Mr McHaggis,
I'm not sure what " i'm having issues when it comes to reading my
data in rows rather than columns " means, but here's some thoughts on
your problem:
ExData <- structure(list(Noun = c(21L, 26L, 31L, 37L, 22L, 12L, 22L, 12L,
27L, 20L, 21L, 29L, 16L, 23L, 29L, 33L, 29L, 24L, 28L, 32L,
Try this:
shared <- vec3[ (vec3 %in% vec1) & (vec3 %in% vec2)]
Michael
On Sat, Oct 1, 2011 at 2:00 AM, Chris Conner wrote:
> Help-Rs,
>
> I've got three vectors representing participants:
>
> vec1 <-
> c(4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,
You might want to describe how your data is kept now so we can help
with the loading process, but in general, 4D arrays are loaded with
the same basic principles as 2D arrays (matrices).
If you are new to this kind of work in R, it sounds like you might
want to check out the Bioconductor lists for
Help-Rs,
I've got three vectors representing participants:
vec1 <-
c(4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81)
vec2 <- c
(1,2,3,4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60
I realize that this is terribly basic, but I just don't seem to see it at this
moment, so I would very much appreciate your help.
How shall I transform this dataframe:
> df1
Name Index Value
1 a 1 0.1
2 a 2 0.2
3 a 3 0.3
4 a 4 0.4
5 b 1 2.1
6 b
Hello: I am a novice R user, but I have been working my way through the
manuals / tutorials, ... I have R / Deducer up and running, and know the
basics.
I want to analyze a microarray (gene expression) dataset.
I need to input the data into R as a multidimensional (multi-way) array,
something on
Dear all,
I am confused with the output of survfit.coxph.
Someone said that the survival given by summary(survfit.coxph) is the
baseline survival S_0, but some said that is the survival S=S_0^exp{beta*x}.
Which one is correct?
By the way, if I use "newdata=" in the survfit, does that mean the su
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R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, r
Hi Jiang,
where did you get that definition of the Benjamini-Hochberg correction? That is
simply not how it works. You can take a look at the original paper, it is
available online
(http://www.math.tau.ac.il/~ybenja/MyPapers/benjamini_hochberg1995.pdf). You
can also look at the p.adjust functi
hey all, I'm just getting used to R and i'm having issues when it comes to
reading my data in rows rather than columns. any good advice would be much
appreciated !
here is the error:
> data1 <- read.table(file.choose(),header=T)
> x1 <- c(data1[1,1:5])
> shapiro.test(x1)
Error in sort.int(x, na.l
Dear listserv,
Please consider the following dataset:
x <- matrix(nrow = 8, ncol = 2)
colnames(matrix) <- c("classification", "soluble_fiber")
x[1:4,1] <- "bagel"
x[5:8,1] <- "donut"
How would I simulate a dataset for a one-way fixed-effect ANOVA (where
"classification" is the treatment variabl
have a piecewise function which takes a constant value for x greater than
some point.
It looks like this:
y<-function(x,a){
if (xhttp://r.789695.n4.nabble.com/Regarding-the-optimize-function-tp3861257p3861257.html
Sent from the R help mailing list archive at Nabble.com.
_
I had the same problem on Windows and I was only a "regular administrator".
However, going to properties of the Rprofile.site and setting the file's
all privileges for regular users fixed the problem. Tinn R was able to
confiure the environment permanently.
--
View this message in context:
http
Thanks, that kind of helps. However, some of my previous code uses functions
like heatmap.2 which has multiple images (legend/color key) as well as the
actual heatmap. Employing useRaster=TRUE here only applies to the heatmap and
not the legend. Not a huge deal. Is there anyway to set an opt
On Sep 30, 2011, at 2:10 PM, Mike Gibson wrote:
I can't figure out how to add tick marks on both my X and Y axis.
For example, my X axis ranges from 0 to 1 and there are both a tick
mark and a number label at the X-axis values of 0.2,0.4,0.6. and
0.8. I want to add tick marks to the fi
2011/9/12 Göran Broström
> Dear Ehsan,
>
> the cluster option is not implemented in 'eha', although you obviously get
> no error if trying
> I'll fix this. Thanks for the report. (So, use 'coxph' with cluster).
>
> Actually, there is nothing to fix; the cluster function works like the
ident
Hi,
There is a question that I am confused.
I have a set of data like this:
hsa-miR-205--GATA30.797882767 1.08E-13
hsa-miR-205--ITGB4 0.750217593 1.85E-11
hsa-miR-187--PGF0.797604155 3.24E-11
hsa-miR-205--SERPINB5 0.744124886 3.28E-11
hsa-miR-205--PBX1 0.734487224 7.89E-11
hsa-mi
Just for the record, following Bill Dunlap's advice, I think this is
the best answer to the question as originally posed is.
myfun <- function(vec, i=stop("'i' must be supplied")){
vec[i]
}
> myfun(1:40,10)
[1] 10
> myfun(1:10)
Error in myfun(1:10) : 'i' must be supplied
>
--
Paul E. Johnson
P
Someone already suggested that you use match(),
which does what I think you want. Read its help file
for details.
> A <- seq(1,113,4)
> match(c(9, 17, 18), A)
[1] 3 5 NA
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
From: Alaios [mailto:ala...@yahoo.com]
Sent: Friday, September 30, 20
Thanks a lot! This works.
Now I want to do the opposite
let's say that I have one sequence
for example
check in image
http://imageshack.us/photo/my-images/4/unleduso.png/
column A (this is a seq(1,113,4)
and I want when I get the number 9 to say that this is the third number in the
seq (1,113,4
I don't have access to older versions of R right now, but if you have a recent
install you are probably running 2.13.1 or 2.13.0. Can you run the following:
X <- list(a= rnorm(5), b= rnorm(5))
sapply(X, min)
?
sapply calls simplify2array() so if this works take a look at the code for
sapply (j
On 9/30/2011 8:31 AM, Durant, James T. (ATSDR/DTEM/PRMSB) wrote:
Happy Friday fellow R users.
I need some help - I am trying to make a graph using ggplot 2 of some lead isotope
ratios. Normally, the isotope mass number appears as a superscript before the chemical
symbol. However, I cannot fig
On 30/09/2011 2:07 PM, Jim Cheng wrote:
Hi,
How do I use a function inside a regression formula? When I tried to use
min() function inside a regression formula, I ran into errors. Here are
the commands to reproduce the error:
mydata<- read.csv(url("http://www.ats.ucla.edu/stat/r/dae/binary.
I can't figure out how to add tick marks on both my X and Y axis. For example,
my X axis ranges from 0 to 1 and there are both a tick mark and a number label
at the X-axis values of 0.2,0.4,0.6. and 0.8. I want to add tick marks to the
figure at every 0.1 value. This will help a viewer deter
This may be a simple misunderstanding on my part, but I need help
understanding what POT is plotting. I'm trying to analyze a few different
datasets. If my dataset covers 500 years, but I have 60 points above my
threshold, what should be plotted as the (empirical) return period for the
largest valu
Thank you Michael.
I think my initial problem may have been due to a 'clerical error' upriver,
so I appreciate you taking the time to give me this help.
Unfortunately, my version of R does not contain simplify2array() and does
not find it in help (?simplify2array) - which is strange because I jus
Hi,
How do I use a function inside a regression formula? When I tried to use
min() function inside a regression formula, I ran into errors. Here are
the commands to reproduce the error:
mydata <- read.csv(url("http://www.ats.ucla.edu/stat/r/dae/binary.csv";))
attach(mydata)
names(mydata)
m
On 9/29/2011 8:14 PM, Jp zhu wrote:
I am a new R user. I trying to install a package all Matching but failed.
Here is the error msg.
install.packages("Matching", dependencies=TRUE)
Installing package(s) into ‘C:/Users/jzhu/Documents/R/win-library/2.13’
(as ‘lib’ is unspecified)
--- Please selec
>From ?image
" Images for large z on a regular grid are more efficient with useRaster
enabled and can prevent rare anti-aliasing artifacts, but may not be
supported by all graphics devices. "
Adding useRaster=TRUE to the two image() calls gets rid of the white grid
lines.
-Original Message--
On 9/29/2011 8:11 PM, wirichada wrote:
Dear R users,
I am trying to do the forest plot follow the function given on web. However,
the order of the tests has been sorted alphabetically. I would prefer
keeping the order as data frame input so that I can group and compare (from
the graph) the targe
On Fri, Sep 30, 2011 at 4:31 PM, Durant, James T. (ATSDR/DTEM/PRMSB)
wrote:
> Happy Friday fellow R users.
>
> I need some help - I am trying to make a graph using ggplot 2 of some lead
> isotope ratios. Normally, the isotope mass number appears as a superscript
> before the chemical symbol. Ho
First, we strongly recommend 64-bit R. Otherwise, you may not be able
to scale up as far as you would like.
Second, as I think you realize, with big objects you may have to do
things in chunks. I generally recommend working a column at a time
rather than in blocks of rows if possible (better per
is.element(myvector, seq(1,800,4))
or, if you like typing percent signs,
myvector %in% seq(1,800,4)
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of Alaios
> Sent: Fr
On Sep 30, 2011, at 2:16 AM, Petr PIKAL wrote:
David,
thank you for your reply
I tried this
attach(mtcars)
interaction.plot(cyl, gear, mpg, type="o", pch=5:8, lty=1 )
but I got this error:
Error in match.arg(type) : 'arg' should be one of "l", "p", "b"
and in ?interaction.plot, "o" it is no
Suppose that I'm working on Hadley's diamond dataset and I want to
review the relationship between price, colour and carat.
I might run the following:
library(ggplot2)
#plot scatter and add some hex binning
q<-qplot(carat,price,data=diamonds, geom=c("hex"),
main="Variability of
Hi, I'm no longer on the subscribing list, but was hoping to get my question
posted. Please inform if this is ok, although I am guessing you wont post with
the image below. If so, let me know and I will resend without the image.
Thanks
Hi,
I just upgraded my system and my version of R all a
R-listers,
My colleagues and I are working on wind roses using station
information and we have a question regarding the plotting of rings of
the wind rose (see attached for example).
What we would like to do is to add an extra frequency ring to the wind
rose, so it goes up to 15% for instance and
Thank you for the "obvious" help - I already saw this thread. But I thought
this described the "standard" reflection method (which I managed to implement).
In my case, I want to achieve a NEGATIVE reflection which is *not* the same as
the method where you simply reflect the data, estimate the de
I'm about to add weights to a bus on-board survey dataset with ~150 variables
and ~28,000 records. My intention is to weight (for each bus "run") by
boarding stop and alighting stop. I've seen the Rake function of the Survey
package, but it seems that converting to a "svydesign" might be exces
> 5 %in% seq(1,800,4)
[1] TRUE
> 4 %in% seq(1,800,4)
[1] FALSE
or
> is.element(5, seq(1,800,4))
[1] TRUE
> is.element(4, seq(1,800,4))
[1] FALSE
Sarah
On Fri, Sep 30, 2011 at 12:25 PM, Alaios wrote:
> Dear all,
> I have a vector with number that some of them are part of the
>
> seq(1,800,4).
On Sep 30, 2011, at 12:25 PM, Alaios wrote:
Dear all,
I have a vector with number that some of them are part of the
seq(1,800,4). How can I check which of the numbers belong to the
seq(1,800,4)
LEt's say that is called myvector the vector with the numbers.
Is there in R something like this
The error message was:
! LaTeX Error: File `test-003.tikz' not found.
So I'm wondering how your StatET tried to compile the tex file,
especially what was its working directory.
Anyway, I recommend you to turn off the compilation to PDF in
pgfSweave() so that it only generates the tex file, and t
Dear all,
I have a vector with number that some of them are part of the
seq(1,800,4). How can I check which of the numbers belong to the seq(1,800,4)
LEt's say that is called myvector the vector with the numbers.
Is there in R something like this?
is.member(myvector,seq(1,800,4))
I would like
On first glance it seems like it should work, perhaps a minimal
working example would help.
Also, if logictoReduce is a boolean vector, you probably don't need to
test for equality with TRUE; if that test seems necessary (i.e., if
Overloads <- Overloads[logictoReduce] doesn't work) that may be tie
Happy Friday fellow R users.
I need some help - I am trying to make a graph using ggplot 2 of some lead
isotope ratios. Normally, the isotope mass number appears as a superscript
before the chemical symbol. However, I cannot figure out how to do this
ggplot2's axis labels. The closest I have c
On Sep 30, 2011, at 10:14 AM, Duncan Murdoch wrote:
On 30/09/2011 10:00 AM, David Winsemius wrote:
On Sep 30, 2011, at 4:50 AM, sreblam wrote:
> Hi!
> I'm trying to implement in R in an easy way the negative
reflection
> method
> described in Silverman (1986) on p.31, ie I have a non-n
Dear R users,
two quick questions about MCMCpoissonChange of the MCMCpack:
1. my data is stored into a vector (e.g. my_data), and as input for
MCMCpoissonChange I need either a formula or a data frame.
If I simply transform my vector to a data frame with data.frame(my_data), it
does not work.
If
On Sep 30, 2011, at 10:14 AM, Duncan Murdoch wrote:
On 30/09/2011 10:00 AM, David Winsemius wrote:
On Sep 30, 2011, at 4:50 AM, sreblam wrote:
> Hi!
> I'm trying to implement in R in an easy way the negative
reflection
> method
> described in Silverman (1986) on p.31, ie I have a non-n
Dear all,
I would like to put these two lines together
logictoReduce<-((Overloads-1)%%FreqN)==(SpanIndex-1) #0...3 refer to sub spans
1 to 4
Overloads<-Overloads[logictoReduce==TRUE]
and do it like this
Overloads<-Overloads[((Overloads-1)%%FreqN)==(SpanIndex-1)]
which does not seem to work.
Dear R-users,
The following warning messages are displayed when I require a new package
that I am currently developing. Everything seems to work just fine though,
so I am wondering how to get rid of the warnings.
Warning messages:
1: Class "frame" is defined (with package slot 'kiwixposepreprod')
Dear Luc,
IMHO a multinomial mixed model is appropriate for your data. It allows you to
model tree species with bird id and period as covariates. Have a look at the
vignette of the MCMCglmm package. You will find an example on hornets.
Best regards,
Thierry
PS R-sig-mixed models is a better l
On Fri, 30 Sep 2011, Rosario Garcia Gil wrote:
I have a data set with fixed and random effects, therefore I am using the lme
function:
Rosario,
Allow me to recommend reading "Mixed Effects Models and Extentions in
Ecology with R" by Zuur, et al. There are (potentially) serious limitations
On Sep 30, 2011, at 4:47 AM, maxbre wrote:
here is an alternative long and winded solution to the problem
sticking on
the julian function of chron package
test$year <- as.integer(as.character(test$date, "%Y"))
test$month <- as.integer(as.character(test$date, "%m"))
test$day <- as.integer(as.
On 30/09/2011 10:00 AM, David Winsemius wrote:
On Sep 30, 2011, at 4:50 AM, sreblam wrote:
> Hi!
> I'm trying to implement in R in an easy way the negative reflection
> method
> described in Silverman (1986) on p.31, ie I have a non-negative
> dataset and
> would like to estimate the densi
On Sep 30, 2011, at 4:50 AM, sreblam wrote:
Hi!
I'm trying to implement in R in an easy way the negative reflection
method
described in Silverman (1986) on p.31, ie I have a non-negative
dataset and
would like to estimate the density by applying a reflection method
where the
reflected po
Without seeing cvm1_list, I can't guarantee this will work, but consider this:
testList = list(rnorm(500), rnorm(500), rnorm(500), rnorm(500), rnorm(500))
testMat = simplify2array(testList)
covTest = cov(testMat)
Running your code works on my testList, so I can't help there without
a reproducible
Hi Duncan,
I use Eclipse and StatET plus TexClipse and Sweave which comes with the
StatET package.
So fore me it is basically one click as well to produce the pdf from the
.Rnw file.
I installed the MacTex live 2011 version on my computer and thought it might
actually be
easy to find out how and
If there is an ONLINE mechanism, I will donate.
j
Joshua Wiley wrote:
> Dear R Users,
>
> I know issues like this have come up in the past. I am wondering how
> many people would be interested in an online mechanism for donating to
> the R Foundation or for becoming supporting members. Right
Michael Weylandt wrote:
>
> I'm not entirely sure how these two objects are related. Perhaps give a
> little more information on the transform and we can help with
> implementation...
>
Ok, I have got 2 matrices [P,I] and [I,E].
testcontents [P,I]:
structure(list(P = structure(c(1L, 1L, 1L, 2L
Hello
I have a data set with fixed and random effects, therefore I am using the lme
function:
lm(y ~ xfixed, random=~1|xrandom, data)
After this I want to get the F-values for both the fixed and random predictors.
I can easily get the F-value and df for the xfixed predictors (anova()), but
ho
Hi zoe,
it's easy in a spreadsheet to calculate the p-value; estimates/stand.error =
1.96>5%<-1.96
for the asymmetry you must use:
model=mGJR.est(eps1=#1, eps2=#2, order=c(1,1,1))
mvBEKK.diag(model)
cheers
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Am 30.09.2011 11:30, schrieb Alaios:
Dear all,
I have a numeric vector that contains indices.
I also have two matrices of [1,m] dimension and of [m,n] dimension.
I want for every indexto remove the current element from the [1,m] vector an
the row from the [m,n] matrix.
How I can do that efficie
Hello,
I am very new to R (as my Subject probably indicates).
I want to do something that should, I think, be very simple. I have five
vectors in a list and I want to construct a covariance matrix out of them.
Given a 5X5 matrix cvm1, and the list of vectors, cvm1_list, I thought the
following w
On Fri, Sep 30, 2011 at 3:01 AM, Kang Min wrote:
> Hi all,
>
> I was wondering if there's an equivalent to par(new=T) of the plot
> function in lattice. I'm plotting an xyplot, and I would like to
> highlight one point by plotting that one point again using a different
> symbol.
>
> For example, w
On 30/09/2011 8:03 AM, syrvn wrote:
Let's say I have written the following tiny .Rnw file:
_
\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{Sweave}
\usepackage{tikz}
\usepackage{pgf}
\begin{document}
<<>>=
sessionInfo()
@
\end{doc
We have data on habitat use of a bird species (30 radio-tracked individuals).
We followed each bird every day for ~45 min for 6 weeks. We recorded a
number of things, each minute (a device would beep every minute and we would
write down a number of variables). I recorded for example at what kind of
Let's say I have written the following tiny .Rnw file:
_
\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{Sweave}
\usepackage{tikz}
\usepackage{pgf}
\begin{document}
<<>>=
sessionInfo()
@
\end{document}
___
On Fri, Sep 30, 2011 at 5:43 AM, Jan Wijffels wrote:
> Hi R-helpers
>
> I'm looking for a vectorised function which does missing value replacement
> as in last observation carried forward in the zoo package but instead of a
> locf, I would like the locf function to add +1 to each time a missing va
On Fri, Sep 30, 2011 at 4:47 AM, maxbre wrote:
> here is an alternative long and winded solution to the problem sticking on
> the julian function of chron package
>
> test$year <- as.integer(as.character(test$date, "%Y"))
> test$month <- as.integer(as.character(test$date, "%m"))
> test$day <- as.i
Dear Joshua and others,
Please excuse the slow response, but I wanted to consult other R Foundation
members before answering.
The R Foundation is coincidentally discussing fund-raising and the use of funds
that are raised by the Foundation. There are costs associated with keeping R
going, such
Hi:
One way is to create a vector of pch values that you can pass into xyplot, e.g.,
dd <- data.frame(x = 1:10, y = 1:10, pch = c(rep(1, 5), 16, rep(1, 4)))
library('lattice')
xyplot(y ~ x, data = dd, pch = dd$pch, col = 1)
HTH,
Dennis
On Fri, Sep 30, 2011 at 12:01 AM, Kang Min wrote:
> Hi all
On Fri, 30 Sep 2011, Martin Batholdy wrote:
Hi,
I currently running regression models on an experimental dataset.
The model contains one independent continuous variable and two
independent experimental conditions (one with two factors, the other
with three factors) and several covariates.
Try this. As you did not supply a reproducible example my code is untested:
1.m.vector[index.vector] <- NULL
or
new.1.m.vector <- 1.m.vector[- index.vector]
Someting equivalent is possible for the matrix.
HTH
Jannis
On 09/30/2011 11:30 AM, Alaios wrote:
Dear all,
I have a numeric vector th
Hi
I'm creating a sweave (Rnw) from R and running the r code inside the
sweave and then creating report from sweave file using R.
If any error occurs in the running R code inside the sweeve file. it should
stop entire R process itself
Please help me to solve this
--
View this message in cont
here is an alternative long and winded solution to the problem sticking on
the julian function of chron package
test$year <- as.integer(as.character(test$date, "%Y"))
test$month <- as.integer(as.character(test$date, "%m"))
test$day <- as.integer(as.character(test$date, "%d"))
test$hour <- as.integ
i want to use getdata function in sampling package. but if in the vector of
index i write only 1( thats what i need) it gives the entire dataframe.(but
instead of 1 if i give 2 or 3 it extracts the information corresponding to
those indices).can anyone please help me?
--
View this message in con
Hi,
I am trying to fit all subsets for a vector autoregression with exogenous
variables. I have been looking at the 'leaps' function but I not sure how
to get it to work when lags for each variable are included in the model. I
would be really appreciative if someone could provide some links to
e
sorry, I managed to find the solution at last
(by reading the help but sometime is really difficult!)
Class "POSIXlt" is a named list of vectors representing
yday
0–365: day of the year.
another lesson learned
bye
--
View this message in context:
http://r.789695.n4.nabble.com/julian-day-for
Thanks a lot !
At the end I found that the problem was in the data input. Once I normilized
the data input to use the chord distance as measure of dissimilarity
gaps_flor_norm<-decostand(gaps_flor, "norm"), then I run the nMDS several
times comparing them through procrustes
plot(procrustes(gap_f
Hi!
I'm trying to implement in R in an easy way the negative reflection method
described in Silverman (1986) on p.31, ie I have a non-negative dataset and
would like to estimate the density by applying a reflection method where the
reflected points have weight -1.
I thought there should be a way to
Hi all,
I was wondering if there's an equivalent to par(new=T) of the plot
function in lattice. I'm plotting an xyplot, and I would like to
highlight one point by plotting that one point again using a different
symbol.
For example, where 6 is highlighted:
plot(1:10, xlim=c(0,10), ylim=c(0,10))
pa
Hi R-helpers
I'm looking for a vectorised function which does missing value replacement
as in last observation carried forward in the zoo package but instead of a
locf, I would like the locf function to add +1 to each time a missing value
occurred. See below for an example.
> require(zoo)
> x <-
Dear list,
I ran a conditional frailty model with an interaction term (see below). To
interpret the interaction term, I would like to produce plots that reflect
how does a moderator variable (ecogr) shape the effect of the other
interacted variable (elderly).
condfrailty.gamma.em <-coxph(
Hi:
This would be a lot easier to check with a reproducible example, but
here's a simplified version of your problem:
testd <- data.frame(gps = rep(c("ADHALP","ADLCON","ADLARC","BDALAT","BDPARC"),
each = 15),
trt = rep(LETTERS[1:3], each = 5),
Hi,
I currently running regression models on an experimental dataset.
The model contains one independent continuous variable and two independent
experimental conditions (one with two factors, the other with three factors)
and several covariates.
Now I get different results for a covariate in t
Dear all,
I have a numeric vector that contains indices.
I also have two matrices of [1,m] dimension and of [m,n] dimension.
I want for every indexto remove the current element from the [1,m] vector an
the row from the [m,n] matrix.
How I can do that efficiently in R? So to say not have a for loo
On 29.09.2011 22:38, Ben qant wrote:
Hello,
Why does rm.outlier produce a list for me? I know its something about my
data because I can't make a mock up that reproduces the issue.
Any ideas? My data goes in as a matrix and comes out as a list:
class(dat)
[1] "matrix"
str(dat)
would be mo
On Sep 30, 2011, at 08:32 , Mario Valle wrote:
> Not reproducible.
> Could you please attach the dataset
>
> QInflAvgbyPlot
>
> Otherwise I don't see anything obviously wrong here.
> Ciao!
>mario
>
> On 30-Sep-11 01:37, kelseyann wrote:
>> SiteSpp<-
>> c("ADHAL
The byte pixies have rolled up R-2.13.2.tar.gz at 9:00 this morning. This is
intended to be the final release of the 2.13 series, for the benefit of those
apprehensive of putting 2.14.x into production use.
The run-in for 2.14.0 starts on Monday, with a planned release on Oct 31 (The
Great Pum
Hi Chris,
why not using routines for dates
dates <- c("09/10/2003", "10/22/2005")
format(strptime(dates,format="%m/%d/%Y"),"%Y")
or take just the last 4 chars from dates
gsub(".*([0-9]{4})$","\\1",dates)
cheers
Am 29.09.2011 16:23, schrieb Chris Conner:
> Help-Rs,
>
> I'm doing some string man
Hi,
yes, I had a look at pgfSweave package and realised that it uses texi2dvi to
compile the pdf file.
I tried so much last night again that I am not entirely sure whether it is
the same Rnw file or not.
I just deleted everything and created a new R-project including a tiny
example. I also
inclu
Dave, your situation is clearer now. You wrote (see the full context at
the end of the message):
> From this, you will see that I have 4 control sites and 7 treatment
> sites that are measured each week. All 13 locations have different
> names, and Location is a random varaible. Is Location n
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