Liati hotmail.com> writes:
> I would like to create one postscript file with two different xyplots (which
library(lattice)
postscript("myps.ps")
xyplot(1~1,main="Plot 1")
xyplot(2~3,main="Plot 2")
dev.off()
Dieter
__
R-help@r-project.org mailing list
Dimitri Szerman-2 wrote:
>
> Hello,
> I was wondering if there is a function in R that imports tables directly
> from a HTML document.
>
The XML package can do this:
http://markmail.org/message/cyicoa3htme4gei2
Duncan Temple Lang:
The htmlParse() and htmlTreeParse() functions in the XML pac
On Tue, 2009-05-12 at 15:53 -0400, stephen sefick wrote:
> I am trying to apply this technique (M.J Anderson 2001) to a dataset
> of aquatic insect abundances. There is a sample in the unrestored and
> restored segement of a stream for every time period. I would like to
> compare the centroids of
Warren Young wrote:
> Farrel Buchinsky wrote:
>> Is R an appropriate tool for data manipulation and data reshaping and
>> data
>> organizing? I think so but someone who recently joined our group
>> thinks not.
>> The new recruit believes that python or another language is a far better
>> tool for d
Apologies, I seem to have deleted the important part of a sentence
below:
On Wed, 2009-05-13 at 09:37 +0100, Gavin Simpson wrote:
> > adonis(a~site, data=b, strata=b[,"date"] ,Permutations=999)
>
> I don't think the permutations will be stratified correctly - you want
> them to represent a time
At 14:50 12.05.2009, Terry Therneau wrote:
*I´m writing to ask you how can I do Survivals Curves using Time-dependent
*covariates? Which packages I need to Install?*
This is a very difficult problem
statistically. That is, there are not many
good ideas for what SHOULD be done. Hence, there
Hello,
I just installed rJava on
[r...@ug13 ~]# R --version
R version 2.9.0 (2009-04-17)
runing on a
[r...@ug13 ~]# cat /etc/redhat-release
CentOS release 5.3 (Final)
This is the output of
[r...@ug13 ~]# R CMD javareconf
Java interpreter : /usr/bin/java
Java version : 1.4.2_18
Java home p
Dana Sevak wrote:
Dear R Helpers,
I have trouble applying reShape and reshape although I read the documentation
and several posts, so I would very much appreciate your help on the two points
below.
I have a dataframe
df = data.frame(Name=c("a", "a", "a", "b", "b", "c"), X1=c("12", "13", "1
HI,
thank you for that. I had come across a while ago a presentation outlining the
ideas for such a function but can't remember who or where.
Thanks again,
Tim
- Original Message -
From: Duncan Murdoch
Date: Tuesday, May 12, 2009 4:26 pm
Subject: Re: [R] Response surface plot
To: Tim
Andre Nathan wrote:
Hello
I'm plotting 6 graphs using "mfrow = c(2, 3)". In these plots, only
graphs in the first column have titles for the y axis, and only the ones
in the last row have titles for the x axis.
I'd like all plots to be of the same size, and I'm trying to keep them
as near eac
m = matrix(1:4, 2)
apply(m, 1, cat, '\n')
# 1 2
# 3 4
# NULL
why the null?
vQ
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide
one way is the following:
df.index <- df
df.index$Index <- ave(seq_along(df$Name), df$Name, FUN = seq_along)
df.index
df2 <- reshape(df.index[c("Name", "Index", "X1")], timevar = "Index",
idvar = "Name", direction = "wide")
df2
I hope it helps.
Best,
Dimitris
Dana Sevak wrote:
Dear R Hel
Yuanyuan wrote:
Greetings,
I am using rpart for classification with "class" method. The test data is
the Indian diabetes data from package mlbench.
I fitted a classification tree firstly using the original data, and then
exchanged the order of Body mass and Plasma glucose which are the
stron
Hi!
Wacek Kusnierczyk wrote:
> m = matrix(1:4, 2)
>
> apply(m, 1, cat, '\n')
> # 1 2
> # 3 4
> # NULL
>
> why the null?
Could it be the return value of 'cat'. See ?cat, where:
---snip ---
Value
None (invisible NULL).
---snip ---
Kind regrads,
Kimmo
__
Wacek Kusnierczyk wrote:
> m = matrix(1:4, 2)
>
> apply(m, 1, cat, '\n')
> # 1 2
> # 3 4
> # NULL
>
> why the null?
It comes from unlist()ing a list of NULLs, which in turn are the return
values of cat().
It is arguably a design-buglet not to return list(NULL, NULL), but the
Peter Dalgaard wrote:
> Wacek Kusnierczyk wrote:
>
>> m = matrix(1:4, 2)
>>
>> apply(m, 1, cat, '\n')
>> # 1 2
>> # 3 4
>> # NULL
>>
>> why the null?
>>
>
> It comes from unlist()ing a list of NULLs, which in turn are the return
> values of cat().
>
yes; i'd think i
Hi R-masters
I need help to make modified cumulative hazard ratio plot.
I need create a common plot but with the number of subjects in risk each
ticks times for two different groups in bottom of plot (I put one
example in attach).
Do you know a routine for this?
Is possible create a routine for
Hello!!!
I'm trying to do multiple ANOVA tests with R (testing the affect off
different factors on the same response). As a result I get many ANOVA
tables, and I want to extract a list of the "Pr(>F)" from all the tables.
Maybe someone have an idea how to do this?
Thanks
Imri
--
View
Hi Melissa
unless I miss a point, you should get what you want with (for example)
y<-paste(b,collapse=",")
Hope this helps. Olivier
Melissa2k9 wrote:
>
> Hi,
>
> Im trying to put some numbers into a dataframe , I have a list of numbers
> (change points in a time series) like such
>
> [1] 2
dxc13 wrote:
Hi all,
I have posted similar questions regarding this topic, but I just can't seem
to get over the hump and find a straightforward way to do this. I have
attached my file as a reference.
Basically, the attached file is a 5 degree by 5 degree grid of the the world
(2592 cells), most
You might also use ?curve
# same example as Bill's
par(mar = c(5,4,2,4)+0.1, yaxs = "r")
Sample <- rgamma(1000,2.5,.8)
hist(Sample, main = "", freq = FALSE, ylim = c(0,1))
curve(pgamma(x, 2.5, 0.8), add=T, col='red')
curve(dgamma(x, 2.5, 0.8), add=T, col='darkgreen')
axis(4, col = "red")
mtext(s
?mtext
You may need to adjust the margins. For this I recommend adjusting that
mar option in par (see ?par).
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Bernardo Rangel Tura
Sent: Wednesday, May 13, 2009 6:31 AM
To: r-help
Su
Friends,
I have two covariance matrices (m1 and m2) of same size (150x150). I used
contourplot function to make contour plots individually (c1 and c2). I am
interested in making one contourplot overlapping the two individual contours
so that the portion of the plot above and below the diagonal can
dxc13 wrote:
Hi all,
I have posted similar questions regarding this topic, but I just can't seem
to get over the hump and find a straightforward way to do this. I have
attached my file as a reference.
Basically, the attached file is a 5 degree by 5 degree grid of the the world
(2592 cells), most
Oops, forgot to include:
library(plotrix)
Jim
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained
Try this:
DF$Index <- ave(1:nrow(DF), DF$Name, FUN = seq_along)
reshape(DF[-3], dir = "wide", idvar = "Name", timevar = "Index")
Also see the reshape package for another similar facility.
On Wed, May 13, 2009 at 2:02 AM, Dana Sevak wrote:
>
> Dear R Helpers,
>
> I have trouble applying reShap
From: Uwe Ligges
>
> Yuanyuan wrote:
> > Greetings,
> >
> > I am using rpart for classification with "class" method.
> The test data is
> > the Indian diabetes data from package mlbench.
> >
> > I fitted a classification tree firstly using the original
> data, and then
> > exchanged the order
It was the NAs that fooled color2D.matplot. This gets your colors,
although not exactly what you want. Look at the help for color2D.matplot
to get that. I think fiddling with the x and y limits on the map() call
will get the positions right.
temp1<-read.table("time1test.dat",header=TRUE)
libra
> This does it more or less your way:
>
> ds <- split(df, df$Name)
> ds <- lapply(ds, function(x){x$Index <- seq_along(x[,1]); x})
> df2 <- unsplit(ds, df$Name)
> tapply(df2$X1, df2[,c("Name", "Index")], function(x) x)
>
> athough there may exist much easier ways ...
Here's one way with the plyr a
> "TS" == Tao Shi
> on Wed, 10 Oct 2007 06:15:53 + writes:
TS> Thank you very much, Benilton and Prof. Ripley, for the
TS> speedy replies!
TS> Looking forward to the fix!
TS> Tao
I have finally re-stumbled onto this e-mail thread,
and indeed found fixed the p
The coding for an AFT model with time-dependent covariates will be very hard,
and I don't know of anyone who has done it. (But I don't keep watch of other
survival packages, so something might be there).
In a Cox model, a subject's risk depends only on the current value of his/her
covariat
Thank you!
Yes, I am using the plotCI from gplots and I want the line connecting the
centers to be dashed, just as for the bars. However changing the type to be
"p" as you said does not give dashed line but no line at all (only points).
lehe wrote:
>
> Anyone has some clue to this question?
If two variables have exactly the same split importance, then rpart will use
the one that was first in the model statement. So if
rpart(group ~ age + height + weight + sex)
and at some split point both age and weight gave a split with 20 correct and 9
incorrect, then age would be used t
Hello,
I reviewed my code and this will work now for any number of successive "TA",
I hope:
b=matrix(1:64, ncol=4)
rownames(b)=rep(c("AA","AT","TA","TT"),each=4)
key <- rownames(b)
key[key == "AT"] <- "TA"
c <- b
rownames(c)=key
for(i in 2:I(nrow(c))) {
if(rownames(c)[i]=="TA" & rownames(c)[
Dear All,
I am desperately trying to find any R package that fits a mixture survival
models also know as a cure models. These are survival models where the
survival function is improper, which also means that a fraction of subjects
are expected not to expreience the event. A huge literature
Hello All,
as I´m new to R and survival analysis, I´ve got a question about the
Design::validate function:
My Code:
cox <- cph(Surv(t,status) ~ var1 + var2 + var3, data=data, x=TRUE, y=TRUE,
surv=TRUE)
cox.val <- validate(cox, B=10, dxy=TRUE, pr=TRUE);
My output (cox.val):
inde
lehe wrote:
>
> Thank you!
> Yes, I am using the plotCI from gplots and I want the line connecting the
> centers to be dashed, just as for the bars. However changing the type to
> be "p" as you said does not give dashed line but no line at all (only
> points).
>
>
Yes, but the next line
l
On Tue, 12 May 2009, f.query wrote:
Greetings -
Am hoping to use the strucchange package to look for structural breaks in
some messy regression data. A series of preliminary analyses indicate that
BLUE for these data will involve some weighting the data (estimates of a
particular population
Thank you very much, Martin.
Warmest regards, b
Em 13/05/2009, às 09:14, "Martin Maechler"
escreveu:
!#x000a
>> "TS" == Tao Shi
>>on Wed, 10 Oct 2007 06:15:53 + writes:
>
>TS> Thank you very much, Benilton and Prof. Ripley, for the
>TS> speedy replies!
>
>TS> Looking
Hi Dana,
> -- Forwarded message --
> From: Dana Sevak
> To: r-help@r-project.org
> Date: Tue, 12 May 2009 23:02:00 -0700 (PDT)
> Subject: [R] Help with reshape/reShape and indexing
>
> Dear R Helpers,
>
> I have trouble applying reShape and reshape although I read the documentatio
Thanks alot I found the function
x0 <- c(0, sort(Sample))
p0 <- 0:1000/1000
lines(x0, p0, type = "S", col = "blue")
Very helpfull
As it seems to plot an instantaneous representation of the variables in the
gamma distribution
Bill.Venables wrote:
>
> Here are some ideas you might like to co
Hi,
Im trying to put some numbers into a dataframe , I have a list of numbers
(change points in a time series) like such
[1] 2 11 12 20 21 98 99
but I want R to recognise this as just a character string so it will put it
in one row and column, ideally I want them seperated by commas so I would
Thanks, Jim. This seems to be what I am looking for. Just have to fine tune
the colors to get some distinctive greens, blues, yellows and oranges in
there and I should be good to go.
Jim Lemon-2 wrote:
>
> It was the NAs that fooled color2D.matplot. This gets your colors,
> although not exac
Hello
Apologies if this is a simple question, I have searched the help and
have not managed to work out a solution.
Does anybody know an efficient method for reading many text files of the
same format into one table/dataframe?
I have around 90 files that contain continuous data over 3 mont
Dear All,
I am desperately trying to find any R package that fits a mixture survival
models also know as a cure models. This are survival model where the survival
function is improper which also means that a fraction of subjects are
expected not to expreience the event. A Huge literature
Dear Melissa,
Try this:
> x <- c(2, 11, 12, 20, 21, 98, 99)
> paste(x, collapse=",")
[1] "2,11,12,20,21,98,99"
See ?paste for more information.
HTH,
Jorge
On Wed, May 13, 2009 at 5:53 AM, Melissa2k9 wrote:
>
> Hi,
>
> Im trying to put some numbers into a dataframe , I have a list of numbers
Hi, do you have any suggestions how to make 3D scatterplot, BUT under linux.
Worth mentioning is the fact that 'scatterplot3d' does not load under Ubuntu
8.10.
Do you know any alternatives?? I tried cloud or persp but X,Y and Z axes are
emprical in my case, and cannot be replaced by any seq(...).
Check out:
http://www.math.mun.ca/~ypeng/research/
On Wed, May 13, 2009 at 8:34 AM, marc bernard
wrote:
>
> Dear All,
>
>
>
> I am desperately trying to find any R package that fits a mixture survival
> models also know as a cure models. This are survival model where the
> survival function i
Also:
http://post.queensu.ca/~pengp/software.html
On Wed, May 13, 2009 at 9:21 AM, Gabor Grothendieck
wrote:
> Check out:
>
> http://www.math.mun.ca/~ypeng/research/
>
> On Wed, May 13, 2009 at 8:34 AM, marc bernard
> wrote:
>>
>> Dear All,
>>
>>
>>
>> I am desperately trying to find any R pack
Bala subramanian-2 wrote:
>
> Friends,
>
> I have two covariance matrices (m1 and m2) of same size (150x150). I used
> contourplot function to make contour plots individually (c1 and c2). I am
> interested in making one contourplot overlapping the two individual
> contours
> so that the portio
Hi lmri.
You could do this by doing something like this:
Getting an Anova first:#
utils::data(npk, package="MASS")
( npk.aov <- aov(yield ~ block + N*P*K, npk) )
summary(npk.aov) # I want the P value from this summary of aov object.
#here is the code:
summary(npk.aov)[[1]]$P
# [1] 0.015938790 0.0
I'd first try plyr and see if it's efficient enough,
library(plyr)
listOfFiles <- list.files(pattern= ".txt")
d <- ldply(listOfFiles, read.table)
str(d)
alternatively,
d <- do.call(rbind, lapply(listOfFiles, read.table))
HTH,
baptiste
On 13 May 2009, at 12:45, SYKES, Jennifer wrote:
What types of data are in each file? All numbers, or a mix of numbers
and characters? Any missing data or special NA values?
On Wed, May 13, 2009 at 7:45 AM, SYKES, Jennifer
wrote:
> Hello
>
>
>
> Apologies if this is a simple question, I have searched the help and
> have not managed to work out
threshold wrote:
>
> Hi, do you have any suggestions how to make 3D scatterplot, BUT under
> linux. Worth mentioning is the fact that 'scatterplot3d' does not load
> under Ubuntu 8.10.
> Do you know any alternatives?? I tried cloud or persp but X,Y and Z axes
> are emprical in my case, and cann
I wonder - isn't this issue one of the reasons to use RandomForests
rather than CART?
On Wed, May 13, 2009 at 8:03 AM, Liaw, Andy wrote:
> From: Uwe Ligges
>>
>> Yuanyuan wrote:
>> > Greetings,
>> >
>> > I am using rpart for classification with "class" method.
>> The test data is
>> > the Indian
Dieter Menne wrote:
Dimitri Szerman-2 wrote:
Hello,
I was wondering if there is a function in R that imports tables directly
from a HTML document.
The XML package can do this:
http://markmail.org/message/cyicoa3htme4gei2
Duncan Temple Lang:
The htmlParse() and htmlTreeParse() functions in
I would like to change to size of the names in a cluster dendrogram (not
the axis or the header) (package clue). The "normal" things (pch,
cex.label, font) do not work here.
Thanks in advance!
Johannes
__
R-help@r-project.org mailing list
https://stat.e
Dear All,
I would like to use the 'split' function on the dataframe elements contained in
a list L.
For example :
> (df <- data.frame(cbind(c(rep('A',2), rep('B',2)), rep(1:4
X1 X2
1 A 1
2 A 2
3 B 3
4 B 4
> (L<-split(df, df$X1))
$A
X1 X2
1 A 1
2 A 2
$B
X1 X2
3 B 3
4
A new version of Design will be posted to CRAN in the next 2 days.
After than, update your system, including an update to the survival
package. Then re-try.
Your formula is wrong as it can't be negative. LR should be the
likelihood ratio chi-square stat : -2 times the difference in the two
Hello!
I very minor point.
I typed help.search("classification").
It found a bunch of things including "randomForests" - which makes a lot sense.
I am wondering why "rpart" was not found. I think - it should make sense too.
--
Dimitri Liakhovitski
MarketTools, Inc.
dimitri.liakhovit...@markett
I'm afraid I have no experience with the clue package, but if all else fails
you could consider the hclust package.
You change font size in the conventional way with this.
Cheers, Simon.
- Original Message -
From: "Penner, Johannes"
To:
Sent: Wednesday, May 13, 2009 3:08 PM
Subjec
On May 13, 2009, at 9:12 AM, Martial Sankar wrote:
Dear All,
I would like to use the 'split' function on the dataframe elements
contained in a list L.
For example :
(df <- data.frame(cbind(c(rep('A',2), rep('B',2)), rep(1:4
X1 X2
1 A 1
2 A 2
3 B 3
4 B 4
(L<-split(df, df$X1
can you provide reproducible code please?
even a fake example would help.
I would
1) set up a loop to read in each file from a directory
2) inside the loop chop up/ aggregate the data, each file in turn and spit
each new aggreagated file out to a directory using write.table(). This will
redu
I tried for example:
Plot(mycluster, font=2)
But this changes only the font size of the y-axis.
Regards
Johannes
--
Project Coordinator BIOTA West Amphibians
Museum of Natural History
Dep. of Research (Herpetology)
Invalidenstrasse 43
D-10115 Berlin
Tel: +49 (0)30 2093 8708
Fax: +49 (0)30 2093
> out <- apply(m, 1, cat, '\n')
1 3
2 4
> out
NULL
On Wed, May 13, 2009 at 5:23 AM, Wacek Kusnierczyk
wrote:
> m = matrix(1:4, 2)
>
> apply(m, 1, cat, '\n')
> # 1 2
> # 3 4
> # NULL
>
> why the null?
>
> vQ
>
> __
> R-help@r-project.or
Hi all,
I am doing some explorations using a dataset with the following
structure (id, value, flag).
For instance:
a, 2.2, 1
b, 3.0, 1
c, 2.9, 0
d, 3.1, 1
...
I have plotted a standard histogram using a simple command like:
hist(data$value)
My question:
I would like to superimpose a line ([0%-
Hi all,
I am doing some explorations using a dataset with the following
structure (id, value, flag).
For instance:
a, 2.2, 1
b, 3.0, 1
c, 2.9, 0
d, 3.1, 1
...
I have plotted a standard histogram using a simple command like:
hist(data$value)
My question:
I would like to superimpose a line ([0%-
On 13-May-09 14:43:17, Gabor Grothendieck wrote:
>> out <- apply(m, 1, cat, '\n')
> 1 3
> 2 4
>> out
> NULL
Or, more explicitly, from ?cat :
Value:
None (invisible 'NULL').
Ted.
> On Wed, May 13, 2009 at 5:23 AM, Wacek Kusnierczyk
> wrote:
>> _ _m = matrix(1:4, 2)
>>
>> _ _apply(m,
A few points to consider:
- If all the data are numeric, then use matrices instead of data frames.
- With either data frames or matrices, there is no way (that I'm aware
of anyway) in R to stack them without making at least one copy in
memory.
- Since none of the files has a header row, I would
Dear R users,
Can anyone please tell me how to generate a large number of samples in R, given
certain distribution and size.
For example, if I want to generate 1000 samples of size n=100, with a N(0,1)
distribution, how should I proceed?
(Since I dont want to do "rnorm(100,0,1)" in R for 10
Dear R users,
Can anyone please tell me how to generate a large number of samples in R, given
certain distribution and size.
For example, if I want to generate 1000 samples of size n=100, with a N(0,1)
distribution, how should I proceed?
(Since I dont want to do "rnorm(100,0,1)" in R for 1000 t
On Wed, May 13, 2009 at 5:13 PM, Debbie Zhang wrote:
>
>
> Dear R users,
>
> Can anyone please tell me how to generate a large number of samples in R,
> given certain distribution and size.
>
> For example, if I want to generate 1000 samples of size n=100, with a N(0,1)
> distribution, how shoul
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of Debbie Zhang
> Sent: Wednesday, May 13, 2009 8:18 AM
> To: r-help@r-project.org
> Subject: [R] Problems with randomly generating samples
>
>
> Dear R users,
> Can anyone please t
what about putting in a matrix, e.g.,
matrix(rnorm(1000*100), 1000, 100)
I hope it helps.
Best,
Dimitris
Debbie Zhang wrote:
Dear R users,
Can anyone please tell me how to generate a large number of samples in R, given
certain distribution and size.
For example, if I want to generate 10
If you want k samples of size n, why generate k*n samples and put them
in a k-by-n matrix where you can do what you want to each sample:
k = 10
n = 100
x=matrix(rnorm(k*n),k,n)
rowMeans(x)
If you need to do more complex things to each sample and if k is large
enough that you don't want the matrix
Uwe Ligges wrote:
> So you want some software that can do symbolic calculations? In that
> case use other software. R is designed for numerical analyses.
In particular, if you are looking for good free software, you
might try Maxima.
--
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed ar
On Wed, May 13, 2009 at 4:26 PM, Gábor Csárdi wrote:
> On Wed, May 13, 2009 at 5:13 PM, Debbie Zhang wrote:
>>
>>
>> Dear R users,
>>
>> Can anyone please tell me how to generate a large number of samples in R,
>> given certain distribution and size.
>>
>> For example, if I want to generate 1000
Dear Debbie,
Here are two options:
# Parameters
N <- 1000
n <- 100
# Option 1
mys <- replicate(N, rnorm(n))
mys
# Option 2
mys2 <- matrix(rnorm(N*n),ncol=N)
mys2
HTH,
Jorge
On Wed, May 13, 2009 at 11:13 AM, Debbie Zhang wrote:
>
>
> Dear R users,
>
> Can anyone please tell me how to generat
To all of you who answered me: Thank you so much!
Each approach taught me something new and I really appreciate your help!
Best regards,
Dana Sevak
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the pos
On 13-May-09 15:18:05, Debbie Zhang wrote:
> Dear R users,
> Can anyone please tell me how to generate a large number of samples in
> R, given certain distribution and size.
> For example, if I want to generate 1000 samples of size n=100, with a
> N(0,1) distribution, how should I proceed?
> (Sinc
Does every 100 numbers in rnorm(100 * 1000, 0, 1) have the N(0,1) distribution?
On Wed, May 13, 2009 at 11:13 PM, Debbie Zhang wrote:
>
>
> Dear R users,
>
> Can anyone please tell me how to generate a large number of samples in R,
> given certain distribution and size.
>
> For example, if I wan
Hi all,
I try to assess the parameters (K1,K2) of a model that describes the
adsorption of a molecule onto on adsorbent.
equation: dq/dt = K1*C*(qm-q)-K2*q
I know the value of 'qm' and I experimentally measure the variables 'q',
'C', and the time 't'.
t C q
1 0 144.0
Try the rSymPy or Ryacas packages.
In the rSymPy code below the var command defines x
as symbolic to sympy and then we perform the
computation:
> library(rSymPy)
Loading required package: rJava
> sympy("var('x')")
[1] "x"
> sympy("limit(x*x + x + 2, x, 2)")
[1] "8"
Or using devel version define
Good Day to All,
When sweaving the following:
\begin{table}
\centering
<>=
ftable(ifmtm$type, ifmtm$gender, ifmtm$marche , ifmtm$nfic,
dnn=c("Type","Gender","Ambulant","Visit"))
@
\caption{Four-way cross-tabulation on all data}
\label{tab:crosstab}
\end{table}
the output of ftable is not centere
Barry Rowlingson wrote:
> On Wed, May 13, 2009 at 4:26 PM, Gábor Csárdi wrote:
>
>> On Wed, May 13, 2009 at 5:13 PM, Debbie Zhang wrote:
>>
>>> Dear R users,
>>>
>>> Can anyone please tell me how to generate a large number of samples in R,
>>> given certain distribution and size.
>>>
>>>
Benoit Boulinguiez ensc-rennes.fr> writes:
> I try to assess the parameters (K1,K2) of a model that describes the
> adsorption of a molecule onto on adsorbent.
>
> equation: dq/dt = K1*C*(qm-q)-K2*q
>
> I know the value of 'qm' and I experimentally measure the variables 'q',
> 'C', and the time
You can automate this step
>key[key == "AT"] <- "TA"
## create a function to reverse a string -- see strsplit help page for this
strReverse function
reverse <- function(x) sapply(lapply(strsplit(x, NULL), rev), paste,
collapse="")
key <- rownames(a)
# combine rownames with reverse (rownames)
n<-
melt.updn <- structure(list(date = structure(c(11808, 11869, 11961, 11992,
12084, 12173, 12265, 12418, 12600, 12631, 12753, 12996, 13057,
13149, 11808, 11869, 11961, 11992, 12084, 12173, 12265, 12418,
12600, 12631, 12753, 12996, 13057, 13149), class = "Date"), variable =
structure(c(1L,
1L, 1L, 1L,
On Wed, 2009-05-13 at 11:22 +0200, Uwe Ligges wrote:
> If not, example:
>
> par(mfrow = c(2,3), mar = c(0,0,0,0), oma = c(5,5,0,0), xpd=NA)
> plot(1, xaxt="n", xlab="", ylab="A")
> plot(1, xaxt="n", yaxt="n", xlab="", ylab="")
> plot(1, xaxt="n", yaxt="n", xlab="", ylab="")
> plot(1, xlab="I", yla
Hi, Currently I am a .net programmer and would like to use R for my
statistical computations engine. I already have installed RServer250.exe so
that I could call R from my .net programming environment, however
unfortunately, i could not be able to find RServer250.exe in the R-(D) COM
Interface reg
On Wed, May 13, 2009 at 5:36 PM, Wacek Kusnierczyk
wrote:
> Barry Rowlingson wrote:
>> Soln - "for" loop:
>>
>> > z=list()
>> > for(i in 1:1000){z[[i]]=rnorm(100,0,1)}
>>
>> now inspect the individual bits:
>>
>> > hist(z[[1]])
>> > hist(z[[545]])
>>
>> If that's the problem, then I suggest
On Wed, 2009-05-13 at 12:43 -0400, stephen sefick wrote:
> melt.updn <- structure(list(date = structure(c(11808, 11869, 11961, 11992,
> 12084, 12173, 12265, 12418, 12600, 12631, 12753, 12996, 13057,
> 13149, 11808, 11869, 11961, 11992, 12084, 12173, 12265, 12418,
> 12600, 12631, 12753, 12996, 13057
I am creating an R package. I ran R CMD check on the package, and everything
passed until it tried to run the examples. Then, the result was:
* checking examples ... ERROR
Running examples in REEMtree-Ex.R failed.
The error most likely occurred in:
> ### * AutoCorrelationLRtest
>
> flush(stde
Can anyone see what I'm doing wrong here (highlighted below)? This is driving
me crazy... probably a ')' or something equally moronic...
> genw1[,1]
A2 A3 A5 A7 A9 A00010 A00012 A00013 A00014 A00015 A00017
A00018 A00019 A00021 A00023 A00024
CC CC CC CC CC
Take a look at this article on CodeProject:
http://www.codeproject.com/KB/cs/RtoCSharp.aspx
Cheers,
Dave
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Arun Kumar Saha
Sent: Wednesday, May 13, 2009 10:33 AM
To: r-h...@stat.math.e
Dear useRs,
I've been trying to run a Mann-Kendall test in my data in order to detect
trends.
I studied the examples given at the Kendall package and I can understand pretty
well how it works on time-series data.
However, my data consists of values in different sites per year, as I display
belo
Here is a response to almost exactly the same question from a couple of weeks
ago:
http://finzi.psych.upenn.edu/R/Rhelp08/2009-April/196967.html
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> F
Dear R group,
Simple anova question:
I am attempting to recreate a figure (from chapter 10 of "Mordern Statistics
for the Life Sciences", chapter 10, figure 10.8).
It is an interaction diagram plotting BYIELD (continuous) as a function of
BSPACING (categorical) with different lines/colours for an
To see what's available in other packages, try the following:
library(RSiteSearch)
AFT <- RSiteSearch.function('AFT model')
summary(AFT) # 24 help files found in 8 different packages
HTML(AFT) # opens a table with 24 rows in a web browser.
There may be nothing here that will help you,
Hi!!
I am interested in plotting 3 different (x,y,z) coordinate sets on the same
plot. How do I achieve using scatterplot3d?
Is there an easy method to call to change the projection or rotate the figure
along a particular axis? The following is the code that plots if one at a
time. Any help i
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