Here is a dodge I often use. This is a mock-up example.
___
bar <- data.frame(matrix(rnorm(1001), nrow = 1))
names(bar)[1] <- "y" ## say
head(bar[,1:5])
nbar <- names(bar)
form <- as.formula(paste(nbar[1], "~", paste(nbar[-1], collapse = "+")))
fitModel <- substitute(tm <- rpart(FO
Adrienne - this solves the problem nicely. Thanks for your help.
David S. Herzberg, Ph.D.
Vice President, Research and Development
Western Psychological Services
12031 Wilshire Blvd.
Los Angeles, CA 90025-1251
Phone: (310)478-2061 x144
FAX: (310)478-7838
email: dav...@wpspublish.com
From: woot
On Oct 23, 2010, at 7:44 PM, Jason Kwok wrote:
Thanks Jorge. It works.
Is there a way to keep the actual price in the price column instead of
TRUE/FALSE but filtering on when price>100?
Huh? When I use subset I get what you ask for:
> subset(x, Price > 100)
Price
2010-10-12 10
On Oct 23, 2010, at 6:56 PM, Gabor Grothendieck wrote:
On Sat, Oct 23, 2010 at 9:51 PM, James Hirschorn
wrote:
What is a good way to enter a very long model formula. For example:
y ~ Input.2 + Input.3 + ... + Input.1000
(assuming the corresponding dataframe has many other columns).
Is the
Hi Liping,
On Sat, Oct 23, 2010 at 2:18 AM, 刘力平 wrote:
> Dear Sir/Madam:
>
> Great thanks for R project and you contribution.
>
> I am Liping Liu, a beginner of R. Recently, I use R much. I wish you could
> improve the manual by making it search engine friendly.
>
> The "Introduction to R" page i
Hi,
I have a data-matrix:
> PID
sato hrs fim health
214 3 4.376430 6.582958 5
193 6 4.361825 3.138525 6
8441 6 4.205771 3.835886 7
7525 6 4.284489 3.245139 6
6806 7 4.168926 2.821833 7
5682 7 1.788707 1.212653 7
5225 6 1.
Thanks Jorge. It works.
Is there a way to keep the actual price in the price column instead of
TRUE/FALSE but filtering on when price>100?
Thanks,
Jay
On Sat, Oct 23, 2010 at 10:37 PM, Jorge Ivan Velez wrote:
> Hi Jay,
>
> If "x" is your data, you could use subset() to do what you want:
>
>
Dear R People
I figured it out. I should RTFM before asking questions, particularly
on Saturday nights!
Thanks for your patience.
Sincerely,
Erin
--
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodg...@gmai
Thanks for the help Jim.
As a new user and member of this mailing list, I'm very impressed with all
the support!
Jay
On Sat, Oct 23, 2010 at 10:21 PM, jim holtman wrote:
> Need to understand how 'indexing' is done in R:
>
> > x <- read.table(textConnection(" Price
> + 2010-10
Hi Jay,
If "x" is your data, you could use subset() to do what you want:
subset(x, Price > 100)
See ?subset for more information.
HTH,
Jorge
On Sat, Oct 23, 2010 at 9:56 PM, Jason Kwok <> wrote:
>Price
> 2010-10-11 99
> 2010-10-12101
> 2010-10-13102
> 2010-10-
Need to understand how 'indexing' is done in R:
> x <- read.table(textConnection(" Price
+ 2010-10-11 99
+ 2010-10-12101
+ 2010-10-13102
+ 2010-10-14103
+ 2010-10-15 99
+ 2010-10-18 98
+ 2010-10-19 97
+ 2010-10-20101
+ 2010-10-21101
+ 2010-10-2
On Sat, Oct 23, 2010 at 9:51 PM, James Hirschorn
wrote:
>
> What is a good way to enter a very long model formula. For example:
>
> y ~ Input.2 + Input.3 + ... + Input.1000
>
> (assuming the corresponding dataframe has many other columns).
>
> Is there a way to convert a character string to a form
Price
2010-10-11 99
2010-10-12101
2010-10-13102
2010-10-14103
2010-10-15 99
2010-10-18 98
2010-10-19 97
2010-10-20101
2010-10-21101
2010-10-22101
I have this dataset and I only want to return instances when the Price is >
100.
If I use t
What is a good way to enter a very long model formula. For example:
y ~ Input.2 + Input.3 + ... + Input.1000
(assuming the corresponding dataframe has many other columns).
Is there a way to convert a character string to a formula? Are there command
line expansions in R besides the simple '.'?
Dear R People:
Here is a pretty lame question, so please don't be too distressed.
I'm trying to get the compiled HTML files on Windows when installing
from source. I've set the BUILD HTML = YES and put the directory
where the Inno Setup files are into the MkRules.dist and then copied
it over to
Here is another way of doing it using some of the functions in a
step-by-step manner:
> # had to put some separators in since data format was not apparent
> # best to provide sample data with 'dput'
> x <- read.table(textConnection("Cat1|Cat2 |Cat3 | COG |Counts
+ A | B | C |COG1 |10
+
Hello Ted,
Wow, that is some good incite and food for thought. A bit past my learning
curve in statistics at this point but I will get there.
Thank you for showing me another area to consider. I have not come across
circular statistics yet.
Will
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View this message in context:
http://r.78
Yes, I guess I should update.
> R.version.string
[1] "R version 2.9.0 (2009-04-17)"
On 24-Oct-10, at 1:12 AM, Gabor Grothendieck wrote:
R.version.string
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PLEASE do read
Dear List,
I am trying to use Fast Fourier Transformation to detect cyclical trends in the
detection of acoustically tagged animals on an array of underwater receivers.
I
have found two different methods to plot periodograms based on FFT, but they
give me different results. They find the same
Thanks!
I tried reading the help for aggregate and can't figure out which form
of the formula I am using, and therefore the syntax.
I'm getting the below error.
> aggregate(counts ~ ind, merge(stack(CAT2COG), df, by = 1), sum)
Error in as.data.frame.default(x) :
cannot coerce class "formul
On Sat, Oct 23, 2010 at 7:03 PM, Alison Waller wrote:
> Thanks!
>
> I tried reading the help for aggregate and can't figure out which form of
> the formula I am using, and therefore the syntax.
>
> I'm getting the below error.
>
>> aggregate(counts ~ ind, merge(stack(CAT2COG), df, by = 1), sum)
>
On Sat, Oct 23, 2010 at 6:15 PM, Alison Waller wrote:
> Hi all,
>
> I have some data as follows.
>
> Cat1 Cat2 Cat3 COG Counts
> A B C COG1 10
> B D COG2 20
> C COG3 30
> D COG4 40
>
> I would like to sum all the counts for each category:
Hi all,
I have some data as follows.
Cat1 Cat2 Cat3 COG Counts
ABC COG1 10
BD COG2 20
C COG3 30
D COG4 40
I would like to sum all the counts for each category:
A B C D
10 30 40 60
>CAT2COG<-
lis
On 23-Oct-10 21:15:37, will phillips wrote:
> Hello Josh,
> Thank you for the tip on the cut function. I'm new to R and have
> not come across this one yet. I'll give it a go.
>
> Regarding the rationale for segmenting the wind direction, I have
> not come across any theory to drive this. My motiv
I've uploaded a new version of DAAG with clearer documentation
about cv.lm (for simple regression) and CVlm (for more general
problems.)
Sincerely,
W. John Braun, Professor and Graduate Chair
Dept. of Stat. and Act. Sci.
Western Science Centre, Rm 262
University of Western Ontario
London, Ontari
Thank you David,
I'll check that out too.
Will
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View this message in context:
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Sent from the R help mailing list archive at Nabble.com.
___
Hello Josh,
Thank you for the tip on the cut function. I'm new to R and have not come
across this one yet. I'll give it a go.
Regarding the rationale for segmenting the wind direction, I have not come
across any theory to drive this. My motivation is model fit. This wind
direction variable re
On Oct 23, 2010, at 1:40 PM, will phillips wrote:
Hello,
I have a data set that includes a predictor variable "wind
direction". This
variable is in degrees with 0=North. I've put this predictor into a
linear
model and its coefficient is far from significant.
I was thinking about conve
On Sat, Oct 23, 2010 at 1:40 PM, will phillips wrote:
>
> Hello,
>
> I have a data set that includes a predictor variable "wind direction". This
> variable is in degrees with 0=North. I've put this predictor into a linear
> model and its coefficient is far from significant.
>
> I was thinking ab
Hello,
I have a data set that includes a predictor variable "wind direction". This
variable is in degrees with 0=North. I've put this predictor into a linear
model and its coefficient is far from significant.
I was thinking about converting this variable into 8 factors "north"
"northwest" "wes
Dear Liping Liu,
You may already be familiar with this, but most browser have the
ability to search for text on the current page. Via menu's often
something like Edit -> Find or with the keyboard shortcut, Ctrl + F.
This is much more convenient than scrolling through a long page of
text looking f
Dears R
Thank you very much
Mastaki
> From: landronim...@gmail.com
> Date: Sat, 23 Oct 2010 16:56:29 +0200
> Subject: Re: [R] help
> To: dwinsem...@comcast.net
> CC: jkmast...@hotmail.com; r-help@r-project.org
>
> On Sat, Oct 23, 2010 at 4:37 PM, David Winsemius
> wrote:
> > That wasn't what
Hi, all:
My opinion is, provide a PDF tutorial is important, but not one web page
containing everything.
>From the perspective of end-user programming, most people will have a fast
reading of your tutorial to get principles of R. When they become working
with R, they need come back often to sear
Dear List,
Just curiosity (disclaimer: I never used random forests till now for
more than a little playing around):
Is there no out-of-bag estimate available?
I mean, there are already ca. 1/e trees where a (one) given sample is
out-of-bag, as Andy explained. If now the voting is done only ov
I think you should use 10 fold cross validation to judge your performance on
the validation parts. What you did will be overfitted for sure, you test on
the same training set used for your model buliding.
On Sat, Oct 23, 2010 at 6:39 AM, mxkuhn wrote:
> I think the issue is that you really can'
Hello Uwe,
Thank you very much! Works like a charm. I wouldn't have thought of that
fix on my own.
Will
--
View this message in context:
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Sent from the R help mailing list archive at Nabble.com
This is fixed in recent versions of R:
r52862 | hornik | 2010-09-01 18:21:49 -0400 (Wed, 01 Sep 2010) | 1 line
Changed paths:
M /trunk/src/library/stats/R/aggregate.R
Avoid integer overflows.
Uwe Ligges
On 22.10.20
On Sat, Oct 23, 2010 at 6:43 PM, Lee Hachadoorian
wrote:
> sh -c 'R_DEFAULT_PACKAGES="$R_DEFAULT_PACKAGES Rcmdr" R "$@"'
>
> This is pulled directly from the launcher that Ubuntu creates when it
> installs Rcmdr from the repository.
>
It seems that the CRAN Rcmdr also ships an Rcmdr.desktop file i
On Sat, Oct 23, 2010 at 6:43 PM, Lee Hachadoorian
wrote:
> sh -c 'R_DEFAULT_PACKAGES="$R_DEFAULT_PACKAGES Rcmdr" R "$@"'
>
Oh, nice! Thanks a lot, it works like a charm. Regards
Liviu
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R-help@r-project.org mailing list
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> From: David Winsemius [mailto:dwinsem...@comcast.net]
> Sent: Friday, October 22, 2010 9:43 PM
> To: William Dunlap
> Cc: Dimitri Liakhovitski; r-help
> Subject: Re: [R] lm looking for weights outside of the
> user-defined function
>
>
> On Oct 22, 2010, at 12:17 PM, William Dunlap wrote:
...
Liviu,
Try
sh -c 'R_DEFAULT_PACKAGES="$R_DEFAULT_PACKAGES Rcmdr" R "$@"'
This is pulled directly from the launcher that Ubuntu creates when it
installs Rcmdr from the repository.
--Lee
On 10/23/2010 11:37 AM, Liviu Andronic wrote:
> On Sat, Oct 23, 2010 at 5:30 PM, Henrique Dallazuanna
> wro
A tutorial on EMACS as an end-user GUI (form) to an R process
Item 4 at
http://mysite.verizon.net/mbcladwell/
Mortimer
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PLEASE
David Winsemius writes:
> On Oct 22, 2010, at 12:50 PM, wrote:
>
>> Tal Galili writes:
>>
>>> I suspect that using "dev.copy2eps" Is not going to help you here.
>>>
>>> Please try again using:
>>>
>>> pdf(...) # Check: ?pdf
>>> for(i in something)
>>> {
>>> plot(things)
>>> }
>>> dev.
Hi all,
I have found a couple posts on this topic but could not (yet) find an
answer. Is there a way to extract the model (trees and weights) from
the GBM package in order to program the prediction in a non R
environment (SQL database)? The constraint of not using R is based on
production requirem
Hi list,
>From the xyplot() documentation I'm guessing this may not be possible, but is
>there a way to specify a scale definition something between relation="free"
>and relation="same" such that the scales are fixed across rows and column
>margins are removed for a M x N conditioning plot (so
On 22.10.2010 19:36, Marcelo Lima wrote:
Hi,
Created a covariance matrix and i would like to add a diagonal line to the
plot, any suggestions?
I do not really understand your question. If you actually want to access
the main diagonal of a matrix or add a diagonal matrix to another
matrix,
On 23.10.2010 00:17, Daniel Weitzenfeld wrote:
<< repost because previous attempt was not plain text, sorry!>>
Hi Folks,
I have a pretty simple problem: after building a multivariate linear model,
I need to report my 95% confidence interval for predictions based on future
observations.
I kno
On 21.10.2010 22:20, Stratos Laskarides wrote:
Hi there
Thank you for everyone's help in all my previous questions.
By way of intro, I am a masters student in actuarial science at the
University of Cape Town, and I am doing a project in R on some healthcare
cost data. Just for clarity befor
On 21.10.2010 19:53, David Winsemius wrote:
On Oct 21, 2010, at 11:59 AM, omerle wrote:
Thanks for you answer.
It s sufficient but I d like to know why my system think I am CEST and
yours think your are EDT.
It probably acquired it from your OS at the time of R's installation.
No, the OS
On Sat, Oct 23, 2010 at 5:30 PM, Henrique Dallazuanna wrote:
> In windows it work's fine
>
After further experimentation, it does work when I escape the
parentheses. However, both
l...@liv-laptop:~$ R --interactive -e require\(Rcmdr\)
and
l...@liv-laptop:~$ R -e require\(Rcmdr\) --interactive
fa
In windows it work's fine
On Sat, Oct 23, 2010 at 12:36 PM, Liviu Andronic wrote:
> On Sat, Oct 23, 2010 at 2:07 PM, Henrique Dallazuanna
> wrote:
> > You've tried removing the quotes around require?
> >
> Yes, but it fails:
> l...@liv-laptop:~$ R --interactive -e require(Rcmdr)
> bash: syntax e
On 21.10.2010 00:39, Alejo C.S. wrote:
Dear list, I'm trying to make a biplot, but instead of plotting the row
number for each observation, plot a group factor.
Example:
prcomp(iris[,1:4]) -> PCA
biplot(PCA) #this makes a nice biplot but with row names
Instead of row numbers I want to
On Sat, Oct 23, 2010 at 10:52 AM, Dimitri Liakhovitski
wrote:
> Just tried it on my work computer (Windows XP, I only have 2 GB RAM):
> I've run your code, just indicated the separator "|" in read.table (in
> DF line) and added the actual processing (writing out of the result
> with a file name) -
Also am running the same code on my powerful home PC.
It's been running for 25 minutes already, and still has not printed
the first end time (does it mean it's still trying to read in DF for
the first time)?
On Sat, Oct 23, 2010 at 10:52 AM, Dimitri Liakhovitski
wrote:
> Just tried it on my work
On 23.10.2010 08:28, karthicklakshman wrote:
Hello Petr Pikal,
Thanks for the suggestion.
I am sorry for not being very clear in my mail. from your example, Its clear
to me now about how to turn factors to character values.
I am working on large data sets, and the ultimate aim is to create
On 23.10.2010 17:08, will phillips wrote:
Hello Dr. Pagel,
Thank you very much for the input. It is "almost" working. It will
indicate every day of the week except Sunday. Any multiple of 7 is giving
.
I'll tinker with it a bit. I really appreciate the direction you've
provided.
foo <-
Hello Dr. Pagel,
Thank you very much for the input. It is "almost" working. It will
indicate every day of the week except Sunday. Any multiple of 7 is giving
.
I'll tinker with it a bit. I really appreciate the direction you've
provided.
Will
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Could you please paste the exact code you are using? (the one with the pdf
and dev.off, outside the loop )
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatist
On Sat, Oct 23, 2010 at 4:37 PM, David Winsemius wrote:
> That wasn't what I understood him to be asking, but rather how to create new
> variables within existing dataframes. My suggestion would be to work with
> the examples on the help(with) and help(transform) pages.
>
Oh, then Quick-R [1] may
Just tried it on my work computer (Windows XP, I only have 2 GB RAM):
I've run your code, just indicated the separator "|" in read.table (in
DF line) and added the actual processing (writing out of the result
with a file name) - see below.
I got:
Error in textConnection(x) : cannot allocate memory
> I have a vector of numbers ranging form 20 to 500. The numbers represent
> days since a starting point. The list is not consecutive, some numbers
> skipped and some numbers duplicated. I know day 1 was a Monday. I want to
> use this vector in a lm but I need to factor by day. I'm wondering ho
On Thu, Oct 21, 2010 at 2:00 PM, Ben Bolker wrote:
> Michal Figurski mail.med.upenn.edu> writes:
>
>> I have a data set of roughly 10 million records, 7 columns. It has only
>> about 500MB as a csv, so it fits in the memory. It's painfully slow to
>> do anything with it, but it's possible. I also
On Oct 23, 2010, at 4:13 AM, Liviu Andronic wrote:
Hello
On Sat, Oct 23, 2010 at 10:43 AM, Mastaki Kambale > wrote:
Dears R
I am a self taught novice user of R. I begin to understand its
philosophy and some basics like objects, vectors, arrays, lists
etc...I still am not able to manipula
On Sat, Oct 23, 2010 at 2:07 PM, Henrique Dallazuanna wrote:
> You've tried removing the quotes around require?
>
Yes, but it fails:
l...@liv-laptop:~$ R --interactive -e require(Rcmdr)
bash: syntax error near unexpected token `('
l...@liv-laptop:~$ R -e require(Rcmdr) --interactive
bash: syntax e
Gabor, thanks a lot. So, I don't really need sql? That's great.
I'll try your code.
To finish with sql, I've run this:
(I wanted to skip the first 11 million rows)
mydata<-read.csv.sql("my.file.txt", sep="|", eol="\r\n", sql =
"select * from file limit 100, 1099")
After 20 min (on a 4-co
If Dennis' interpretation of your request is correct then Harrell rms/
Hmisc packages provide a mechanism for restricting plotting of
contours to the region within a perimeter. He has a perimeter function
and the bplot function takes a perim argument. The reason I did not
offer it earlier is
On Sat, Oct 23, 2010 at 10:07 AM, Dimitri Liakhovitski
wrote:
> I just tried it:
>
> for(i in 11:16){ #i<-11
> start<-Sys.time()
> print(start)
> flush.console()
> filename<-paste("skipped millions- ",i,".txt",sep="")
> mydata<-read.csv.sql("myfilel.txt", sep="|", eol="\r\n", sql =
> "select
Hello,
I have seen a few posts about changing a vector of numbers to days of the
week where the numbers are 1-7. I have a similar problem with a twist.
I have a vector of numbers ranging form 20 to 500. The numbers represent
days since a starting point. The list is not consecutive, some numbers
O, wait a sec - does it mean I can't feed my objects into sql commands?
On Sat, Oct 23, 2010 at 10:07 AM, Dimitri Liakhovitski
wrote:
> I just tried it:
>
> for(i in 11:16){ #i<-11
> start<-Sys.time()
> print(start)
> flush.console()
> filename<-paste("skipped millions- ",i,".txt",sep="")
>
I just tried it:
for(i in 11:16){ #i<-11
start<-Sys.time()
print(start)
flush.console()
filename<-paste("skipped millions- ",i,".txt",sep="")
mydata<-read.csv.sql("myfilel.txt", sep="|", eol="\r\n", sql =
"select * from file limit 100, (100*i-1)")
write.table(mydata,file=filename,sep
2011 Regression Modeling Strategies Short Course by Frank E. Harrell, Jr.,
Ph.D., Professor and Chair, Department of Biostatistics, Vanderbilt University
School of Medicine.
2011 Dates: Wednesday, March 9 (8:00AM-11:00AM), Thursday, March 10
(8:00AM-4:00PM) and Friday, March 11, 2011 (8:00AM-
Oh, I understand - I did not realize it's reading in the whole file.
So, is there any way to make it read it in only once and the spit into
R just one piece (e.g., 1 million rows), write a regular file out
(e.g., a txt using write.table), and then grab the next million?
Because I was planning to do
I think the issue is that you really can't use the training set to judge this
(without resampling).
For example, k nearest neighbors are not known to over fit, but a 1nn model
will always perfectly predict the training data.
Max
On Oct 23, 2010, at 9:05 AM, "Liaw, Andy" wrote:
> What Breim
On Sat, Oct 23, 2010 at 9:20 AM, Dimitri Liakhovitski
wrote:
> This is very helpful, Gabor.
> I've run the code to figure out the end of the line and here is what I
> am seeing at the end of each line: \r\n
> So, I specified like this:
> mydata<-read.csv.sql("myfile.txt", sep="|", eol="\r\n", sql
This is very helpful, Gabor.
I've run the code to figure out the end of the line and here is what I
am seeing at the end of each line: \r\n
So, I specified like this:
mydata<-read.csv.sql("myfile.txt", sep="|", eol="\r\n", sql = "select
* from file limit 200, 100")
However, again it's hanging agai
What Breiman meant is that as the model gets more complex (i.e., as the
number of trees tends to infinity) the geneeralization error (test set
error) does not increase. This does not hold for boosting, for example;
i.e., you can't "boost forever", which nececitate the need to find the
optimal numb
Hi Jim,
You don't mention whether you have any prior information regarding X2
that can be used to constrain values imputed for it. I think you will
need some because without it values sampled for b and X2 respectively
will just "see-saw" against each other.
Michael
On 22 October 2010 18:37, Jim
On Sat, Oct 23, 2010 at 7:44 AM, Dimitri Liakhovitski
wrote:
> Gabor,
> maybe some of my code is wrong (I don't know sql at all). I tried the
> following with just a few lines as a test:
> library(sqldf)
> mydata<-read.csv.sql("myfile.txt",sep="|", sql = "select * from file 200,
> 100")
"limit"
You've tried removing the quotes around require?
On Sat, Oct 23, 2010 at 6:19 AM, Liviu Andronic wrote:
> Dear all
> I would like to start R with Rcmdr from the cli, without tweaking
> Rprofile.site. This has been discussed in the past [1], but I don't
> see a solution that (1) could be used with
http://www.sangermanomobili.it/mfoto.php
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Gabor,
maybe some of my code is wrong (I don't know sql at all). I tried the
following with just a few lines as a test:
library(sqldf)
mydata<-read.csv.sql("myfile.txt",sep="|", sql = "select * from file 200, 100")
But it's just hanging. The same happened when I wrote:
mydata<-read.csv.sql("myfile.
No (and I have an excuse).
It is a tree of pages rather than a
single document. My impression is
that a pdf needs to be linear.
On 23/10/2010 10:09, Liviu Andronic wrote:
(off-topic)
Dear Patrick
On Sat, Oct 23, 2010 at 10:57 AM, Patrick Burns
wrote:
Perhaps 'Some hints for the R beginner'
Hello
On Sat, Oct 23, 2010 at 10:43 AM, Mastaki Kambale wrote:
>
> Dears R
> I am a self taught novice user of R. I begin to understand its philosophy and
> some basics like objects, vectors, arrays, lists etc...I still am not able to
> manipulate variables (objects!) in dataframes (objects als
Dears R
I am a self taught novice user of R. I begin to understand its philosophy and
some basics like objects, vectors, arrays, lists etc...I still am not able to
manipulate variables (objects!) in dataframes (objects also !!!) already
imported from my usual statistical package (stata 10/SE) d
(off-topic)
Dear Patrick
On Sat, Oct 23, 2010 at 10:57 AM, Patrick Burns
wrote:
> Perhaps 'Some hints for the R beginner'
> http://www.burns-stat.com/pages/Tutor/hints_R_begin.html
>
Do you provide a PDF version of this human-friendly introduction to R? :)
Regards
Liviu
> is closer to what you
Perhaps 'Some hints for the R beginner'
http://www.burns-stat.com/pages/Tutor/hints_R_begin.html
is closer to what you have in mind.
It includes links to other documents
that are possibly along the lines you
seek.
On 23/10/2010 07:18, 刘力平 wrote:
Dear Sir/Madam:
Great thanks for R project and yo
I'm not quite familiar with E-M algorithm, but I think what I did was the
first step of the iteration.
The method used in the original article is as follow:
http://r.789695.n4.nabble.com/file/n3008241/untitled.png
I gave lamda an initial value, and maximized the likelihood function.
This is the
Dear all
I would like to start R with Rcmdr from the cli, without tweaking
Rprofile.site. This has been discussed in the past [1], but I don't
see a solution that (1) could be used with any working directory and
(2) would avoid starting Rcmdr on every R start-up.
Personally I tried the following,
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