Hi Simon,
Thanks for that! Yes the circular variable is a predictor variable - great
that it can be done using GAMs.
I actually would like to do a GAM-GEE model - do you know if I can do this
within R yet? I'm using GLM-GEEs because I can't do GAM-GEEs (I have data
collected over the same
#dummy data:
master=as.data.frame(list(clientId=c(1:4,2), date=1001:1005,
value=10001:10005))
control=as.data.frame(list(clientId=c(2,3), mindate=c(100,1005),
maxdate=c(1005,1005), control.params=c(1,2)))
#reducing master df:
#generating TRUE FALSE index:
idIndex=master$clientId %in%
Is it possible to make forecasts with L-STAR model (or alternatively E-STAR)
?
Although function for LSTAR exists I did not find an indication of
forecasting possibilities in the documentation.
[[alternative HTML version deleted]]
__
I am trying to do binning on three variables (3d binning). The bin boundaries
are specified by the user separately for each variable. I used the bin2
function in the 'ash' package for 2d binning that involves only two
variables but didn't any package for similar binning with three variables.
Are
Hello, all experts,
My major is computer-aied drug design ( main QSAR).
Now, my paper need be reviesed, and one reviewer ask me do genetic algorithm
coupled with gaussian process method (GA+GP).
my data:
training set: 191*106
test set: 73*106
here, I need use GA+GP to do variable
Hi Everybody,
My problem is that nlminb doesn't converge, in minimising a logLikelihood
function, with 31*6 parameters(2 weibull parameters+29 regressors repeated 6
times).
I use nlminb like this :
res1-nlminb(vect, V, lower=c(rep(0.01, 12), rep(0.01, 3), rep(-Inf, n-15)),
upper=c(rep(Inf, 12),
Dear List,
I have a data-frame
#prepare the data
example - data.frame(letters[1:9],
sample(letters, 9),
sample(letters, 9),
sample(letters, 9),
sample(letters, 9),
sample(letters, 9),
sample(letters, 9),
sample(letters, 9),
sample(letters,
On Thu, Jan 20, 2011 at 03:14:01PM -0800, Changbin Du wrote:
ROCR
I appreciate this information, which is new for me. Up to now, i was
using the function
get.auc - function(statistic, label, negative, positive)
{
xmove - as.numeric(label == negative)
ymove - as.numeric(label
Hello,
Having measured two populations' characteristics at one particular time[with
great precision] with R, I would like to extend this to measuring the same
populations starting at t1, and then again at t2, and try to develop a growth
model (something like
Try this:
replicate(500, example[sample(nrow(example), 3),], simplify = FALSE)
On Fri, Jan 21, 2011 at 8:47 AM, Sam sam_sm...@me.com wrote:
Dear List,
I have a data-frame
#prepare the data
example - data.frame(letters[1:9],
sample(letters, 9),
sample(letters, 9),
Dear Mrs Rachel Pearce,
I am looking for a function cutpt-coxph in R - like you did some years ago.
How have you solved the problem? Have you found it or a similar function?
thank you, Sincerely, Friederike
The title says it all really; I am looking for a function along the lines of
cutpt.coxph
kamel gaanoun wrote:
I use nlminb like this :
res1-nlminb(vect, V, lower=c(rep(0.01, 12), rep(0.01, 3), rep(-Inf,
n-15)), upper=c(rep(Inf, 12), rep(0.99, 3), rep(Inf, n-15)), control =
list(maxit=1000) )
and that's the result :
Message d'avis :
In nlminb(vect, V, lower = c(rep(0.01,
HI Everybody
Does anyone know of documentation about different ways of obtaining user
input in R. I have used readline() but I wondered is there are sophisticated
packages that does things like validate answers or generate selection
lists.
bets regards
Christaan
[[alternative HTML
Hi friends, there is methods() function to see the all available methods for
a particular function, for example:
head(methods(print))
[1] print.acf print.anova print.aov print.aovlist
print.ar print.Arima
In this list, there are some functions which are asterisked like
Try this:
getS3method(print, acf)
On Fri, Jan 21, 2011 at 11:02 AM, Bogaso Christofer
bogaso.christo...@gmail.com wrote:
Hi friends, there is methods() function to see the all available methods
for
a particular function, for example:
head(methods(print))
[1] print.acf print.anova
You can also use:
getAnywhere(functionName)
On Fri, Jan 21, 2011 at 8:02 AM, Bogaso Christofer
bogaso.christo...@gmail.com wrote:
Hi friends, there is methods() function to see the all available methods for
a particular function, for example:
head(methods(print))
[1] print.acf
try 'sqldf'
master=as.data.frame(list(clientId=c(1:4,2), date=1001:1005,
+ value=10001:10005))
control=as.data.frame(list(clientId=c(2,3), mindate=c(100,1005),
+ maxdate=c(1005,1005), control.params=c(1,2)))
master
clientId date value
11 1001 10001
22 1002 10002
33
forgot the control parameters:
sqldf(
+ select m.*, c.control_params
+ from master m, control c
+ where m.clientId = c.clientID
+ and m.date between c.mindate and c.maxdate
+ )
clientId date value control_params
12 1002 10002 1
2
Dear all,
Thank you for the prompt responses. It is until today that I have managed
to scrap together the time to develop my R-project further. In my free
time, I have been reading various intro manuals, so I have a rough idea of
what needs doing. Sometimes, though, putting it into practice
Hello Christian,
for an example of interacting with graphic output, just run
example(getGraphicsEvent)
However, on X11, that feature had ceased to work since a pre-release
of R-2.12 if Cairo support was enabled at compile time. The reason for
this defect had already been documented in R's
Dear [R] people
Could you please help with following data transformation.
Any suggestions, hints, references and even guessing on performing any
of the following steps are highly appreciated. Those transformations are
crucial for my work.
(n_, _n, j_, k_ signify numbers)
SOURCE DATA:
id
It is very uncommon for the assumptions underlying this method to be
satisfied. These assumptions include (1) the relationship between X and log
relative hazard is discontinuous at X=c and only X=c; (2) c is correctly
found as the cutpoint; (3) X vs log hazard is flat to the left of c; (4) X
vs
On 1/20/2011 4:42 PM, Achim Zeileis wrote:
On Thu, 20 Jan 2011, Mojo wrote:
I'm new to R and some what new to the world of stats. I got
frustrated with excel and found R. Enough of that already.
I'm trying to test and correct for Heteroskedasticity
I have data in a csv file that I load
On Fri, 21 Jan 2011, Mojo wrote:
On 1/20/2011 4:42 PM, Achim Zeileis wrote:
On Thu, 20 Jan 2011, Mojo wrote:
I'm new to R and some what new to the world of stats. I got frustrated
with excel and found R. Enough of that already.
I'm trying to test and correct for Heteroskedasticity
I
Martyn Plummer's 'coda' package has some nice interactive menus. The
package appears to be written entirely in R. You could start with the
codamenu() function in the package source:
http://cran.r-project.org/web/packages/coda/index.html
-Matt
On Fri, 2011-01-21 at 14:26 +0200, christiaan pauw
Christian
Have you looked at the http://www.stats.gla.ac.uk/~adrian/rpanel/ rpanel
package?
I have a post which shows an example of interactive input that allows user
to adjust plot parameters.
http://chartsgraphs.wordpress.com/2009/05/08/rpanel-package-adds-interactive-capabilites-to-r/
Denis,
Have a look at paste(), aggregate(), ddply() (from the plyr package) and melt()
and cast() (both from the reshape package).
Best regards,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
Hi Denis,
#minimal example:
test-as.data.frame(list(id=c(1,1,1,2,2,2), cycle1=c(c, m, f, m,
f, c)))
#gettin your first cell of Result 1
paste(sort(test$cycle1[test$id==1]), collapse=)
Hope this helps for the first task ...
Moritz
__
Moritz Grenke
http://www.360mix.de
Probably, iplots may be useful for you:
http://cran.r-project.org/web/packages/iplots/index.html
Kinds,
Mauricio
--
===
Linux user #454569 -- Ubuntu user #17469
===
2011/1/21 christiaan pauw cjp...@gmail.com:
HI Everybody
Does anyone
Hello R-experts,
I wonder whether any of the R-packages cover the Hilbert-Huang Transform
methodology (HHT)?
Regards,
Torbjorn
--
Torbjørn Lorentzen | torbjorn.lorent...@bjerknes.uib.no
|torbjorn.lorent...@uni.no | http://www.bjerknes.uib.no/
Phone: +47 55 58 25 05 | Cellphone: +47 906
Hello
I am trying to compare two models using anova(), however I get a message error
(see below).
In the net I only found some information on certain library(car) for which one
should use anova with A capital letter (Anova instead of anova), but I could
not find car library as it says it does
Hi list,
I want to plot two plot in the same figure. I set par(new=TRUE). But
it does not work.
library(lattice)
myPanel - function(x,...)
{
panel.histogram(x,alpha=0.4,...)
ltext(0.4,1.5,paste(Mean=,0.05,digit=2)),cex=0.8)
ltext(0.8,1.5,paste(s.d.=,0.06,digit=2)),cex=0.8)
}
On 1/21/2011 9:13 AM, Achim Zeileis wrote:
On Fri, 21 Jan 2011, Mojo wrote:
On 1/20/2011 4:42 PM, Achim Zeileis wrote:
On Thu, 20 Jan 2011, Mojo wrote:
I'm new to R and some what new to the world of stats. I got
frustrated with excel and found R. Enough of that already.
I'm trying to
On Fri, 21 Jan 2011, Mojo wrote:
On 1/21/2011 9:13 AM, Achim Zeileis wrote:
On Fri, 21 Jan 2011, Mojo wrote:
On 1/20/2011 4:42 PM, Achim Zeileis wrote:
On Thu, 20 Jan 2011, Mojo wrote:
I'm new to R and some what new to the world of stats. I got frustrated
with excel and found R. Enough
Thanks Jim and Henrique for your replies. I would like to know why some
particular functions are asterisked? What is the pros and cons while making
a typical UDF asterisked? How can I make a typical function asterisked? For
example print.anova() is not asterisked however print.acf() is. How can I
Dear Rosario,
Because of missing data in the additional variable PHt, the two models
weren't fit to the same subset of valid observations -- the default in lm()
is to use complete cases for the variables in the model.
A mechanical solution is to use na.omit() to filter your data set, only for
hello,
i'm pete ,how can i order rows of matrix by max to min value?
I have a matrix of membership degrees, with 82 (i) rows and K coloumns, K
are clusters.
I need first and second largest elements of the i-th row.
for example
1 0.66 0.04 0.01 0.30
2 0.02 0.89 0.09 0.00
3 0.06 0.92 0.01 0.01
Try this:
aggregate(.~ id, lapply(test, as.character), FUN = paste, collapse = )
On Fri, Jan 21, 2011 at 10:25 AM, Den d.kazakiew...@gmail.com wrote:
Dear [R] people
Could you please help with following data transformation.
Any suggestions, hints, references and even guessing on performing
use 'apply':
head(x.m)
V2 V3 V4 V5
[1,] 0.66 0.04 0.01 0.30
[2,] 0.02 0.89 0.09 0.00
[3,] 0.06 0.92 0.01 0.01
[4,] 0.07 0.71 0.21 0.01
[5,] 0.10 0.85 0.04 0.01
[6,] 0.91 0.04 0.02 0.02
x.m.sort - apply(x.m, 1, sort, decreasing = TRUE)
head(t(x.m.sort))
[,1] [,2] [,3] [,4]
Dear R users,
I'm having a problem with maxiter specification in VGLM function. I tried to
increase the number of iteration to 100, but it still stopped at 30, which
is the default. Here is my script:
FIT - vglm(SFH_PCT ~ RD_DEN + CAR_HH + TRS + RES_L, tobit(Lower=0), maxiter
= 100)
Thanks
On Jan 21, 2011, at 12:34 PM, Hongwei Dong wrote:
Dear R users,
I'm having a problem with maxiter specification in VGLM function. I
tried to
increase the number of iteration to 100, but it still stopped at 30,
which
is the default. Here is my script:
FIT - vglm(SFH_PCT ~ RD_DEN + CAR_HH
-- begin inclusion ---
I'm running a Tobit model but convergence can not be reached within 30
iterations. Is there anyway I can change the max number of iterations?
Thanks.
--- end inclusion ---
Tobit is simply a linear model with censored data. You don't say how
you are fitting this, but I'll
I grep for n, n) in all the R code of the package (current version),
and the only place that happens is in creating proximity. Can you do a
traceback() and see where it happens?
You should seriously consider upgrading R and the packages...
Andy
-Original Message-
From:
On Fri, Jan 21, 2011 at 3:51 AM, kamel gaanoun kamel.gaan...@gmail.com wrote:
Hi Everybody,
My problem is that nlminb doesn't converge, in minimising a logLikelihood
function, with 31*6 parameters(2 weibull parameters+29 regressors repeated 6
times).
Hmm, the length of the parameter vector
Hi,
It is indeed annoying that each optimization code has different names for the
parameters that control the behavior of the algorithms. This is one of the
reasons that we have developed optimx - to unify the calling convention for
the various algorithms. You can call the optimization
On 20/01/2011 9:33 PM, D Kelly O'Day wrote:
Bill Duncan
Thanks for your quick reply. I would still be looking for days.
Now I have to figure out how the bad data got into cts since I generate this
file each month.
When I read that .csv file in OpenOffice, the lines with the NAs arise
Dear all,
I have a model with simple terms, quadratic effects, and interactions.
I am wondering what to do when a variable is involved in a significant
interaction and in a non-significant quadratic effect. Here is an
example
d = data.frame(a=runif(20), b=runif(20))
d$y = d$a +
Hi all
I am using this model for a time series analysis :
lung_new - (glmmPQL(LUNG ~ 1, random = ~ 1 | GUID, family = poisson, data =
ts0004lag)
Im interested in extracting just the random intercept
can anyone point me in the right direction
thx
zeltak
[[alternative HTML version
Hi all
I am using this model for a time series analysis :
lung_new - (glmmPQL(LUNG ~ 1, random = ~ 1 | GUID, family = poisson,
data = ts0004lag)
Im interested in extracting just the random intercept
can anyone point me in the right direction
thx
zeltak
John,
The first thing I would do is create a simpler example, i.e., to help isolate
the issue. Heres a simple example:
The contents of a file are:
#! /usr/bin/Rscript
pdf('test1.pdf')
plot(1:10)
dev.off()
pdf('test2.pdf')
plot(10:1)
dev.off()
Try this:
aggregate(.~ id, lapply(replace(df, is.na(df), ''), as.character), FUN =
paste, collapse = , na.action = na.pass)
On Fri, Jan 21, 2011 at 5:45 PM, Den d.kazakiew...@gmail.com wrote:
Dear Henrique
Thank you again for helping me
Unfortunately, your code seems not to be working
correction:
aggregate(.~ id, lapply(df, as.character), FUN = paste, collapse = ,
na.action = na.pass)
On Fri, Jan 21, 2011 at 5:56 PM, Henrique Dallazuanna www...@gmail.comwrote:
Try this:
aggregate(.~ id, lapply(replace(df, is.na(df), ''), as.character), FUN =
paste, collapse = , na.action
Dear Henrique
Thank you again for helping me
Unfortunately, your code seems not to be working
aggregate(.~ id, lapply(df, as.character), FUN = paste, collapse = )
id cycle1 cycle2 cycle3
1 1cmfcmfcmf
2 2mfcmfcmfc
3 3 cf cf cf
(letter 'a' missing in
Hello
I am student of Bioinformatics and I am doin somework in R in which some
problem occurs. So Please help me to solve these problems.
I have two problems:
1. How to generate a graph in which there are 8 rows and 20 columns are
present?
2. And how to put some title in the end of the graph i.e
Folks,
I am trying to get a loop to run which increments the object name as part of
the loop. Here fit1 fit2 fit3 and fit4 are linear regression models
that I have created.
for (ii in c(1:4)){
+ SSE[ii]=rbind(anova(fit[ii])$Sum Sq)
+ dfe[ii]=rbind(summary(fit[ii])$df)
+ }
Error in
Hi,
I am using the clusters function in the evd package in order to determine
storm events from a wave time series.
So far I have the code working as I want it for wave height on its own but I
would now like to include the period as well. The input data is in the form
of:
H t
H t
H t
so
Hi,
I have a circular shaped set of point on the plane (X,Y) centered in
zero. The distribution is more dense close to zero and less dense far
from zero.
I need to find the radius of a circle centered in zero that contains
65% of the points in the sample. Is there any R directive that can do
I am trying to return an index for a data set by searching using filenames.
The name may be ANG_AUT.N.0734C70411A-1_1sA_0734C70411A.fasta, but i'd just
like to search it using the term 0734C70411 as the file may be
0734C70411A or 0734C70411C or 0734C70411D
Any way to do this other than doing
thank you ,you have been very kind
--
View this message in context:
http://r.789695.n4.nabble.com/clustering-fuzzy-tp3229853p3230228.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
christiaan pauw cjpauw at gmail.com writes:
HI Everybody
Does anyone know of documentation about different ways of obtaining user
input in R. I have used readline() but I wondered is there are sophisticated
packages that does things like validate answers or generate selection
lists.
You
Hi,
is there a R function that order a matrix according to some criteria
based on the rows(or cols) of that matrix?
For example, let's say that my matrix S is composed by n rows S_1,
S_2,.., S_n and that I compute some real value g_i=g(S_i) for each
row.
Then I want to order this set of g_i (from
There are several pattern matching functions that will solve your problem:
grep regexpr
do RSiteSearch(pattern match)
On Fri, Jan 21, 2011 at 12:26 PM, poppinkid j...@bcm.edu wrote:
I am trying to return an index for a data set by searching using filenames.
The name may be
Take a look on grep function.
On Fri, Jan 21, 2011 at 3:26 PM, poppinkid j...@bcm.edu wrote:
I am trying to return an index for a data set by searching using filenames.
The name may be ANG_AUT.N.0734C70411A-1_1sA_0734C70411A.fasta, but i'd just
like to search it using the term 0734C70411
Just change the FUN function:
aggregate(.~ id, lapply(df, as.character), FUN = function(x)paste(sort(x),
collapse = ''), na.action = na.pass)
On Fri, Jan 21, 2011 at 6:27 PM, Den d.kazakiew...@gmail.com wrote:
Thank you for your efforts.
Although it is still not working, it feels like
look at 'order'
yourMatrix[order(yourMatrix[, 'yourCol']), ]
On Fri, Jan 21, 2011 at 2:38 PM, Francesco Petrogalli
francesco.petroga...@gmail.com wrote:
Hi,
is there a R function that order a matrix according to some criteria
based on the rows(or cols) of that matrix?
For example, let's say
I think you want the following, assuming you defined your function g():
gValues = apply(S, 1, g);
Sordered = S[order(gValues), ]
Peter
On Fri, Jan 21, 2011 at 11:38 AM, Francesco Petrogalli
francesco.petroga...@gmail.com wrote:
Hi,
is there a R function that order a matrix according to some
On Jan 21, 2011, at 3:29 PM, Brahmachary, Manisha wrote:
Hi David,
Thanks a lot for you inputs. I have modified my code accordingly.
There
is one more place that I need some help.
This is my code:
=
=
==
==
X-
On Jan 21, 2011, at 2:59 PM, Akash wrote:
Hello
I am student of Bioinformatics and I am doin somework in R in which
some
problem occurs. So Please help me to solve these problems.
I have two problems:
1. How to generate a graph in which there are 8 rows and 20 columns
are
present?
2.
On Jan 21, 2011, at 11:33 AM, Francesco Petrogalli wrote:
Hi,
I have a circular shaped set of point on the plane (X,Y) centered in
zero. The distribution is more dense close to zero and less dense far
from zero.
I need to find the radius of a circle centered in zero that contains
65% of the
This is FAQ 7.21.
The real gem in the answer there is at the end where it tells you that it is
easier to just use a list. If your fit1, fit2, fit3, and fit4 were elements in
a list then you can just loop through the list elements, or even easier use the
lapply function to loop through the
I'm doing regression with least median squares (LMS) using the lmsreg
command. I've got the coefficients (slope and intercept), but how do I get
the LMS correlation coefficient?
Thanks, in advance, for any help!
--
View this message in context:
Thank you for your efforts.
Although it is still not working, it feels like getting closer and
closer.
id cycle1 cycle2 cycle3
1 1cmfcmfcmf
2 2mfcmfcmfc
3 3 acfNA acfNA NAcfm
I really appreciate transformation from subsets (c,m,f) to cmf.
That was critical for
I have built a package that I would like to submit to the CRAN. When I perform
a R CMD
check I get the following warning:
* checking Rd cross-references ... WARNING
Error in .find.package(package, lib.loc) :
there is no package called 'foreign'
Calls: Anonymous - lapply - FUN - .find.package
Hi David,
Thanks a lot for you inputs. I have modified my code accordingly. There
is one more place that I need some help.
This is my code:
==
X- read.table(X.txt,as.is=T,header=T,row.names=1)
Y-
-- Forwarded message --
From: Freddy Gamma freddy.ga...@gmail.com
Date: 2011/1/21
Subject: TRADUCING lmer() syntax into lme()
To: r-sig-mixed-mod...@r-project.org
Dear Rsociety,
I'd like to kingly ask to anyone is willing to answer me how to implement a
NON NESTED random effects
I follow Alan Lenarcic's very helpful tutorial on building R package for
Windows (XP), which could be found in
www.stat.columbia.edu/~gelman/stuff_for_blog/AlanRPackageTutorial.pdfhttp://www.stat.columbia.edu/~gelman/stuff_for_blog/AlanRPackageTutorial.pdf.
The package involves a small dll
On 11-01-21 3:33 PM, la...@buffalo.edu wrote:
I have built a package that I would like to submit to the CRAN. When I perform
a R CMD
check I get the following warning:
* checking Rd cross-references ... WARNING
Error in .find.package(package, lib.loc) :
there is no package called 'foreign'
Hello
Consider following dataframe named df
var1var2var3
3771354 565
654654 963 6677
775 147 657754
df - read.table('clipboard', header = TRUE)
df
#find indexes with '77' in var 1
myIndexes - grep( glob2rx(*77*), df$var1)
myIndexes
#find actual values of seach above
That great! It's working! Thank you so much!
It is a pure magic which makes my head spin.
aggregate(.~ id, lapply(df, as.character), FUN =
function(x)paste(sort(x), collapse = ''), na.action = na.pass)
1. help says:
Note that ‘paste()’ coerces ‘NA_character_’, the character missing
value, to
Dear list,
the following came up in an introductory class. Please help me understand the
-1 (or 0+) syntax in formulae: Why do the enumerator dfs, F-statisics etc.
differ between the models lm(y ~ x1) and lm(y ~ x0 + x1 - 1), if x0 is a vector
containing simply ones?
Example:
N - 40
x0 -
Hi:
Here's an example of how to extract pieces from model objects using the plyr
package. I'm using the attitude data set from the datasets package
(autoloaded).
# Generate four models
m1 - lm(rating ~ ., data = attitude)
m2 - lm(rating ~ complaints + learning, data = attitude)
m3 - lm(rating ~
On Jan 21, 2011, at 9:03 PM, jochen laubrock wrote:
Dear list,
the following came up in an introductory class. Please help me
understand the -1 (or 0+) syntax in formulae: Why do the enumerator
dfs, F-statisics etc. differ between the models lm(y ~ x1) and lm(y
~ x0 + x1 - 1), if x0 is
Hello, I am new to R (coming from Perl) and have what is, at least at this
point, a philosophical question and a request for comment on some basic
code. As I understand it - R emphasizes ,or at least supports, the
functional programming model. I've come across some code that was markedly
absent in
Well ... as x1 is continuous(numeric), it has no levels. So ...??
Note that the fits are identical for both models. The issue is only
what is the Null that you are testing in the two cases. In the first
case, it is just y = constant, so you are testing the 1 df for x1. In
the second, it is y = 0
Thank you all (including Dennis), this was elucidating.
I would have (maybe naively) anticipated that in this somewhat pathological
case of fitting without an intercept and re-introducing it via constant x1, R
might check whether the design matrix includes a column of ones, and adjust the
I have a problem as follows:
1. If we have 3 matrices A,B,C and we merge them in a single matrix ABC by
any method like addition , subtraction division,multiplication,etc
2. and then we want to retrieve original 3 matrices A,B,C from single ABC
matrix
What will be the algorithm?
Dear List
I use synaptic to download R on my Ubuntu 10.10. It seems latest version of
R on Ubuntu is 2.11.1
Even when I use debian.cran.r-project.org to update my packages the problem
remains (latest versions on CRAN are almost always 2 updates ahead of Debian
packages) This is also true for a
I think this is not an R issue, but one of MAMP. On my server's
sql service, I can connect using password, however, on my local
MAMP, I need the socket:
dbCon - dbConnect(dbdr, user=root, password=root,
dbname=mydb,
unix.socket=/Applications/MAMP/tmp/mysql/mysql.sock)
HTH, *S*
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