On Aug 11, 2011, at 10:27 AM, Uwe Ligges wrote:
On 11.08.2011 19:22, David Winsemius wrote:
Hmm, when you want to add a level without changing the class of the
factor object, you will have to add the level at first and then
assign the level to the elements of the object. I'd probably rebui
Hi,
I need a custom axis function for a plot, but it seems
that current.panel.limits() sometimes returns NaN limits for the plot, which
it much harder to calculate anything sensible.
An illustration:
Given this axis function:
vs.axis <- function(...){
xlim <- current.panel.limits()$xlim
y
My mental model is that the left hand side forms a sort of "virtual vector"
where each element really points to an element in the vector being modified.
Then the right hand side scalar is extended in the usual repetitious way (if
necessary) until it is a vector just as long as the "virtual vecto
W dniu 12 sierpnia 2011 05:19 u¿ytkownik Chris Howden <
ch...@trickysolutions.com.au> napisa³:
> Thanks for the suggestion, I'll look into it
>
It seems to work! :)
library(multiv)
data(iris)
iris <- as.matrix(iris[,1:4])
h <- hierclust(iris, method=2)
d<- dist(iris)
hk<-hclust(d)
>str(hk)
List
I am new to R but I have managed to use mlogit to run multivariate logit
models successfully. My data violates the Independence of Irrelevant
Alternatives assumption and now I would like to run a mixed logit model. It
is a "wide" data set with 9 independent (individual) variables and three
choices
Hi All:
I'm looking to find out a bit more about how subassignment actually works and
am hoping someone with knowledge of the details can fill me in (I've looked at
the source code, but my knowledge of C is lacking).
In the case of vectors, my reading of ?"[" would indicate that for a vector,
The previous two posters basically covered everything, but since I'm on the
train with not too much to do, here's a more detailed response building on
what they said. The following code is "shovel-ready" and can be pasted
directly to your command line if you have your main data frame called "d"
ava
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of Rolf Turner
> Sent: Thursday, August 11, 2011 5:24 PM
> To: Heinz Tuechler
> Cc: Zeki Çatav; r-help@r-project.org; Uwe Ligges
> Subject: Re: [R] value.labels
>
> On 12/08/11 12:5
On 12/08/11 12:53, Heinz Tuechler wrote:
At 12.08.2011 11:05 +1200, Rolf Turner wrote:
On 12/08/11 11:34, Heinz Tuechler wrote:
At 12.08.2011 09:11 +1200, Rolf Turner wrote:
On 12/08/11 09:59, Heinz Tuechler wrote:
At 11.08.2011 21:50 +0300, Zeki Çatav wrote:
PrÅŸ, 2011-08-11 tarihinde 19:27
At 12.08.2011 01:53 +0100, Heinz Tuechler wrote:
At 12.08.2011 11:05 +1200, Rolf Turner wrote:
On 12/08/11 11:34, Heinz Tuechler wrote:
At 12.08.2011 09:11 +1200, Rolf Turner wrote:
On 12/08/11 09:59, Heinz Tuechler wrote:
At 11.08.2011 21:50 +0300, Zeki Çatav wrote:
PrÅ, 2011-08-11 tarihin
Hi:
samp_func() doesn't return anything. Either (1) type test as the last
line of the function body or (2) don't assign the last sum to an
object.
HTH,
Dennis
On Thu, Aug 11, 2011 at 1:59 PM, Sean Bignami wrote:
> Hello R-universe...
>
> I am having trouble writing a function which contains a l
At 12.08.2011 11:05 +1200, Rolf Turner wrote:
On 12/08/11 11:34, Heinz Tuechler wrote:
At 12.08.2011 09:11 +1200, Rolf Turner wrote:
On 12/08/11 09:59, Heinz Tuechler wrote:
At 11.08.2011 21:50 +0300, Zeki Çatav wrote:
PrÅ, 2011-08-11 tarihinde 19:27 +0200 saatinde, Uwe Ligges yazdı:
>
> On
I would like to know if there is a way to reduce the space between the
legend title and the first line of the legend, without reducing all
the vertical space using y.intersp. Because of lack of space, I would
like to differentiate my title by bolding it, and reduce the vertical
space under the titl
Thanks. Actually I thought of something like
Hanley JA, McNeil BJ. A method of comparing the areas under receiver operating
characteristic curves derived from the same cases. Radiology. 1983; 148:
839–843.
http://radiology.rsna.org/content/148/3/839.full.pdf+html
Has anybody R-code for this or
On 12/08/11 11:34, Heinz Tuechler wrote:
At 12.08.2011 09:11 +1200, Rolf Turner wrote:
On 12/08/11 09:59, Heinz Tuechler wrote:
At 11.08.2011 21:50 +0300, Zeki Çatav wrote:
Prş, 2011-08-11 tarihinde 19:27 +0200 saatinde, Uwe Ligges yazdı:
>
> On 11.08.2011 19:22, David Winsemius wrote:
> >
>
I am afraid this is one of these posts where I have to quote David Winsemius:
"The advancement of science would be safer if you knew what you were doing."
Moreover, these are questions best addressed to your local statistician
rather than the R-help list. With exceptions, the R-help list helps to s
On 12/08/11 07:37, m.marcinmichal wrote:
Hi,
It's my problem, supppose that we have a data.frame:
t
a b c
1 1 1 1
2 0 1 1
3 1 1 1
4 0 0 0
5 1 0 1
6 0 1 0
7 1 1 1
8 0 1 0
I need extract duplicat row i.e i nedd frame like this
a b c
3 1 1 1
8 0 1 0
I try use subset(t, duplicated(t)) and t
At 12.08.2011 09:11 +1200, Rolf Turner wrote:
On 12/08/11 09:59, Heinz Tuechler wrote:
At 11.08.2011 21:50 +0300, Zeki Çatav wrote:
PrÅ, 2011-08-11 tarihinde 19:27 +0200 saatinde, Uwe Ligges yazdı:
>
> On 11.08.2011 19:22, David Winsemius wrote:
> >
> > On Aug 11, 2011, at 11:42 AM, Uwe Ligge
it is in the consumer risk modeling team in Cincinnati ohio.
pls send resume to wensui@53.com if interested.
thx
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
Hi all:
Having browsed Rinternals.h, it's a little unclear to me how to get
attributes that aren't in the "Symbol Table Shortcuts" section of that
file. In particular, I would like to extract the attribute
"scaled:center" from a SEXP.
Thanks
[[alternative HTML version deleted]]
I am not sure what purpose the while loop has. However, the main problem
seems to be that you need to put:
i<-sample(1:(n-40),1) #This sample from 1 to n-40
rather than
i<-sample(1:n-40,1) #this samples one 1:n and then subtracts 40
Otherwise, you may get negative index values
Best,
Daniel
m.marcinmichal gmail.com> writes:
>
> Hi,
> It's my problem, supppose that we have a data.frame:
>
-snip-
You should avoid using t as a variable name since its an important
R function!
> I need extract duplicat row i.e i nedd frame like this
>
> a b c
> 3 1 1 1
> 8 0 1 0
>
not sure if t
On 08/11/2011 01:01 PM, Andra Isan wrote:
Hi All,
I am trying to run cv.glmnet(x,y,family="multinomial", nfolds =4) and I only
have 8 observations and the number of features I have is 1000, so my x matrix is 8 by
1000 and when I run the following, I get this error, I am not sure what is causing
On 12/08/11 09:59, Heinz Tuechler wrote:
At 11.08.2011 21:50 +0300, Zeki Çatav wrote:
Prş, 2011-08-11 tarihinde 19:27 +0200 saatinde, Uwe Ligges yazdı:
>
> On 11.08.2011 19:22, David Winsemius wrote:
> >
> > On Aug 11, 2011, at 11:42 AM, Uwe Ligges wrote:
> >
> >>
> >>
> >> On 11.08.2011 16:10
I am using two mixed effect models. Firstly, what I am trying to do is to
compare green roofs abundance with brownfield, green roof with green space
abundance, and finally green
space with brownfield abundance. I am unsure if I have done the
correct model. I have to use a mixed effect model because
Hi,
It's my problem, supppose that we have a data.frame:
t
a b c
1 1 1 1
2 0 1 1
3 1 1 1
4 0 0 0
5 1 0 1
6 0 1 0
7 1 1 1
8 0 1 0
I need extract duplicat row i.e i nedd frame like this
a b c
3 1 1 1
8 0 1 0
I try use subset(t, duplicated(t)) and t[duplicated(t), ] but this command
return
Hello R-universe...
I am having trouble writing a function which contains a loop so I can sapply()
it to a list of data frames
Each data frame has 241 observations of 15 variables. My loop takes a random
sample of one row until the 40 consecutive rows after the sample have a
d2p(variable) sum
At 11.08.2011 21:50 +0300, Zeki Çatav wrote:
PrÅ, 2011-08-11 tarihinde 19:27 +0200 saatinde, Uwe Ligges yazdı:
>
> On 11.08.2011 19:22, David Winsemius wrote:
> >
> > On Aug 11, 2011, at 11:42 AM, Uwe Ligges wrote:
> >
> >>
> >>
> >> On 11.08.2011 16:10, zcatav wrote:
> >>> Hello R people,
> >>
On Wed, Aug 10, 2011 at 11:39 PM, David Winsemius
wrote:
>> is.vector(x)
> [1] TRUE
>
> You probably didn't realize that lists _are_ vectors before this.
>
Nice to know.
> Hopefully this expected invitation to grilling will not result in severe
> burns. I note that one of the *apply family would
Thank you so much, Michael and Duncan. It worked.
Annie
On Thu, Aug 11, 2011 at 2:23 PM, Duncan Murdoch wrote:
> On 11/08/2011 3:11 PM, annie Zhang wrote:
>
>> Hi All,
>>
>> I have a 2-dim density defined on 0> formula of the density. How can I visualize it? What plot functions can I
>> use?
>>
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of R. Michael
> Weylandt
> Sent: Thursday, August 11, 2011 10:09 AM
> To: Srinivas Iyyer
> Cc: r-help@r-project.org
> Subject: Re: [R] help with loops
>
> No problem,
>
> By the wa
No problem,
By the way, you can't (or at least shouldn't) use return() outside of a
function -- that was the source of your old error message.
If you, for whatever reason, couldn't use unlist() you would write:
OurUnlist <- function(c, unique = F) {
if (!is.list(c)) return(c)
z <- NU
On 11/08/2011 3:11 PM, annie Zhang wrote:
Hi All,
I have a 2-dim density defined on 0
persp() or contour() are in the graphics package. There are similar
ones in lattice (and I think in ggplot2), but I forget their names.
There's also persp3d() in the rgl package for a rotatable version of
I'd suggest either a color plot as given by image() and related functions or
a 3d mesh-plot which you can get from persp()
E.g.,
x = seq(0,1,by=0.01); y = x
z = outer(x,y+1,"/") # z = x/(y+1) -- I know that's not a density but you
can adapt as necessary
filled.contour(x,y,z)
persp(x,y,z)
There
Hi All,
I have a 2-dim density defined on 0https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Is there a way of using weighted data with npcdensbw (in the np package)?
thanks
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide
Use factor -- puhleeze read the Help file therefor:
factor(x = character(), levels, labels = levels,
exclude = NA, ordered = is.ordered(x))
either an optional vector of labels for the levels (in the same order
as levels after removing those in exclude), or a character string of
length 1.
Prş, 2011-08-11 tarihinde 19:27 +0200 saatinde, Uwe Ligges yazdı:
>
> On 11.08.2011 19:22, David Winsemius wrote:
> >
> > On Aug 11, 2011, at 11:42 AM, Uwe Ligges wrote:
> >
> >>
> >>
> >> On 11.08.2011 16:10, zcatav wrote:
> >>> Hello R people,
> >>>
> >>> I have a "data.frame". Status variable h
On Wed, Aug 10, 2011 at 5:52 PM, Jean V Adams wrote:
> data.frame(lapply(x, function(y) if(is.numeric(y)) round(y, 2) else y))
>
Building on this, I came up with a 'data.frame' method for round().
I'm not sure how orthodox it is, but it seems to do the job as
intended:
round.data.frame <-
func
On Thu, Aug 11, 2011 at 4:58 PM, David Winsemius wrote:
>>> numVars <- sapply(iris, is.numeric)
>>> iris[numVars] <- lapply(iris[numVars], round, digits = 2)
>>> head(iris)
>>>
> Then drop the assignment operation and just print:
>
> ( lapply(iris[numVars], round, digits = 2) )
>
That's a nice cat
Am 11.08.2011 17:39, schrieb Uwe Ligges:
>
>
> On 11.08.2011 17:27, Bond, Stephen wrote:
>> Hello useRs,
>>
>> Pls help with removing a single interaction term from a formula:
>>
>> summary(
>> glm.turn.2<-
>> glm(cbind(turn.cnt,tot.cnt-turn.cnt)~sn+poly(relAge,2,raw=T)+termfac+rate:te
Hello
On Thu, Aug 11, 2011 at 4:34 PM, Martin Maechler
wrote:
> Well, as you say it's "View()" only, so why don't you just
> "view" the result of
>
> something like
> print(, digits = 2)
>
Unfortunately print(..., digits = 2) suffers of the same deficiencies
as format(..., digits = 2):
On 11/08/2011 1:33 PM, Duncan Murdoch wrote:
On 11/08/2011 12:01 PM, Kathie wrote:
> almost forgot. In fact, I want to generate correlated Poisson random vectors.
Saying you want two random variables to be correlated doesn't specify
the joint distribution, so there will be a lot of solutions.
Here is a simple method
z1 <- rpois(n,mu1)
z2 <- rpois(n,mu1)
z3 <- rpois(n,mu2)
Y <- z1 + z3
X <- z2 + z3
Cov(X,Y) = mu2, so Cor(X,Y) = mu2/(mu1+mu2)
albyn
On Thu, Aug 11, 2011 at 09:01:50AM -0700, Kathie wrote:
> almost forgot. In fact, I want to generate correlated Poisson random vectors.
>
On 11/08/2011 12:01 PM, Kathie wrote:
almost forgot. In fact, I want to generate correlated Poisson random vectors.
Saying you want two random variables to be correlated doesn't specify
the joint distribution, so there will be a lot of solutions. Here's
one, for the case where both variables
On Wed, Aug 10, 2011 at 5:52 PM, Jean V Adams wrote:
>
> As it says in
>
> ?format
>
> the digits argument specifies "... how many significant digits are to be
> used ... enough decimal places will be used so that the smallest (in
> magnitude) number has this many significant digits ..."
>
> In yo
On 11.08.2011 19:22, David Winsemius wrote:
On Aug 11, 2011, at 11:42 AM, Uwe Ligges wrote:
On 11.08.2011 16:10, zcatav wrote:
Hello R people,
I have a "data.frame". Status variable has 3 values. 0->alive,
1->dead and
2->missed
Status as a factor have correct levels. Levels and labels ou
On Aug 11, 2011, at 11:42 AM, Uwe Ligges wrote:
On 11.08.2011 16:10, zcatav wrote:
Hello R people,
I have a "data.frame". Status variable has 3 values. 0->alive, 1-
>dead and
2->missed
Status as a factor have correct levels. Levels and labels output as
follows;
levels(Adbf$status); la
almost forgot. In fact, I want to generate correlated Poisson random vectors.
Thank you anyway
--
View this message in context:
http://r.789695.n4.nabble.com/generate-two-sets-of-random-numbers-that-are-correlated-tp3736161p3736287.html
Sent from the R help mailing list archive at Nabble.com.
__
Hi Stefán
you might not to see the wood for the trees, but ?subset is a R function
as well.
MalesData <- subset(Datatemp,Datatemp$sex==1)
btw. your selection
> MalesData <- Datatemp[Datatemp $sex==1]
went wrong for two reasons:
(a) the extra space befor $
(b) incorrect indexing. Datatemp is a dat
On 03.08.2011 16:33, Diana Schwegler wrote:
Hello I am using the "step" function in order to do backward selection for a
linear model of more than 200 variables but it doesn't work correctly.
I think, there is a problem, if the matrix has same or more columns than
rows.
And if the matrix has too
Hi All,
I am trying to run cv.glmnet(x,y,family="multinomial", nfolds =4) and I only
have 8 observations and the number of features I have is 1000, so my x matrix
is 8 by 1000 and when I run the following, I get this error, I am not sure what
is causing this problem.
Error in predmat[which, ,
Thank you. that was very easy.
-srini
--- On Thu, 8/11/11, R. Michael Weylandt wrote:
From: R. Michael Weylandt
Subject: Re: [R] help with loops
To: "Srinivas Iyyer"
Cc: r-help@r-project.org
Date: Thursday, August 11, 2011, 12:49 PM
unlist()
Michael Weylandt
On Thu, Aug 11, 2011 at 12:46 P
On 11.08.2011 18:32, Eik Vettorazzi wrote:
Hi Stephen,
have a look at ?update.formula
glm.turn.3<-update(glm.turn.2,.~.-termfac1:rate)
No, "1" is a level of the variable "termfac" here.
Uwe Ligges
should do the trick.
hth.
Am 11.08.2011 17:27, schrieb Bond, Stephen:
Hello useRs,
Pls
This is extremely tricky since Windows does not always accept "//"
rather than "\\". Additionally, there is not implemented system call in
Windows, hence ?Sys.glob tells us a "partial emulation" is provided and
"An attempt is made to handle UNC paths starting with a double backslash."
As you h
1) Read about the changes to the colourspace in 2.13.0.
2) Try R-devel: it has compression for PDF files (or use a compressor
on your final pdf file, e.g. tools::compactPDF).
On Thu, 11 Aug 2011, Uwe Ligges wrote:
On 04.08.2011 13:44, eriksengewald wrote:
Dear R-Users,
I am using R for y
unlist()
Michael Weylandt
On Thu, Aug 11, 2011 at 12:46 PM, Srinivas Iyyer
wrote:
> hi I need help with list object.
>
> I have a list object
>
> > a <- c('apple','orange','grape')
> > b <- c('car','truck','jeep')
> > c <- list(a,b)
> > names(c) <- c('fruit','vehicle')
> > c
> $fruit
> [1] "appl
hi I need help with list object.
I have a list object
> a <- c('apple','orange','grape')
> b <- c('car','truck','jeep')
> c <- list(a,b)
> names(c) <- c('fruit','vehicle')
> c
$fruit
[1] "apple" "orange" "grape"
$vehicle
[1] "car" "truck" "jeep"
I want to write all the elements of this l
Hi,
Back in June I posted the message below, but had no replies. I've made a
little progress since then so this is to update anyone interested (!) and to
ask for comments.
Brief problem statement:
Under Windows, some parts of R don't handle UNC paths beginning with
backslashes. Specifically
a)
Hi Stephen,
have a look at ?update.formula
glm.turn.3<-update(glm.turn.2,.~.-termfac1:rate)
should do the trick.
hth.
Am 11.08.2011 17:27, schrieb Bond, Stephen:
> Hello useRs,
>
> Pls help with removing a single interaction term from a formula:
>
> summary(
> glm.turn.2 <-
> glm(cbin
On Thu, Aug 11, 2011 at 5:04 PM, Juliet Hannah wrote:
> I am trying to improve the look of an HTML table for a report (that
> needs to be pasted into Word).
> In the output, I would like to improve the justification of the
> numbers (or any other suggestion to make
> the HTML look nicer). The col
Using glm.fit
I can remove the unwanted column from model.matrix(glm.turn.2) manually and
then call glm.fit directly.
Q: how can I stuff the output from glm.fit into a regular glm object, so I can
use prediction functions, etc.?? the help does not describe how to use output
from glm.fit in the
On 04.08.2011 13:44, eriksengewald wrote:
Dear R-Users,
I am using R for years now but recently I encounter a problem with the
pdf-size of graphics generated with sweave. However, I am new in this forum.
Hence, please don't hesitate if I am wrong here.
I use a script which runs perfectly in R
2011/8/11 Chris Howden
> In that my distance matrix has too many entries for R's architecture to
> know how to store in
> memory
>
There was an multiv package with hierclust function and a bign option.
"Is n big? If storage is problemsome, a different implementation of the Ward
criterion may be
Please report to the package maintainer.
Uwe Ligges
On 11.08.2011 18:04, Juliet Hannah wrote:
I am trying to improve the look of an HTML table for a report (that
needs to be pasted into Word).
Here is an example.
table2<- structure(c(26L, 0L, 40L, 0L, 10L, 0L, 0L, 188L, 0L, 281L, 0L,
0L, 0L,
I am trying to improve the look of an HTML table for a report (that
needs to be pasted into Word).
Here is an example.
table2 <- structure(c(26L, 0L, 40L, 0L, 10L, 0L, 0L, 188L, 0L, 281L, 0L,
0L, 0L, 0L, 0L, 0L, 0L, 4L), .Dim = c(6L, 3L), .Dimnames = structure(list(
myvar = c("Don't know", "S
If you want random numbers sampled from the normal distribution, you
can use the mvrnorm function in MASS.
Best,
Ista
On Thu, Aug 11, 2011 at 8:23 AM, Kathie wrote:
> Dear R users
>
> I'd like to generate two sets of random numbers with a fixed correlation
> coefficient, say .4, using R.
>
> Any
Hi Laura,
On Thu, Aug 11, 2011 at 7:01 AM, Lali wrote:
> Hi everyone,
> I have a data frame that looks *sort of* like this:
>
> name <- letters[1:5]
> signal.1 <- c("12", "bad signal", "noise", "10", "X")
> length.signal.1 <- 5:9
> intensity.signal.1 <- 3:7
> signal.2 <- c("13", "noise", "19.2",
This sounds very much like a recursive problem: something like this seems to
get the gist of what you want.
DataSplits <- function(Data, alpha = 0.05) {
DataSplitsCore <- function(Data, alpha, level) {
tt <- t.test(Data[,1],Data[,2])
print(tt)
if (tt$p.value > alpha) {
On 11.08.2011 16:10, zcatav wrote:
Hello R people,
I have a "data.frame". Status variable has 3 values. 0->alive, 1->dead and
2->missed
Status as a factor have correct levels. Levels and labels output as follows;
levels(Adbf$status); labels(Adbf$status)
[1] "0" "1" "2"
[1] "1" "2" "3"
On 11.08.2011 17:27, Bond, Stephen wrote:
Hello useRs,
Pls help with removing a single interaction term from a formula:
summary(
glm.turn.2<-
glm(cbind(turn.cnt,tot.cnt-turn.cnt)~sn+poly(relAge,2,raw=T)+termfac+rate:termfac,data=fix,
family="quasibinomial")
Hello useRs,
Pls help with removing a single interaction term from a formula:
summary(
glm.turn.2 <-
glm(cbind(turn.cnt,tot.cnt-turn.cnt)~sn+poly(relAge,2,raw=T)+termfac+rate:termfac,data=fix,
family="quasibinomial")
)
Gives
Coefficients:
Hello R people,
I have a "data.frame". Status variable has 3 values. 0->alive, 1->dead and
2->missed
Status as a factor have correct levels. Levels and labels output as follows;
levels(Adbf$status); labels(Adbf$status)
[1] "0" "1" "2"
[1] "1" "2" "3" "4" "5" "6" "7" "8" "9" "1
*Dear R community*
* *
*I have two questions on data subsample manipulation. I am starting to use R
again after a long brake and feel a bit rusty.*
* *
*I want to select a subsample of data for males and females separately*
* *
library(foreign)
Datatemp <- read.spss("H:/Skjol/Data/HL/t1a
Hi Jeff, yes I can confirm that the xtabs solution does not work with the
original method.
Here's how it went:
HHum02 <- Hum02[1:30,] # select subset for demonstration purposes
> HHum02[1:5,]
CASW Btype Yr CO2Group NumVeh
170597 00CCFA CARS 2002C 2
170598 00CCFA CARS 2002
Well, without saying what sort of random numbers you mean, it's a little
hard, but here's one straightforward way to do it for 2 normally distributed
rvs.
X1 = rnorm(100)
X2 = rnorm(100)
Y = X1
Z = 0.4*X1+sqrt(1-0.4)*X2
then
cor(Y,Z) ~ 0.4
In function terms:
CorrNorm <- function(n=100, rho =
I want to implement the following algorithm in R:
I want to split my data, use a t test to compare both means of the groups to
see if they significantly differ from each other. If this is a yes (p < alpha)
I want to split again (into 4 groups) and do the same procedure twice, and
stop otherw
Or just read the R Data Import/Export manual that includes comments on
how to deal with Excel.
Best,
Uwe Ligges
On 11.08.2011 11:21, Petr PIKAL wrote:
Hi
In Excel, make sure that your data has a format that corresponds to an R
data frame (first row with column names, consistent column
On Aug 11, 2011, at 7:46 AM, Meier Dario wrote:
Hello All
I've just started to use RExcel instead of CMD Batches. But I don't
get
the console output to an data.frame and push to Excel.
With the CMD batch you got the console out relatively easy with
C:\LocalData\R\bin\R CMD BATCH --slave %
Works for me with JAGS 3.1.0.
Uwe Ligges
On 11.08.2011 14:09, David Wooff wrote:
There is a thread on this topic already:
http://finzi.psych.upenn.edu/Rhelp10/2010-August/250934.html
I'm rather mystified by a similar problem and wondering whether I've
overlooked something obvious. I'm running
Hi everyone,
I have a data frame that looks *sort of* like this:
name <- letters[1:5]
signal.1 <- c("12", "bad signal", "noise", "10", "X")
length.signal.1 <- 5:9
intensity.signal.1 <- 3:7
signal.2 <- c("13", "noise", "19.2", "X", "V")
length.signal.2 <- 2:6
intensity.signal.2 <- 1:5
signal.3 <- c
Dear R users
I'd like to generate two sets of random numbers with a fixed correlation
coefficient, say .4, using R.
Any suggestion will be greatly appreciated.
Regards,
Kathryn Lord
--
View this message in context:
http://r.789695.n4.nabble.com/generate-two-sets-of-random-numbers-that-are-co
Hello All
I've just started to use RExcel instead of CMD Batches. But I don't get
the console output to an data.frame and push to Excel.
With the CMD batch you got the console out relatively easy with
C:\LocalData\R\bin\R CMD BATCH --slave %rscript% %logfile%
to a file. But how can I get it to
There is a thread on this topic already:
http://finzi.psych.upenn.edu/Rhelp10/2010-August/250934.html
I'm rather mystified by a similar problem and wondering whether I've
overlooked something obvious. I'm running with latest versions of R and
all packages, and latest version of JAGS running und
On Aug 10, 2011, at 5:46 AM, Liviu Andronic wrote:
Hello
On Wed, Aug 10, 2011 at 11:41 AM, Dimitris Rizopoulos
wrote:
One approach is the following:
numVars <- sapply(iris, is.numeric)
iris[numVars] <- lapply(iris[numVars], round, digits = 2)
head(iris)
That's interesting, but still doesn
> Liviu Andronic
> on Wed, 10 Aug 2011 11:46:55 +0200 writes:
> Hello On Wed, Aug 10, 2011 at 11:41 AM, Dimitris
> Rizopoulos wrote:
>> One approach is the following:
>>
>> numVars <- sapply(iris, is.numeric) iris[numVars] <-
>> lapply(iris[numVars], round, d
Hello everyone,
I am trying to run a repeated measures Anova in R followed by some specific
contrasts on that dataset. So far I think the correct approach would be to use
Anova() from the car package.
Â
Lets illustrate my question with the example taken from ?Anova using the
OBrienKaiser data:
We
On Aug 11, 2011, at 8:24 AM, Michael Karol wrote:
Perhaps the split() function would do.
Something like split(dfrm, 1:nrow(dfrm)) or split(dfrm, rownames(dfrm))
--
Regards,
Michael
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org
] On B
Perhaps the split() function would do.
Regards,
Michael
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Jonathan Greenberg
Sent: Wednesday, August 10, 2011 10:36 PM
To: r-help
Subject: [R] Data frame to list?
R-helpers:
Is there
On Aug 11, 2011, at 3:38 AM, Peter Maclean wrote:
How do I move the legend from default position (right and within the
plot) to the "bottomleft" of the plot?
interaction.plot(YEAR, ID GROWTH, legend=TRUE, col = 2:7,xlab="Year",
ylim=c(0,2), ylab="Growth",leg.bty = "o")
You display t
Dear Veronika,
> I'm calculating matrix correlations with permutation tests and I got this
> funny result. All correlation coefficients are the same with mantel.test
> {ncf} and pcol {simba} but the two functions yield dramatically different
> p-values (using the same number of permutations). Co
On 08/11/2011 11:19 AM, Jesse Brown wrote:
I've run across what I think is a small bug in the plotrix package.
I've tried to contact the maintainer (Jim Lemon) directly but email is
returned 'undeliverable' at the provided address.
What is the best method to push a patch to a CRAN package in this
On 08/10/2011 06:38 PM, gavfung wrote:
Hi, I just started learning R, and one of the most frequent thing that I need
to calculate is cohen kappa in my psychology lab and I figure being able to
do inter rater reliability is a great way for me to explore R. There are
two different scenario in whic
Hi,
I am constructing a plotting function that I would like to behave like
plotting functions within the lattice package. It takes a "groups" argument,
which I process, and then I would like to pass that argument on to the
xyplot function for the actual plotting. However, what ever I do, get an
er
Hi
>
> In Excel, make sure that your data has a format that corresponds to an R
> data frame (first row with column names, consistent column size and data
type).
> Export your .XLS worksheet as .CSV file (mydata.csv).
> In R, read it into a data frame with
>
> > read.csv( "mydata.csv" )
Anot
Hi Justin,
In data.table 1.6.1 there was this news item :
oj's environment is now consistently reused so
that local variables may be set which persist
from group to group; e.g., incrementing a group
counter :
DT[,list(z,groupInd<-groupInd+1),by=x]
One of
In Excel, make sure that your data has a format that corresponds to an R data
frame (first row with column names, consistent column size and data type).
Export your .XLS worksheet as .CSV file (mydata.csv).
In R, read it into a data frame with
> read.csv( "mydata.csv" )
>From here, you shold be
On Thu, 11 Aug 2011, Jesse Brown wrote:
On Thu, Aug 11, 2011 at 12:09 AM, Rolf Turner wrote:
On 11/08/11 13:19, Jesse Brown wrote:
I've run across what I think is a small bug in the plotrix package.
I've tried to contact the maintainer (Jim Lemon) directly but email is
returned 'undeliverabl
How do I move the legend from default position (right and within the plot) to
the "bottomleft" of the plot?
interaction.plot(YEAR, ID GROWTH, legend=TRUE, col = 2:7,xlab="Year",
ylim=c(0,2), ylab="Growth",leg.bty = "o")
Peter Maclean
Department of Economics
UDSM
___
Dear all,
I'm calculating matrix correlations with permutation tests and I got this
funny result. All correlation coefficients are the same with mantel.test
{ncf} and pcol {simba} but the two functions yield dramatically different
p-values (using the same number of permutations). Could anyone
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