Brian,
I'm a bit confused about how the following line works, specifically, what is
happening in freq=length(x)? Is it just taking the length of x after it has
been summarized by different combinations x & y? I guess that must be the
case, because that gives the same result as using freq=length(y)
Hi:
As Uwe suggested...
pdf('testgraph.pdf')
layout( matrix( 1:2 , nrow=2 ) )
for ( i in 1:2 ) {
plot( 0 , 0 , xlab=bquote(mu[.(i)]) )
}
dev.off()
postscript('testgraph.ps')
layout( matrix( 1:2 , nrow=2 ) )
for ( i in 1:2 ) {
plot( 0 , 0 , xlab=bquote(mu[.(i)]) )
}
dev.off()
png('testgrap
On Wed, 22 Jun 2011, Jim Silverton wrote:
I am generating 1,000 replicates of 10,000 of these 2 x 3 tables but R
cannot seem to save it. Its over 1 Gig. Any ideas on how I can store
this large amount of data? Should I use a list or a matrix?
Is English your first language? If so, you can pro
On Jun 22, 2011, at 11:57 PM, Jim Silverton wrote:
I am generating 1,000 replicates of 10,000 of these 2 x 3 tables but R
cannot seem to save it.
What does that mean? Error messages?
Its over 1 Gig. Any ideas on how I can store this
large amount of data? Should I use a list or a matrix?
H
I am generating 1,000 replicates of 10,000 of these 2 x 3 tables but R
cannot seem to save it. Its over 1 Gig. Any ideas on how I can store this
large amount of data? Should I use a list or a matrix?
Jim
On Wed, Jun 22, 2011 at 10:21 PM, Mike Miller wrote:
> On Thu, 23 Jun 2011, David Duffy wro
I am not an expert in this. But try try() :)
hth,
Daniel
Sam Nicol wrote:
>
> Hi R-users,
>
> I'm attempting to fit a number of mixed models, all with the same
> structure, across a spatial grid with data points collected at various
> time points within each grid cell. I'm trying to use a
Here's a fairly minimal-case example in which the saved EPS does not match
the screen. The error comes when using bquote(.(i)) instead of bquote(1), as
demonstrated by the two minimally different cases below. Very strange. Any
clues as to why?
# begin ---
# Version
If you have any specific features of the time series of soil moisture, you
could either model that or directly estimate it and test for differences in the
4 treatments. If you do not have any such specific considerations, you might
want to consider some nonparametric approaches such as function
In the limit as x goes to infinity, the integrand x f(x) should go to 0
sufficiently fast in order for the integral to be finite. The error indicates
that the integrand becomes infinite for large x. Check to ensure that the
integrand is correctly specified.
I don't understand how you can repla
Hi Elizabeth,
I just found your thread after experiencing a similar problem (I was also
using some IRanges/GenomicRanges functions). You've probably figured it
out by this time - I'm actually curious to know what you found?
I think I've tracked it down in my case, where a small minority of the
Tena koe Nate
You can use the fact that R recycles. If yourData is a dataframe, then (as
examples):
yourData[c(TRUE,FALSE),] will give you every second row, starting with the
first. Similarly,
yourData[c(FALSE,TRUE,FALSE),] will give every third row, starting with the
second; and
yourData[c(
On Thu, 23 Jun 2011, David Duffy wrote:
I am interested in simulating 10,000 2 x 3 tables for SNPs data with
the Hardy Weinberg formulation. Is there a quick way to do this? I am
assuming that the minor allelle frequency is uniform in (0.05, 0.25).
rmultinom() with HWE expectations
I'm als
I am trying to run gev (general extreme value) function in “evir” package. My
data is divided by state. I am using the following codes but it is not working.
I will appreciate any help.
#Split data
MAS <- split(MA, MA$states)
CP <- lapply(MAS, function(x){gev(MAS$CP1, 100, method = "BFGS", c
Hi R-users,
I'm attempting to fit a number of mixed models, all with the same
structure, across a spatial grid with data points collected at various
time points within each grid cell. I'm trying to use a 'for' loop to try
the model fit on each grid cell. In some cells lme does not converge,
g
I would like to subset data from a larger dataset and generate a smaller
dataset. However, I don't want to use sample() because it does it randomly.
I would like to take non-random subsamples, for example, every 2nd number,
or every 3rd number. Is there a procedure that does this?
Thanks, Nate
Dear R users,
I have a question about numerical integration in R.
I am facing the 'non-finite function value' error while integrating the
function
xf(x)
using 'integrate'. f(x) is a probability density function and assumed to
follow the three parameter (min = 0) beta
> Date: Wed, 22 Jun 2011 17:21:52 -0700
> From: jmo...@student.canterbury.ac.nz
> To: r-help@r-project.org
> Subject: Re: [R] Time-series analysis with treatment effects - statistical
> approach
>
> Hi Mike, here's a sample of my data so that you get an idea what I'm working
> with.
Thanks,
Resending to correct bad subject line...
On Mon, 20 Jun 2011, Jim Silverton wrote:
I a using plink on a large SNP dataset with a .map and .ped file. I want
to get some sort of file say a list of all the SNPs that plink is saying
that I have. ANyideas on how to do this?
All the SNPs you hav
On Mon, 20 Jun 2011, Jim Silverton wrote:
I a using plink on a large SNP dataset with a .map and .ped file. I want
to get some sort of file say a list of all the SNPs that plink is saying
that I have. ANyideas on how to do this?
All the SNPs you have are listed in the .map file. An easy way
Dennis,
Thanks. That makes sense, but I don't think it's clearly documented.
The default assumption that I and at least some others in this
discussion made is that everything in the list of plotmath features in
the helpfile works the same way, since they're all in the same list.
And if for some o
Hi:
>From the plotmath help page:
x %->% y x right-arrow y
so this is behaving like a binary operator. There happen to be several
of these in plotmath
On Wed, Jun 22, 2011 at 5:49 PM, Sarah Goslee wrote:
> Interesting. I don't know the explanation, but look at this:
> # works
> plot(1:
Thanks to both David and Sarah. I'm glad I asked, as I had tried some
of the combos Sarah suggested and observed the same behavior, which
puzzled me. David, thanks for reminding me about ~ as that is a
different way to get a space into the string. I just don't use
plotmath often enough t
On Jun 22, 2011, at 8:10 PM, Bryan Hanson wrote:
Hello R Masters and the Rest of Us:
The first of these works fine, the 2nd is accepted but too literal
(the "%->%" is shown in the plot label and in the wrong position).
The 3rd throws and error due to "unexpected SPECIAL". Would someone
Interesting. I don't know the explanation, but look at this:
# works
plot(1:10, 1:10, xlab=expression(a %->% b))
# doesn't work
plot(1:10, 1:10, xlab=expression(%->%))
# works
plot(1:10, 1:10, xlab=expression(paste("something" %->% "else")))
# doesn't work
plot(1:10, 1:10, xlab=expression(paste("s
Hi Mike, here's a sample of my data so that you get an idea what I'm working
with.
http://r.789695.n4.nabble.com/file/n3618615/SampleDataSet.txt
SampleDataSet.txt
Also, I've uploaded an image showing a sample graph of daily soil moisture
by treatment. The legend shows IP, IP+, PP, PP+ which are
Hello R Masters and the Rest of Us:
The first of these works fine, the 2nd is accepted but too literal
(the "%->%" is shown in the plot label and in the wrong position).
The 3rd throws and error due to "unexpected SPECIAL". Would someone
recommend a way to format this? I want the two phr
http://bakaneko.fr/friends.page.php?igjhotmailID=28aq2
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PLEASE do read the post
On Wed, Jun 22, 2011 at 7:07 PM, Changbin Du wrote:
> INstalling of "RSQLite" was successful.
>
> in R:
>> packageVersion("RSQLite")
> [1] '0.9.4'
>
>
>
> When I try to install "sqldf", I found the following errors:
>
>> install.packages("sqldf")
> Installing package(s) into '/house/homedirs/c/cdu
INstalling of "RSQLite" was successful.
in R:
> packageVersion("RSQLite")
[1] '0.9.4'
When I try to install "sqldf", I found the following errors:
> install.packages("sqldf")
Installing package(s) into '/house/homedirs/c/cdu/library/'
(as 'lib' is unspecified)
trying URL 'http://cran.cnr.Berke
I will try this first.
Thanks, Gabor!
On Wed, Jun 22, 2011 at 3:15 PM, Gabor Grothendieck wrote:
> On Wed, Jun 22, 2011 at 6:10 PM, Changbin Du wrote:
> > My R is 2.12.0.
> >
> >> R.version.string
> > [1] "R version 2.12.0 (2010-10-15)"
> >> packageVersion("RSQLite")
> > [1] '0.8.0'
> >> pac
On Wed, Jun 22, 2011 at 6:10 PM, Changbin Du wrote:
> My R is 2.12.0.
>
>> R.version.string
> [1] "R version 2.12.0 (2010-10-15)"
>> packageVersion("RSQLite")
> [1] '0.8.0'
>> packageVersion("sqldf")
> [1] '0.3.5'
>
> So it seems I have to update or install the 2.13.0 version in my linux
> machine
My R is 2.12.0.
> R.version.string
[1] "R version 2.12.0 (2010-10-15)"
> packageVersion("RSQLite")
[1] '0.8.0'
> packageVersion("sqldf")
[1] '0.3.5'
So it seems I have to update or install the 2.13.0 version in my linux
machine.
On Wed, Jun 22, 2011 at 3:04 PM, Gabor Grothendieck wrote:
>
On Wed, Jun 22, 2011 at 6:01 PM, Changbin Du wrote:
> I found the following errors:
>
>
>> library(sqldf)
> Loading required package: DBI
> Loading required package: RSQLite
> Loading required package: RSQLite.extfuns
> Error: package 'RSQLite' 0.8-0 is loaded, but >= 0.9.1 is required by
> 'RSQLi
I found the following errors:
> library(sqldf)
Loading required package: DBI
Loading required package: RSQLite
Loading required package: RSQLite.extfuns
*Error: package 'RSQLite' 0.8-0 is loaded, but >= 0.9.1 is required by
'RSQLite.extfuns'*
> hh<-read.csv.sql("/house/homedirs/c/cdu/operon/gh5/
Hi, Gabor,
Thanks so much, I will try it and let you know the results.
Appreciated!
On Wed, Jun 22, 2011 at 2:54 PM, Gabor Grothendieck wrote:
> On Wed, Jun 22, 2011 at 5:45 PM, Changbin Du wrote:
> > HI, Dear R community,
> >
> > I have a large data set names dd.txt, the columns are: there
I am interested in simulating 10,000 2 x 3 tables for SNPs data with the
Hardy Weinberg formulation. Is there a quick way to do this? I am assuming
that the minor allelle frequency is uniform in (0.05, 0.25).
rmultinom() with HWE expectations
__
R-
On Wed, Jun 22, 2011 at 5:45 PM, Changbin Du wrote:
> HI, Dear R community,
>
> I have a large data set names dd.txt, the columns are: there are 2402
> variables.
>
> a1, b1, ..z1, a11, b11, ...z11, a111, b111, ..z111..
>
> IF I dont know the relative position of the columns, but I know I need the
HI, Dear R community,
I have a large data set names dd.txt, the columns are: there are 2402
variables.
a1, b1, ..z1, a11, b11, ...z11, a111, b111, ..z111..
IF I dont know the relative position of the columns, but I know I need the
following variables:
var<-c(a1, c1,a11,b11,f111)
Can I use read.
You lost me with the TRN and TRN_CLUSTER bits, but are you trying to
make a list of lists?
> Data_ <- list()
> SN <- 1:12
> for(sn in SN) {
+ Data_[[sn]] <- list()
+ for(i in 1:10) {
+ Data.X <- rnorm(5, 0, 10)
+ Data_[[sn]][[i]] <- Data.X
+ }}
>
> Data_[[3]][[2]]
[1] -5.687070 -2.365589 12.378359
I second the fortune nomination, probably the 1st paragraph is sufficient for a
fortune.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
Varimax is orthogonal, promax is oblique. Varimax is generally not
recommended. See: Preacher, K. J., & MacCallum, R. C. (2003).
Repairing Tom Swift's electric factor analysis machine. Understanding
Statistics, 2(1), 13-43. (Google the title and you'll find a PDF).
The fa() function in the psy
On 6/22/2011 4:09 PM, Brian Diggs wrote:
> On 6/22/2011 1:37 PM, Alexander Shenkin wrote:
>> On 6/22/2011 3:34 PM, Brian Diggs wrote:
>>> On 6/22/2011 12:09 PM, Luke Miller wrote:
For what it's worth, I cannot reproduce this problem under a nearly
identical instance of R (R 2.12.1, Win 7
Hello
I seem to find only two types of rotation for the factanal function in R, the
Varimax and Promax, but is it possible to run a orthogonal and oblique
rotations in R?
Thanks in advance
Rosario
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R-help@r-project.org mailing list
https://stat.ethz.
On Wed, 22 Jun 2011, Quang Anh Duong wrote:
Hello,?
I am pretty new to mlogit, and still trying to figure out what models to
use.I have a data set of N individuals, each of which faces I
alternatives. The utility function of individual n, for choice i is:?
u(i,n) = alpha(i) * x1(i,n) + beta
On 6/22/2011 1:37 PM, Alexander Shenkin wrote:
On 6/22/2011 3:34 PM, Brian Diggs wrote:
On 6/22/2011 12:09 PM, Luke Miller wrote:
For what it's worth, I cannot reproduce this problem under a nearly
identical instance of R (R 2.12.1, Win 7 Pro 64-bit). I also can't
reproduce the problem with R 2
I know this a newbie question, but I've only just started using AIC for
model comparison and after a bunch of different keyword searches I've
failed to find a page laying out what the differences are between the
AIC scores assigned by AIC() and mle.aic() using default settings.
I started by usin
So im here now b/c im incredibly frustrated. Please consider the following:
#Try 1
Data_<-list()
Sn<-1:12
for(sn in Sn){
for(i in 1:10){
Data.X <- rnorm(100,0,10)
Data_[[paste(sn,i,sep="-")]]<-Data.X
}
}
##Try 2
Data_<-list()
Sn<-1:12
for(sn
On 6/22/2011 1:23 PM, William Dunlap wrote:
The isdst value -1 doesn't seem right. Shouldn't it
be either 0 (not daylight savings time) or 1 (yes dst)?
I've only seen isdst==-1 when all the other entries
were NA (that happens when the string doesn't match
the format).
A isdst of -1 indicates t
On 6/22/2011 3:34 PM, Brian Diggs wrote:
> On 6/22/2011 12:09 PM, Luke Miller wrote:
>> For what it's worth, I cannot reproduce this problem under a nearly
>> identical instance of R (R 2.12.1, Win 7 Pro 64-bit). I also can't
>> reproduce the problem with R 2.13.0. You've got something truly weird
On 6/22/2011 12:09 PM, Luke Miller wrote:
For what it's worth, I cannot reproduce this problem under a nearly
identical instance of R (R 2.12.1, Win 7 Pro 64-bit). I also can't
reproduce the problem with R 2.13.0. You've got something truly weird
going on with your particular instance of R.
is
Wow. Setting my timezone to UTC -5 Bogota (where there is no daylight
savings time), I get the error:
> is.na(strptime("5/3/1992", format="%m/%d/%Y"))
[1] TRUE
But setting it to UTC -5 East Coast Time (whether or not I tell windows
to adjust for DST) I get:
> is.na(strptime("5/3/1992", format="
I can reproduce your problem when using a time that
doesn't exist because it is between 2am and 3am on
the Sunday that we switch from winter time to summer
time:
> z <- strptime(paste(paste(sep="/", 4, 5, 1992), "2:30"),
format="%m/%d/%Y %H:%M")
> z
[1] "1992-04-05 02:30:00"
> is.na(z)
[1] TRUE
>
The isdst value -1 doesn't seem right. Shouldn't it
be either 0 (not daylight savings time) or 1 (yes dst)?
I've only seen isdst==-1 when all the other entries
were NA (that happens when the string doesn't match
the format).
In the parts of the US where daylight savings time is
used the switchove
Hi
On 23/06/2011 2:58 a.m., Simon Goodman wrote:
Using layout I've created a function that makes a 2 panel plot - comprising a
main plot, and a sub-panel with custom legend.
I would now like to use layout to create multiple panels with plots created
by my function, however the values for layout
Thanks all the issue is closed.
in this case I had a data element FILE.PARAMETERS = list()
the .Rd files created by package.skelton() for data objects had the
following for \usage.
\usage{data(FILE.PARAMETERS)}
I left that as is and CHECK throws a warning.
"checking for code/d
Hello,
I am pretty new to mlogit, and still trying to figure out what models to use.I
have a data set of N individuals, each of which faces I alternatives. The
utility function of individual n, for choice i is:
u(i,n) = alpha(i) * x1(i,n) + beta * x2(i,n)
where alpha(i) is the individual sp
Hello,
When evaluating different learning methods for a categorization problem with
the (really useful!) caret package, I'm getting confusing results from the
Kappa computation. The data is about 20,000 rows and a few dozen columns,
and the categories are quite asymmetrical, 4.1% in one category a
Daniel,
That indeed does work... and I didn't even need to learn a new function.
Thanks!
--
Ryan Utz, Ph.D.
Aquatic Ecologist/STREON Scientist
National Ecological Observatory Network
Home/Cell: (724) 272-7769
Work: (720) 746-4844 ext. 2488
[[alternative HTML version deleted]]
___
For what it's worth, I cannot reproduce this problem under a nearly
identical instance of R (R 2.12.1, Win 7 Pro 64-bit). I also can't
reproduce the problem with R 2.13.0. You've got something truly weird
going on with your particular instance of R.
> is.na(strptime("5/3/1992", format="%m/%d/%Y")
1st of all Dr Utz, thanks for your recent pubs on regional differences
between the piedmont and coastal plain streams.
and to add to Daniels post (giving your binary yes/no):
df<-merge(x,y,all.x=T,all.y=F)
df["exceed"] <- ifelse(df$Q>df$Threshold_Q , 1, 0)
## now look at df
df
Daniel Mal
The memisc package also offers functionality for documenting data.
Jan
On 06/22/2011 04:57 PM, Robert Lundqvist wrote:
Every now and then I realize that my attempts to document what all dataframes
consist of are unsufficient. So far, I have been writing notes in an external
file. Are there an
On 6/22/2011 1:34 PM, Sarah Goslee wrote:
> On Wed, Jun 22, 2011 at 2:28 PM, David Winsemius
> wrote:
>>
>> On Jun 22, 2011, at 2:03 PM, Sarah Goslee wrote:
>>
>>> Hi,
>>>
>>> On Wed, Jun 22, 2011 at 11:40 AM, Alexander Shenkin
>>> wrote:
>
> is.na(strptime("5/2/1992", format="%m/%d/%Y")
I assume that you are working in package MatrixCalc. Lets
say you have a matrix X. You can call the columns of X this way:
X[,1] for the first column
X[,2] for the second column
X[,3] for the third column
Etc.
So lets say that you want to add the first and third column,
then you would just
On Wed, Jun 22, 2011 at 2:28 PM, David Winsemius wrote:
>
> On Jun 22, 2011, at 2:03 PM, Sarah Goslee wrote:
>
>> Hi,
>>
>> On Wed, Jun 22, 2011 at 11:40 AM, Alexander Shenkin
>> wrote:
is.na(strptime("5/2/1992", format="%m/%d/%Y"))
>>>
>>> [1] FALSE
is.na(strptime("5/3/1992",
For example, you can merge the two data frames and do a direct comparison:
df<-merge(x,y,all.x=T,all.y=F)
df
df$Q>df$Threshold_Q
HTH,
Daniel
Ryan Utz-2 wrote:
>
> Hi all,
>
> I have two datasets, one that represents a long-term time series and one
> that represents summary data for the time
On Jun 22, 2011, at 2:03 PM, Sarah Goslee wrote:
Hi,
On Wed, Jun 22, 2011 at 11:40 AM, Alexander Shenkin
wrote:
is.na(strptime("5/2/1992", format="%m/%d/%Y"))
[1] FALSE
is.na(strptime("5/3/1992", format="%m/%d/%Y"))
[1] TRUE
I can't reproduce your problem on R 2.13.0 on linux:
I als
On 6/22/2011 1:03 PM, Sarah Goslee wrote:
> Hi,
>
> On Wed, Jun 22, 2011 at 11:40 AM, Alexander Shenkin wrote:
>>> is.na(strptime("5/2/1992", format="%m/%d/%Y"))
>> [1] FALSE
>>> is.na(strptime("5/3/1992", format="%m/%d/%Y"))
>> [1] TRUE
>
> I can't reproduce your problem on R 2.13.0 on linux:
>
Hi,
On Wed, Jun 22, 2011 at 11:40 AM, Alexander Shenkin wrote:
>> is.na(strptime("5/2/1992", format="%m/%d/%Y"))
> [1] FALSE
>> is.na(strptime("5/3/1992", format="%m/%d/%Y"))
> [1] TRUE
I can't reproduce your problem on R 2.13.0 on linux:
> strptime("5/2/1992", format="%m/%d/%Y")
[1] "1992-05-0
Hi all,
I have two datasets, one that represents a long-term time series and one
that represents summary data for the time series. It looks something like
this:
x<-data.frame(Year=c(2001,2001,2001,2001,2001,2001,2002,2002,2002,2002,2002,2002),
Month=c(1,1,1,2,2,2),Q=c(5,5,5,6,6,6,3,3,3,4,4,5))
y<
Jürg.
It's not that nobody knows the answer, necessarily, it's that your
inquiry is so vague we don't know what the *question* is, let alone
the answer.
We don't know anything about your data, your intended function and
model, anything.
A toy reproducible example with clear explanation would be
> is.na(strptime("5/2/1992", format="%m/%d/%Y"))
[1] FALSE
> is.na(strptime("5/3/1992", format="%m/%d/%Y"))
[1] TRUE
Any idea what's going on with this? Running strptime against all dates
from around 1946, only 5/3/1992 was converted as "NA". Even stranger,
it still seems to have a value associa
Does really nobody has a coment to this question?
Dear R-help members
I would like to use the R package goalprog, weighted and lexicographical goal
programming and optimization to optimize a location problem.
In my model I need a "yes" or "no" decision - in this case, whether to select a
site
Hi,
I would like to fit a Vector Auto Regression with lags that are not
consecutive with the vars package (or other if there is one as good). Is it
possible?
For example, rather than having lags 1, 2, 3, 4, 5 have 1, 2, 5.
Thanks.
--
View this message in context:
http://r.789695.n4.nabble.com
Hello R users,
I have a puzzle with the VGAM package, on my first excursion into
generalized additive models, in that this very nice package seems to
want to do either more or less than what I want.
Precisely, I have a 4-component outcome, y, and am fitting multinomial
logistic regression with one
H-W only gives you the expected frequency of AA, AB, and BB genotypes (i.e.
a 1x3 table):
minor <- runif(1, 0.05, 0.25)
major <- 1-minor
AA <- minor^2
AB <- 2*minor*major
BB <- major^2
df <- cbind(AA, AB, BB)
-Aaron
On Tue, Jun 21, 2011 at 9:30 PM, Jim Silverton wrote:
> Hello all,
> I am
Have a look at the AnnotatedDataFrame class in the Biobase package
[1]. Here is the description from the manual:
An ‘AnnotatedDataFrame’ consists of two parts. There is a collection
of samples and the values of variables measured on those samples.
There is also a description of each variable measu
There is a 'comment' function. It sets an attribute which gets carried
along with the dataframe when it is saved or copied:
> df1 <-data.frame(NA)
> df1
NA.
1 NA
> comment(df1) <- "empty dataframe"
> comment(df1)
[1] "empty dataframe"
> df2 <- df1
> comment(df2) <- c(comment(df1), "copy of d
Thanks Duncan, I'll join Dev and ask the questions over there.
Steve
On Wed, Jun 22, 2011 at 7:19 AM, Duncan Murdoch wrote:
> On 11-06-21 11:58 PM, steven mosher wrote:
>
>> Thanks to all your help I've just finished my first package and I have a
>> couple of questions
>>
>>
>>
>> I want to su
Tom,
thanks for spotting a bug in glmmML; internally, glmmML sorts data by
cluster. The bug is that I missed to sort the weights accordingly.
Weights are produced when the response is a two-column matrix, as in
your case. So, glmmML calls glm.fit with wrong weights, and the
warning comes from that
The best method would probably be proportional odds regression using
polyr() in 'MASS'.
At least it's a starting point.
At 09:19 AM 6/22/2011, Matt Ellis \(Research\) wrote:
Hello,
I am struggling to figure out how to analyse a dataset I have inherited
(please note this was conducted some tim
Using layout I've created a function that makes a 2 panel plot - comprising a
main plot, and a sub-panel with custom legend.
I would now like to use layout to create multiple panels with plots created
by my function, however the values for layout set in the function act
globally, stopping me from
Thanks for the suggestion, Dennis. Unfortunately, I was not able to make it
work. Maybe I'm not using as.formula properly. I posted below some new things I
tried. What am I doing wrong?
Thanks for any feedback!
Rita
First attempt:
> eqSystem2 <-paste(paste("form", 1:4, sep=""), as.formula(paste
Every now and then I realize that my attempts to document what all dataframes
consist of are unsufficient. So far, I have been writing notes in an external
file. Are there any better ways to do this within R? One possibility could be
to set up the data as packages, but I would like to have a sol
On Jun 21, 2011, at 10:31 AM, Nevil Amos wrote:
I am plotting a number of lines on a standard plot. I would like to
add labels at the end (rhs) of each line. is there a way to do this
other than defining the individual xy coordinates and placing each
label using text()
Without an examp
On Jun 22, 2011, at 9:46 AM, Marius Hofert wrote:
Hi David,
thanks for the quick response. That's nice. Is there also a way
without loading an additional package? I'd prefer loading less
packages if possible.
> xtb <- xtabs(value ~ year + block, data = df)
> xtb
block
year a b c
You could analyze these data with a multinomial logit model, with an ordinal
response. I don't have my copy handy, but I know that Agresti (Categorical
Data Analysis, Wiley) covers these models.
Cheers
David Cross
d.cr...@tcu.edu
www.davidcross.us
On Jun 22, 2011, at 8:19 AM, Matt Ellis (R
On 11-06-21 11:58 PM, steven mosher wrote:
Thanks to all your help I've just finished my first package and I have a
couple of questions
I want to submit to CRAN but I have 1 warning
" checking for code/documentation mismatches ... WARNING
Data sets with usage in documentation object 'FI
On Wed, Jun 22, 2011 at 2:35 AM, Nabila Binte Zahur wrote:
> Dear Sirs/Madam,
>
> I am a beginner to R, and I am currently working on a data matrix which looks
> like this:
>
>> head(oligo)
>
> ko:K1 ko:K3 ko:K5 ko:K8 ko:K9 ko:K00010 ko:K00012
> AAA 370 6
On 11-06-21 10:31 AM, Nevil Amos wrote:
I am plotting a number of lines on a standard plot. I would like to add
labels at the end (rhs) of each line. is there a way to do this other
than defining the individual xy coordinates and placing each label using
text()
Probably, but what you describe
Hi David,
thanks for the quick response. That's nice. Is there also a way without loading
an additional package? I'd prefer loading less packages if possible.
Cheers,
Marius
On 2011-06-22, at 15:38 , David Winsemius wrote:
>
> On Jun 22, 2011, at 9:19 AM, Marius Hofert wrote:
>
>> Hi,
>>
Hi:
Based on the information you provided, I would suggest looking into
the transform() and within() functions in base R, and perhaps the
mutate() function in package plyr.
HTH,
Dennis
On Tue, Jun 21, 2011 at 11:35 PM, Nabila Binte Zahur wrote:
> Dear Sirs/Madam,
>
> I am a beginner to R, and I
I am plotting a number of lines on a standard plot. I would like to add
labels at the end (rhs) of each line. is there a way to do this other
than defining the individual xy coordinates and placing each label using
text()
Thanks
Nevil Amos
__
R-h
Dear all,
I am a new user of R. I want use R to plot four momentum vectors(variable)
in form of tetrahedral. The data(momentum vector) is in form of
distribution(e.g. momentum of particle1 vs intensity).
Thanks in advance.
Best Regards
Rajesh
--
View this message in context:
http://r.78969
Good afternoon sir,
i'm a student in Indonesia who study technology management, i need to review
the software i'v been develop, i was told to use bayesian SEM because i
don't have large sample. i don't know much about statistics but i try to
make a code via winbugs.. and a i got a problem. here i a
Hello,
I am struggling to figure out how to analyse a dataset I have inherited
(please note this was conducted some time ago, so the data is as it is,
and I know it isn't perfect!).
A brief description of the experiment follows:
Pots of grass were grown in 1l pots of standad potting medium for 1
Dear Sirs/Madam,
I am a beginner to R, and I am currently working on a data matrix which looks
like this:
> head(oligo)
ko:K1 ko:K3 ko:K5 ko:K8 ko:K9 ko:K00010 ko:K00012
AAA 370 631 365 67 164
455
On Jun 22, 2011, at 9:19 AM, Marius Hofert wrote:
Hi,
and what's the simplest way to obtain a *data.frame* with all years?
The matching seems more difficult here because the years can/will
show up several times...
(df <- data.frame(year=c(2000, 2001, 2002, 2001, 2000, 2001),
I think you should write out your model formula and then go over it term by
term to see which term adds what to your understanding of the data. If
necessary, pick up a text about the interpretation of coefficients. For
example, you will find that Reduction is not just the slope for the
condition QF
Hi,
and what's the simplest way to obtain a *data.frame* with all years?
The matching seems more difficult here because the years can/will show up
several times...
(df <- data.frame(year=c(2000, 2001, 2002, 2001, 2000, 2001),
block=c("a","a","a","b","c","c"), value=1:6))
(df.
..I cant imagine myself without this site!
http://www.stadcopolyproducts.com/friends.page.php?utopic=07x1
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