hello all
i am busy testing some code that will be used for parallel computations
on a Moab cluster. I have written a C++ program and am linking it with R
using the .C command - this works correctly.
Extracts of the r code (as well as the *.sh file) is included below. I
am able to run the
Hi,
Thank you for the pointer; I'd overlooked that demo which contains an
alternative way of generating ellipsoids. It is slightly annoying that
ellipsoid3d is not defined in the main package but in the demo; I'll
have to duplicate the code. Playing with this idea, I realised the
bottleneck of my
Hello R-help
I donât know how to interpret significance from the contr.poly() function .
From
the example below
: how can I tell if data has a significant Linear/quadratic/cubic trend?
contr.poly(4, c(1,2,4,8))
             .L        .Q         .C
[1,]
I have the problem with the basic test too.
But I installed D(COM) for use with the R2wd package.
Despite the problem with the basic test, R2wd works like a charm.
So just try your code, it actually might work fine.
Bart
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Hi,
Peter: thank you, I have taken a look at ?approxfun but I'm not sure it does
what I'm after.
Eduardo:
The data doesn't represent functions. Basically the X values represent the
distance across a sample and the Y values are a measure of the colour
intensity at that point across the sample
Hi
r-help-boun...@r-project.org napsal dne 03.02.2011 00:56:40:
Thanks for the reply!
This sounds great. Is there a nice way to store these 100 variable names
in
a list without typing them all out?
Why? When you need your 42nd variable from a list lll you can just use
lll[42]
and if
Hi
r-help-boun...@r-project.org napsal dne 03.02.2011 10:36:57:
Hi,
Peter: thank you, I have taken a look at ?approxfun but I'm not sure it
does
what I'm after.
Hm, maybe yes. But not approxfun but approx
x1-1:15
x2-50:100
y1-rnorm(15)
y2-rnorm(51)
yy2-approx(x2,y2)$y
Hi Everybody!
I must start with a declaration that I am a sparse user of R. I am
creating a credit scorecard using a dataset which has a variable
depicting actual credit history (good/bad) and 41 other variables of
yes/no type. The procedure I am asked to follow is to use a penalized
logistic
Goodmorning List Member,
I would like to ask your help using mapply or Vectorize to make a loop more
efficient.
I have a m*4 matrix called borders and I would like to add a 5th column. Thus
first
A. I add the new 5th column
borders-cbind(borders,matrix(data=NA,nrow=nrow(borders)))
B. For every
As Greg wrote, a list is in most circumstances a better way to store
many objects.
But you can use 'assign' and 'get' to create and access (global) variables
#creation
for (i in 1:100) assign(paste(var,i,sep=),rnorm(5))
#access i-th variable
i-15
get(paste(var,i,sep=))
hth.
Am 02.02.2011
Hello I would like to ask you if I can use the same method but for functions.
That means that I want not to assign some value but a function.
So is it possible to try something like that:
for (i in 1:10) for (j in 1:10) assign(paste(var,i,j,sep=),myfunction)
I would like to thank you in
Hi R-helpers, i am using the following dataset.This dataset is stored in a
mysql database.
W(x)pH(y)
10 1
15 1
20 4
5
7.5 3
13
9 5
11.5
13.53
16 2
1
9.6 1
I am using RJDBC package to read the data from the database into a
Thanks Dennis,
I have used the codes as.table = TRUE and aspect = 1 to obtain what i needed.
Maybe I'll ask you more about xyplot, is very powerfull tool!
Cheers,
Francesco
Date: Mon, 31 Jan 2011 04:33:27 -0800
Subject: Re: [R] [r] align xyplot
From: djmu...@gmail.com
To:
Hi
Well, no data so a wild guess. You want select values from matrix sr based
on values in borders[,1] and borders[,2].
If it is the case plain selection could be far better
mat-matrix(1:12, 4,4)
mat
[,1] [,2] [,3] [,4]
[1,]1591
[2,]26 102
[3,]37
Hello Sambit.
Step1:
Create a matrix out of your predictor data, having columns for every
predictor, coding 1 for yes and 0 for no. he matrix should have a row for
each observation (called pred.mat below)
Besides that, you need a vector with the outcome variable for each
observation (best if this
Hello Petr,
I am sorry that I did not provide all the required data (for me is not very
straight-forward to understand what I have to provide and what not)
findCell-function(x,sr){ # It is just for me understand how mapply works
sr[x[1],x[2]]
}
and I want to call mapply like that.
On Thu, Feb 03, 2011 at 01:36:57AM -0800, mattnixon wrote:
The data doesn't represent functions. Basically the X values represent the
distance across a sample and the Y values are a measure of the colour
intensity at that point across the sample (i.e. a line plot across the
sample). Each
Hi,
I have a function myFun which I want to call multiple times, using different
argument lists.
myFun(v1, 2009, 1)
myFun(v2, 2008, 1)
myFun(q, 2001)
How can I easily do this in R? Should I use mapply?
I unsuccessfully tried something like:
x - list(c(v1, 2009, 1), c(v2, 2008, 1), c(q, 2001))
*Warning messages: *appear after dredging global model in MMI and
requesting model selection table
dd(global model)-dredge(global model) - runs OK
dd(global model)
* 1: In x[i] - value[[j]] :
number of items to replace is not a multiple of replacement length*
Also at model averaging stage I
On Thu, Feb 3, 2011 at 1:26 PM, Albert-Jan Roskam fo...@yahoo.com wrote:
Hi,
I have a function myFun which I want to call multiple times, using
different
argument lists.
myFun(v1, 2009, 1)
myFun(v2, 2008, 1)
myFun(q, 2001)
Notice that the third call is different, you have 3 args in
Hi
Alaios ala...@yahoo.com napsal dne 03.02.2011 12:16:45:
Hello Petr,
I am sorry that I did not provide all the required data (for me is not
very
straight-forward to understand what I have to provide and what not)
findCell-function(x,sr){ # It is just for me understand how mapply
On Wed, Feb 02, 2011 at 06:01:36PM -0500, Carl Witthoft wrote:
Hi, subject more or less says it all.
I freely admit to not having bothered to find some of the online papers
about method of testing the quality of random number generators -- but
in an idle moment I wondered what to expect
Dear R-Users,
I have a trivial problem, but extensive googling and ??'ing did not solve it: I
want to obtain the sums of squares from a summary.aov() object for later use.
Example:
DV - rnorm(100)
IV1 - as.factor(rep(c(male, female), times = 50))
IV2 - as.factor(rep(c(young, old), times =
Hello there
I have the following model based on the hollings disc equation for the type
II functional response for 2 data sets:
nls(eaten~(a*suppl)/(1+a*h*suppl)
where eaten is the number of prey eaten by a predator and suppl is the
number of prey initially supplied to the same predator.
I
Hello R-help
(sorry if this message gets posted twice, i think I may have accidently
postponed it)
I donât know how to interpret significance from the contr.poly() function .
From
the example below
: how can I tell if data has a significant Linear/quadratic/cubic trend?
contr.poly(4,
On Thu, Feb 3, 2011 at 1:16 PM, Alaios ala...@yahoo.com wrote:
I am sorry that I did not provide all the required data (for me is not very
straight-forward to understand what I have to provide and what not)
findCell-function(x,sr){ # It is just for me understand how mapply works
On 2011-02-03 04:30, Bertolt Meyer wrote:
Dear R-Users,
I have a trivial problem, but extensive googling and ??'ing did not solve it: I
want to obtain the sums of squares from a summary.aov() object for later use.
Example:
DV- rnorm(100)
IV1- as.factor(rep(c(male, female), times = 50))
IV2-
Hi,
If you do
test - summary(aov(DV ~ IV1 * IV2))
str(test)
you will see that
test[[1]][2]
gives you what you want.
Reading more on indexing will also probably help you. str() is a very
useful function, to use without moderation!
HTH,
Ivan
Le 2/3/2011 13:30, Bertolt Meyer a écrit :
Cristiano Strieder cstrieder at gmail.com writes:
Hi all,
I have commited a new release of my package and waited for more than
one day. After that
install.packages(tests,repos=http://r-forge.r-projet.org;) still
returns package 'tests' is not available. I have done the local
build
Dear R experts,
For a fixed seed, the first random number produced by rnorm and runif
has the same rank within the distribution, which I find useful. The
following ranks differ, however.
set.seed(123)
runif(4)
[1] *0.2875775* 0.7883051 *0.4089769* 0.8830174
set.seed(123)
pnorm(rnorm(4))
Dear Peter,
thank you so much for the quick and helpful reply - it was exactly what I was
looking for.
Regards,
Bertolt
Am 03.02.2011 um 13:49 schrieb Peter Ehlers:
On 2011-02-03 04:30, Bertolt Meyer wrote:
Dear R-Users,
I have a trivial problem, but extensive googling and ??'ing did not
On Thu, 3 Feb 2011, Matthias Gondan wrote:
Dear R experts,
For a fixed seed, the first random number produced by rnorm and runif
has the same rank within the distribution, which I find useful. The
following ranks differ, however.
set.seed(123)
runif(4)
[1] *0.2875775* 0.7883051 *0.4089769*
I would like to thank you very much both.
Your replies helped me understand.
I will bookmark you replies for future reference :)
Best Regards
Alex
--- On Thu, 2/3/11, Kenn Konstabel lebats...@gmail.com wrote:
From: Kenn Konstabel lebats...@gmail.com
Subject: Re: [R] Odp: Loop to mapply. Error
Dear All,
Is there any function in R that find the minimum steiner tree not
minimum spanning tree?
Regards,
Amir
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
hello all
For those interested! i figured out the problem!
I needed to put the dyn.load and dyn.unload lines inside the loop!
library(doMPI)
cl - startMPIcluster(count=2)#this will
I am exploring the coxme function. The help page uses two examples that use the
colon2 dataframe. The data frame is not included in the material that is
installed when one loads the coxme package. The web site that contains the
colon2 data, does not have the file in an immediately usable
By fitting some kind of model. contr.poly doesn't fit a model or test
significance, it just sets contrasts. Here is an example
data(mtcars)
mtcars$carb - factor(mtcars$carb)
contrasts(mtcars$carb) - contr.poly(n=levels(mtcars$carb))
contrasts(mtcars$carb)
.L .Q .C
You can use the summary with the split argument.
See
?summary.aov
for an example.
This gives similar results to the regression coefficients approach that Ista
Zahn
suggested. I usually prefer the ANOVA table approach for factors.
On Thu, Feb 3, 2011 at 3:36 AM, Asan Ramzan asanram...@yahoo.com
a typo in r-projeCt.org?
install.packages(tests,repos=http://r-forge.r-project.org;)
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Hi,
I'm trying to present a table of some experimental data, and I want to order
the rows by the instance names. The issue I've got is that there are a
variety of conventions for the instance names (e.g. competition01,
competition13, small_1, big_20, med_9). What I want to be able to sort them
On Feb 3, 2011, at 10:12 AM, Alastair wrote:
Hi,
I'm trying to present a table of some experimental data, and I want
to order
the rows by the instance names. The issue I've got is that there are a
variety of conventions for the instance names (e.g. competition01,
competition13, small_1,
Hi,
Suppose a function that checks an object:
stop.if.dims - function(x) {
if (! is.null(dim(x))) {
stop(cannot handle dimensional data)
}
}
This would be used by other functions that can only work with
dimensionless objects. The problem is the error message would need to
include the
To sort a character vector in a desired order
you can convert it to a factor with the levels
in the desired order. To sort strings like 2
and 11 in numerical order, use convert them
to numbers with as.numeric. To sort by two variables,
using the second to break ties in the first,
use
I found a solution (certainly not the best one but it works).
I add a 45th column full of 0 to the 44-columns data.frame.
When I copy the data.frame to the database with sqlsave, the last column of
the table is not full of 0, but it autoincrements.
Another small question: what is the command to
On Feb 3, 2011, at 10:27 AM, Ernest Adrogué wrote:
Hi,
Suppose a function that checks an object:
stop.if.dims - function(x) {
if (! is.null(dim(x))) {
stop(cannot handle dimensional data)
}
}
mtx - matrix(c(1,0,0,1), 2)
stop.if.dims - function(x) { objname - deparse(substitute(x))
+
Hi,
I have data like this
print(x)
ID VAL1VAL2
1 B A
2 P Q
3 T S
What I would like is data like this...
ID VAL1VAL2
1 A B
2 P Q
3 S T
So that VAL1 and VAL2 are alphabetically
On Mon, Apr 13, 2009 at 12:41 PM, Dan Dube ddube-at-advisen.com wrote:
i use tapply and by often, but i always end up banging my head against
the wall with the output.
The proposed solution of Dan's problem posted on R-help was:
do.call(rbind,a)
When I use this 'solution' I get 'ERROR:
Try this:
g - function(.x) tryCatch(stop.if.dims(.x), error=function(e)sprintf(Error
in %s: %s, deparse(sys.call(1)), e$message))
g(rbind(2, 3))
2011/2/3 Ernest Adrogué nfdi...@gmail.com
Hi,
Suppose a function that checks an object:
stop.if.dims - function(x) {
if (! is.null(dim(x))) {
Dear R members,
I have a quite large of function that are named like that
f11,f12,...f15
f21,f22,...f25
..
f51,f52,...f52
These are static (hard-coded) functions that the only common they have is that
they take the same number and type of input fij(a,b,c,d). As you might
understand this is
Hello R users,
I have a little problem with a for loop.
Below there is an simple example of my problem.
I want to delet the commas in the character string. Fore this reason I
create a for loop to unpick the string and rebuild him without the commas.
The problem is, that paste does not work in
Chris82 rubenbauar at gmx.de writes:
Hello R users,
I have a little problem with a for loop.
Below there is an simple example of my problem.
I want to delet the commas in the character string. Fore this reason I
create a for loop to unpick the string and rebuild him without the
Try this:
x[2:3] - t(apply(x[-1], 1, sort))
On Thu, Feb 3, 2011 at 1:57 PM, sudhir cr sudhir...@gmail.com wrote:
Hi,
I have data like this
print(x)
ID VAL1VAL2
1 B A
2 P Q
3 T S
What I would like is data like this...
ID
Hi Chris,
'gsub' does exactly what you want:
gsub(,,,text)
so there is no need for a loop.
Btw. your loop assigns a new value to m in each step and you see only
the last assignment.
you could do something like
m - paste(m,substring(text,i,i+2),sep = )
hth
Am 03.02.2011 17:35, schrieb
Seems funny to me:
f - list (mean, sd, median, sum)
dim (f) - c (2, 2)
or in one line:
f - structure (.Data=list (mean, sd, median, sum), dim = c(2,2))
f
[,1] [,2]
[1,] ??
[2,] ??
f [1,1]
[[1]]
function (x, ...)
UseMethod(mean)
environment: namespace:base
f [[1,1]] (1:3)
[1]
Oh, that's of course a better solution. I've never red or heard about gsub.
Thanks a lot!
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Hi:
u - matrix(sample(LETTERS[1:24]), nrow = 8)
u
[,1] [,2] [,3]
[1,] W J M
[2,] K V P
[3,] X E U
[4,] T B N
[5,] I Q F
[6,] G R S
[7,] A C O
[8,] D H L
t(apply(u, 1, function(x) sort(x)))
[,1] [,2] [,3]
[1,] J M W
[2,] K P V
[3,] E U X
[4,] B N T
[5,] F I Q
://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
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It depends on what you are assigning. A simple example of assigning the values
1 through 100:
mylist - lapply(1:100, I)
names(mylist) - paste('var',1:100, sep='')
Or if you have 100 files named dat1.txt, dat2.txt, ..., dat100.txt and you want
to read them in:
mylist - lapply( paste('dat',
It is not clear what you are trying to do, but you can have lists (or vectors)
of functions and that should simplify what you are trying to do:
trigfuns - list( s=sin, c=cos, t=tan )
trigfuns
$s
function (x) .Primitive(sin)
$c
function (x) .Primitive(cos)
$t
function (x) .Primitive(tan)
3/02/11 @ 11:25 (-0500), David Winsemius escriu:
On Feb 3, 2011, at 10:27 AM, Ernest Adrogué wrote:
Hi,
Suppose a function that checks an object:
stop.if.dims - function(x) {
if (! is.null(dim(x))) {
stop(cannot handle dimensional data)
}
}
mtx - matrix(c(1,0,0,1), 2)
3/02/11 @ 14:30 (-0200), Henrique Dallazuanna escriu:
Try this:
g - function(.x) tryCatch(stop.if.dims(.x), error=function(e)sprintf(Error
in %s: %s, deparse(sys.call(1)), e$message))
g(rbind(2, 3))
This is it. Thanks!
Cheers.
--
Ernest
__
I am trying to run a mixed model logistic regression with participants
nested within state with a certain amount of covariates. Here is what my
model looks like:
m1 - lmer(Overweight ~ age + factor(A_RACE_G) + Prevalance +
HH_Income_Dicot + Unemployment_Rate + Intensity_effect + (1 | state2)
Yes - that is exactly what was needed.
Applying approx to each data set then allowed for straight forward averaging
afterwards.
Many thanks.
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Dear Dennis
Thank you again
It is funny how stupid I was. I was afraid of the word inference in
elrm package description while performing my first search.
elrm package looks like what I need.
They have very good intro with examples
Zamar D, McNeney B and Graham J. elrm: Software Implementing
Try
as.data.frame(as.table(a))
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
and provide commented, minimal, self-contained, reproducible code.
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On Feb 3, 2011, at 11:29 AM, Graves, Gregory wrote:
On Mon, Apr 13, 2009 at 12:41 PM, Dan Dube ddube-at-advisen.com
wrote:
That is pushing two years ago, so I doubt very many people still have
that posting on their mail-clients. (When I did go to the archives Dan
Dube's problem was
Yes, as far as I can tell, sampling.date is a character vector of the format
1/15/2008. It resides in the leftmost column of the tapply output.
station.code are the A, B, C column headers which refer actual water quality
station locations, and the values below those headers correspond to the
On Feb 3, 2011, at 1:05 PM, Graves, Gregory wrote:
Yes, as far as I can tell, sampling.date is a character vector of
the format 1/15/2008. It resides in the leftmost column of the
tapply output.
station.code are the A, B, C column headers which refer actual
water quality station
On Thu, Feb 3, 2011 at 1:11 PM, David Winsemius dwinsem...@comcast.net wrote:
On Feb 3, 2011, at 1:05 PM, Graves, Gregory wrote:
Yes, as far as I can tell, sampling.date is a character vector of the
format 1/15/2008. It resides in the leftmost column of the tapply output.
station.code are
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http
Dear all, I am into some bigger project and in implementing that, I
have come across a problem, wherein I have to ask user to create a
Matrix with all elements either NA value or some Date object,
preferably in mm/dd/yy format. Therefore I would like to force user to
create following sort of
On 02/02/2011 09:29 AM, David Winsemius wrote:
On Feb 2, 2011, at 8:22 AM, Ben Bolker wrote:
Ramya ramya.victory at gmail.com writes:
I have the code for the density plot
j - 8
plot(density(diff_in_sample[,1]), main = list.files()[j])
for(i in 1:25){
lines(density(diff_in_sample[,i]))
Dear R-help members,
I'm trying to run LME model on some behavioral data and need
confirmations about what I'm doing...
Here's the story...
I have some behavioral reaction time (RT) data (participants have to
detect dome kind of auditory stimuli). the dependant variable is RT
measured in
I have a model with quant vars only and the error message does not make sense:
(mod1 - coxph(Surv(time=strt,time2=stp,event=(resp==1))~
+incpost+I(amt/1e5)+rate+strata(termfac),
subset=dt2010-08-30, data=inc,method=efron))
Call:
coxph(formula = Surv(time = strt, time2 = stp, event
This works. Thanks.
Gregory A. Graves, Lead Scientist
Everglades REstoration COoordination and VERification (RECOVER)
Wetland Watershed Sciences / Restoration Sciences Department
South Florida Water Management District
Phones: DESK: 561 / 682 - 2429
CELL: 561 / 719 - 8157
Hello,
I´m trying to do some analysis using survreg function. I need to implement
there my own distribution with density:
lambda*exp(-lambda*y), where y = a1/(1+exp(-a2*x)).
a1, a2 are unknown parameters and x 0.
I need to get estimates of a1 and a2 (and lambda of course)
I’m really
Hi there
I am looking at the functional response (the consumption of single predators
of prey over a range of prey densities) and Im having issues with the
following script when trying to obtain mutliple replicates of coefficients
(a and h) from the following nls model based on Hollings disc
Dear list,
Plots generated with the plot command have labels on the vertical y axis
rotated counterclockwise. How do I specify that they should be
positioned horizontally (I mean each label should read from left to right)?
Thank you.
L.
__
On Feb 3, 2011, at 1:16 PM, Longe wrote:
Dear list,
Plots generated with the plot command have labels on the vertical y
axis rotated counterclockwise. How do I specify that they should be
positioned horizontally (I mean each label should read from left to
right)?
?par
The las
On Feb 3, 2011, at 2:14 PM, Ben Bolker wrote:
On 02/02/2011 09:29 AM, David Winsemius wrote:
On Feb 2, 2011, at 8:22 AM, Ben Bolker wrote:
Ramya ramya.victory at gmail.com writes:
I have the code for the density plot
j - 8
plot(density(diff_in_sample[,1]), main = list.files()[j])
for(i
My concern was that it was outside the density function and I thought
the density function would throw an error before it passed anything to
na.omit().
plot(na.omit(density(c(1,1,1,1,1,NA,4,4,4,4))) )
Error in density.default(c(1, 1, 1, 1, 1, NA, 4, 4, 4, 4)) :
'x' contains missing
Tena koe
?par
and check the las argument.
HTH
Peter Alspach
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Longe
Sent: Friday, 4 February 2011 7:16 a.m.
To: r-help@r-project.org
Subject: [R] Changing the direction
Hi, dear R users,
I'm running a Tobit regression and using summary to display model results.
It used to work. But this time, I kept getting this:
summary(RES_TOBIT)
Length Class Mode
1 vglm S4
Could anyone tell me how to solve this problem, and why I got this problem?
Thanks.
On Feb 3, 2011, at 2:14 PM, Bond, Stephen wrote:
I have a model with quant vars only and the error message does not
make sense:
(mod1 - coxph(Surv(time=strt,time2=stp,event=(resp==1))~ +incpost
+I(amt/1e5)+rate+strata(termfac),
subset=dt2010-08-30, data=inc,method=efron))
2011/2/3 Den d.kazakiew...@gmail.com
Thank you again
It is funny how stupid I was
Elrm, clogit {survival} or exactLoglinTest are only exact-like, the truth
is, R don't have it... and glm is poor.
http://sas-and-r.blogspot.com/2010/12/example-818-monte-carlo-experiment.html
Hello,
I'd like to transpose data to create an analysis-friendly dataframe. See
below for an example, I was unable to use t(x) and I couldn't find a
function with options like PROC TRANSPOSE in SAS.
The ideal solution handles variable quantities of SITE - but beggars can't
be choosers. :-)
Responding to the suggestion by D Winsemius :
s1 - survfit(mod1,newdata=inc[50050:50100,c(strt,stp,incpost,
amt,rate, termfac)],
+ se.fit=F,individual=T,type=aa)
Error in Surv(time = strt, time2 = stp, event = (resp == 1)) :
object 'resp' not found
it appears it wants to fit
Hello:
I found the hubers function in MASS library is NOT working on the following
data:
a -
Hi Mike
reshape will be your friend.
reshape(RAW,direction=wide,timevar=SITE,idvar=USER_ID)
there is also the 'reshape'-package, which can do some more
sophisticated transformations.
hth.
Am 03.02.2011 20:41, schrieb Mike Schumacher:
Hello,
I'd like to transpose data to create an
Hi,
On Thu, Feb 3, 2011 at 2:41 PM, Mike Schumacher
mike.schumac...@gmail.com wrote:
Hello,
I'd like to transpose data to create an analysis-friendly dataframe. See
below for an example, I was unable to use t(x) and I couldn't find a
function with options like PROC TRANSPOSE in SAS.
The
Dear everyone,
I am trying to run rgenoud on several chips simultaneusly. I used the
instructions provided on Jasjeet Sekhon's Homepage
(http://sekhon.berkeley.edu/rgenoud/multiple_cpus.html).
However, I have the newer version of R (R 2.12) installed - for a
64-bit machine. So, when I tried to
Just a small correction: the package snow does install. But once I
try to load it:
library(snow),
I get an error:
Error: package 'snow' was built before R 2.10.0: please re-install it
Dimitri
On Thu, Feb 3, 2011 at 3:57 PM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Dear
I am using the R statistical package in a pretty straightforward manner, just
interested in getting summary statistics and reliable estimates of means,
variances, confidence intervals, p-values using standard tests, etc. I've been
using the generalized estimating equation package because I
Hi:
This also works, except that the result is of class 'table':
xtabs(COUNTS ~ USER_ID + SITE, data = RAW)
SITE
USER_ID SITE1 SITE2 SITE3
1101322
2101212
31344 0
4 0 099
If you need a data frame, then the earlier
Thanks a lot! It really helps.
Zunqiu
From: Jude Ryan [mailto:jr...@marketshare.com]
Sent: Thursday, February 03, 2011 3:28 PM
To: Zunqiu Chen
Cc: R-help@r-project.org
Subject: Re: [R] any similiar R fuction for matlab function 'fprintf'?
There does not seem to be a function exactly similar to
try
subset(D, D$x 5|D$y 5)
HTH
Pete
--
View this message in context:
http://r.789695.n4.nabble.com/problem-subsetting-a-data-frame-tp3258981p3259360.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing
I am trying to make some plots for a poster. Each one needs to be 6 inches by
inches. Right now the fonts are too small and the plots don't read well on
my poster. I am pretty much an R newbie and I can't figure out how to change
the fonts. It would also be nice to know how to specify the size of
There does not seem to be a function exactly similar to MATLAB's fprintf in
R, but you can achieve pretty much the same results using something like the
code below:
a - 1:10
b - 11:20
ab - cbind(a,b)
sink(C:\\R\\test.txt) # open file to write data to - file will be deleted if
it exists
On 02/03/2011 01:57 PM, Peter Alspach wrote:
Tena koe
?par
and check the las argument.
HTH
Peter Alspach
Thank you, Peter, and also David and William. The las argument indeed
helps in setting the tick labels horizontally. Beautiful! But how do I
rotate also the axis label, which
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