On Sat, 27 Nov 2010, Mike Prager wrote:
Dear Gurus,
R 2.11.1 on Windows XP.
This is a problem in interaction between R and pdftex.
I need to generate a plot with both open and filled circles. It is
simple enough, using pch=1 and pch=16.
The R pdf graphics output is going into pdftex 1.40.10
Dear Peter,
thanks a lot, modifyList() did it perfectly!
Cheers,
Marius
On 2010-11-28, at 01:26 , Peter Ehlers wrote:
> On 2010-11-27 15:03, Marius Hofert wrote:
>> Dear Peter,
>>
>> do you know anything similar for a cloud() plot?
>> This does not work:
>>
>> library(lattice)
>> x<- matrix
Dear Gurus,
R 2.11.1 on Windows XP.
This is a problem in interaction between R and pdftex.
I need to generate a plot with both open and filled circles. It is
simple enough, using pch=1 and pch=16.
The R pdf graphics output is going into pdftex 1.40.10 (MikTeX 2.8).
The R pdf is correct when vi
On Sat, Nov 27, 2010 at 1:56 PM, Georg Ruß wrote:
> On 27/11/10 19:04:27, Serdar Akin wrote:
>> Hi
>> No its has to be like this:
>> a b
>> 1 1
>> 2 2
>> 3 3
>> 4
>> 5
>> 6
>
Assuming the empty cells are to be NAs turn a and b into ts objects
(since ts objects w
I think all you need is
?split
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Eduardo de Oliveira Horta
Sent: Sunday, 28 November 2010 8:02 AM
To: r-help@r-project.org
Subject: [R] Two time measures
Hello!
I have a csv file of
Actually, I had until I created this file had everything on one line,
or had separate \SweaveOpts commands.
Putting everything on one line ensures that the graphics file
goes to the subdirectory snArt, but the file test1.tex is unchanged.
Note however the difference between the files test1.tex an
On 27/11/2010 7:57 PM, John Maindonald wrote:
Actually, I spoke too soon. The files process without obvious error,
but keep.source=TRUE is ignored. I have posted small files
test1.Rnw and test2.Rnw that can be used to demonstrate the
problems at:
http://wwwmaths.anu.edu.au/~johnm/r/issues/
On 27/11/2010 7:57 PM, John Maindonald wrote:
Actually, I spoke too soon. The files process without obvious error,
but keep.source=TRUE is ignored. I have posted small files
test1.Rnw and test2.Rnw that can be used to demonstrate the
problems at:
http://wwwmaths.anu.edu.au/~johnm/r/issues/
Actually, I spoke too soon. The files process without obvious error,
but keep.source=TRUE is ignored. I have posted small files
test1.Rnw and test2.Rnw that can be used to demonstrate the
problems at:
http://wwwmaths.anu.edu.au/~johnm/r/issues/
Sweave("test1") ## includes SweaveOpts settin
On Sat, Nov 27, 2010 at 5:02 PM, Eduardo de Oliveira Horta
wrote:
> Hello!
>
> I have a csv file of intra-day financial data (5-min closing prices) that
> looks like this: (obs - the dates are formated as day/month/year, as is
> usual here in Brazil)
>
> Date;Time;Close
> 01/09/2009;10:00;56567
>
On Wed, Nov 17, 2010 at 2:27 PM, Paolo Rossi
wrote:
> I sent a post to find a clever way to compute a Rolling Average of columns
> in a matrix and I was given the solution below which I am very pleased
> with.
>
There is a zoo function that does this. The following converts a to
zoo, performs t
On 2010-11-27 15:03, Marius Hofert wrote:
Dear Peter,
do you know anything similar for a cloud() plot?
This does not work:
library(lattice)
x<- matrix(runif(900),ncol=3)
cloud(x[,3]~x[,1]*x[,2],scales = list(col = 1, arrows=FALSE),
par.settings = list(standard.theme(color=FALS
Hi Dr. Friendly,
On Sat, Nov 27, 2010 at 2:56 PM, Michael Friendly wrote:
> Just as as.vector() takes a vector, matrix or array and returns a vector in
> row-major order,
> I'd like to write a function to take such an object and return the dimension
> names,
> pasted with some separator, as a si
Dear Peter,
do you know anything similar for a cloud() plot?
This does not work:
library(lattice)
x <- matrix(runif(900),ncol=3)
cloud(x[,3]~x[,1]*x[,2],scales = list(col = 1, arrows=FALSE),
par.settings = list(standard.theme(color=FALSE),
axis.line=list(col="t
On 11/27/2010 11:45 PM, 44whyfrog wrote:
Hi all,
I'm new to R and I'm struggling with loading a data file without attribute
names, like:
1,72,0,5.6431,28.199
1,72,0,12.666,28.447
1,72,0,19.681,28.695
1,72,0,25.647,28.905
It has no names for the columns nor the rows. I tried
data<- read.table
Just as as.vector() takes a vector, matrix or array and returns a
vector in row-major order,
I'd like to write a function to take such an object and return the
dimension names,
pasted with some separator, as a similar vector.
Here is something ugly cobbled together to demonstrate what I want:
Try this:
> x <- structure(list(Date = c("01/09/2009", "01/09/2009", "01/09/2009",
+ "01/09/2009", "01/09/2009", "01/09/2009", "02/09/2009", "02/09/2009",
+ "02/09/2009", "02/09/2009", "02/09/2009", "02/09/2009"), Time = c("10:00",
+ "10:05", "10:10", "16:45", "16:50", "16:55", "10:00", "10:05",
+
Hi there,
Thanks a lot. It helped.
Best,
Rudra
On Wed, Nov 24, 2010 at 3:34 PM, JCFaria [via R] <
ml-node+3058122-1766967341-203...@n4.nabble.com
> wrote:
> Hello,
>
> All you need are explained at Help/Main/User guide/HTML from Tinn-R menu.
>
> Basically:
> 1. Close R
> 2. Menu R/Configure/
Awesome - thanks!
Paolo
On 17 November 2010 19:44, Ray Brownrigg wrote:
> On Thu, 18 Nov 2010, Paolo Rossi wrote:
> > I sent a post to find a clever way to compute a Rolling Average of
> columns
> > in a matrix and I was given the solution below which I am very pleased
> > with.
> >
> >
> > R
Hello!
I have a csv file of intra-day financial data (5-min closing prices) that
looks like this: (obs - the dates are formated as day/month/year, as is
usual here in Brazil)
Date;Time;Close
01/09/2009;10:00;56567
01/09/2009;10:05;56463
01/09/2009;10:10;56370
##(goes on all day)
01/09/2009;16:45;
Hi Serdar,
One way would be:
l <- list(a, b)
do.call(cbind, lapply(l, function(x) x[1:max(sapply(l, length))]))
HTH,
Jorge
On Sat, Nov 27, 2010 at 10:04 AM, Serdar Akin <> wrote:
> Hi
>
> I'm trying two combine two vectors that have different lengths. This
> without
> recursive the shorter on
On 27/11/10 19:04:27, Serdar Akin wrote:
>Hi
>No its has to be like this:
>a b
>1 1
>2 2
>3 3
> 4
> 5
> 6
Hmm, "empty" elements in such an array? Seems not really recommended, if
it's possible at all. You may try filling up the shorter vector with NA's
or any
okay, solved :-))
It is mentioned here:
http://r.789695.n4.nabble.com/How-to-remove-outer-box-from-Wireframe-plots-td824819.html
so ...
wireframe(z ~ x*y, data = test, scales = list(col = "black", arrows = FALSE),
par.settings = list(axis.line = list(col = "transparent")))
... solves it.
Cheer
Dear expeRts,
below is a minimal example from the thread
http://www.mail-archive.com/r-help@r-project.org/msg48098.html
about how to remove the outer box / frame of a wireframe plot.
As one can see, the suggested code does remove the box (by making it
transparent),
however, it also removes the
Hi Romildo,
Merge two table by id2 first, then reshape to the wide format, sum by source
at last. Hope it helps.
### Data simulation
lsp.text <- " id source destiny id2 caminho order
1 1 2 4 7 0 0
2 2 6 10 4 0 0
3 3 6
if you want linear models (not specified), something like this should work:
Put your 1800 response variables (as columns) in a nx1800 matrix
resp_mat, and then
lm(resp_mat ~ latitude*age) # interactions
lm(resp_mat ~ latitude+age # without interactions
Kjetil
On Fri, Nov 26, 2010 at 9:01 PM,
On 27/11/10 16:04:35, Serdar Akin wrote:
> I'm trying two combine two vectors that have different lengths. This without
> recursive the shorter one. E.g.,
>
> a <- seq(1:3)
> b <- seq(1:6)
If that means your output should be (1 2 3 1 2 3 4 5 6) then
c <- c(a,b) should solve this. Looks like _the_
Hi
I'm trying two combine two vectors that have different lengths. This without
recursive the shorter one. E.g.,
a <- seq(1:3)
b <- seq(1:6)
Thanks in advance
Serdar
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
h
On 11/25/2010 10:30 AM, Peter Ehlers wrote:
On 2010-11-25 07:06, statmobile wrote:
On 11/25/2010 09:44 AM, Dimitris Rizopoulos wrote:
try this:
Reduce("+", x) / length(x)
Thanks Dimitris, that's very slick, I was unaware of this Reduce
function.
The issue, is that I actually wanted to do a
On 2010-11-26 22:33, Troy Lynch wrote:
Thank you, Joshua -- great name by the way; he was a Biblical champ! -- fro
your suggestion. Sorry about the belated response. Nope, even the script
editor will not allow pastes (after the R Console has also refused to allow
pastes). I do agree that it is p
Am Samstag, 27. November 2010, 15:59:46 schrieb Stephen Liu:
> Hi folks,
>
> I can't figure out using help.search to find the name of the dataset on
> database. If it is NOT the right tool please advise which tool shall I
> use? TIA
>
> B.R.
> Stephen L
>
>
>
> [[alternative HTML versio
>
> So in this example, it seems more efficient to sort first and use the
> algorithm assuming that the data is sorted.
>
> There is probably a way to be smarter in nodup_cpp where the bottleneck
> is likely to be related to map::find.
If you just use a hash table, std::map should work too,
I d
Hi folks,
I can't figure out using help.search to find the name of the dataset on
database. If it is NOT the right tool please advise which tool shall I use?
TIA
B.R.
Stephen L
[[alternative HTML version deleted]]
__
R-help@r-project.org
I am having problems installing RWinEdt on a Windows 7 machine after
upgrading to R 2.12 and running R as an administrator. I have WinEdt 5.x
installed on my machine (no WinEdt 6). Please see the r session as below.
Would appreciate any feedback.
Thx.
_
Hello,
Given the matrices LSPs and services, need to generate the matrix
(mtraffic) as follows:
1. Browse all lines of LSPs
2. Collect the value of bw (matrix services) in accordance with id2
3. Sum bw in mtraffic (line = source) (column = destiny)
Thanks!
Romildo Martins
***
Hello,
Someone pointed out to me off list about this construct:
nodup_sort <- function(x, fun = nodup3){
i <- sort.list(x)
x[i] <- fun(x[i])
x
}
which deals more efficiently with the reordering.
> x <- sample( 1:10, size = 30, replace = TRUE )
> system.time( nodup_cpp( x )
You need to follow the posting guide and show exactly what you did. I
read in your data and can print it. You did not show what 'x', and
'y' were in your data:
> myData <- read.table('clipboard', sep=',')
> myData
V1 V2 V3 V4 V5
1 1 72 0 5.6431 28.199
2 1 72 0 12.6660 28.447
3
Thanks very much, exactly what I was looking for :-)))
Cheers,
Marius
On 2010-11-27, at 13:16 , Peter Ehlers wrote:
> On 2010-11-27 03:31, Marius Hofert wrote:
>> Hi,
>>
>> I get a warning () using
>>
>> xyplot.<- function(u) {
>> BW.theme<-
>> list(strip.background = list(col =
Hi all,
I'm new to R and I'm struggling with loading a data file without attribute
names, like:
1,72,0,5.6431,28.199
1,72,0,12.666,28.447
1,72,0,19.681,28.695
1,72,0,25.647,28.905
It has no names for the columns nor the rows. I tried
data <- read.table(path,header = FALSE, sep = ",")
and it s
On Fri, Nov 26, 2010 at 6:35 PM, Marius Hofert wrote:
> I am not sure if I found a bug...
> I would like to create a function that itself creates a lattice plot without
> colors. Following
> http://www.mail-archive.com/r-help@r-project.org/msg64699.html
> I use trellis.device() to set the colors
On 2010-11-27 03:31, Marius Hofert wrote:
Hi,
I get a warning () using
xyplot.<- function(u) {
BW.theme<-
list(strip.background = list(col = "gray90"),
strip.shingle = list(col=c("gray75")),
layout.heights = list(strip = c(1,1)),
>
> >
> >> Date: Thu, 25 Nov 2010 21:22:54 -0600
> >> To: santosh.srini...@gmail.com
> >> From: e...@debian.org
> >> CC: r-help@r-project.org
> >> Subject: Re: [R] Installing RQuantLib on Win 7 64 Bit
> >>
> >>
> >> On 26 November 2010 at 07:05, Santosh Sri
Ron_M wrote:
>
> I am not sure if I understood the help page. It says "fixed notation will
> be preferred unless it is more than âscipenâ digits wider". If I
> understood correctly it says, the corresponding number needs to be less
> wider than 'scipen' digit, to print it numerically. Let s
Hi,
I get a warning () using
xyplot. <- function(u) {
BW.theme <-
list(strip.background = list(col = "gray90"),
strip.shingle = list(col=c("gray75")),
layout.heights = list(strip = c(1,1)),
axis.text = list(cex = 0.8),
I am not sure if I understood the help page. It says "fixed notation will be
preferred unless it is more than âscipenâ digits wider". If I understood
correctly it says, the corresponding number needs to be less wider than
'scipen' digit, to print it numerically. Let say:
Â
> options(scipen
Il giorno sab, 27/11/2010 alle 00.35 +0100, Marius Hofert ha scritto:
> The reason why I would like to use trellis.device() within a function
> is that
> the plot contains a panel.function which contains many calls to
> panel.xyplot()
> and I do not want to write "col = 1" (e.g.) all the time...
Dear Dave,
Thank you for your recommendation. I looked over the website of AD Model
Builder for fast optimization. I want to ask you whether the software can be
used in R programming as a kind of R package? Or is there any possibility
that it can be jointly used with R packages?
Regards,
Wonsang
On 2010-11-27 02:15, Ron Michael wrote:
Hi all, can somebody help me on my little problem? I want to print a number say
"10^10" is numerical format not in scientific notation. I ttied following:
options(scipen = 1)
print(10^10, 10)
[1] 1e+10
I am not getting my desired output in simple numer
Hi all, can somebody help me on my little problem? I want to print a number say
"10^10" is numerical format not in scientific notation. I ttied following:
> options(scipen = 1)
> print(10^10, 10)
[1] 1e+10
I am not getting my desired output in simple numerical format. How can I get
that?
Tha
On Fri, 26 Nov 2010, Mike Marchywka wrote:
Date: Thu, 25 Nov 2010 21:22:54 -0600
To: santosh.srini...@gmail.com
From: e...@debian.org
CC: r-help@r-project.org
Subject: Re: [R] Installing RQuantLib on Win 7 64 Bit
On 26 November 2010 at 07:05, Santosh S
Hi folks,
library(AER)
data()
I found the datasets of AER package.
But I couldn't remove AER with:
either
detach("package:AER")
or
detach("package:AER", unload = TRUE)
data()
still found "car" there.
What will be the correct way to remove it? TIA
Besides:-
I couldn't find EcDat
> librar
Dear David,
thanks for your help. I completely missed the point of trellis.device()... It
is probably not the right thing for what I want to achieve. I do not want to
open a device or plot the xyplot-object, I just want to create it and save it
in a variable. I would like to *not* having to wri
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