On May 26, 2011 Andrew Halford wrote:
> I am using ordiellipse to plot the ellipses and it works fine except one
> of my groups
> contains only 2 sites and I cannot get an ellipse around them. I'm
> assuming
> that 2 points is not enough to perform the relevant calculations here,
> however I wo
Hi Eric,
Hopefully the following addresses your question:
library(XML)
## please do not include rm(list=ls()) in code other's might copy and paste
## it could remove things precious to them
url <-
"http://webapp.montcopa.org/sherreal/salelist.asp?saledate=05/25/2011";
tbl <-data.frame(readHTMLTab
Hi,
On Thu, May 26, 2011 at 12:49 AM, eric wrote:
> Statement 9 using sapply does not seem to give the correct answer (or at
> least to me). Yet I do what I think is the same thing with statement 11 and
> I get the answer I'm looking for.
>
> 9 : s <-sapply(unlist(v[c(1:length(v))]), max)
> 11: f
Dear R-help,
Can anybody tell me which R package has Lo-Mendell Rubin LR test and Bootstrap
LR test to compare the model fit between k class and k+1 class model for Latent
class analysis?
Thanks in advance,
warn regards,Ms.Karunambigai M
PhD Scholar
Dept. of Biostatistics
NIMHANS
Bangalore
India
hi, I want to know how about r package Robust CP in all possible regression
method...can you help me??
thanks before...
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https://stat.ethz.ch/mailman/listinfo/r-help
PL
Statement 9 using sapply does not seem to give the correct answer (or at
least to me). Yet I do what I think is the same thing with statement 11 and
I get the answer I'm looking for.
9 : s <-sapply(unlist(v[c(1:length(v))]), max)
11: for(i in 1 :length(v)) v1[i] <- max(unlist(v[i]))
Shouldn't I
Hi Users,
I am trying to plot 95% confidence ellipses around the 4 groupings found in
a PCA ordination and identified a-priori by clustering. I am using
ordiellipse to plot the ellipses and it works fine except one of my groups
contains only 2 sites and I cannot get an ellipse around them. I'm ass
On May 25, 2011, at 10:21 PM, Rafael Terra wrote:
Dear R-project members,
I'm a newbie in R and I'm trying to install the "splm" package to
analyze spatial panel data. I have the R x64 2.12.0 beta version
installed in my computer. When I try to install the package from
within R typing "
Dear R-project members,
I'm a newbie in R and I'm trying to install the "splm" package to analyze
spatial panel data. I have the R x64 2.12.0 beta version installed in my
computer. When I try to install the package from within R typing
">install.packages("splm", repos="http://R-Forge.R-project
Dear R Helpers,
I was looking at the email help threads in trying to find a calculation in
R of Thiel's uncertainty coefficient. One of the writers offered to send
the function in custom code to the inquirer. Can I get a copy of that
code, or does anyone know if the calculation is now available
Hi all,
I'm adjusting a nonlinear regression model for data that has a categorigal
variable present. So, I can use nls() to do this considering the categorical
variable, like this
#
da <- expand.grid(tr=gl(2,1,la=c("tr")), x=1:12)
da$y <
Hi All,
I am using ksvm method in kernlab R package for support vector
machines. I learned the multiclass one-against-one svm from training data
and using it to classify new datapoints. But I want to update/finetune the
'svm weights' based on some criteria and use the updated svm weights
On Wed, 25 May 2011 19:33:24 -0500,
"Sebastian P. Luque" wrote:
> which shows me that the estimate for at least one parameter is outside
> the bounds. I'll try to prepare a simplified example to reproduce.
I got it, it turned out to be the ndeps being too large so it pushed the
L-BFGS-B over th
On Wed, 25 May 2011 19:33:24 -0500,
"Sebastian P. Luque" wrote:
> which shows me that the estimate for at least one parameter is outside
> the bounds.
I meant the value for the parameter during the failing iteration, not
the estimate, of course.
--
Seb
Dear Users,
I would like to know if any of you know some R packages for appling the
Thiessen method; in my case I would like to interpolete with this method
some rain gauges.
Tanks a lot
[[alternative HTML version deleted]]
__
R-help@r-project
David, Peter (and others),
If you're interested, I submitted this as a bug, and was informed of the
error of my ways by Professor Ripley
* His informative reply is copied below. *
The short answer is that panel.first is not a documented function of
"plot.formula", which is called by the generic "
On Wed, 25 May 2011 23:46:02 +,
Ben Bolker wrote:
> Sebastian P. Luque gmail.com> writes:
>> Hi,
>> When using method L-BFGS-B along with a parscale argument, should the
>> lower and upper bounds provided be on the scaled or unscaled values?
>> Thanks.
> I think you can figure this out b
Sebastian P. Luque gmail.com> writes:
>
> Hi,
>
> When using method L-BFGS-B along with a parscale argument, should the
> lower and upper bounds provided be on the scaled or unscaled values?
> Thanks.
I think you can figure this out by experimentation on your own,
but I believe that all of t
I have a loop that regularly checks for new data to analyse in my database. In
order to facilitate this, the database table has a timestamp column with the
time that the data was inserted into the database. Something like this:
while () {
load(timetoken.Rdata)
df <- sqlQuery(con, pas
Hi,
When using method L-BFGS-B along with a parscale argument, should the
lower and upper bounds provided be on the scaled or unscaled values?
Thanks.
Cheers,
--
Seb
__
R-help@r-project.org mailing list
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PL
Hi
On 15/05/2011 2:01 a.m., Larry White wrote:
Hi,
I'm trying to use Grid plots and would like to have an X axis that
represents dates. I have several years of data so I would like to be able to
have labeled tick marks only intermittently (not one per date). I can
transform the initial data fr
On May 25, 2011, at 5:56 PM, Gene Leynes wrote:
David, Peter (and others),
If you're interested, I submitted this as a bug, and was informed of
the error of my ways by Professor Ripley
* His informative reply is copied below. *
The short answer is that panel.first is not a documented funct
That worked perfectly. Thank you Dennis - I very much appreciate the
help!
Sara Maxwell, PhD, Postdoctoral Fellow
Marine Conservation Institute
University of California Santa Cruz
Long Marine Laboratory
100 Shaffer Road
Santa Cruz CA 95060 USA
+1 206 355 3249
sara.maxw...@marine-conservation.or
On May 25, 2011, at 5:50 PM, Dennis Murphy wrote:
Hi:
On Wed, May 25, 2011 at 12:42 PM, rudi
wrote:
Hi,
can anyone help me to figure out how to compute the percentile of an
individual observation with respect to a reference distribution.
What I mean is. Let's assume I have a vector consi
On 25/05/2011 5:43 PM, John C Frain wrote:
I have no problems configuring .r files to start in Emacs or RStudio
and then use Emacs or RStudio to call the required version of R.
You might check when you open with other from Windows Explorer that
the check box "Always open with this program is tic
Hi:
On Wed, May 25, 2011 at 12:42 PM, rudi wrote:
> Hi,
>
> can anyone help me to figure out how to compute the percentile of an
> individual observation with respect to a reference distribution.
>
> What I mean is. Let's assume I have a vector consisting of 10 numbers
> {3,5,8,1,9,5,4,3,5.5,7} a
Dear all,
may I suggest the acronym IOTT for the inter-ocular trauma test?
Now we just need someone to implement iot.test(). I assume it will
appear on CRAN within the next 24 hours.
Looking forward to yet another base package,
Stephan
Am 25.05.2011 23:36, schrieb Greg Snow:
How can anyon
I have no problems configuring .r files to start in Emacs or RStudio
and then use Emacs or RStudio to call the required version of R.
You might check when you open with other from Windows Explorer that
the check box "Always open with this program is ticked.
If you are using Windows 7 you can set
How can anyone overlook the intra-ocular trauma test (or sometimes called the
inter-ocular concussion test). But the i-o trauma test needs either a small
data set or an appropriate graph of the data (or can you look at a dataset of a
hundred columns and a million rows and do an intra-ocular tra
Hi Rudi,
Take a look at ?ecdf
HTH,
Jorge
On Wed, May 25, 2011 at 3:42 PM, rudi <> wrote:
> Hi,
>
> can anyone help me to figure out how to compute the percentile of an
> individual observation with respect to a reference distribution.
>
> What I mean is. Let's assume I have a vector consisting
On May 25, 2011, at 3:42 PM, rudi wrote:
Hi,
can anyone help me to figure out how to compute the percentile of an
individual observation with respect to a reference distribution.
What I mean is. Let's assume I have a vector consisting of 10 numbers
{3,5,8,1,9,5,4,3,5.5,7} and I want figure ou
Hi,
can anyone help me to figure out how to compute the percentile of an
individual observation with respect to a reference distribution.
What I mean is. Let's assume I have a vector consisting of 10 numbers
{3,5,8,1,9,5,4,3,5.5,7} and I want figure out what percentile the
number 4.9 corresponds
Hello Dr. Winsemius,
First of all, thank you for your prompt and helpful reply. Also, for
providing something I hoped would be produced from joining this mailing
list: a means of discovering incredibly useful packages such as the
"reshape2" one you have introduced me too.
I have a follow up
> Date: Wed, 25 May 2011 12:32:37 -0400
> Subject: Re: [R] Processing large datasets
> From: mailinglist.honey...@gmail.com
> To: marchy...@hotmail.com
> CC: ro...@bestroman.com; r-help@r-project.org
>
> Hi,
>
> On Wed, May 25, 2011 at 11:00 AM, Mike
[See in-line below]
On 25-May-11 19:14:11, Michael Dewey wrote:
> At 00:41 25/05/2011, Greg Snow wrote:
>>The only statistical method that I know of that can be
>>applied to any dataset without further definition of the
>>nature of the data or the question being asked is
>>SnowsCorrectlySizedButOt
Hi:
Interesting problem. Here's one approach:
library(plyr)
# Read in your datasets as data frames rather than matrices
dataset1 <- data.frame(id1 = rep(1:3, each = 10),
value1 = sample(seq_len(100), 30, replace = TRUE))
dataset2 <- data.frame(id2 = 1:3, subtract.value = c(
On May 25, 2011, at 3:25 PM, Seth W Bigelow wrote:
I have a list that is made of lists of varying length. I wish to
create a
new vector that contains the last element of each list. So far I
have used
sapply to determine the length of each list, but I'm stymied at the
part
where I index the
On May 25, 2011, at 2:25 PM, Seth W Bigelow wrote:
> I have a list that is made of lists of varying length. I wish to create a
> new vector that contains the last element of each list. So far I have used
> sapply to determine the length of each list, but I'm stymied at the part
> where I index
On May 25, 2011, at 3:25 PM, Seth W Bigelow wrote:
I have a list that is made of lists of varying length. I wish to
create a
new vector that contains the last element of each list. So far I
have used
sapply to determine the length of each list, but I'm stymied at the
part
where I index the
I have a list that is made of lists of varying length. I wish to create a
new vector that contains the last element of each list. So far I have used
sapply to determine the length of each list, but I'm stymied at the part
where I index the list to make a new vector containing only the last item
At 00:41 25/05/2011, Greg Snow wrote:
The only statistical method that I know of that can be applied to
any dataset without further definition of the nature of the data or
the question being asked is
SnowsCorrectlySizedButOtherwiseUselessTestOfAnything which is found
in the TeachingDemos packa
Dear Colleagues,
I'd like to draw your attention to the following job available at the Harvard
Business School. We are looking for a candidate with strong
statistical/econometrical background, with strong programming skills in R or
Stata. Please apply through the following link. If you know
I get a data frame on my end:
lines <- "2011-05-13 00:00:00 EONAAL330 dfa13002516PSCNONA
2011-05-13 00:00:01 EONAAL223 laa13044510AS.NONM
2011-05-13 00:00:05 EONBHS229 mia13001621NON"
df = read.fwf(textConnection(lines), widths=c(19,-4,7,3,8,2,1,3,1),
col.names=c("DateTime","Flight","Dest","ArrTi
It's very easy to do in two steps:
> testmat <- matrix(c(.2, .3, 1, -1, 3, .2, .4, 5, .5, -1), byrow=TRUE, nrow=2)
> testmat
[,1] [,2] [,3] [,4] [,5]
[1,] 0.2 0.31 -1.03
[2,] 0.2 0.45 0.5 -1
> testmat[testmat >= 1] <- 1
> testmat[testmat < 0] <- 0
> testmat
[,1] [,2] [,
Hello everyone,
I have a 2 x 5 matrix: say
0.2 0.3 1 -1 3
0.2. 0.4 5 0.5 -1
I want to replace all the values greater than or equal to 1 with 1 and those
less than or equal to 0 with 0. So I should end up with a mtrix looking
like:
0.2 0.3 1 0 1
0.2. 0.4 1 0.5 0
An
try this using strsplit:
> x <- round(runif(10)*10, digits=0)
> y <- as.Date(x, origin="1970-01-01")
> str(y)
Class 'Date' num [1:10] 26551 37212 57285 90821 20168 ...
> y1 <- as.character(y)
> str(y1)
chr [1:10] "2042-09-11" "2071-11-19" "2126-11-04" "2218-08-30"
"2025-03-21" "2215-12-22" .
Hi:
Here are two alternatives that do work as you expect; sprintf() is your friend:
> sprintf("%2d", 1:12)
[1] " 1" " 2" " 3" " 4" " 5" " 6" " 7" " 8" " 9" "10" "11" "12"
> sprintf("%02d", 1:12)
[1] "01" "02" "03" "04" "05" "06" "07" "08" "09" "10" "11" "12"
> sprintf("%2d", 1:12) < 10
[1] TR
Hi:
Does this work?
dd <- read.table(textConnection("
C C C C T T G G A A C C G G C C
G G T T A A A A T A T T C C G G
C C C C T T G G A A C C G G C C
"), stringsAsFactors = FALSE)
# Convert the data frame to a ch
On May 25, 2011, at 1:16 PM, Scott Hatcher wrote:
Hello Dr. Winsemius,
First of all, thank you for your prompt and helpful reply. Also, for
providing something I hoped would be produced from joining this
mailing list: a means of discovering incredibly useful packages such
as the "reshape
You can produce a graph similar to the ggplot with lattice::barchart,
require(lattice)
dataset <- data.frame(Main=c("A","A","A","B","B"),
Detail=c("a","b","c","1","2"),
value=runif(5, min= 0.5, max=1))
barchart(value~Detail|Main, data=dataset,
s
Dear R users,
I have two datasets:
id1 <- c(rep(1,10), rep(2,10), rep(3,10))
value1 <- sample(1:100, 30, replace=TRUE)
dataset1 <- cbind(id1,value1)
id2 <- c(1,2,3)
subtract.value <- c(1,3,5)
dataset2 <- cbind(id2, subtract.value)
I want to subtract the number of rows in the subtract.value that
Many thanks for your reply. I have run a stepwise selection in Stata and R
using the function fastbw (rule="p") from Design package. Both functions
give the same results. Is this because both functions do the same job or can
it be that for different data one will have different results?
Many thank
Thankyou very much, I managed to count he numbr of Markers 2 linked to
Markers 3. And Markers 1 to Markers 3 with the aggregate function:
with(data,aggregate(Marker1,list(Marker2=Marker2),length))
data2<-with(data,aggregate(Marker1,list(Marker2=Marker2,Marker3=Merker3),length))
So, now is easy I
Hi Josh,
You are definitely right. And were all time.
Yes, the problem was always with the write.csv(). I though it was with the "ds".
Thank you very much.
Cheers,
Rui
> Date: Tue, 24 May 2011 14:30:56 -0700
> Subject: Re: [R] How to intantiate a list of data.frames?
> From: jwiley.ps...@gmail.
On May 25, 2011, at 12:11 PM, linda Porz wrote:
Many thanks for your reply. I have run a stepwise selection in Stata
and R using the function fastbw (rule="p") from Design package. Both
functions give the same results. Is this because both functions do
the same job or can it be that for di
Matthew,
You can change the matrix (restriction) involved. Start from
help(contr.sum)
to know how specify this.
Walmes.
==
Walmes Marques Zeviani
LEG (Laboratório de Estatística e Geoinformação, 25.450418 S, 49.231759 W)
D
Hi,
On Wed, May 25, 2011 at 11:00 AM, Mike Marchywka wrote:
[snip]
>> > If your datasets are *really* huge, check out some packages listed
>> > under the "Large memory and out-of-memory data" section of the
>> > "HighPerformanceComputing" task view at CRAN:
>>
>> > http://cran.r-project.org/web/v
John -
Try
infert[,toolong] = sapply(infert[,toolong],cut2,g=10,levels.mean=TRUE)
- Phil Spector
Statistical Computing Facility
Department of Statistics
Sorry, I forgot to be more specific.
I am using Windows XP.
I am using R.12.2
I installed both packages from the install packages menu.
I always write library(name.of.library), and it is enough.
But when I write library(nlme), R does not find nlme right away
I load nlme first and it says pac
Victor,
I agree with Marc's point of view. So, if you can use another representation
of you data, like points, considering looking at
http://lmdvr.r-forge.r-project.org/figures/figures.html figures 10.20 and
10.21 for a start point.
Walmes.
===
You need to use get() so that you are acting on the dataframe,
and not the string that names the dataframe.
Sarah
On Wed, May 25, 2011 at 12:02 PM, Sparks, John James wrote:
> Dear R Helpers,
>
> I am having trouble combining some pieces of programming that work fine
> individually, but fall dow
Hi John,
The issue is that:
"infert$age" != infert$age
One is a text string, the other references the information stored in
the age variable of the infert object. If you need to pass the names
as a string, use "[" instead:
## for a data frame
infert[, "age"]
## for a list
infert[["age"]]
It l
Well, that answered some of my questions, though you forgot to send
your answer to the r-help list rather than just to me. I don't use
windows, so someone else may have better advice.
On Wed, May 25, 2011 at 12:02 PM, wrote:
> Sorry, I forgot to be more specific.
>
> I am using Windows XP.
>
> I
Dear R Helpers,
I am having trouble combining some pieces of programming that work fine
individually, but fall down when I try to get them to work together.
The end goal is to take a data frame, and if any of the variables has more
than 10 values, then use cut2 to reduce the number of (effective)
With PostgreSQL at least, R can also be used as implementation
language for stored procedures. Hence data transfers between
processes can be avoided alltogether.
http://www.joeconway.com/plr/
Implemention of such a procedure in R appears to be straighforward:
CREATE OR REPLACE FUNCTION
See the Vignette in the glmnet package for one alternative approach to
variable selection. Of course, you need to gain some background to
know what you're doing here.
-- Bert
On Wed, May 25, 2011 at 8:38 AM, Marc Schwartz wrote:
> Hi,
>
> You are unlikely to find one, as fundamentally, stepwise
Everything looks OK. Does this help?
> test <-
>data.frame(alpha=as.factor(c("A","A","B","B","C")),number=c(1,2,3,4,5))
> mode(test)
[1] "list"
> class(test)
[1] "data.frame"
> sapply(test, mode)
alphanumber
"numeric" "numeric"
> sapply(test, class)
alphanumber
"factor" "numeric
I have a data set where the lines look like:
2011-05-13 00:00:00 EONAAL330 dfa13002516PSCNONA
2011-05-13 00:00:01 EONAAL223 laa13044510AS.NONM
Some lines are missing the field before and after the NON:
2011-05-13 00:00:05 EONBHS229 mia13001621NON
I read them into R using
df = read.fwf(file, wi
Hi,
You are unlikely to find one, as fundamentally, stepwise procedures are a bad
way to engage in covariate selection. Search the list archives at rseek.org
using 'stepwise' as the keyword to see a plethora of discussion on this point.
This is not a new issue BTW, as I happened to stumble upon
> Date: Wed, 25 May 2011 10:18:48 -0400
> From: ro...@bestroman.com
> To: mailinglist.honey...@gmail.com
> CC: r-help@r-project.org
> Subject: Re: [R] Processing large datasets
>
> > Hi,
> > If your datasets are *really* huge, check out some packages list
Or use melt in the reshape2 package to melt all columns to one with an indexing
column to boot...
__Scott Chamberlain
Rice University, EEB Dept.
On Wednesday, May 25, 2011 at 7:06 AM, zoe.cryocla wrote:
> Ok, I found how to do,
> with the function paste()
>
> --
> View th
We really need some more information to be able to help you (as
requested in the posting guide):
What OS?
What version of R?
How did you install nlme? Were there any messages?
What happens when you type library(nlme) at the R prompt?
How did you install mgcv? Were there any messages?
On Wed,
On May 25, 2011, at 7:25 AM, Lutz Fischer wrote:
Thanks a lot for both replies.
If I setup the option as proposed everything works as I wanted it to.
I guess as.character would work as well. Only then I guess I would
need
to loop through the data frame.
as.character is vectorized. You
On May 25, 2011, at 5:28 AM, linda Porz wrote:
Sorry, I have wrote a wrong subject in the first email!
Regards,
Linda
-- Forwarded message --
From: linda Porz
Date: 2011/5/25
Subject: combined odds ratio
To: r-help@r-project.org
Cc: r-help-requ...@stat.math.ethz.ch
Dear all
Hi.
I have been trying to load the mgcv package but I always get the error
message:
there is no package called 'nlme'
Error: package/namespace load failed for 'mgcv'
I load the package nlme and still I get the same message. I have noticed
that there are some problems in using nlme in recent v
I suggest a couple of courses before proceeding. Multinomial logistic models
have special challenges. And note that you have two nomenclature errors in
your note, which is usually a sign of not having taken the relevant
coursework.
Frank
Belle wrote:
>
> Does anyone know how to run Multinomial
Shant Ch yahoo.com> writes:
>
> Yes I had included the library(maptools) in my code, it is already
> installed in
> my computer. but still it is showing the same error.
>
In that case you should (1) read the posting guide, (2) copy and
paste the code you ran, and the precise error you got,
On May 25, 2011, at 7:56 AM, Victor Gabillon wrote:
> Hello,
>
> I want to use the function barplot do display several group of bars.
> A standard example is given at this link
> http://onertipaday.blogspot.com/2007/05/make-many-barplot-into-one-plot.html
>
> But in their example the 4 groups of
> Date: Wed, 25 May 2011 09:49:00 -0400
> From: ro...@bestroman.com
> To: biomathjda...@gmail.com
> CC: r-help@r-project.org
> Subject: Re: [R] Processing large datasets
>
> Thanks Jonathan.
>
> I'm already using RMySQL to load data for couple of days.
Hi,
On Wed, May 25, 2011 at 10:18 AM, Roman Naumenko wrote:
[snip]
> I don't think data.table is fundamentally different from data.frame type, but
> thanks for the suggestion.
>
> http://cran.r-project.org/web/packages/data.table/vignettes/datatable-intro.pdf
> "Just like data.frames, data.table
On May 25, 2011, at 4:46 AM, zoe.cryocla wrote:
Hi again,
I've got another question...
I often use the symbol == to select some levels of factor variables
like :
data[data$var=="blabla", [
But this time, I'd like to select all the levels of my variable wich
contain
the letter "B", is t
Take a look at the High-Performance and Parallel Computing with R CRAN Task
View:
http://cran.us.r-project.org/web/views/HighPerformanceComputing.html
specifically at the section labeled "Large memory and out-of-memory data".
There are some specific R features that have been implemented in a
On 25/05/2011 6:06 AM, Niklaus Kuehnis wrote:
What's the logic behind the following, and where can I find any
documentation about it? In particular, why are 2:9 - as characters - not
regarded as being smaller than 10?
# R-Code:
a<- as.character(1:12)
a< 10
# [1] TRUE FALSE FALSE FALSE FALSE
On May 24, 2011, at 11:42 PM, Gene Leynes wrote:
Peter,
Good idea! (why didn't I think of that?)
If it stumped the r-list, I think there is probably a slight bug
with the
plot formula.
Problems like this make me realize how amazingly full featured and
relatively bug free R is. A problem
Then use as.matrix. Transpose is not a well-defined operation for data frames.
---
Jeff Newmiller The . . Go Live...
DCN: Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/Batteries
Thanks Jonathan.
I'm already using RMySQL to load data for couple of days.
I wanted to know what are the relevant R capabilities if I want to process much
bigger tables.
R always reads the whole set into memory and this might be a limitation in case
of big tables, correct?
Doesn't it use te
> Hi,
> On Wed, May 25, 2011 at 12:29 AM, Roman Naumenko
> wrote:
> > Hi R list,
> >
> > I'm new to R software, so I'd like to ask about it is capabilities.
> > What I'm looking to do is to run some statistical tests on quite
> > big
> > tables which are aggregated quotes from a market feed.
> >
I am trying to calculate Poisson regression based adjusted rate ratios in R,
but R's default in glm does not code the intercept as the global rate. In
SAS I use "cell means" coding so that the intercept is the global rate, but
I do not know how to do this in R. If anyone knows a way to make glm u
Yes I had included the library(maptools) in my code, it is already installed in
my computer. but still it is showing the same error.
From: Ben Bolker
To: r-h...@stat.math.ethz.ch
Sent: Wed, May 25, 2011 8:06:19 AM
Subject: Re: [R] plotting texas school distric
Thanks a lot for both replies.
If I setup the option as proposed everything works as I wanted it to.
I guess as.character would work as well. Only then I guess I would need
to loop through the data frame.
Lutz
On 24/05/11 22:42, Ista Zahn wrote:
> This is a FAQ:
>
> http://cran.r-project.org
On May 24, 2011; 11:06pm Belle wrote:
> Does anyone know how to run Multinomial logistical Model in R in order to
> get predicted probability?
Yes. I could stop there but you shouldn't. The author of the package
provides plenty of examples (and two good vignettes) showing you how to do
this. Sugg
What's the logic behind the following, and where can I find any
documentation about it? In particular, why are 2:9 - as characters - not
regarded as being smaller than 10?
# R-Code:
a <- as.character(1:12)
a < 10
# [1] TRUE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE
FALSE
Ok, I found how to do,
with the function paste()
--
View this message in context:
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Sent from the R help mailing list archive at Nabble.com.
__
R-help
Sorry, I have wrote a wrong subject in the first email!
Regards,
Linda
-- Forwarded message --
From: linda Porz
Date: 2011/5/25
Subject: combined odds ratio
To: r-help@r-project.org
Cc: r-help-requ...@stat.math.ethz.ch
Dear all,
I am looking for an R function which does stepwi
Hi,
I have a problem during choosing a Cran mirror, a&n error messages comes:
> In open.connection (con, "r")
connection to 'cran.r-project.org' impossible to prt 80.
I don't know why? can you help me to choose a cran mirror.
thanks for any suggestion.
--
View this message in contex
Hi,
I have a data-matrix:
> CB
                  Zeit         Low
2Â Â 2011-05-02 08:05:05 7596.0
3Â Â 2011-05-02 08:10:06 7593.5
4Â Â 2011-05-02 08:15:11 7594.5
5Â Â 2011-05-02 08:20:15 7597.5
6Â Â 2011-05-02 08:25:18 7595.0
7Â Â 2011-05-02 08:30:20
Dear all,
I am looking for an R function which does stepwise selection cox model in r
(delta chisq likelihood ratio test) similar to the stepwise, pe (0.05) lr:
stcox in STATA.
I am very thankful for any reply.
Regards,
Linda
[[alternative HTML version deleted]]
___
Hi,
I’m an R beginner and I'd really appreciate an hand…
I'd like to create a new column in a dataframe in wich will be print the
content of several other columns.
For instance :
I’ve got 2 columns : "site" – "sampling number" and I would like to create a
third column "ID", in wich will appear b
Hi again,
I've got another question...
I often use the symbol == to select some levels of factor variables like :
data[data$var=="blabla", [
But this time, I'd like to select all the levels of my variable wich contain
the letter "B", is that a way to determine this conditions ?
Thanks a lot !
Hello,
I am trying to run JRI example from rJava, but I have some issues. I have read
many posts and didn't find any solution to my problem.
I have the following code:
Rengine re = new Rengine(null, false, null);
System.out.println("Rengine created, waiting for R");
if (!re.waitForR()
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