Il giorno mar, 19/10/2010 alle 11.12 -0700, Dieter Menne ha scritto:
Thanks Dieter for your help, but unfortunately your suggestion results
only in changing the color of the *lines* and not the color of the
*area* of the polygon.
I also tried to call "col" from within the panel.superpose
xyplot(
On Tue, Oct 19, 2010 at 10:58 PM, Daniel Weitzenfeld
wrote:
> Hi Josh,
> What I'm really trying to do is to refer to objects whose names I have
> stored in a vector. This example was arbitrary.
> I do a lot of looping through files in the working directory, or through
> objects in the namespace,
Hi
r-help-boun...@r-project.org napsal dne 20.10.2010 07:58:29:
> Hi Josh,
> What I'm really trying to do is to refer to objects whose names I have
> stored in a vector. This example was arbitrary.
> I do a lot of looping through files in the working directory, or through
> objects in the namesp
Dear All
I want to generate variable with Bivariate Normal Distribution by
use mean1 = a, variance1 = b, mean2 = c, variance2 = d, rho = e.
How I can do this.
Many Thanks.
IRD
[[alternative HTML version deleted]]
___
Hi Josh,
What I'm really trying to do is to refer to objects whose names I have
stored in a vector. This example was arbitrary.
I do a lot of looping through files in the working directory, or through
objects in the namespace, and I'm confused about how best to call upon them
from within a loop.
T
Hi, all.
I'd like to add legend on my graph but I can't. My code is follows.
library(ggplot2)
score1<-rnorm(100,0,5)
score2<-rnorm(400,10,15)
mydata<-data.frame(score1,score2)
ggplot(mydata,aes(y=score2,x=score1))+geom_point()+stat_quantile(quantiles=c(0.50),col="red")+stat_quantile(quantiles=c(0
Hi Daniel,
get() will work for any object, but cat() may not. cat() should work
for arrays, but it will be messy even for relatively small ones. For
example, run:
cat("Hello", array(1:100, dim = c(10, 10)), sep = " ")
What are you really trying to do? If you are just trying to figure
out what
# Let's say I have 5 objects, object_1, object_2, etc.
for (i in 1:5) {
assign(paste("object_",i, sep=""), i+500)
}
# Now, for whatever reason, I don't know the names of the objects I've
created, but I want to operate on them.
list<-ls(pattern="^obj")
#Is get best?
for (l in list) {
cat("
If b1+b2+b3 = 0 can't you put b3 = -b1-b2 and re-write the model in terms of b1
and b2 alone? The model is stil (g)linear.
If the parameters to which you refer corresponds to the levels of a factor,
then you can use the contr.sum contrast matrices. It essentailly does the
above.
-Origin
i am trying to use optim() fn in R to estimate mle of my pdf. even though I
am able to get the results, but there are always warning message, which says
that NaN produced. I am not very sure if I should ignore these warning
message since I have got solution without error message.
I am wondering
Hi:
Following up on Ben's suggestion re ggplot2, here's a manufactured example:
# Fake data:
mortrate <- round(runif(100), 3)
dd <- data.frame(rate = mortrate, moe = 1.96 * sqrt(mortrate * (1 -
mortrate))/10,
hosp = factor(paste('H', 1:100, sep = '')))
dim(dd)
[1] 100 3
# Set
I'm looking for a function or package to estimate a glm with linear
restrictions (e.g. the sum of some parameters needs to be zero). I
found the function orlm in the package ic.infer which works for lm
models, but I need it for glm.
Thanks,
Markus
__
Hi All,
Are there any escape characters that I should be aware of when using
table.read? I don't have any '#' characters in this table.
I get the error:
A<-read.table("P:/temp.csv",header=TRUE, sep=",");
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines,
na.strings, :
line 11018 d
Hi:
I agree with Ista's point that you shouldn't be doing loess with these data
(x and y both need to be continuous for loess, but your x is discrete), but
you shouldn't be computing boxplots at each YMRS_Sum value either because
you don't have enough resid observations at Sum = 3 and 4. A combina
Hi Solafah,
You are right that two commands are equivalent when p= pnorm(a). You can
check the results by following codes.
n <- 5
a <- -1
set.seed(123456)
qnorm(runif(n,0,pnorm(a)))
p <- pnorm(a)
set.seed(123456)
qnorm(p*runif(n))
Anyway, the elements of the lower tail are not chosen equally by
XINLI LI gmail.com> writes:
>
> Dear R Users:
>
>I have the individual mortality rate and 95% CI of 100 hospitals,
> how to do the plot with the individual hospital in the Yaxis, and the
> mortality rate and 95% CI in the Xais and a overall mean as a reference
> line?
Something lik
Hi everyone,
Ive recently added a private library as a way to manage my R libraries. And
I did this by simply copying my old library to a new folder and then linking
this to R by setting my R_LIBS environmental variable in .Renviron.
However I have run into a problem.
When I update my pa
Try this:
rm(list = setdiff(ls(), 'poprho.3'))
On Tue, Oct 19, 2010 at 11:29 PM, Jumlong Vongprasert <
jumlong.u...@gmail.com> wrote:
> Dear All
>I have this
> > ls()
> [1] "IWJR.complete""IWJR.missing" "IWJR.reg.temp"
> [4] "IWJR.reg.temp.x" "IWJR.reg.temp.y" "I
Dear All
I have this
> ls()
[1] "IWJR.complete""IWJR.missing" "IWJR.reg.temp"
[4] "IWJR.reg.temp.x" "IWJR.reg.temp.y" "IWJR.temp"
[7] "Power.record.100.3.5" "col.delete" "correlation.100.3.5"
[10] "i""index.temp" "iterate"
[
Hi:
This is how you could do the same in ggplot2; geom_ribbon() does the
shading. For your example, it seemed reasonable to put in reference lines,
especially since the upper limits of one confidence band abutted the lower
limits of the other in group a, so I averaged the upper and lower limits to
Hello Steve,
> I've been asked to help evaluate a vegetation data set, specifically to
> examine it for community similarity. The initial problem I see is that the
> data is ordinal. At best this only captures a relative ranking of
> abundance and ordinal ranks are assigned after data collection
Dear R Users:
I have the individual mortality rate and 95% CI of 100 hospitals,
how to do the plot with the individual hospital in the Yaxis, and the
mortality rate and 95% CI in the Xais and a overall mean as a reference
line?
Thanks and regards,
Xin
[[alternative HTML version
Hello
If i want to resample from the lower tail of normal distribution , are these
commands equivelant??
lower tail :qnorm(runif(n,0,pnorm(a))) if a is a lower tail bound
or
lower tail:qnorm(p*runif(n)) if p is the probability of each interval(the
observations are divided to intervals)
Regard
Ok so it works when I delete it from the first library (and not the
second). I misunderstood...
thanks!
Remko
Hi Duncan,
this is it:
> .libPaths()
[1] "c:\\remko\\rstuff\\library" "C:/PROGRA~1/R/R-212~1.0/library"
and you are right, I do have lattice installed in the latter
I de
Hi Duncan,
this is it:
> .libPaths()
[1] "c:\\remko\\rstuff\\library" "C:/PROGRA~1/R/R-212~1.0/library"
and you are right, I do have lattice installed in the latter
I deleted it from the second library, but it still gives me the same
error message.
Remko
--
On 19/10/2010 6:50 PM, Remko Duursma wrote:
Dear R-helpers,
I have a fresh installation of windows vista, and R 2.12.0 (session info below).
I have seen a similar error reported when someone had a copy of lattice
in a library that came ahead of the system one. What does .libPaths()
show you
Dear R-helpers,
I have a fresh installation of windows vista, and R 2.12.0 (session info below).
Problem:
> require(sp)
Loading required package: sp
Error in library.dynam(lib, package, package.lib) :
DLL 'lattice' not found: maybe not installed for this architecture?
> require(lattice)
Loadi
Argh, just now I saw a scrambled start-up message when running
xlsReadWrite1.5.2 in R2.12.0 (32-bit) on a Win7 64-bit platform. If
you have this situation and use xlsReadWrite 1.5.2 (probably all
earlier versions also) you can download a quick fix, see below. I
don't know if this also affects Vista
Hi,
First of all, I'm a complete rookie to R (~2 weeks). But anyway, I'm
trying to use the RWeka interface for C4.5 (J48) classification.
As a proof of concept I'm using the Iris data set to create a training
set of 30 instances (10 per species) and use the remaining 120
instances as my test set.
> From: nicol...@buffalo.edu
> Date: Tue, 19 Oct 2010 18:23:27 -0400
> To: r-help@r-project.org
> Subject: [R] comparing two data files
>
> I have 2 large data files that I need to compare and find the differences
> between data file x and data file y in o
On Oct 19, 2010, at 4:24 PM, Peter Francis wrote:
Dear List,
I am unsure if this is specifically a R question or a stats
question? I thought i would ask here and if i get no replies it will
answer that!
I am trying to calculate Gini coefficients in R, based on a slight
modification of
Here is some ways:
all.equal(readLines(file1), readLines(file2))
You could try compare md5sum of the files:
library(tools)
identical(md5sum(file1), md5sum(file2))
On Tue, Oct 19, 2010 at 8:23 PM, Nicole Brandt wrote:
> I have 2 large data files that I need to compare and find the differences
I have 2 large data files that I need to compare and find the differences
between data file x and data file y in order to correct data entry error.
Theoretically both data files should be identical. I am trying to figure out a
way to do this in R. Any help would be great!
___
On Oct 19, 2010, at 5:43 PM, phoebe kong wrote:
Hi there,
I would like to draw a scatter plot and fit a smooth line by loess.
Below is the data.
However, the curve line started from 0, which my "resid" list doesn't
consist of 0 value.
It returned some warnings which I don't know if this is the
The fundamental problem is that you only have five distinct x values.
lowess cannot work in this situation. Try side-by-side boxplots:
boxplot(resid.value ~ YMRS_Sum)
-Ista
On Tue, Oct 19, 2010 at 5:43 PM, phoebe kong wrote:
> Hi there,
>
> I would like to draw a scatter plot and fit a smooth l
Dear List,
I am unsure if this is specifically a R question or a stats question? I thought
i would ask here and if i get no replies it will answer that!
I am trying to calculate Gini coefficients in R, based on a slight modification
of the typical equation that i have seen in a paper.
Past
Hi there,
I would like to draw a scatter plot and fit a smooth line by loess.
Below is the data.
However, the curve line started from 0, which my "resid" list doesn't
consist of 0 value.
It returned some warnings which I don't know if this is the reason
affecting such problem. Here I also attached
You will need to install the RSQLite package, see e.g.
http://cran.r-project.org/web/packages/RSQLite/index.html
Review the installation instructions there for the setup appropriate for your
situation.
Review the pdf manual there for examples of command sequences involved with
connecting to the
Look at the EBImage package from bioconductor.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Roger Gill
> S
Look at my.symbols and ms.image in the TeachingDemos package.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of
JRI/rJava/JGR have their own mailing lists, and it would be better to
ask there.
But there was a rJava update this morning, and it is consequently
little tested. (I know for example that 64-bit JRI will need furtehr
work.) It may be that other things also need an update (like the JGR
stub).
Since upgrading to 2.12.0, I'm having trouble getting the JGR to start under
Windows 7, but I'm not quite sure what's happening.
When I try to run the JGR.exe stub, the dialog says can't find Java R interface
jri.dll. As nearly as I can tell from a Google search this is to be a part of
the r
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of Phil Spector
> Sent: Tuesday, October 19, 2010 10:49 AM
> To: David Winsemius
> Cc: r-help@r-project.org; johannes rara
> Subject: Re: [R] How to read only ten rows from a SAS data
In R, I know how to write ti csv files. However, how do I write to database
files?
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-write-to-sqlite-files-tp3002586p3002586.html
Sent from the R help mailing list archive at Nabble.com.
___
I need a picture like this:
http://rwiki.sciviews.org/doku.php?id=graph_gallery:graph38
http://rwiki.sciviews.org/doku.php?id=graph_gallery:graph38
but when I try compile it
require("hexbin")
data(NHANES)# pretty large data set!
good <- !(is.na(NHANES$Albumin) | is.na(NHANES$Transferin))
NH.var
Thanks Phil,
I'll do so now.
Much appreciated.
Steve
Steve Friedman Ph. D.
Spatial Statistical Analyst
Everglades and Dry Tortugas National Park
950 N Krome Ave (3rd Floor)
Homestead, Florida 33034
steve_fried...@nps.gov
Office (305) 224 - 4282
Fax (305) 224 - 4147
Thanks Phil, it is exactly what I was looking for.
David, I took into account how to make valid math operations, so I
understand your concern about it.
I will definitely change all my scripts and functions to considered the time
as character, but as I need a clear output soon (deadline is close)
On Oct 19, 2010, at 6:38 AM, Toni López Mayol wrote:
Hello friends of R,
My name is Toni, i'm 25 and I'm working on the Meteorological
Investigation team from Balearic Islands.
I had contact to you because I have a problem:
I done a file for every day since 1912 about precipitation. That
Steve -
Take a look at daisy() in the cluster package.
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Be
Hello
I've been asked to help evaluate a vegetation data set, specifically to
examine it for community similarity. The initial problem I see is that the
data is ordinal. At best this only captures a relative ranking of
abundance and ordinal ranks are assigned after data collection.I've
been
Ottorino-Luca Pantani wrote:
>
> The areas I would like to have in gray, are confidence bands
>
> This link is my starting point
> http://tolstoy.newcastle.edu.au/R/e2/help/07/04/15595.html
>
>
Thanks for the code example and for all the work you already put into it!
I think this is an over
I'm trying to create an R script that will execute the HMAC algorithm for
key-hashing messages. My hope is to use this script for some web
authentication via R.
The algorithm is found at http://www.ietf.org/rfc/rfc2104.txt
Here is some example code that I have done that does not work for HMAC-MD
On Oct 19, 2010, at 1:30 PM, Phil Spector wrote:
The following will create a POSIXlt object using the current date:
strptime(sprintf('%06d',breaks),'%H%M%S')
[1] "2010-10-19 07:00:00" "2010-10-19 07:15:00" "2010-10-19 07:30:00"
[4] "2010-10-19 07:45:00" "2010-10-19 08:00:00" "2010-10-19 08:1
I've verified that David's solution will work, but
a) since if is a reserved word, you must use the full name
of the argument, namely ifs
b) the argument passed through ifs= should be a full
subsetting if statement.
So adding
ifs='if _n_ <= 10'
to your sas.get call will retur
I have previously tried to use Hmisc's sas.get function, but I have
had problems with it. I think I go with your last suggestion.
-J
2010/10/19 David Winsemius :
>
> On Oct 19, 2010, at 1:31 PM, johannes rara wrote:
>
>> Thanks David,
>>
>> Yes, my code really works (using the foreign package), b
Grzesiek wrote:
>
> I need a picture like this:
> http://rwiki.sciviews.org/doku.php?id=graph_gallery:graph38
> http://rwiki.sciviews.org/doku.php?id=graph_gallery:graph38
>
> .. follows code from the web site
>
> I get an error:
> Error: could not find function "hmatplot"
>
> What is wron
On Oct 19, 2010, at 1:31 PM, johannes rara wrote:
Thanks David,
Yes, my code really works (using the foreign package), but when
handling a SAS file which contains > 500 000 rows and > 100 cols it is
not really fun anymore. My intention was do some preliminary research
from the data and the who
No.
> ?sample
to see what sample() does.
On Tue, Oct 19, 2010 at 02:59:05AM -0700, emj83 wrote:
>
> Hi,
>
> Please can someone tell me if using sample() in R is actually a quick way of
> doing the Inverse Transform Sampling Method?
>
> Many thanks Emma
> --
> View this message in context
Thanks David,
Yes, my code really works (using the foreign package), but when
handling a SAS file which contains > 500 000 rows and > 100 cols it is
not really fun anymore. My intention was do some preliminary research
from the data and the whole dataset was not needed.
After all, I could not fin
The following will create a POSIXlt object using the current date:
strptime(sprintf('%06d',breaks),'%H%M%S')
[1] "2010-10-19 07:00:00" "2010-10-19 07:15:00" "2010-10-19 07:30:00"
[4] "2010-10-19 07:45:00" "2010-10-19 08:00:00" "2010-10-19 08:15:00"
[7] "2010-10-19 08:30:00" "2010-10-19 08:45
I do not think that importing the time as character will help me, as I need
to perform several operation with them. Again, maybe I am not able to
express clearly enough. Let's just focus on this series:
> breaks
[1] 7 71500 73000 74500 8 81500 83000 84500 9 91500
93000 94
You want the 'corner' function.
It isn't (yet) in an R package but you
can find it to 'source' it in near the
bottom of the 'Public Domain Code' page
of www.burns-stat.com
Your case is precisely the reason that
'corner' came into being.
On 19/10/2010 17:10, brbell01 wrote:
Hi Just a simple qu
You may want to try something like this:
x1<-rnorm(500)
plot(x1)
test<-seq(1987, 2002, by=1)
test_2<-seq(2003, 2006, by=1)
test<-format(c(test, test_2), width=5)
xxx<-seq(1,500,length=length(test))
axis(1,at=xxx,labels=test,line=1,col=0)
You'll need to specify where you want the labels (in this c
Dear Simon,
I think the main issue is that mtext() is designed to work with a
single character string, not a character vector. Here is one approach
collapsing using paste with some space:
x1<-rnorm(500)
plot(x1)
test<-seq(1987, 2002, by=1)
test_2<-seq(2003, 2006, by=1)
mtext(paste(c(test, test_2
Let f be your estimated function. Suppose we have a root function, say
root(). You are looking for
b = root(f-a)
where a is some constant.
Now suppose we consider the inverse of f, call it f.inv. Then the following
holds:
a = root(f.inv-b).
In your code, you find
b = root(f-a)
and
c = ro
Dear colleagues, this seems like an easy problem, and I found some suggestions
which I've incorporated in the help list, but I can't quite get it right.
I want to add a series of years to a second x-axis category label. I generate
them with test and test_2 below, format them with some spacing (
On Oct 19, 2010, at 12:19 PM, Manta wrote:
David Winsemius wrote:
You seen to be under the mistaken impression that the internal
representation of DateTime classes of 08:00 would be 8. Since the
internal representation of time is in seconds, the even number hours
would be at integer mu
On 19/10/2010 12:10 PM, brbell01 wrote:
Hi Just a simple question really. I´ve got these large 2d matrices that I´d
like to inspect, but not from start to finish. The head() command is
convenient when columns are few. For large nxn matrices, however, head() and
head.matrix() are still cumbersom
Dear all,
My name is Saidi Helmi and I'm a PhD student at Sassari University (Italy).
I want to ask if there is any package for the estimation of the parameters
of "Two Component Extreme Value"(TCEV) distribution.
Thank you,
best regards,
Saidi Helmi
[[alternative HTML version deleted]
Hi Just a simple question really. I´ve got these large 2d matrices that I´d
like to inspect, but not from start to finish. The head() command is
convenient when columns are few. For large nxn matrices, however, head() and
head.matrix() are still cumbersome. Is there a simple way of viewing both
Dear R-helpers,
the problem I'm facing today is to convince lattice to paint some areas
in gray.
The areas I would like to have in gray, are confidence bands
I've googled around in the mailing list archives and eventually find
some clues.
This link is my starting point
http://tolstoy.newcastle.ed
David Winsemius wrote:
>
>
> You seen to be under the mistaken impression that the internal
> representation of DateTime classes of 08:00 would be 8. Since the
> internal representation of time is in seconds, the even number hours
> would be at integer multiples of 60*60. In addition
On Oct 19, 2010, at 11:25 AM, Manta wrote:
Dear R users, I have the following script to create bins of
specified time
intervals
bin_end=60/bin_size
bin_size=bin_size*100
h=seq(07,18,by=1)
breaks=c()
for (i in h)
{
for (j in 0:(bin_end-1))
{
Paul Murrell-2 wrote:
>
> Hi
>
> This is a rounding (truncation) problem.
> Working on a fix.
>
> Paul
>
> Sharpie wrote:
>>
>> Michael Sumner-2 wrote:
>>> I think there's something about the "discrete cell" versus "centre
>>> value"
>>> interpretation here, and you are pushing the "pixels"
Dear R users, I have the following script to create bins of specified time
intervals
bin_end=60/bin_size
bin_size=bin_size*100
h=seq(07,18,by=1)
breaks=c()
for (i in h)
{
for (j in 0:(bin_end-1))
{
value=i+(bin_size)*j
b
You cannot use `optimize' when there are two or more parameters to be
optimized. I dont know if other have suggested any solution to this, but
here are 2 approaches:
# Estimating LCL and UCL separately using `optimize'.
prior.lcl <- function(x, alpha, mean, var) {
a <- abs(plnorm(x, mean, var
lines(1:5, means.cl)
HTH,
Dennis
On Tue, Oct 19, 2010 at 7:13 AM, ashz wrote:
>
> Hi,
>
> Thanks for the tip.
>
> I run this script:
> means.cl <- c(82, 79, 110, 136,103)
> stderr.cl <- c(8.1,9.2,7.4,1.6,7.6)
> plotCI(x = means.cl , uiw = stderr.cl, pch=24)
>
> But how can I connect the mean t
Hi,
Here is an example using ggplot2. For future reference, it would be
convenient if you provided sample data. This is actually pretty easy
to do: dput(yourdata) or if your data is very large:
dput(head(yourdata)). At any rate, here is an example with the means
plotted as points and connected
Hi,
Thanks for the tip.
I run this script:
means.cl <- c(82, 79, 110, 136,103)
stderr.cl <- c(8.1,9.2,7.4,1.6,7.6)
plotCI(x = means.cl , uiw = stderr.cl, pch=24)
But how can I connect the mean triangles with a line?
Thanks
--
View this message in context:
http://r.789695.n4.nabble.com/poin
Dear Deepayan,
I had to swap "x" and "y" (see below), but otherwise it worked
perfectly. Thank you for your help.
mypanel.average <- function(x, y, FUN = mean, ...)
{
aa <- aggregate(x ~ as.numeric(y), data = environment(), FUN = FUN)
panel.points(aa[[2]], aa[[1]], ...)
}
plot <- bwplot(year
Hi Chris,
There is a jobs mailing list: https://stat.ethz.ch/mailman/listinfo/r-sig-jobs
-Ista
On Tue, Oct 19, 2010 at 10:10 AM, aquatrade wrote:
>
> Hi,
>
> There seems to be no subsection for work related postings, so please excuse
> me if this is in the wrong place.
>
> I am looking for an En
Hi,
R tells you that you don't have any object called "short" in your
workspace.
From your question, I would guess that you don't plan to have it.
What do you want the output of paste(...) to look like? Which parts are
supposed to be called through objects (that contain characters), which
o
Hi Viki,
On Tue, Oct 19, 2010 at 10:03 AM, Viki S wrote:
>
> Hi guys,
> Can anyone tell me what is the meaning of following command ?
>
> paste(execDir,paste(short,"myfile",sep="_"),sep="\")
The command means paste together the values in the variable execDir
with the pasted-together values in sh
On Oct 19, 2010, at 10:03 AM, Viki S wrote:
Hi guys,
Can anyone tell me what is the meaning of following command ?
paste(execDir,paste(short,"myfile",sep="_"),sep="\")
R gives me an error :
Error: object 'short' not found
I tried to find help about 'short' in R, but could not find any such
Hi,
There seems to be no subsection for work related postings, so please excuse
me if this is in the wrong place.
I am looking for an English speaking person with very strong R Language,
statistics and some financial math knowledge to do statistical research into
USA stock tick data.
You proba
Hi guys,
Can anyone tell me what is the meaning of following command ?
paste(execDir,paste(short,"myfile",sep="_"),sep="\")
R gives me an error :
Error: object 'short' not found
I tried to find help about 'short' in R, but could not find any such function/
object.
Viki
On Oct 19, 2010, at 7:27 AM, johannes rara wrote:
I have a text file containing data:
Som text
::
asdf
@ 1 ds $ 5. /*Edmp */
@ 8 asu $ 3. /*daf*/
@ 8 asdala $ 2. /*asdfa*/
@ 13 astun $ 11. /*daf */
@ 26 dft $ 3. /*asdf */
@ 31 dsfp $ 2. /*asdf */
asjk
asdfö
My intent
On Oct 19, 2010, at 6:47 AM, johannes rara wrote:
I'm trying to read SAS datasets on Windows:
sashome <- "C:/Program Files/SAS/SAS 9.1"
fold <- "C:/temp"
g <- read.ssd(fold, "sasfile", sascmd = file.path(sashome, "sas.exe"))
And this was successful?
How to get only e.g first ten rows into
You can do this.
dsm = c(800,600,NA,525,NA,450,400,NA,NA,NA,0)
s3 = seq(0.05,1.05,0.1)
plot(s3,dsm,col="blue",las=1,xlab="fraction",ylab="distance (km)")
fc <- function(x,a,b){a*exp(-b*x)}
fm <- nls(dsm~fc(s3,a,b),start=c(a=800,b=0))
co <- coef(fm)
curve(fc(x,a=co[1],b=co[2]),add=TRUE,col="bla
This requires the rgdal and sp packages to be installed, and assumes a
3-bandfile called image.tif
## (untested)
library(rgdal)
x <- readGDAL("image.tif")
## first band
red <- as.image.SpatialGridDataFrame(x[1])$z
## second
green <- as.image.SpatialGridDataFrame(x[2])$z
## third
blue <- as.image
It seems indeed that it is a locale issue :
> Sys.getlocale()
[1]
"LC_CTYPE=fr_FR.UTF-8;LC_NUMERIC=C;LC_TIME=fr_FR.UTF-8;LC_COLLATE=fr_FR.UTF-8;LC_MONETARY=C;LC_MESSAGES=fr_FR.UTF-8;LC_PAPER=fr_FR.UTF-8;LC_NAME=C;LC_ADDRESS=C;LC_TELEPHONE=C;LC_MEASUREMENT=fr_FR.UTF-8;LC_IDENTIFICATION=C"
> inst
Hi to all,
is there any function where I can substitute the characters with an
(jpg) image ?
Kind regards
Knut
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PLEASE do read the posting guide http://www.R-project.or
Hello friends of R,
My name is Toni, i'm 25 and I'm working on the Meteorological Investigation
team from Balearic Islands.
I had contact to you because I have a problem:
I done a file for every day since 1912 about precipitation. That file has the
following structure:
> str(Ast)
Loading req
Thanks for your help
RKoenker
I want to deal with the problem through bootstrap.so I can get p-value and
T-statistics.
Do you think so?
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View this message in context:
http://r.789695.n4.nabble.com/Question-of-Quantile-Regression-for-Longitudinal-Data-tp883458p3001875.html
Sent from the R he
Dear listers,
I have a collection of tif images that I would like to convert, in R, to a
matrix containing the values of the 8bit colour. Ideally, I would like a matrix
for each of the colour channels (red, blue and green). I have 'googled' and
searched the help list but have yet to find a solu
Hi,
There seems to be no subsection for work related postings, so please excuse
me if this is in the wrong place.
I am looking for an English speaking person with very strong R Language,
statistics and some financial math knowledge to do statistical research into
USA stock tick data.
You are p
Hello
On Tue, Oct 19, 2010 at 12:16 PM, BumSeok Jeong wrote:
> Dear R experts,
>
> I'm new in R and a beginner in terms of statistics.
> It should be simple question, but definitely difficult to solve it by
> myself.
>
> I'd like to see main effect of group(gender: sample size is
> different(M:F=
On Tue, Oct 19, 2010 at 4:18 PM, Alexandr Malusek
wrote:
> Hi,
>
> The behavior of panel.average has changed. In March 2010, I plotted
> the attached r_plotViolinOfAnnualE_old.eps. (I don't know the version
> of R). Today, I plotted the attached r_plotViolinOfAnnualE_new.eps
> using R version 2.1
On 10/19/2010 07:41 PM, ashz wrote:
Hi,
I have a data set with 3 rows (X=date, Y1=arithmetic mean and Y2=standard
deviation). How can I create a graph(e.g., points) which will show the
+-stdev as well (similar to excel).
Hi ashz,
See FAQ 7.38.
Jim
___
Looks like this may be a problem in the French translations. Please
try with LANGUAGE=en.
On Tue, 19 Oct 2010, vincent chouraki wrote:
Dear R users,
I have just upgraded R from 2.11 to 2.12 on Ubuntu 9.04 (see more informations
at the end) from the cran apt-get repository. One of the new thi
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