The group would be happy to answer your question if you can show an example
data frame on what is there and what is required.
Â
Cheers,
Pratap
--- On Wed, 17/9/08, Rajasekaramya <[EMAIL PROTECTED]> wrote:
From: Rajasekaramya <[EMAIL PROTECTED]>
Subject: [R] inserting values for null
To: r-help@
Hi Hadley,
As for now, I have not yet delved deep enough into the new version to be
sure if I like it or not. It's just that I like the freedom to choose, and
the previous form was great. Any chance you may put it back as an optional
parameter?
Thanks,
Pedro
hadley wrote:
>
> On Wed, Sep 17, 200
Hi
[EMAIL PROTECTED] napsal dne 17.09.2008 11:08:29:
> Greetings everyone,
>
> I'm trying to add a specific table or a specific number of rows (e.g.44)
to a
> table with no success.
>
> This is my basic table
> > head(dataA)
> yearplot spp prop.BDCA1DCA2DCA3DCA
I don't quite understand your R code (I think your random numbers make
the graph very hard to read!), but I have also written an example for
the interaction effect:
## 400 bubbles to show the interaction of x and z
sq = seq(0, 10, length = 20)
x = rep(sq, 20)
z = rep(sq, each = 20)
y = c(outer(sq,
ODBC,
didn't think of that, thanks.
el
On 18 Sep 2008, at 00:31 , David Winsemius wrote:
On Sep 17, 2008, at 6:00 PM, Dr Eberhard W Lisse wrote:
Hi,
is there a Rdbi or other package to use firebird in R?
I am reviewing options for my Practice software and might have
to switch to a firebi
Hi, you may use list.files('dir-of-your-files', ...) to get the paths
of all the files, and use file.info() to get the date attribute, then
order them by date, and finally in a loop
for(i in paths-of-your-files){
open.ncdf(i, ...)
...
}
Regards,
Yihui
--
Yihui Xie <[EMAIL PROTECTED]>
Phone: +86-(
I am having trouble manipulating the simulated effects of a circle graph. I've
created a pseudo 3D plot using circle size as 3rd variable. The code I attached
has simulated data values for all 3 variable, and is plotting a graph showing
an interaction with all 3variables. I am trying to create
Hi Ramya,
Assuming that the problem is well defined (i.e. the values in col1 of the
data.frames are unique and every value in D.F.sub.2[,1] appears also in
D.F1[,1]) you can do the following:
ind <- match(D.F.sub.2[,1],D.F1[,1])
D.F1[ind,] <- D.F.sub.2
--- On Thu, 18/9/08, Rajasekaramya <[EMA
Thanks Duncan, I have also been wondering about this problem for a long time.
Regards,
Yihui
--
Yihui Xie <[EMAIL PROTECTED]>
Phone: +86-(0)10-82509086 Fax: +86-(0)10-82509086
Mobile: +86-15810805877
Homepage: http://www.yihui.name
School of Statistics, Room 1037, Mingde Main Building,
Renmin Univ
Thanks to all who help out with this question.. Cut computation time
by a fourth! Victor Hernando Cervantes Botero's idea work great. As
well as Dan Davidson's
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEA
Thanks to all who replied to this question. Jorge's script worked a treat.
Hi, can someone please tell me how to convert a square matrix to a list in R?
i.e. I want to convert from:
a b c
a 1 1 1
b 2 2 2
c 3 3 3
to:
a
On Wed, Sep 17, 2008 at 8:52 PM, Pinder, Adrian
<[EMAIL PROTECTED]> wrote:
> Hi, can someone please tell me how to convert a square matrix to a list in R?
>
> i.e. I want to convert from:
>
>a b c
> a 1 1 1
> b 2 2 2
> c 3 3
Hi, can someone please tell me how to convert a square matrix to a list in R?
i.e. I want to convert from:
a b c
a 1 1 1
b 2 2 2
c 3 3 3
to:
a a 1
a b 1
a c 1
b a 2
b
Dear J.J.Harden
I think that on spatial stat you will find several ways of simulate spatial
pattern that (point or line) that may be what you are looking for. Case not,
please let me know and may be we can improve some solution.
Best wishes,
miltinho astronauta
brazil
On Wed, Sep 17, 2008 at
Such a silly mistake! Thanks a lot, John!
Gang
On Wed, Sep 17, 2008 at 7:21 PM, John Fox <[EMAIL PROTECTED]> wrote:
> Dear Gang,
>
> Your for loop is in error; try
>
> for (ii in seq(length=nWin))
>
> I hope this helps,
> John
>
> --
> John Fox, Professor
> Department
Hi David,
Thanks, survdiff actually only has the G(rho) family, i.e. gamma is
set to 0. There is another package called surv2sample, that I found
only after I sent out the email, that contains what I am looking for.
Thanks,
Ritwik
On Wed, Sep 17, 2008 at 5:53 PM, David Winsemius <[EMAIL PROTECTE
The survdiff() function in the survival package does the G(rho) family
(ie, G(rho, gamma=0)).
-thomas
On Wed, 17 Sep 2008, Ritwik Sinha wrote:
Hi,
Is there an implementation of the G(rho,gamma) class of function
indexed weighted log-rank statistics in R? For example those mentione
Dear Duncan and Vincent,
Thanks for your help. It took me some time to upgrade R because
atp-get install would not actually install the packages,
but I used
sudo aptitude install r-base
and that managed to upgrade the r-base package.
I'm also happy to say that RCurl as well as BiomaRt could now
Well, I don't see why you need the CTRL-R functionality when you can
just as rapidly and efficiently using SEARCH functionality in scripts
too (CTRL-F in most applications, CTRL-S in emacs etc).
BTW, I am quite familiar with Unix, Linux and Sun Solaris and what
CTRL-R does (yes, I used it fre
Hi,
I have a dataframe like the following:
xfact yfact zfact response
--- --- --- --
x1 y1 z1 r1
x1 y1 z2 r2
...
I want output that looks like:
___ zfac levels___
xfact yfact z1 z2 ... zn
---
Hi Ramya,
In this particular case, something like ?"complete.cases" should do the job.
With this function you can delete rows with one or more NA's.
Here is an example:
set.seed(123)
DF<-matrix(rnorm(100),ncol=10)
DF[1,2]<-NA
DF[1,3]<-NA
DF[4,10]<-NA
dim(DF)
[1] 10 10
DF.noNA <- DF[complete.cases
Hi,
I'm doing some coxph fits using the survival package. There are a large
number of potential predictors and so I was considering using stepAIC
for model selection. However, in the early stages I'm getting complaints
like the following:
Warning message:
In fitter(X, Y, strats, offset, init, co
Dear Sam,
The "basis" matrix for your contrasts is not orthogonal, and so the tests
are almost surely not what you intended. Moreover, the "basis" matrix is not
even of rank 5, as you can see from the message produced by lm(),
"Coefficients: (1 not defined because of singularities)," and the missi
Dear Gang,
Your for loop is in error; try
for (ii in seq(length=nWin))
I hope this helps,
John
--
John Fox, Professor
Department of Sociology
McMaster University
Hamilton, Ontario, Canada
web: socserv.mcmaster.ca/jfox
> -Original Message-
> From: [EMAIL PRO
On 17-Sep-08 22:36:50, jjh21 wrote:
> I want to create a dataset in R with spatial correlation (i.e.
> clustering) built in for a linear regression analysis. Any tips
> on how to do this?
> Thanks.
The package 'spatstat' has functions for simulating several
different kinds of spatial process. Hopi
On 17/09/2008 4:58 PM, Gillian Silver wrote:
Hi, how can I create a rainbow gradient in R? For example, let's say I have
a plot of y = x...and I want the plot to go from red -> orange -> yellow ->
green -> blue -> etc.
Right now, I know how to do something like go from red to blue, using the
plot
On Wed, Sep 17, 2008 at 3:58 PM, Gillian Silver <[EMAIL PROTECTED]> wrote:
> Hi, how can I create a rainbow gradient in R? For example, let's say I have
> a plot of y = x...and I want the plot to go from red -> orange -> yellow ->
> green -> blue -> etc.
Why would you want to? See
http://epub.wu-
I want to create a dataset in R with spatial correlation (i.e. clustering)
built in for a linear regression analysis. Any tips on how to do this?
Thanks.
--
View this message in context:
http://www.nabble.com/Need-help-creating-spatial-correlation-for-MC-simulation-tp19542145p19542145.html
Sent
The example pointed to below is a good example of fortune(197).
It is possible to do using polygon (and is probably not as hard as you are
making it), but there is probably a better way to present your data. What
question are you trying to answer with this plot?
> -Original Message-
>
On 18/09/2008, at 9:50 AM, <[EMAIL PROTECTED]> wrote:
Dear all,
I want to simulate a Strauss Hard Core process in 3D. I have found
that
someone else tried to do the same and he recived this answer,
"If you need this immediately, I suggest you follow Brian Ripley's
advice.
This probably
On Sep 17, 2008, at 6:00 PM, Dr Eberhard W Lisse wrote:
Hi,
is there a Rdbi or other package to use firebird in R?
I am reviewing options for my Practice software and might have
to switch to a firebird based package so I would of course like
to be able to do some stats in R.
Per Prof Riple
On second thought, this is more likely to be what you're looking for...
library(rgl)
x <- rnorm(1000)
y <- rnorm(1000)
z <- x + y
plot3d(x, y, z, col = rainbow(1000, end = 5/6)[rank(z)], size = 3)
On Wed, Sep 17, 2008 at 4:06 PM, Kingsford Jones
<[EMAIL PROTECTED]> wrote:
> On Wed, Sep 17, 2008
Hello,
I am fairly new to R programming. I have a series of netcdf files that
I am able to open one at a time using open.ncdf. I want to write this
into an R script so that I can successively open each file by date in a
for-loop. Any suggestions?
Thanks
Brian Pettegrew
--
Brian Pettegre
Others have answered the question that you asked (it is also a variation of Faq
7.21), but here is an answer to the question that you should have asked:
When working with datasets like this, it is better to create a list rather than
separate objects with names like dat1, dat2, etc.
For example:
On Wed, Sep 17, 2008 at 3:11 PM, Gillian Silver <[EMAIL PROTECTED]> wrote:
> What would I do if I have something like:
>
> x <- rnorm(1:1000)
> y <- rnorm(1:1000)
> z <- x + y
>
> and I want the rainbow to increase with z? (i.e., red for lowest z...all the
> way up to the last color in the rainbow
Hi,
is there a Rdbi or other package to use firebird in R?
I am reviewing options for my Practice software and might have
to switch to a firebird based package so I would of course like
to be able to do some stats in R.
greetings, el
__
R-help@r-proj
Hi Bo,
>> I can't seem to find the right set of commands to enable me to do perform
>> a
>> regression with cluster-adjusted standard-errors.
Frank Harrell's Design package has ?bootcov and ?robcov, which will both do
it.
Regards, Mark.
Bo Cowgill wrote:
>
> I can't seem to find the right se
Dear all,
I want to simulate a Strauss Hard Core process in 3D. I have found
that someone else tried to do the same and he recived this answer,
"If you need this immediately, I suggest you follow Brian Ripley's advice.
This probably involves downloading a source tar file of the R package
an
On Sep 17, 2008, at 5:25 PM, Ritwik Sinha wrote:
Hi,
Is there an implementation of the G(rho,gamma) class of function
indexed weighted log-rank statistics in R? For example those mentioned
in the paper by Kosorok and Lin (1999): The Versatility of
Function-Indexed Weighted Log-Rank Statistics
Hi,
Is there an implementation of the G(rho,gamma) class of function
indexed weighted log-rank statistics in R? For example those mentioned
in the paper by Kosorok and Lin (1999): The Versatility of
Function-Indexed Weighted Log-Rank Statistics [JSTOR link :
http://www.jstor.org/pss/2669706]. I wi
On Sep 17, 2008, at 3:50 PM, Stacey Burrows wrote:
Dear R-users,
I have some very simple data where 1's represent events and zeroes
non-events, e.g.
temp <- rbind(c(0,1,0,0,1,1,1,0), c(0,0,0,1,0,0,0,0))
For each row in the matrix, I would like to replace a singelton
event by a 0. That is
What would I do if I have something like:
x <- rnorm(1:1000)
y <- rnorm(1:1000)
z <- x + y
and I want the rainbow to increase with z? (i.e., red for lowest z...all the
way up to the last color in the rainbow for the highest z)
On Wed, Sep 17, 2008 at 2:05 PM, stephen sefick <[EMAIL PROTECTED]> w
Dear Gillian,
See ?rainbow and its example.
HTH,
Jorge
On Wed, Sep 17, 2008 at 4:58 PM, Gillian Silver <[EMAIL PROTECTED]>wrote:
> Hi, how can I create a rainbow gradient in R? For example, let's say I have
> a plot of y = x...and I want the plot to go from red -> orange -> yellow ->
> green
plot(1:20, col=rainbow(20))
On Wed, Sep 17, 2008 at 4:58 PM, Gillian Silver <[EMAIL PROTECTED]> wrote:
> Hi, how can I create a rainbow gradient in R? For example, let's say I have
> a plot of y = x...and I want the plot to go from red -> orange -> yellow ->
> green -> blue -> etc.
> Right now, I
Dear Raja,
Give a look on merge() function.
Case you need more help, send us a short sample of your D.F1 and DF.sub.2
dataframes.
Hope this helps,
best wishes,
miltinho astronauta
brazil
On Wed, Sep 17, 2008 at 2:13 PM, Rajasekaramya <[EMAIL PROTECTED]>wrote:
>
> I have a dataframe D.F1
>
> >d
Hi, how can I create a rainbow gradient in R? For example, let's say I have
a plot of y = x...and I want the plot to go from red -> orange -> yellow ->
green -> blue -> etc.
Right now, I know how to do something like go from red to blue, using the
plotrix library:
library(plotrix)
redToBlue <-
col
Dear Help List,
Thanks in advance for reading...I hope my questions are not too ignorant.
I have an experiment looking at evolution of wing size [centroid] in
fruitflies and the effect of 6 different experimental treatments
[treatment]. I have five replicate populations [replic] in each
treat
Hi, Sorry for bothering your guys. I am still working on boxplot.
How can I extend the whisker to the 5% and the 95% quantiles? What I should
do if I only want to show the most extreme outlier, like 0.01% and 99.99%
percentiles?
I saw something on boxplot.stat, but I even donot know how to conn
Bo,
Try using RSiteSearch with the strings 'huber-white', 'sandwich' or
even 'clustered standard errors'.
You may also want to consider a mixed models approach -- see:
http://www.stat.columbia.edu/~cook/movabletype/archives/2007/11/clustered_stand.html
HTH,
Kingsford Jones
On Tue, Sep 16, 2
On Wed, Sep 17, 2008 at 1:25 PM, Deepayan Sarkar
<[EMAIL PROTECTED]> wrote:
> On Wed, Sep 17, 2008 at 1:12 PM, David Carslaw
> <[EMAIL PROTECTED]> wrote:
>>
>> I think this is a very useful function that I imagine has wide appeal -
>> thanks. Using the code below produces the plot OK but when I tr
Javier Acuña gmail.com> writes:
>
> Hi, I'm a new user of R. My background is Electrical Engineering, so
> please bear with me if this is a silly question.
>
> I'm trying to assess whether the results of an experiment satisfy the
> hypothesis of homoscedasticity (my ultimate goal is to use ANOV
I'm trying to use the following loop to open a window multiple times
to select files, but only the last window shows up. What am I missing?
library(tcltk)
nWin <- 6
fn <- vector('list', nWin)
for (ii in nWin) {
fn[[ii]] <- tclvalue( tkgetOpenFile( filetypes =
"{{Files} {.1D}} {{All files
On Wed, Sep 17, 2008 at 1:12 PM, David Carslaw
<[EMAIL PROTECTED]> wrote:
>
> I think this is a very useful function that I imagine has wide appeal -
> thanks. Using the code below produces the plot OK but when I try and
> copy/save it (as a metafile) I receive the following error and an hourglass
Try this:
do.call(rbind, strsplit(gsub("010", "000", apply(temp, 1, paste, collapse =
"")), NULL))
On Wed, Sep 17, 2008 at 4:50 PM, Stacey Burrows <[EMAIL PROTECTED]>wrote:
> Dear R-users,
>
> I have some very simple data where 1's represent events and zeroes
> non-events, e.g.
> temp <- rbind(c
On Sep 17, 2008, at 3:36 PM, Jorge Ivan Velez wrote:
Hi Chris82,
Try this:
res=c(which(a == max(a), arr.ind = T),max(a))
names(res)=c('row','col','value')
write.csv(res,"C://yourfile.csv",row.names=TRUE)
I wasn't sure that max(x) or whatever target was specified would be
unique, and in th
Dear R-users,
I have some very simple data where 1's represent events and zeroes non-events,
e.g.
temp <- rbind(c(0,1,0,0,1,1,1,0), c(0,0,0,1,0,0,0,0))
For each row in the matrix, I would like to replace a singelton event by a 0.
That is, any 1 surrounded by zeroes (010) should be replaced by a
I think this is a very useful function that I imagine has wide appeal -
thanks. Using the code below produces the plot OK but when I try and
copy/save it (as a metafile) I receive the following error and an hourglass:
Error: invalid graphics state
[using XP, 2.72, lattice 0.17.13]
Regards,
Dav
> I therefore wish to examine all values of urban.long[,3] which are
> greater than 1. I have tried the following, but receive error
> messages each time:
> > hist(urban.long[,3]>1)
> Error in hist.default(urban.long[, 3]> 1) : 'x' must be numeric
> > hist(urban.long[urban.long[,3]>1])
> Error i
On Wed, 17 Sep 2008, Peter Dalgaard wrote:
fisher.test(, simulate.p.value=TRUE) might be more direct. Also
works for chisq.test().
And, contrary to popular belief, fisher.test() does work for larger
than2x2 tables, although you may run into space/time limitations.
The 'exact' test comput
I submitted this to rmetrics help list as well...
I've been using R-2.4 with Rmetrics successfuly for a year or two.
I recently moved to Ubuntu Linux 8.04, loaded R via apt-get install R-base
etc. etc...
then in the R interface i ran install.packages("fMultivar"), chose the CRAN
mirror and it lo
Both shape parameters of rbeta can be vectors; for
x <- rbeta(n, shape1, shape2)
x[i] ~ Beta(shape1[i], shape2[i])
so
bbsim <- function(m=1000, num.post.draws=1e4, size.a=100, prob.a=.27,
prior.count=1) {
data.count <- rbinom(m, size.a, prob.a)
shape1 <- rep(prior.count + data.count, e
Hi,
you might try this:
set.seed(100)
m <- 10
size.a<- 10
prob.a<- 0.3
prior.constant = 0
draw1 = rbinom( m , size.a, prob.a )
beta.draws <- function(draw, size.a, prior.constant, n) {
rbeta(n, prior.constant + draw, prior.constant + size.a - draw)
}
bdraws <- sapply(d
On 9/17/2008 2:29 PM, Victor Homar wrote:
Thanks a lot for your suggestion but...
Can I do that using the/a land-sea information from the 'worldHires'
database (from mapdata)?
Yes, you use the map.where function to identify the location of the
points. If NA, it's out in the ocean s
Gao, Aijun i3statprobe.com> writes:
>
>
> Hi:
>
> I am trying to run your SCHOOLS example as following and I get an error
message stated that : Error: could not
> find function "bugs"
> Would you please help me since I would like to run some WINBUG programs from
your R by reading external data
Hi Chris82,
Try this:
res=c(which(a == max(a), arr.ind = T),max(a))
names(res)=c('row','col','value')
write.csv(res,"C://yourfile.csv",row.names=TRUE)
HTH,
Jorge
On Wed, Sep 17, 2008 at 1:47 PM, Chris82 <[EMAIL PROTECTED]> wrote:
>
> Hello R users,
>
> I want to readout the row and column
Hi Jathine,
And then to see things more clearly still, you can do something like this on
your test results:
format(formatC(p1$var$coord, digits=15, format="f"), justify="right")
and
format(formatC(p1$var$coord, digits=16, format="f"), justify="right")
Though I do hope that the second command
Thanks a lot for your suggestion but...
Can I do that using the/a land-sea information from the 'worldHires'
database (from mapdata)?
Best,
VÃctor.
Greg Snow wrote:
After you have interpolated your data, replace the values in the areas of the o
cean with NA, then filled.conto
I wrote a function that reads data from a file and manipulates it to build
and return a matrix with a million rows and three columns. I also need to
return some metadata: these are about a half-dozen single numbers or short
character strings, plus one numeric vector of length 5,000. I've been
in
Thank you for your reply.
Here are some more info, I hope this can explain the problem a bit more
clearly.
Why PCA gives different results on the two different platforms?
freqtest.txt file line text :
M1 M2 M3 M4 M5 M6 M7 M8
-1 -1 -1 -1 -1 -1 -1 -1
0 0 0 0 -1 -1 1 1
-1 -1 -1 -1 -1 -1 -1 -1
0 0
Hello R users,
I want to readout the row and column postion from a certain matrix value
into a csv file.
I have only found this syntax
"which(a == b, arr.ind = T)"
so I get
a = matrix
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
[1,]11222112
[2,]123
Hi:
I am trying to run your SCHOOLS example as following and I get an error message
stated that : Error: could not find function "bugs"
Would you please help me since I would like to run some WINBUG programs from
your R by reading external data and I am new to R?
Do I missing some function? Sh
> I have a column within a dataframe of values which range between 1 and
> 2. I want to display graphically the distribution of these values
> (i.e. are they clustered towards either exteme? Or spread evenly?).
> What is a good way of doing this in R?
>
> I've tried a few things, including using
I have a problem in where i generate m independent draws from a
binomial distribution,
say
draw1 = rbinom( m , size.a, prob.a )
then I need to use each draw to generate a beta distribution. So,
like using a beta prior, binomial likelihood, and obtain beta
posterior, m many times. I have
Dear Phil and Jorge,
Many thanks for your quick replies. I found that:> hist(urban.long[,3]) worked
and displayed the data as I hoped. This reveals that the data are strongly
distributed towards the value '1', and the other bars on the histogram are
difficult to distinguish from each other a
Hi Jathine,
>> I hope this can explain the problem a bit more clearly.
>> Why PCA gives different results on the two different platforms?
What is amazing, Jathine, is how nearly exactly identical the two sets of
results are, not that they begin to differ at the 16th decimal place. To
assuage yo
Steve Murray hotmail.com> writes:
>
>
> Dear all,
>
> I have a column within a dataframe of values which range between 1 and 2. I
want to display graphically the
> distribution of these values (i.e. are they clustered towards either exteme?
Or spread evenly?). What is
> a good way of doing thi
On Wed, Sep 17, 2008 at 1:01 PM, Josip Dasovic <[EMAIL PROTECTED]> wrote:
> Hi:
>
> I've searched the archives and the Internet for hours but have yet to find a
> way to do stacked area plots (like the kind in Excel) in R. I think that
> polygon may work but it would require a bit of manipulatio
Hi:
I've searched the archives and the Internet for hours but have yet to find a
way to do stacked area plots (like the kind in Excel) in R. I think that
polygon may work but it would require a bit of manipulation of my data. I was
hoping for an easier way.
An example of what I'm trying to do
On 9/17/2008 1:42 PM, Farr, David wrote:
Could someone please tell me how to stop the package/function name from
being included before the command prompt? This started happening today
after I made some changes to my Rprofile.site file and I don't know why.
For example: if I enter example(AIC), i
On 9/15/08, Waichler, Scott R <[EMAIL PROTECTED]> wrote:
> When I use panel.contourplot() with filled color regions, the coloring
> follows the stair-step edge of the underlying grid instead the smooth
> contour lines themselves. How can I get the latter behavior? I would
> guess there is a mu
Farr, David wrote:
> Could someone please tell me how to stop the package/function name from
> being included before the command prompt? This started happening today
> after I made some changes to my Rprofile.site file and I don't know why.
> For example: if I enter example(AIC), instead of just g
Mike,
There are several options to pursue, depending on your answer
to the question:
Why are you staying within the Rgui if you are already an
Emacs ESS user?
1. If you don't need any other feature of Rgui on Windows,
then don't use it. From emacs, enter
M-x R
and you will immediately
On 9/17/2008 1:13 PM, Koen Stegen wrote:
Dear all,
The documentation on the function open3d in the rgl package, reads:
open3d opens a new rgl device, and sets the parameters as requested.
I want the new rgl device (window) to be sized and positioned in a specific
place on my screen. So, I
This is to announce that we plan to release R version 2.8.0 on Monday,
October 20, 2008.
Release procedures start Friday, September 19. The detailed schedule can
be found on http://developer.r-project.org
The source tarballs will be made available daily (barring build
troubles) and the tarballs c
Could someone please tell me how to stop the package/function name from
being included before the command prompt? This started happening today
after I made some changes to my Rprofile.site file and I don't know why.
For example: if I enter example(AIC), instead of just getting the
regular '>' befo
I have been using the nb2WB() package for the car.normal function in WinBUGS,
but it will not create the C[] matrix; it only creates adj[], num[], and
weights[]. I was planning on using this function to create the C[] matrix
(by using the num matix) required for the car.proper, but I got slipped u
Dear all,
I have a column within a dataframe of values which range between 1 and 2. I
want to display graphically the distribution of these values (i.e. are they
clustered towards either exteme? Or spread evenly?). What is a good way of
doing this in R?
I've tried a few things, including usin
On Sep 17, 2008, at 1:22 PM, Rajasekaramya wrote:
Hi,
I have a dataframe with 14319rows and 9 colums. for some rows there
are null
values.I want a dataframe without these null values.I wanna select
only
those that have values !=NA.
kindly let me know how to do that.
?is.na
--
David
Hi,
I have a dataframe with 14319rows and 9 colums. for some rows there are null
values.I want a dataframe without these null values.I wanna select only
those that have values !=NA.
kindly let me know how to do that.
Ramya
--
View this message in context:
http://www.nabble.com/selecting-dat
Check prop.test().
At 12:41 PM 9/17/2008, Bunny, lautloscrew.com wrote:
Hi all,
though i know this is a simple question, i really hope someone could.
I am just trying to compare percents respectively the difference in
percents by a simple test. t.test usually compares means and is
working like
Dear all,
The documentation on the function open3d in the rgl package, reads:
open3d opens a new rgl device, and sets the parameters as requested.
I want the new rgl device (window) to be sized and positioned in a specific
place on my screen. So, I try to set the "windowRect" parameter as fo
On Sep 17, 2008, at 12:41 PM, Bunny, lautloscrew.com wrote:
Hi all,
though i know this is a simple question, i really hope someone could.
I am just trying to compare percents respectively the difference in
percents by a simple test. t.test usually compares means and is
working like it is s
Look at GNU Emacs with ESS, you'll get what you want out of the box
--- and much more! See
http://vgoulet.act.ulaval.ca/en/emacs
[shameless plug] for a distribution of Emacs bundled with ESS.
HTH
Vincent
Le mer. 17 sept. à 09:26, mfrumin a écrit :
Hi all,
I am generally quite f
Adaikalavan, thanks.
Perhaps I was not so specific enough in what I want, for those not so
familiar with unix commandline featuers. I'm looking for the 'reverse
search' functionality where you hit CTRL-R, then start typing a bit of text
and it finds previous commands with that bit of text, which
Sounds like a homework problem. Consult any basic statistics text. Hint:
You don't use a t-test to test for a difference in percentages. Check
"chi-squared" and/or "contingency table."
Cheers,
Bert Gunter
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of B
On Sep 17, 2008, at 9:26 AM, mfrumin wrote:
Hi all,
I am generally quite fond of the unix commandline keystrokes (e.g.
searching
back in your history with [CTRL]-R, and cutting/pasting with [CTRL]-
K/Y)
which work in the R commandline in *nix. Does anyone know if
there's any
way to get
Hi all,
though i know this is a simple question, i really hope someone could.
I am just trying to compare percents respectively the difference in
percents by a simple test. t.test usually compares means and is
working like it is supposed to be. Now i wonder how i can use a test
in R to test
On Wed, Sep 17, 2008 at 5:34 AM, Pedro Barros <[EMAIL PROTECTED]> wrote:
>
> In the help for scale_fill_identity, it is written
> ## Not run:
> colour <- c("red","green","blue","yellow")
> qplot(1:4, 1:4, fill=colour, geom="tile")
> qplot(1:4, 1:4, fill=colour, geom="tile")
After you have interpolated your data, replace the values in the areas of the
ocean with NA, then filled.contour will not plot in those areas.
Hope this helps,
> -Original Message-
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
> project.org] On Behalf Of Victor Homar
> Sent: Tuesda
For purely educational purposes I would like to see the spectrum of a kernel. I
tried:
spectrum(kernel("daniell", 100), taper=0, log="no")
but I get:
Error in complete.cases(object) : not all arguments have the same length
I can plot the kernel but that is only in the time-domain. I would like
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