Dear All,
I'd like to trim the output produced in a Sweave code chunk. For
instance, in
fit - lm(conc ~ . - Plant, data = CO2)
summary(fit)
I'd like, skip the info after the coefficients' table, and possibly
replace it with '...'.
I've created this small function to do this, which is
On Feb 25, 2011, at 1:55 AM, Noah Silverman wrote:
How can I dynamically use a variable as the name for another variable?
I realize this sounds cryptic, so an example is best:
#Start with an array of codes
codes - c(a1, b24, q99)
Is there some reason not to use list(a1, b24, q99)? If not
On Feb 24, 2011, at 3:38 PM, Kent Alleman wrote:
Hello,
I'm fairly new to R. I'm a chemist, not a programmer so please bear
with me.
I have a large data.frame that I want to break down (subset) into
smaller data.frames for analysis. I would like to give the
data.frames descriptive
Hi:
I want to give an index with all the dates between Sept. to Nov. as 1, and
anything else is 0. It doesn't matter which year it is, as long as it is
between Sept. to Nov, then set up to 1, otherwise is 0.
My data frame looks like below:
ID Date
201 1/1/05 6:07 AM
201 3/27/09
Hello,
I came across a package called cubature (
http://cran.r-project.org/web/packages/cubature/index.html) to perform
multivariate integration. I was not able to understand few stuff:
What is the need for package flags under src/Makevars?
What is the purpose of fWrapper in the rcubature.c
I think I got it, I post it here see if you have better way, please let me
know.
index - rep(0, length(mydata[,1]))
index[as.Date(mydata3$Date) as.Date(2006-11-30 23:29:29 PM)
as.Date(mydata3$Date) as.Date(2006-09-01 00:00:00 AM)] - 1
index[as.Date(mydata3$Date) as.Date(2007-11-30 23:29:29
Hello,
I was searching online to find more info about Biometics
and I came across your information.
Can you tell me, are you still involved with Biometics?
If you are, how are things going for you?
Please let me know.
Sincerely,
Will Hammack
__
Hi,
Please someone let me know that the installation of both R for Windows
2.12.2 and MS office 2010 on the same system will interfere each other or
not.
In short, are these two tools compatible to each other?
Thanks in advance.
Best Regards,
Vedajit
[[alternative HTML version
One of my hypotheses of what you want is:
for(code in codes) {
get(code)
}
The other one is:
for(code in codes) {
as.name(code)
}
On 25/02/2011 06:55, Noah Silverman wrote:
How can I dynamically use a variable as the name for another variable?
I realize this sounds cryptic,
On Fri, 25 Feb 2011, Vedajit Boyd wrote:
Hi,
Please someone let me know that the installation of both R for Windows
2.12.2 and MS office 2010 on the same system will interfere each other or
not.
In short, are these two tools compatible to each other?
There is nothing special about R, but you
Hi Celine,
GLM outputs usually give the null deviance and residual deviance in the
summary() term - so you can work out % deviance explained for a variable/model
from this. Hope this helps.
Best wishes,
Clare
Dr Clare B Embling
Visiting Research Fellow
Marine
I can't think of a reason why they would...
Rob Tirrell
On Thu, Feb 24, 2011 at 23:56, Vedajit Boyd vedajit.b...@gmail.com wrote:
Hi,
Please someone let me know that the installation of both R for Windows
2.12.2 and MS office 2010 on the same system will interfere each other or
not.
In
I am having following problem:
I´m constructing model for calculation of area of triangle.
I know sides a, b, and gamma angle.
I wish to calculate the area using heron´s formula:
S - sqrt(s*(s-a)*(s-b)*(s-c))
where
s - (a+b+c)/2
and c is calculated using law of cosines:
c - sqrt(a^2 + b^2
Try
my.date - strptime(20/2/06 11:16:16.683, %d/%m/%y %H:%M:%OS)
Then you can examine my.date$mon.
--
Robert Tirrell | r...@stanford.edu | (607) 437-6532
Program in Biomedical Informatics | Butte Lab | Stanford University
On Thu, Feb 24, 2011 at 14:12, Belle ping...@gmail.com wrote:
I
Dear users,
I have a double for loop that does exactly what I want, but is quite
slow. It is not so much with this simplified example, but IRL it is slow.
Can anyone help me improve it?
The data and code for foo_reg() are available at the end of the email; I
preferred going directly into the
Hi,
If I follow you correctly, you could write a function:
foo - function(a,b,gamma){
c - sqrt(a^2 + b^2 -2*a*b*cos(gamma))
s - (a+b+c)/2
A - sqrt(s*(s-a)*(s-b)*(s-c))
return(A)
}
I hope I didn't make mistakes, but it can still help you, I guess.
Ivan
Le 2/25/2011 10:11,
Simply avoiding the for loops by using lapply (I may have missed a bracket
here or there cause I did this without opening R)...
Haven't checked the speed up, though.
lapply(seq.yvar, function(k){
plot(mydata1[[k]]~mydata1[[ind.xvar]], type=p,
xlab=names(mydata1)[ind.xvar],
On Fri, Feb 25, 2011 at 4:11 AM, zbynek.jano...@gmail.com
zbynek.jano...@centrum.cz wrote:
I am having following problem:
I´m constructing model for calculation of area of triangle.
I know sides a, b, and gamma angle.
I wish to calculate the area using heron´s formula:
S -
Hi,
I have two X1,X2 and Y1,Y2 and I want to draw them ((X1,Y1), (X2,Y2)) in
a scatter graph.
How can I draw both of them in a same graph with different legends?
And is there any way to show different labels on each point?
Regards,
Amir
__
Hi,
I am using this loop
par(mfrow=c(3,3))
annos-c(2001:2007,2009)
for (i in annos) {
t-subset(masia,YEAR==i)
t$FAMILIA-drop.levels(t$FAMILIA)
pie(table(t$FAMILIA),main=i)
}
To make piecharts of species composition among years (my data frame is
called masia). So I get 1 piechart of the
Hi,
Take a look at ?points, ?legend and ?par (specifically col and pch)
HTH,
Ivan
Le 2/25/2011 11:58, amir a écrit :
Hi,
I have two X1,X2 and Y1,Y2 and I want to draw them ((X1,Y1), (X2,Y2)) in
a scatter graph.
How can I draw both of them in a same graph with different legends?
And is there
Hi all,
I am modelling a time series with missing data.
*Q1)* However, I am not sure if I should use the next *graphics* to
understand my data:
*a)* ACF PACF (original series)
*b)* ACF PACF (residuals)
* *
*Q2)* I am using *tsdiag*, so I obtain a graphic with 3 plots: stand.
residuals vs time;
Thanks Nick for your quick answer.
It does work (no missed bracket!) but unfortunately doesn't really speed
up anything: with my real data, it takes 82.78 seconds with the double
lapply() instead of 83.59s with the double loop (about 0.8 s).
It looks like my double loop was not that bad. Does
use Rprof to find where time is being spent. probably in 'plot' which might
imply it is not the 'for' loop and therefore beyond your control.
Sent from my iPad
On Feb 25, 2011, at 6:19, Ivan Calandra ivan.calan...@uni-hamburg.de wrote:
Thanks Nick for your quick answer.
It does work (no
On 02/25/2011 09:33 PM, Lucia Rueda wrote:
Hi,
I am using this loop
par(mfrow=c(3,3))
annos-c(2001:2007,2009)
for (i in annos) {
t-subset(masia,YEAR==i)
t$FAMILIA-drop.levels(t$FAMILIA)
pie(table(t$FAMILIA),main=i)
}
To make piecharts of species composition among years (my data frame is
I want to do a lm regression, some of the variables are going to be affected
with log, I would like not no take into account the values which imply doing
log(0)
for just one variable I have done the following but it doesn't work:
lmod1.lm -
Hi all,
i have a little problem, and i think it is really simple to solve, but i
dont know exactly how to.
here is the challange:
i have a data.frame with n colum, i have to group 2 of them and calculate
the mean value of the 3. one. so far so good, that was easy - i used
aggregate function to
Hi Jessica,
try this: Q[k:c(k+3)]
--
View this message in context:
http://r.789695.n4.nabble.com/select-element-from-vector-tp3323725p3324286.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Dear Jim,
I've tried to use Rprof() as you advised me, but I don't understand how
it works.
I've done this:
Rprof(for (i in seq_along(seq.yvar)){
all_my_commands
})
summaryRprof()
But I got this error:
Error in summaryRprof() : no lines found in ‘Rprof.out’
I couldn't really understand
You need to use == instead of = for testing equality. While you're at it,
you should check for positive values, not just screening out 0s. This works
for me:
R mydata = data.frame(x=0:10, y=runif(11))
R fm = lm(y ~ log(x), mydata, subset=x0)
Andy
-Original Message-
From:
Hi,
I think ave() might do what you want:
df - data.frame(a=rep(c(this,that),5), b1=rnorm(10), b2=rnorm(10))
ave(df[,2], df[,1], FUN=mean)
For all columns, you could do that:
d - lapply(df[,2:3], FUN=function(x)ave(x,df[,1],FUN=mean))
df2 - cbind(df, d)
HTH,
Ivan
Le 2/25/2011 12:11, zem a
hello dear list! I wonder about the layout of my csv for my study design:
i have 11 different sites.
each site had been visited 9 times.
on each visit, 6 distinctive water parameters had been taken ONCE on
each visit (as continuous variables).
on each visit, the fish abundance was counted
Hi,
I have two data set of normalized Affymetrix CEL files, wild type vs Control
type.(each set have further three replicates).
wild.fish
AffyBatch object
size of arrays=712x712 features (10 kb)
cdf=Zebrafish (15617 affyids)
number of samples=3
number of genes=15617
annotation=zebrafish
notes=
Dear Sacha,
Do you revisit the same locations per site? If so, use (1|site/location) as
random effect. Otherwise use just (1|site). You might want to add a crossed
random effect (1|date) if you can expect an effect of phenology.
Best regards,
Thierry
PS R-sig-mixed-models is a better list
I've rolled up R-2.12.2.tar.gz a short while ago. This is an update release,
which fixes a number of mostly minor issues, and one major issue in which
complex arithmetic was being messed up on some compiler platform.
You can get it from
http://cran.r-project.org/src/base/R-2/R-2.12.2.tar.gz
Dear All,
I need to plot some points on the surface of a sphere, but I am not sure
about how to proceed to achieve this in R (or if it is suitable for this
at all).
In any case, I am not looking for really fancy visualizations; for
instance you can consider the images between formulae 5 and 6
You invoke Rprof, run your code and then terminate it:
Rprof()
... code you want to profile
Rprof(NULL) # generate output
summaryRprof()
example:
Rprof()
for (i in 1:1e6) sin(i) + cos(i) + sqrt(i)
Rprof(NULL)
summaryRprof()
$by.self
self.time self.pct total.time total.pct
sin
Ha... it was way too simple!
I thought it would be like system.time()... my bad. Thanks for the tip!
As we thought, foo_reg() takes most of the computing time, and I cannot
improve that.
Any ideas of how to improve the rest?
Thanks again for your help
Ivan
Le 2/25/2011 14:29, jim holtman a
On Feb 24, 2011, at 4:50 PM, Denis Kazakiewicz wrote:
Dear R people
Could you please help with following
Trying to compare accuracy of tumor size evaluation by different
methods. So data looks like
id true metod1 method2 ...
1 2 2 2.5
2 1.52 2
3 2 2 2
And in that vein, the recently released MethComp package by Bendix
Carstensen may be of service.
HTH,
Dennis
On Fri, Feb 25, 2011 at 5:39 AM, Marc Schwartz marc_schwa...@me.com wrote:
On Feb 24, 2011, at 4:50 PM, Denis Kazakiewicz wrote:
Dear R people
Could you please help with following
Brian Tsai btsai00 at gmail.com writes:
Hi all,
I'm trying to figure out the effective differences between BFGS and L-BFGS-B
are, besides the obvious that L-BFGS-B should be using a lot less memory,
and the user can provide box constraints.
1) Why would you ever want to use BFGS, if
On 25/02/2011 8:21 AM, Lorenzo Isella wrote:
Dear All,
I need to plot some points on the surface of a sphere, but I am not sure
about how to proceed to achieve this in R (or if it is suitable for this
at all).
In any case, I am not looking for really fancy visualizations; for
instance you can
That's interesting. You might also like:
http://en.wikipedia.org/wiki/Von_Mises%E2%80%93Fisher_distribution
I'm not sure how to plot the wireframe sphere, but you can visualize the
points by transforming to Cartesian coordinates like so:
u - runif(1000,0,1)
v - runif(1000,0,1)
theta - 2 * pi * u
Here's the way I would explore this, and some of the code is made more tidy.
Note that also you could vectorize your simulation. I have used set.seed
multiple times to make bootstrap samples the same across runs. -Frank
. . .
if (data[i, 3] == 4) data[i, 5] - sample(c(0, 1), 1, prob=c(.06,
Apologies, I'm really new with R, Can you help me with the syntax?
here is my data.frame in which I introduce independent variables:
varind -
data.frame(datpos$hdom2,datpos$NumPies,datpos$InHart,datpos$CV,datpos$CA,datpos$FCC)
varind has dimensions(194, 6), in case that's necessary. Then I
hi,
I would like to find the x value (independent variable) for a certain dependent
value using the fitted model with nls.
with (predict) I can find y that corresponds to a list of x. I need the other
way around. can it be done?
thanks,
afadda
__
Apologies, I'm really new with R, Can you help me with the syntax?
here is my data.frame in which I introduce independent variables:
varind -
data.frame(datpos$hdom2,datpos$NumPies,datpos$InHart,datpos$CV,datpos$CA,datpos$FCC)
varind has dimensions(194, 6), in case that's necessary. Then I
Date: Thu, 24 Feb 2011 13:28:18 -0800
From: dannyb...@gmail.com
To: r-help@r-project.org
Subject: Re: [R] Group rows by common ID and plot?
does this do what you want?
library(lattice)
Hi Ivan,
thanks for your replay!
but the problem is there that the dataframe has 2 rows and ca. 2000
groups, but i dont have the column with the groupnames, because the groups
are depending on 2 onother columns ...
any other idea or i didnt understand waht are you posted ... :(
--
View
I imagine you want the ggplot2 package.
something like:
ggplot(dataframe, aes(x = yourxvar, y = youryvar)) +
geom_point() +
facet_wrap(~ ProbeSet.ID)
Or facet_grid(), either of which makes a different panel for each unique level
of ProbeSet.ID
see gggplot help here:
10x i solved it ... mein problem was that i had 2 column by them i have to
group, i just pasted the values together so that at the end i have one
column to group and then was easy ...
here is the script that i used:
http://tolstoy.newcastle.edu.au/R/help/06/07/30184.html
Ivan thanks for the help
Hi, I am running the following script for a different (much larger data
frame):
DF = data.frame(read.table(textConnection(A B C D E
1 1 a 1999 1 0
2 1 b 1999 0 1
3 1 c 1999 0 1
4 1 d 1999 1 0
5 2 c 2001 1 0
6 2 d 2001 0 1
7 3 a 2004 0 1
8 3 b 2004 0
Hi,
I'm trying to utilize the kohonen package to build SOM's. However,
trying this on my data I get the error:
Argument data should be numeric
when running the som(data.train, grid = somgrid(6, 6, hexagonal))
function. As you see, there is a problem with the data type of
data.train which is a
Sorry for being unclear: the example works fine on my machine too. However,
with the much larger dataset (dim(5,108)) I get the reported error.
Mathijs
On Fri, Feb 25, 2011 at 3:56 PM, Scott Chamberlain
scttchamberla...@gmail.com wrote:
Works fine on my machine:
DF
A BC D E
1
Hi,
I don't get any error...
DF - cbind(DF[,c(1:3)],ave(DF[, c(4:5)],DF$B, FUN = f))
DF
A BC D E
1 1 a 1999 0 0
7 3 a 2004 1 0
2 1 b 1999 0 0
10 4 b 2001 0 1
8 3 b 2004 1 1
3 1 c 1999 0 0
5 2 c 2001 0 1
11 4 c 2001 1 1
4 1 d 1999 0 0
6 2 d 2001 1 0
12 4 d 2001 1 1
9 3 d 2004 1 2
Hello.
I am trying to fit my data sample x with different distributions such that
the integral from min(x) to max(x) of the fitted distribution will be one.
Therefore I have wrote my own log-likelihood functions and then I am using
mle {stats4}. So, for example:
ll_gamma - function(a,b) {
Works fine on my machine:
DF
A B C D E
1 1 a 1999 0 0
2 1 b 1999 0 0
3 1 c 1999 0 0
4 1 d 1999 0 0
5 2 c 2001 0 1
6 2 d 2001 1 0
7 3 a 2004 1 0
8 3 b 2004 0 1
9 3 d 2004 1 1
10 4 b 2001 0 2
11 4 c 2001 1 1
12 4 d 2001 1 2
here's my session info:
sessionInfo()
R version 2.12.1 (2010-12-16)
Hi,
I wanted to check the difference in results (using lme4) , if I treated a
particular variable (beadchip) as a random effect vs if I treated it as a
fixed effect.
For the first case, my formula is:
lmer.result - lmer(expression ~ cancerClass + (1|beadchip))
For the second case, I want
Yeah, you are right
i want to post an short example what i want to do .. and in the meantime i
solved the problem ...
but here is:
i have something like this dataframe:
c1-c(1,2,3,2,2,3,1,2,2,2)
c2-c(5,6,7,7,5,7,5,7,6,6)
c3-rnorm(10)
x-cbind(c1,c2,c3)
x
c1 c2 c3
[1,] 1 5
Bill,
what will be the fastest way to output not just single lines but small data
frames of about 60 rows?
I prefer writing to a text file because the final output is large 47k times
60 rows and since I do not know the size of it I have to use rbind to build
the object which creates the memory
Hi everyone,
I have two different results which is determined by (x,y)
x1 - c(1,5,8)
y1 - c(8,9,10)
x2 - c(1,7,9)
y2 - c(5,7,9)
Let call one=(x1,y1) and Two=(x2,y2)
how can I draw them in R in a scatter plot showing (x,y) with two
different legends (One, Two)
Regards,
Amir
Hello All!
I am training to train a NN with function train() after splitting data with
the function splitForTrainingAndTest(). The split is ok (checked it), but
when I get a try on training I get this message:
Error in UseMethod(train) :
no applicable method for 'train' applied to an object
On Feb 25, 2011, at 7:25 AM, agent dunham wrote:
Apologies, I'm really new with R, Can you help me with the syntax?
here is my data.frame in which I introduce independent variables:
varind -
data.frame(datpos$hdom2,datpos$NumPies,datpos$InHart,datpos
$CV,datpos$CA,datpos$FCC)
varind has
Ok, now I think I've understood, but I'm not sure since I think that my
ave() solution does work. Although, I though you have several numerical
variables and 1 factor; it is the opposite but it is still possible:
c3_mean - ave(x[,3], list(x[,1],x[,2]), FUN=mean) #note that values
are
On Feb 25, 2011, at 10:14 AM, zem wrote:
Yeah, you are right
i want to post an short example what i want to do .. and in the
meantime i
solved the problem ...
but here is:
i have something like this dataframe:
c1-c(1,2,3,2,2,3,1,2,2,2)
c2-c(5,6,7,7,5,7,5,7,6,6)
c3-rnorm(10)
On Feb 25, 2011, at 10:26 AM, amir wrote:
Hi everyone,
I have two different results which is determined by (x,y)
x1 - c(1,5,8)
y1 - c(8,9,10)
x2 - c(1,7,9)
y2 - c(5,7,9)
Let call one=(x1,y1) and Two=(x2,y2)
how can I draw them in R in a scatter plot showing (x,y) with two
different
There are considerable differences between the algorithms. And BFGS is an
unfortunate
nomenclature, since there are so many variants that are VERY different. It was
called
variable metric in my book from which the code was derived, and that code was
from Roger
Fletcher's Fortran VM code based
No, as the error states, you need random effects in lmer. But, you don't for
lm() and that is what you're running with no random effects. However, some
caution is warranted on the comparison.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
Dear R list,
I get a strange error in R:
*** caught segfault ***
address 0x6951c20, cause 'memory not mapped'
Traceback:
1: .C(spline_eval, z$method, nu = as.integer(n), x = as.double(xout), y
= double(n), z$n, z$x, z$y, z$b, z$c, z$d, PACKAGE = stats)
2: spline(gam.data$x[, col.data],
Hi:
Here's another way:
c1-c(1,2,3,2,2,3,1,2,2,2)
c2-c(5,6,7,7,5,7,5,7,6,6)
c3-rnorm(10)
x - data.frame(c1 = factor(c1), c2 = factor(c2), c3)
x - transform(x, mean = ave(c3, c1, c2, FUN = mean))
Yet another with function ddply() in package plyr:
ddply(x, .(c1, c2), transform, mean = mean(c3))
On 02/25/2011 04:26 AM, Sukhbir Rattan wrote:
Hi,
I have two data set of normalized Affymetrix CEL files, wild type vs Control
type.(each set have further three replicates).
wild.fish
AffyBatch object
size of arrays=712x712 features (10 kb)
cdf=Zebrafish (15617 affyids)
number of
On Fri, Feb 25, 2011 at 6:09 AM, Abeer Fadda
a.fa...@zmbh.uni-heidelberg.de wrote:
hi,
I would like to find the x value (independent variable) for a certain
dependent value using the fitted model with nls.
with (predict) I can find y that corresponds to a list of x. I need the other
way
My actual code is several things with adaptive filtering. This will
require accessing data sporadically. The loop was just a quick example
for the e-mail.
One application is to work with online (streaming) data. If I get a new
data point in for code a1, I'll need to be able to reference the
Hello, I'm attempting to access a specific number of sub diagonals in a
MATRIX and have been accustomed to using spdiags in MATLAB or Octave. I've
got a solution pieced together using for loops and it works though isn't
vectorized and liable to run very slow
for large matrices.
As an example:
A
Hello all
I am a very new R user
I am used to using STATA
My problem:
I want to build a Cox model and validate this.
I have a large number of clinical relevant factors and feel the need to
reduce these. Meanwhile I have some clinical variables I deem sufficiently
important to
Dear R community members and R experts
I am stuck at a point and I tried with my colleagues and did not get it out.
Sorry, I need your help.
Here my data (just created to show the example):
# generating a dataset just to show how my dataset look like, here I have x
variables
# x1
I simply don't understand why I get this error when using a larger dataset.
Error in `[-.data.frame`(`*tmp*`, i, , value = integer(0)) :
replacement has 0 items, need 37597770
In addition: Warning message:
In max(i) : no non-missing arguments to max; returning -Inf
Any ideas on what this
Hi, As part of my dissertation, I'm going to be doing an Anova,
comparing the dead zone diameters on plates of microbial growth with
little paper disks loaded with antimicrobial, a clear zone appears
where death occurs, the size depending on the strength and
succeptibility. So it's basically 4
Thank so much to everybody who found time to answer my question
All your messages are of great help.
Good luck
У Пят, 25/02/2011 у 05:46 -0800, Dennis Murphy піша:
And in that vein, the recently released MethComp package by Bendix
Carstensen may be of service.
HTH,
Dennis
On Fri, Feb
Are you clear about the question you are asking? Do you want to know whether
there are 6 balls or at least 6 balls? (It sounds like at least.) Do you
want to know whether there are at least 6 balls in the first box, or at least 6
balls in exactly one box or at least 6 balls in at least one
Hi,
I'm trying to install a module - gputools - and keep getting compile
time errors about missing R.h
Does anyone know where this file can be found?
Thanks!
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
To access a variable by a character string name, try
for(code in codes)
{
dat - get(code)
[stuff]
}
Other options include ?assign if you need to manipulate the original, or
?with to use the subject of codes as an environment.
--
Jonathan P. Daily
Technician -
On Fri, Feb 25, 2011 at 11:26 AM, Mingo catojo...@gmail.com wrote:
Hello, I'm attempting to access a specific number of sub diagonals in a
MATRIX and have been accustomed to using spdiags in MATLAB or Octave. I've
got a solution pieced together using for loops and it works though isn't
On Feb 25, 2011, at 12:33 PM, Noah Silverman wrote:
My actual code is several things with adaptive filtering. This will
require accessing data sporadically. The loop was just a quick
example
for the e-mail.
One application is to work with online (streaming) data. If I get a
new
data
P.S. I used the latest version of the rms package to run this. The Design
package is no longer supported.
Frank
-
Frank Harrell
Department of Biostatistics, Vanderbilt University
--
View this message in context:
On Feb 25, 2011, at 1:09 PM, David Winsemius wrote:
On Feb 25, 2011, at 12:33 PM, Noah Silverman wrote:
My actual code is several things with adaptive filtering. This will
require accessing data sporadically. The loop was just a quick
example
for the e-mail.
One application is to work
Hi John,
Thanks so much for the informative reply! I'm currently trying to optimize
~10,000 parameters simultaneously - for some reason, when I compare the
memory usage for L-BFGS-B and BFGS, the L-BFGS-B only uses about 1/7 of the
memory, with all default input parameters, I'm a bit surprised
Hi Rex,
Thanks for you explain. In fact, my question is: When I observed that
there are 6 or more balls in one box, what is this probability? The
ball is randomly put into the boxes.
I think it is: 1-pbinom(6,142,1/491) = 2.272026e-08.
When the sample size is large, how should I do this? using
I can hopefully save bandwidth here by suggesting that this belongs on
the R-sig-mixed-models list.
-- Bert
As an aside, shouldn't you be figuring this out yourself or seeking
local consulting expertise?
On Fri, Feb 25, 2011 at 9:08 AM, Ben Ward benjamin.w...@bathspa.org wrote:
Hi, As part of
Hi All,
I have two Rs, one has been installed in Windows system and
another one has been installed under UNIX system. Is there any environmental
variable or function to tell me which R I am using? The reason that I need to
know it is under different system, the data path could
I'm trying to use tapply to output means and SD or SE for my data but
seem to be limited by how many times I can subset it. Here's a snippet
of my data
stems353[1:10,]
Time DataSource Plot Elevation Aspect Slope Type Species
SizeClass Stems
1 ModernCameron 70F221 1730
Thanks Mike - this doesn't quite do it, but I think that you've hit of the
right method.
I am just trying to use 'plot' initially - I don't care so much about the
arrangement in the file.
plot(df$y,group=df$f) outputs the Y column in the appropriate plot. What I
would like to do is have 10 Y
This is the first time that I've posted to this list, so if I'm doing
something wrong, please let me know. Also, if there is a searchable forum
where I can find help, that would be good too.
I'm doing a card sorting experiment, and I'm having problems imputing my
data into R for later
What types of interaction do you want?
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Abhishek Pratap
Sent:
Does it work for FUN=mean? If yes, you need to print out the results of f
before you return them to find the anomalous value.
BTW Error is not a very good subject line. I don't see many posts from
people reporting how well things are going :)
-Original Message-
From:
Dear R users
I am new R user, execuse me I bother you, but I worked hard to find a
solution:
# data
ID - c(1:100)
set.seed(21)
y - rnorm(100, 10,2)
x1 - rnorm(100, 10,2)
x2 - rnorm(100, 10,2)
x3 - rnorm(100, 10,2)
x4 - rnorm(100, 10,2)
x5 - rnorm(100, 10,2)
x6 - rnorm(100, 10,2)
mydf -
Hi Hui,
May be sessionInfo() is what you are looking for. See ?sessionInfo as well
as ?version for more details. You can run the following on your R session
and see what comes up:
sessionInfo()
sessionInfo()$R.version$platform
version$platform
Then, you might use ifelse() to set up the right
On Feb 25, 2011, at 12:23 PM, Hui Du wrote:
Hi All,
I have two Rs, one has been installed in Windows system and
another one has been installed under UNIX system. Is there any environmental
variable or function to tell me which R I am using? The reason that I need to
know
Hi,
see ?R.version
Something like
if(version$os == mingw32) {
path = /ABC} else {
path = /DEF
}
might do it, but I'm not sure exactly what possible values version$os
can take or what determines the value exactly.
Best,
Ista
On Fri, Feb 25, 2011 at 1:23 PM, Hui
On Feb 25, 2011, at 1:23 PM, Hui Du wrote:
Hi All,
I have two Rs, one has been installed in Windows
system and another one has been installed under UNIX system. Is
there any environmental variable or function to tell me which R I am
using? The reason that I need to know
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