your data might give a hint to why your example
fails Btw: It is generally not a good idea to use F for a parameter because
F usually means FALSE.
Regards
Søren
___
Manisha -
Will this work instead?
if 'a' is your matrix, try
ifelse(a == "A", 0, 1)
Best,
Erik Iverson
Manisha Brahmachary wrote:
Hello,
I will appreciate any suggestion for this simple problem. I have a matrix of
characters "A", "P", "M".
I want to convert those characters to inte
Hello,
I will appreciate any suggestion for this simple problem. I have a matrix of
characters "A", "P", "M".
I want to convert those characters to integers 0,1, 1 respectively. I am
using the following R statements:
exprs.new<-gsub("P",1,exprs)
exprs.new1 <- gsub("A",0,exprs.new)
e
On 10/06/2008, at 6:08 PM, Ivan Adzhubey wrote:
Hi Rolf,
On Monday 09 June 2008 11:16:57 pm Rolf Turner wrote:
Your approach tacitly assumes --- as did the poster's question ---
that
the probability of passing an item by one method is *independent* of
whether it is passed by the other metho
DrakeGis wrote:
Hi all,
I observed that the 'link' between R and BUGS (winBugs/linBugs) has
totally disappeared. I'm wondering what package can be use to run
bayesian models specified using the BUGS language in R (specifically
under Linux). Is there any other option besides JAGS ?
Thanks
T
Hi all,
I observed that the 'link' between R and BUGS (winBugs/linBugs) has
totally disappeared. I'm wondering what package can be use to run
bayesian models specified using the BUGS language in R (specifically
under Linux). Is there any other option besides JAGS ?
Thanks
Hi all,
I observed that the 'link' between R and BUGS (winBugs/linBugs) has
totally disappeared. I'm wondering what package can be use to run
bayesian models specified using the BUGS language in R (specifically
under Linux). Is there any other option besides JAGS ?
Thanks
Just wanted to say thanks to all suggestions.
My code works fine now *_0
Carl
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide com
Could someone please indicate if there is a package capable of computing a
hierarchical two-sided tobit model. Thanks in advance.
---
Anthony A. Pezzola
[EMAIL PROTECTED]
(02) 354-7823
Profesor de Ciencia Política
Instituto de Ciencia Política
Universi
mfrow is for classic graphics and when the graphs are unrelated.
lattice is for grid graphics and typically when the panels are related
such as being the same plot but conditioned on different factor levels.
These are typical uses only as one can write arbitary panels with lattice
and produce rel
FWIW:
I use lattice exclusively. One difference from the mfrow approach is that
lattice automatically provides (if desired) the same scaling on all plots,
necessary to make visual comparisons. It also provides an easy way to
appropriately label and and arrange the plots, as well as to provide
stan
Instead of placing this information in the title we could
consider placing it in a legend.
s <- "a=1,b=2,c=3"
plot(1:10)
legend("topleft", legend = strsplit(s, ",")[[1]], ncol = 1, cex = 0.5,
bty = "n")
On Tue, Jun 10, 2008 at 12:07 PM, Hua Li <[EMAIL PROTECTED]> wrote:
> Hi All,
>
> I have a pr
Dieter
crosscorr.plot is in the coda package, which I should have noted. The
function wasn't producing a chart. It was only returning NULL. But, when
I updated packages, it is now.
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Dieter Menne
> Sent
Doran, Harold air.org> writes:
>
> Just out of curiosity, why might this be occuring:
>
> > class(x6)
> [1] "mcmc"
> > crosscorr.plot(x6)
> NULL
>
> # Replicable code
>
> example(lmer)
> x6 <- mcmcsamp(fm1, n=1000)
> crosscorr.plot(x6)
>
I cannot reproduce this with the Current Sourceforge
I have had good sucess with the par(mfrow=c(#,#)) for formating graphs and
they look good to me. I have seen a lot of use of the lattice package and
thought I would go fishing on the list for y'all's comments. Is there a
time when lattice would be easier more appropriate for certain graphics over
Here is one approach:
> tmp <-
> "p=0.05:A-B=3,C-D=10,D-E=100,A-F=2,AFR-E=3,ACE-D=1,ADEF-M=0,AED-E=10,DE-F=3,AB-J=4,AC-J=10,ED-F=1,ED-B=4,AF-B=10,CD-S=10,AM-C=4"
> tmp2 <- gsub(',',', ',tmp)
> tmp3 <- strwrap(tmp2, 30)
> par(mar=c(5,4,10,1)+.1)
> plot(1:10, main=paste(tmp3, collapse="\n"))
Hope
In your plot and lines function call you specify type="b" which says to use
"b"oth lines and points with gaps in the lines around the points. If you
change that to type="o" then it will "o"verplot the points and lines (no gaps).
The different types are documented in ?plot.default.
Hope this he
Dear Tariq,
A good starting point would be ?matplot. Also, you can try this:
set.seed(123)
X=cbind(1:10,matrix(rnorm(10*5),ncol=5))
matplot(X[,1],X[,2:5],type='o',lty=1,col=1,pch=1:5,xlab="Variable
X",ylab="Outcome")
and the add your any text you want around.
HTH,
Jorge
On Tue, Jun 10, 200
Hua Li wrote:
Hi All,
I have a problem of putting long titles on a graph:
for example,
x= seq(1:100)
y=seq(1:100)
plot(x,y,main="p=0.05:A-B=3,C-D=10,D-E=100,A-F=2,AFR-E=3,ACE-D=1,ADEF-M=0,AED-E=10,DE-F=3,AB-J=4,AC-J=10,ED-F=1,ED-B=4,AF-B=10,CD-S=10,AM-C=4")
R seems not able to print the whole
Dear Daren,
Try this:
tapply(t[,"value"],t[,"id"],mean)
HTH,
Jorge
On Tue, Jun 10, 2008 at 11:37 AM, Daren Tan <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> How do I collapse (average in the simplest case) the values of those
> duplicated ids (i.e., 2, 5, 6, 9) to give a table of unique ids ?
>
>
does lty not work? please read the posting guide.
On Tue, Jun 10, 2008 at 12:13 PM, Tariq Perwez <[EMAIL PROTECTED]>
wrote:
> Hi,
> I am trying to plot multiple lines on one plot such that all lines are of
> the same color (black) and continuous. I need to distinguish these multiple
> plots from
Look at ?print.trellis in the lattice package (specifically the split and more
argumnets).
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801) 408-8111
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Beh
?tapply
?aggregate
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801) 408-8111
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Daren Tan
> Sent: Tuesday, June 10, 2008 9:37 AM
> To: r-help@r-pr
#try this cex.main=1.1 This is a par parameter ?par
plot(x,y,main="p=0.05:A-B=3,C-D=10,D-E=100,A-F=2,AFR-E=3,ACE-D=1,ADEF-M=0,AED-E=10,DE-F=3,AB-J=4,AC-J=10,ED-F=1,ED-B=4,AF-B=10,CD-S=10,AM-C=4",
cex.main=1.1)
On Tue, Jun 10, 2008 at 12:07 PM, Hua Li <[EMAIL PROTECTED]> wrote:
> Hi All,
>
> I
Dear Hua,
Try using "\n" in the title or the "cex.main" argument. See ?par for
details.
# First attempt
x= seq(1:100)
y=seq(1:100)
plot(x,y,main="p=0.05:A-B=3,C-D=10,D-E=100,A-F=2,AFR-E=3,ACE-D=1,ADEF-M=0,\n
AED-E=10,DE-F=3,AB-J=4,AC-J=10,\n ED-F=1,ED-B=4,AF-B=10,CD-S=10,AM-C=4")
# Second attemp
Hi,
I am trying to plot multiple lines on one plot such that all lines are of
the same color (black) and continuous. I need to distinguish these multiple
plots from each other by using different symbols (I am using pch=). However,
all my lines are broken on both sides of the symbols. This unfortuna
Hi All,
I have a problem of putting long titles on a graph:
for example,
x= seq(1:100)
y=seq(1:100)
plot(x,y,main="p=0.05:A-B=3,C-D=10,D-E=100,A-F=2,AFR-E=3,ACE-D=1,ADEF-M=0,AED-E=10,DE-F=3,AB-J=4,AC-J=10,ED-F=1,ED-B=4,AF-B=10,CD-S=10,AM-C=4")
R seems not able to print the whole title. The titl
I from a first thought I would say that you are apply this wrong! The
fourier transform convolves a function (cos(x)+isin(x) (this may not be the
exact formula but I don't have my books near)) to the data and then
integrates over -1/2 to 1/2 takes the modulus and plots this- the
periodogram. The
Hi Jim,
This is genotype data of 170 samples. I selected subsets of SNP
optimized for different types of germplasm. So it is a matrix with 170
rows and 1536, 384 or 96 columns of binary data (0, 1). I have 14 of
such matrices in a list.
x <- list()
for (i in 1:14) {
set.seed(i)
x[[i]] <- ma
I wrote
> Hello
>
> Using R 2.7.0 on Windows.
>
> I am running a linear discriminant analysis as follows
>
>
> discrim1 <- lda(normvar~ mafmahal+ mrfmahal+ mffmahal+ bafmahal+ brfmahal+
> cofmahal+ bmfmahal+ cfmahal+ fractmahal+ antmahal+ absmifmahal+
> absifmahal, subset = train)
Dear experts,
I tried to put the two plots into one final PNG figure
with the following script.
However instead of giving 2 plots in one figure,
it only gives the the last plot in one figure.
What's wrong with my script below?
__BEGIN__
in_fname <- paste("mydata.txt.",sep="")
out_fname <- past
Hi,
How do I collapse (average in the simplest case) the values of those duplicated
ids (i.e., 2, 5, 6, 9) to give a table of unique ids ?
t <- cbind(id=c(1:10, 2,5,6,9), value=rnorm(14))
_
[[alternative HTML ver
I wrote (in part)
>
> I am running a linear discriminant analysis as follows
>
>
> discrim1 <- lda(normvar~ mafmahal+ mrfmahal+ mffmahal+ bafmahal+ brfmahal+
> cofmahal+ bmfmahal+ cfmahal+ fractmahal+ antmahal+ absmifmahal+
> absifmahal, subset = train)
> prediction <- predict(discr
Hi Pratt --
ppatel3026 <[EMAIL PROTECTED]> writes:
> Could someone provide a link or examples of parsing XML document in R? Few
> specific questions below:
Always helpful to know what software you're using; here's mine
> library(XML)
> sessionInfo()
R version 2.8.0 Under development (unstable)
Hello list!
I have a proble trying to perform a SAM analysis using the function samr
from the samr package. I have put the option *center.arrays=TRUE *in order
to scale all the experiments to median=0. I would like to retrieved the
scaled data but it seems that samr does not return it...Does anyon
Hi,
I have the following problem while running a "gam" regression:
test.gam = gam(fmla,data=Final.Df)
where fmla is a regression formula that looks like: "Var1 ~ poly(c(1:160),
degree = 5) + VarC1 + VarC2 + . VarC12
Within SPlus I used the following phrase to find the coefficients
Peter Flom wrote:
Hello
Using R 2.7.0 on Windows.
I am running a linear discriminant analysis as follows
discrim1 <- lda(normvar~ mafmahal+ mrfmahal+ mffmahal+ bafmahal+ brfmahal+
cofmahal+ bmfmahal+ cfmahal+ fractmahal+ antmahal+ absmifmahal+ absifmahal, subset = train)
predic
Alberto Monteiro wrote:
> I found a curious bug in read.xls. I don't know if it's reproducible.
>
> It's like this: suppose I do a read.xls in a spreadsheet. A column
> begins with a number. Then, any strings below it will be rendered as NA.
> If the column begins with a string, then it will be ren
Hello
Using R 2.7.0 on Windows.
I am running a linear discriminant analysis as follows
discrim1 <- lda(normvar~ mafmahal+ mrfmahal+ mffmahal+ bafmahal+ brfmahal+
cofmahal+ bmfmahal+ cfmahal+ fractmahal+ antmahal+ absmifmahal+
absifmahal, subset = train)
prediction <- predict(discri
Hello,
I have to read in a SPSS-file.
I use spss.get() from the Hmisc-package (version 3.4-3) and win-R(2.7.0)
My Problem now is, that the length of all variable names is cutted to 8
characters. Can I avoid this?
Thank you!
--
Ist Ihr Browser Vista-kompatibel? Jetzt die neuesten
_
I believe read.xls has a colClasses argument. If you import using
read.xls(filename, colClasses='character')
everything will be imported as a string, and you can re-convert after
importing
Alberto Monteiro wrote:
I found a curious bug in read.xls. I don't know if it's reproducible.
It's like
In addition to Gabor's suggestion, note the following warning from ?nls
Warning
Do not use nls on artificial "zero-residual" data.
The nls function uses a relative-offset convergence criterion that
compares the numerical imprecision at the current parameter estimates
to the residual sum-of-
Could someone provide a link or examples of parsing XML document in R? Few
specific questions below:
For instance I can retrieve specific nodes using this:
node <- xpathApply(xml, "//" %+% xtag, xmlValue)
1) I want to be able to retrieve parent node for this node, how can I do
this? getParentN
So this works... Thanks. My mistake was leaving out seq_len()
for (i in seq_len(nrow(Volumes))){
plot(as.numeric(deltas[i,]))
Sys.sleep(0.5); }
Ken Spriggs wrote:
>
> I appreciate the response but if this is what you have in mind I didn't
> get anything different.
> Any ideas why?
>
> f
The goal is to look at an evolution of a process over 400 steps. I don't
really need to page back and forth so much as I'd like to just watch it like
a flip book.
jholtman wrote:
>
> Write it out to a PDF file and you can view at your leasure. On WIndows
> you
> have the option of paging b
Actually, if you have the information on the individual units, then the
production line information is redundant and you can just use Mcnemar's test
comparing QA1 to QA2. Though as Rolf mentioned, this will not give the same
information as if you have true state and can compare false positives
I appreciate the response but if this is what you have in mind I didn't get
anything different.
Any ideas why?
for (i in nrow(Volumes)){
plot(as.numeric(deltas[i,]))
Sys.sleep(0.5); }
Thanks
Jan T. Kim wrote:
>
> On Mon, Jun 09, 2008 at 02:02:01PM -0700, Ken Spriggs wrote:
>>
>> Hello,
>>
> "MM" == Martin Maechler <[EMAIL PROTECTED]>
> on Tue, 10 Jun 2008 15:05:05 +0200 writes:
> "PD" == Peter Dunn <[EMAIL PROTECTED]>
> on Tue, 10 Jun 2008 09:25:07 +1000 writes:
PD> Hi all After posting what follows, Duncan Murdoch
PD> suggested perhaps a bug in for
I found a curious bug in read.xls. I don't know if it's reproducible.
It's like this: suppose I do a read.xls in a spreadsheet. A column
begins with a number. Then, any strings below it will be rendered as NA.
If the column begins with a string, then it will be rendered correctly.
Alberto Monteir
In MASS there is a nnet() function which returns, among other things, a
wts[] vector giving the weights in the neural network. However, in neither
the book nor in the online documentation for the routine can I find
documentation of which element of wts[] goes with which link in the
network---in
Look at the "image" function and the "levelplot" function in the lattice
package.
-Original Message-
From: "sumit gupta" <[EMAIL PROTECTED]>
To: "r-help@r-project.org"
Sent: 6/10/08 6:55 AM
Subject: [R] Hello
Hello,
I am facing a problem in drawing heat map using R.
I have a 70X3 mat
Try
RSiteSearch("fit a sine")
On Tue, Jun 10, 2008 at 10:25 AM, Jon Loehrke <[EMAIL PROTECTED]> wrote:
> I have been attempting to estimate the periodic contribution of an effect to
> some data but have not been able to fit a sine wave within R.
> It would be nice to start by being able to fit a
Hi
[EMAIL PROTECTED] napsal dne 10.06.2008 14:49:55:
> Hello,
>
> I am facing a problem in drawing heat map using R.
>
> I have a 70X3 matrix and I want to draw a heat map with 1 coloumn on X
axis
> another on Y axis and want to show the value of 3rd coloumn using heat
> colours.
> Could you p
I have been attempting to estimate the periodic contribution of an
effect to some data but have not been able to fit a sine wave within R.
It would be nice to start by being able to fit a sine wave with an
amplitude and frequency.
x<-seq(0,20,by=0.5)
y<-2*sin(2*pi*.5*x) #amplitude =2, frequen
You could put the group averages back into dafSamp using ave():
dafSamp <- data.frame(cbind(c(1972,1984,1969,1976,1999,1996,1976,1984,1976),
c(117,73,92,113,80,78,98,106,99)))
dafSamp$Ay <- ave(dafSamp$X2, dafSamp$X1, FUN=mean)
dafSamp$vecAA <- dafSamp$X2 * (dafSamp$Ay / mean
Well,
Yes, that works just fine! Thank you!
--
Michal J. Figurski
HUP, Pathology & Laboratory Medicine
Xenobiotics Toxicokinetics Research Laboratory
3400 Spruce St. 7 Maloney
Philadelphia, PA 19104
Henrique Dallazuanna wrote:
Try using aggregate:
aggregate(tb[-1], list(tb$Subject), FUN=medi
I have a data set something like this:
"", "Value"
1972 , 117
1984 , 73
1969 , 92
1976 , 113
1999 , 80
1996 , 78
1976 , 98
1984 , 106
1976 , 99
it could be created with:
> dafSamp <-
> data.frame(cbind(c(1972,1984,1969,1976,1999,1996,1976,1984,1976),c(117,73,92,113,80,78,98,1
I am tring to use the rollingRegression function from PerformanceAnalytics.
When I apply the function to R stock data (Boston), the function works fine.
But when I try to apply it to data that I imported from excel, using
xlsReadWrite, I recieve an error message:
> Error in nrow(x): subscript o
On 6/10/2008 9:23 AM, Creighton, Sean wrote:
Hi
I consider myself not a complete beginner in R, however an elegant
solution to this problem stumps me. I have a fairly long time series of
6 or so points, I need to gather the data to create a histogram of
the length of continuous zero periods
Hello,
I would be very thankful to hear how often you search for associative
rules in your daily work and what would you consider the most
important in your tasks:
- Data loading speed
- Data processing speed
- Advanced algorithms for rules post-processing
Thanks a lot for your time!
Best regar
Thank you Arne. Though I didn't detail all of my attempts, I did in
fact try a larger restriction matrix that accounted for the levels of
the factors.
However, I think my error in those attempts was in adding N columns to
the matrix for an N-level factor (rather than N-1 columns), because I
tho
Try using aggregate:
aggregate(tb[-1], list(tb$Subject), FUN=median, na.rm = T)
On Tue, Jun 10, 2008 at 10:18 AM, Michal Figurski <
[EMAIL PROTECTED]> wrote:
> Hello everyone,
>
> I am new to R, I have been using SAS for a while. Not surprisingly, I find
> R much better in graphics, which is pub
Hi
I consider myself not a complete beginner in R, however an elegant
solution to this problem stumps me. I have a fairly long time series of
6 or so points, I need to gather the data to create a histogram of
the length of continuous zero periods in a data set.
So image the data looks like t
Hello everyone,
I am new to R, I have been using SAS for a while. Not surprisingly, I
find R much better in graphics, which is publication ready right away.
Recently, I have been trying to calculate some basic statistics using R.
I have a dataset of multiple rows per subject. For example:
S
> "PD" == Peter Dunn <[EMAIL PROTECTED]>
> on Tue, 10 Jun 2008 09:25:07 +1000 writes:
PD> Hi all After posting what follows, Duncan Murdoch
PD> suggested perhaps a bug in formatC, or an error on
PD> documentation. Any comments?
It could be called a bug in your platform's
Hello,
I am facing a problem in drawing heat map using R.
I have a 70X3 matrix and I want to draw a heat map with 1 coloumn on X axis
another on Y axis and want to show the value of 3rd coloumn using heat
colours.
Could you please help me with this .
Thank you .
Regards,
Sumit
[[alterna
Hello
I don't know exactly what you want to do but:
-why do you use in your example h$counts and not h? Furthermore helpl
file says it should be a time series, why then rather not your time series?
-usually na.action will make the "default" action, which you can see by
getOptions("na.action"
Dylan Beaudette wrote:
Hi,
Is anyone on the list familiar with an R implementation of Piper Diagrams?
Example:
http://faculty.uml.edu/nelson_eby/89.315/IMAGES/Figure%209-78.jpg
I am thinking that two calls to triax.plot (plotrix) along with some kind of
affine-transformed standard plot would
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