On 04/10/11 17:05, R. Michael Weylandt wrote:
SNIP
More importantly, as I said in my initial response, any distance
metric worth its salt is translation invariant.
SNIP
Point of order, Mr. Chairman. (This is really *toadally* off topic;
my apologies, but I couldn't resist --- I trained as a
On Oct 3, 2011, at 21:25 , Mao Jianfeng wrote:
Dear Peter,
I am glad to hearing your reply. That is really nice. Thanks a lot.
###
# (1) the problem of the plot venneuler generated me is sets (A,B,C,D,E,F)
should shared 69604 elements.
# But,
Stylish, but ifelse only includes a cumsum less or equal than v and ignores the
remainder, if v does not fit equally in say the first two weight buckets.
R - c(1.2, 1.3, 1.5)
W - c(3,2,5)
my_cumsum(4, R, W) # should take 3*1.2 + 1*1.3
[1] 4.0
sum(ifelse(cumsum(W) = 4, W, 0) * R) # ignores
?plot
?points
You will probably need to get some R basics down as to how to index certain
subsets of your data. This you find in any introductory R manual.
HTH,
Daniel
--
View this message in context:
please help..
I have estimate the value of parameter for AR,MA and fractional d.but I have
problem on having the right command for forecasting ARFIMA model.please
help..
--
View this message in context:
On 2011 Oct 3, at 4:55 PM, Joshua Ulrich wrote:
ts requires a time-based index, so there's no way to make an index
year-free. What you can do, is split the xts object into years,
convert all the index values to have the same year, and merge them
together.
Ah... of course. I had read the
Have two sets of scatterplot data
hypothetically
a) stem lenght vs number of petals in red flowers
b) stem lenght vs number of petals in white flowers
want to place on same scatter plot with same x,y axis but different collored
markers
How do I do this in R
--
View this message in context:
Hi users!
I am fitting a model with several factor variables as independents using
svm. since there are lots of categorical variables,the training and test
data sets have been created using dummy.data.frame option from dummies
package. I have a factor A in the training data set with 2 levels
I have not read the manual, but I drew 1 random normal vectors and 1
random Poisson vectors of length 1 and was unable to reproduce this
behavior. Can you provide an example (self-contained code) that reproduces
this problem?
Thanks,
Daniel
Jeanne M. Spicer wrote:
The summary
Any comments are very welcome,
So I give it a shot, although I don't have answers but only some ideas which
avenues I would explore, not being an
expert at all:
1. I would try to be more restrictive with the columns used for merge, trying
something like
m1 - merge( x, y, by.x = V1, by.y = V1,
I'm new to R and I'm working on point shapefiles. Is there a way that you could
interpolate a shapefile via kriging in R using an attribute? All examples on
the internet are using txt files and CSVs. Thanks a lot.
[[alternative HTML version deleted]]
Correction to my previous mail: my_cumsum(4,R,W) does not return 4.0, it
returns 4.9!
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of fernando.cabr...@nordea.com
Sent: 4. oktober 2011 08:37
To: r-help@r-project.org
Subject: Re:
On Tue, Oct 4, 2011 at 12:40 AM, Rainer Schuermann
rainer.schuerm...@gmx.net wrote:
Any comments are very welcome,
So I give it a shot, although I don't have answers but only some ideas which
avenues I would explore, not being an
expert at all:
1. I would try to be more restrictive with the
On 04/10/11 19:58, Daniel Malter wrote:
I have not read the manual, but I drew 1 random normal vectors and 1
random Poisson vectors of length 1 and was unable to reproduce this
behavior. Can you provide an example (self-contained code) that reproduces
this problem?
The OP *did*
Joshua Wiley jwiley.ps...@gmail.com wrote in message
news:canz9z_kopuwkzb-zxr96pvulhhf2znxntxso9xnyho-_jum...@mail.gmail.com...
On Tue, Oct 4, 2011 at 12:40 AM, Rainer Schuermann
rainer.schuerm...@gmx.net wrote:
Any comments are very welcome,
3. If that fails, and nobody else has a better
Assuming you can install other packages ok, data.table depends on
R =2.12.0. Which version of R do you have?
_If_ that's the problem, does anyone know if anything prevents
R's error message from stating which dependency isn't satisfied? I think
I've seen users confused by this before, for other
On 10/04/2011 07:48 AM, Leynnard Rey Matillano wrote:
I'm new to R and I'm working on point shapefiles. Is there a way that you
could interpolate a shapefile via kriging in R using an attribute? All
examples on the internet are using txt files and CSVs. Thanks a lot.
[[alternative HTML
On 10/04/2011 06:19 AM, jricci wrote:
Have two sets of scatterplot data
hypothetically
a) stem lenght vs number of petals in red flowers
b) stem lenght vs number of petals in white flowers
want to place on same scatter plot with same x,y axis but different collored
markers
How do I do
Hi everybody
I have a questionnaire with a lot of questions that allow for more than one
option to be chosen (like a tickbox in a html form). The data captured on a
mobile device and is supplied in a format where every option is a separate
variable (logical). I want to develop a generic function
See para 10.3.2 'Identifiers' in the R language definition (always distributed
with R in the html help system), or ?make.names, for a concise statement of
what constitutes a valid variable name in R.
It's actually underscores that might give trouble with older versions, not '.'.
But they'd
saber fallahpour s_fallahpour at yahoo.com writes:
Hi
I want to do simulation on quasi-binomial distribution with some covariates.
Does anyone have an idea how to do that?
There is no such thing as a quasi-binomial distribution, but if you
parameterized the beta-binomial distribution
Dear R forum
I have two datafarmes with category and cat_val forming one dataframe and cust
and cust_category forming another dataframe.
category = c(C, D, B, A)
cat_val = c(0.10, 0.25, 0.40, 0.54)
cust = c(cust_1, cust_2, cust_3, cust_4, cust_5, cust_6, cust_7,
cust_8, cust_9, cust_10)
Hi
Dear R forum
I have two datafarmes with category and cat_val forming one dataframe
and
cust and cust_category forming another dataframe.
category = c(C, D, B, A)
cat_val = c(0.10, 0.25, 0.40, 0.54)
cust = c(cust_1, cust_2, cust_3, cust_4, cust_5, cust_6,
cust_7, cust_8, cust_9,
Will this do it for you:
x - readLines(textConnection(A,B,C
+ B,B
+ A,AA,C
+ A,B,BB,BBB,B,B))
closeAllConnections()
x.s - strsplit(x, ',')
# determine max length
x.max - max(sapply(x.s, length))
# create character matrix
x.mat - matrix(
+ sapply(x.s, function(a) c(a, rep(NA, x.max -
Hello,
I am working on a big R project using Eclipse/StatET/Texlipse. I'd like to
write a Latex document within that project but DO NOT want to Sweave it.
It's pure Latex. Via the external tools configurations I set up 2 different
versions to ensure that my latex document is processed correctly.
Hello,
I wrote a function in C, which works fine if called from the
main-function in C.
But as soon as I try to call this function from R like .C('foo',
as.double(x), as.integer(y)), the programm crashes.
I created a dll with the cmd command R --arch x64 CMD SHLIB foo.c and
loaded it into
Hi,
forgive me if someone has already posted about this but I have had a look and
cannot find the answer, also I am very new to R and been getting the grips with
this.
I have been trying to use Adonis to find out if there are significant
difference between groups on data that I have analyses
Dear all,
propably this question sounds stupid to you, but since I'm new to R I got
some troubles regarding the following issue (The table below does not
represent my real data, it is just a simplified example):
My intention is to first subdivide my data into several groups of vectors,
First of all, I have GAMs
noxd-gam(newNOX~pressure+maxtemp+s(avetemp,bs=cr)+s(mintemp,bs=cr)+s(RH,bs=cr)+s(solar,bs=cr)+s(windspeed,bs=cr)+s(transport,bs=cr),family=gaussian
(link=log),groupD,methods=REML)
Then I type summary(noxd). and show
Family: gaussian
Link function: log
Formula:
Hello,
i trying to create a package using package.skeleton. I use R.oo package to
create oriented-object classes. When i use package.skeleton, this creates
the following file:
classA -
structure(function()
{
extend(Object(),Class A,
Hello,
I've been facing a really stupid problem... When I try to plot using
heatplot or hclust or any similar function, the labels of the x-axis - which
are the samples names - are giant overlapping. I can't even read the
samples names!
I tried cex.lab = 0.5, it helped only with the y axis and
Dear R-help
Can anyone tell me why my curve appears the wrong way round on a rug plot?
I am using the same code as on pg 596 of the Crawley R-book.
mod-glm(mort~logBd,binomial)
par(mfrow=c(2,2))
xv-seq(0,8,0.01)
yv-predict(mod,list(logBd=xv),type=response)
plot(logBd,mort)
lines(xv,yv)
I've tried
Dear R helpers
I would like to plot a string of points as a polygon in xyplot. I'm a bit
lost as to how to get the points plotting in the correct order. I would
also like some hints on how to render or fill the polygon.
Scrpt below and data file attached
Thanks
Markm
library(lattice)
# set
Yes, your code did exactly what I needed.
Thank you!!
-f
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Ok I added quoting and it did work...Not sure why, but thank you for both
your replies!
-f
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Dear all,
I have a directed graph - an Igraph to be more precise - which has some
vertices attributes (like dorm, year etc). Edges and the graph itself do not
have any attributes. Based on the attributes of the vertices, I'd like to
calculate correlation among the edges (e.g. how likely people of
Sorry---I thought it worked but I think I am actually definitely doing
something wrong...
The problem might be that there are NA's and there are also duplicated
values...My fault. I can't figure out what is going wrong...
I'll be more thorough and modify the two df to mirror more what I have to
You are right, but this is difficult or impossible to really solve.
The problem is that summary() is an S3 generic(?UseMethod) -- so essentially
it can mean anything and do anything depending on the structure to which
it's applied. In your case, the structures were a data frame and a vector
(that
markm0705 markm0705 at gmail.com writes:
I would like to plot a string of points as a polygon in xyplot. I'm a bit
lost as to how to get the points plotting in the correct order. I would
also like some hints on how to render or fill the polygon.
Scrpt below and data file attached
Thanks
On 04/10/2011 6:40 AM, pedabreu wrote:
Hello,
i trying to create a package using package.skeleton. I use R.oo package to
create oriented-object classes. When i use package.skeleton, this creates
the following file:
classA-
structure(function()
{
extend(Object(),Class
On Mon, Oct 3, 2011 at 12:24 PM, Thomas Adams thomas.ad...@noaa.gov wrote:
I'm interested in creating a graphic -like- this:
c - ggplot(mtcars, aes(qsec, wt))
c + geom_point() + stat_smooth(fill=blue, colour=darkblue, size=2, alpha
= 0.2)
but I need to show 2 sets of bands (with different
Hi R-Users,
I posted this question a while ago on the bioconductor mailing list but got no
answers. Maybe here is somebody who might know a solution:
I failed at drawing multiple filters in a densityplot() using the
FlowCore/FlowViz packages.
I
found a way to draw multiple filters in
?? Use the appropriate panel function, not panel.xyplot().
If you don't know what this means, you need to read up on lattice/trellis
graphics.
?panel.polygon
-- Bert
On Tue, Oct 4, 2011 at 7:14 AM, Ken Knoblauch ken.knobla...@inserm.frwrote:
markm0705 markm0705 at gmail.com writes:
I would
Hi,
I applied a linear mixed effect model in my data using the nlme package.
lme2-lme(distance~temperature*condition, random=~+1|trial, data) and then
anova.
I want to ask if it is posible to get the least squares means for the
interaction effect and the corresponding 95%ci. And then plot this
New package `partykit': A Toolkit for Recursive Partytioning
The purpose of the package is to provide a toolkit with infrastructure for
representing, summarizing, and visualizing tree-structured regression and
classification models. Thus, the focus is not on _inferring_ such a
tree structure
You need to set the labels...
Hadley
On Sat, Sep 24, 2011 at 3:49 AM, Casper Ti. Vector
caspervec...@gmail.com wrote:
Is there any way to use expression() in legend labels with ggplot2?
It seems that things like
scale_shape_manual(value = c(
x = expression(italic(x)),
y =
Below.
On Tue, Oct 4, 2011 at 7:34 AM, Panagiotis p...@hi.is wrote:
Hi,
I applied a linear mixed effect model in my data using the nlme package.
lme2-lme(distance~temperature*condition, random=~+1|trial, data) and then
anova.
I want to ask if it is posible to get the least squares means
If the data are from one data.frame (e.g., the iris data set), then simply
label the red and white flowers with different colors:
e.g.,
with the iris data set
plot(iris$Sepal.Length,iris$Sepal.Width,col=c(red,blue,black)[iris$Species],pch=c(16:18)[iris$Species])
Bill
On Oct 4, 2011, at
On Tue, Oct 4, 2011 at 7:42 AM, Jeanne M. Spicer xn8spi...@gmail.comwrote:
I'm not sure how returning an incorrect result is ever a 'positive' feature
It is **not** incorrect; perhaps unexpected, but that is not the same.
but at least the documentation could more clearly warn users that
On 03.10.2011 19:19, Cable, Sam B Civ USAF AFMC AFRL/RVBXI wrote:
I am using readLines to read a fairly large ASCII file. readLines reads
a fixed number of lines, then other R code processes the data, then
readLines reads the same number of lines again, then other R code
processes the data,
Hi all,
I have a dataset of individuals where the variable ID corresponds to the
identification of the household where the individual lives. rel.head stands
for the relationship with the household head. so rel.head=1 is the household
head, rel.head=2 is the spouse, rel.head=3 is the children.
On 03.10.2011 18:16, Sandeep Patil wrote:
Hello everyone
I have manually compiled directory of gstat in a particular folder of my
Unix system.
I want to install this and am unable to use either of the following two
commands
1. R CMD INSTALL
2. Install.packages
If this is a precompiled
The Financial Mathematics department of Fraunhofer ITWM
is offering a two-days workshop on Finance with R:
%-
[Workshop] Finance with R
%-
Oct 20, 2011, 10:00-17:00 and
Oct 21, 2011,
On 04.10.2011 08:53, Divyam wrote:
Hi users!
I am fitting a model with several factor variables as independents using
svm. since there are lots of categorical variables,the training and test
data sets have been created using dummy.data.frame option from dummies
package. I have a factor A in
Hello.
Not at all in the way you have shown. Just to improve your code
readability, try to avoid naming your variables beginning with period
(example: .hello).
In contrast with Matlab (for example) the period in R is not to have access
to an object property.
--
View this message in context:
I'm not sure how returning an incorrect result is ever a 'positive' feature but
at least the documentation could more clearly warn users that this method
behaves differently in these cases -- summary(rock[,1]) vs summary(rock[,1:2])
-- and that the method can and does return incorrect results
Hmm, that's my fault when composing this mail, but the problem was
really encountered at that time.
Nevertheless, neither can I reproduce the problem now, perhaps I just
made another mistake at that time.
Thanks all the same, and sorry for the disturbance anyway :|
On Tue, Oct 04, 2011 at
Bert Gunter gunter.berton at gene.com writes:
Below.
On Tue, Oct 4, 2011 at 7:34 AM, Panagiotis pat2 at hi.is wrote:
Hi,
I applied a linear mixed effect model in my data using the nlme package.
lme2-lme(distance~temperature*condition, random=~+1|trial, data) and then
anova.
I
Hi:
Here's a reproducible example:
d - data.frame(grp = factor(rep(c('x', 'y'), each = 5)),
ev = rnorm(10), dv = rnorm(10))
labl - list(expression(italic('x')), expression(italic('y')))
ggplot(d, aes(x = ev, y = dv, shape = grp)) + geom_point() +
scale_shape_manual('Group',
Hi,
On Tue, Oct 4, 2011 at 11:39 AM, jdospina jdosp...@gmail.com wrote:
Hello.
Not at all in the way you have shown. Just to improve your code
readability, try to avoid naming your variables beginning with period
(example: .hello).
Well, that's not exactly true.
It's common practice to
On 04.10.2011 13:30, Peter Minting wrote:
Dear R-help
Can anyone tell me why my curve appears the wrong way round on a rug plot?
I am using the same code as on pg 596 of the Crawley R-book.
mod-glm(mort~logBd,binomial)
What is mort, what is logBd? I don't have access to the book. I have
On 04/10/2011 7:04 AM, S Ellison wrote:
See para 10.3.2 'Identifiers' in the R language definition (always distributed
with R in the html help system), or ?make.names, for a concise statement of
what constitutes a valid variable name in R.
It's actually underscores that might give trouble
On 04.10.2011 16:42, Jeanne M. Spicer wrote:
I'm not sure how returning an incorrect result is ever a 'positive' feature but
at least the documentation could more clearly warn users that this method
behaves differently in these cases -- summary(rock[,1]) vs summary(rock[,1:2])
-- and that
On 04.10.2011 18:18, Duncan Murdoch wrote:
On 04/10/2011 7:04 AM, S Ellison wrote:
See para 10.3.2 'Identifiers' in the R language definition (always
distributed with R in the html help system), or ?make.names, for a
concise statement of what constitutes a valid variable name in R.
It's
Without knowing that C code, we cannot know. Have you read Writing R
Extensions carefully? I.e. take care with memory allocation and printing
as mentioned in the manual.
Uwe Ligges
On 04.10.2011 14:04, Grigory Alexandrovich wrote:
Hello,
I wrote a function in C, which works fine if called
Hi,
I am sure there are better / more efficient ways of doing this, but the
following seems to work ...
ids - sapply(split(df,df$ID),function(x) {length(x$rel.head)==2
any(x$rel.head==1) any(x$rel.head==3)})
ids - as.numeric(names(ids)[ids])
added.dummy - as.numeric(df$ID%in%ids)
This looks like a classic case of not reading the manual, and then compounding
it by not reading the posting guide. The manual would be the Writing R
Extensions pdf that comes with R or you can google it. The posting guide is
referenced at the bottom of this and every other posting on this
On 04.10.2011 11:10, D.Emad wrote:
Hello,
I've been facing a really stupid problem... When I try to plot using
heatplot or hclust or any similar function, the labels of the x-axis - which
are the samples names - are giant overlapping. I can't even read the
samples names!
R heatplot
Error:
I'm trying to use the randomTF function from package palaeoSig to
test the significance of a MAT reconstruction with nine analogs and a
WA-PLS reconstruction with four components. I'm probably missing
something obvious here but how do I make sure that randomTF is testing
the
Hadley,
Thanks for responding. No, not smoothed quantile regression. If you go here:
http://www.erh.noaa.gov/mmefs/index.php and click on one of the colored
squares, you can see we have 'boxplots'. What I want to express is the
uncertainty as depicted in the example from my previous email
Hi:
Here's another way to do it with the plyr package, also not terribly
elegant. It assumes that rel.head is a factor in your original data
frame:
str(df)
'data.frame': 11 obs. of 2 variables:
$ ID : Factor w/ 6 levels 17100,17101,..: 1 1 2 3 4 4 5 5 5 6 ...
$ rel.head: Factor w/ 3
I am using the tm package to do text miniing:
I have a huge list of stopwords (2000+) that are in a csv file. I read it as
follows:
stopwordlist - read.csv(stopwords to be Removed 10042011.csv)
myStopwords - as.character(stopwordlist$stopwords)
When try removing the stopwords using
Hi:
The smooth is not going to replicate the quantile estimates you get
from the 'boxplots'; the smooth is estimating a conditional mean using
loess, with confidence limits associated with uncertainty in the
estimate of the conditional mean function, which are almost certainly
going to be
I have a data frame called chemdata with this structure:
str(chemdata)
'data.frame': 14886 obs. of 4 variables:
$ site: Factor w/ 148 levels BC-0.5,BC-1,..: 104 145 126 115 114 128
124 2 3 3 ...
$ sampdate: Date, format: 1996-12-27 1996-08-22 ...
$ param : Factor w/ 8 levels
Hi Rich,
You can use something like this:
testdata - c(A1, A2, A3, B1, B2, B3)
grep(^A, testdata)
[1] 1 2 3
grepl(^A, testdata)
[1] TRUE TRUE TRUE FALSE FALSE FALSE
Sarah
On Tue, Oct 4, 2011 at 2:39 PM, Rich Shepard rshep...@appl-ecosys.com wrote:
I have a data frame called chemdata
This isn't going to be the most elegant, but it should work:
## Get the factors as characters
ff - as.character(chemdata$site)
## Identify those that match what you want
ff - grepl(ff, BC-)
now use this logical vector to subset
chemdata[ff, ]
Can't test, but should be good to go assuming
On Tue, 4 Oct 2011, Sarah Goslee wrote:
You can use something like this:
testdata - c(A1, A2, A3, B1, B2, B3)
grep(^A, testdata)
[1] 1 2 3
grepl(^A, testdata)
[1] TRUE TRUE TRUE FALSE FALSE FALSE
Sarah,
I don't see how this gives me a data frame containing only those sites I
Hi Rich,
On Tue, Oct 4, 2011 at 2:58 PM, Rich Shepard rshep...@appl-ecosys.com wrote:
On Tue, 4 Oct 2011, Sarah Goslee wrote:
You can use something like this:
testdata - c(A1, A2, A3, B1, B2, B3)
grep(^A, testdata)
[1] 1 2 3
grepl(^A, testdata)
[1] TRUE TRUE TRUE FALSE FALSE FALSE
On Tue, 4 Oct 2011, R. Michael Weylandt wrote:
This isn't going to be the most elegant, but it should work:
## Get the factors as characters
ff - as.character(chemdata$site)
## Identify those that match what you want
ff - grepl(ff, BC-)
Michael,
Apparently grep works differently in R
?grep
?names
Use indexing by name [, namevector]
---
Jeff Newmiller The . . Go Live...
DCN:jdnew...@dcn.davis.ca.us Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/Batteries
Hi,
Using ddply,
ddply(df, .(ID), mutate, nrows=length(rel.head), test = nrows==2
all(rel.head %in% c(1,3)))
HTH,
baptiste
On 5 October 2011 06:02, Dennis Murphy djmu...@gmail.com wrote:
Hi:
Here's another way to do it with the plyr package, also not terribly
elegant. It assumes that
... and, as an aside, if you had simply searched within R for (the
obvious?!)
??wildcard
you would have received the suggestion for glob2rx() in utils, which
actually would have enabled you to use a familiar wildcard expression.
However, the answers you've already received are simpler and more
No, that was just a typo on my end:
the correct order of arguments should have been
ff - grepl(BC-, ff)
On Tue, Oct 4, 2011 at 3:07 PM, Rich Shepard rshep...@appl-ecosys.com wrote:
On Tue, 4 Oct 2011, R. Michael Weylandt wrote:
This isn't going to be the most elegant, but it should work:
##
# Function to compute quantiles and return a data frame
g - function(d) {
qq - as.data.frame(as.list(quantile(d$y, c(.05, .25, .50, .75, .95
names(qq) - paste('Q', c(5, 25, 50, 75, 95), sep = '')
qq }
You could cut out the melt step by making this return a data frame:
g -
I am new to R and have recently tried Tinn-R with very mixed and unexpected
results. Can you point me to a Tinn-R tutorial on the web or a decent
reference book?
Thank you for your help;
Charles McClure
cmccl...@atrcorp.com
cfmccl...@verizon.net
__
The following for loops does the work but it takes a good 30 minutes to run:
for(i in 1:length(myStopwords))
{
currentWord - myStopwords[i]
tr1=tm_map(tr1,removeWords,currentWord)
}
Are there any faster alternatives?? Thank you.
Ravi
--
View this message in context:
Hello all
I'm trying to learn how to fit a nested model in R. I found a toy
example on internet where a dataset that have 3 areas and 4 sites
within these areas. When I use Minitab to fit a nested model to this
data, this is the ANOVA table that I got:
Nested ANOVA: y versus areas, sites
On Mon, Oct 3, 2011 at 10:08 PM, chunjiang he camel...@gmail.com wrote:
Hi,
I have two questions want to ask.
1. If I have a matrix like this, and I want to figure out the rows whose
value in the 3rd column are less than 0.05. How can I do it with R.
hsa-let-7a--MBTD1 0.528239197
On Tue, 4 Oct 2011, Sarah Goslee wrote:
You asked for pointers, and didn't provide a reproducible example, so I
offered a pointer.
Sarah,
I did not realize that your pointer was to the factor component of the
subset() command.
I think the most parsimonious thing for me to do is to
On Tue, 4 Oct 2011, R. Michael Weylandt wrote:
No, that was just a typo on my end:
the correct order of arguments should have been
ff - grepl(BC-, ff)
Michael,
Thank you.
Rich
__
R-help@r-project.org mailing list
Hello everyone,
I know this is very basic question for you people. I'm working with mani
diferent tables, but everyone has the same variables. (V1, V2, V3). The only
think that I need to do is to put together this tables. In other words,
creating just one big table with all the cases showed in
You are, of course, entirely correct and, once again, I tip my hat to
the erudition of those who comment on this list. My initial
formulation, for a distance on a normed space inherited from the norm,
stands trivially, but as you rightly point out, I'm excluding many
interesting and possibly
Perhaps rbind?
Michael
On Tue, Oct 4, 2011 at 3:48 PM, Jose Bustos Melo jbustosm...@yahoo.es wrote:
Hello everyone,
I know this is very basic question for you people. I'm working with mani
diferent tables, but everyone has the same variables. (V1, V2, V3). The only
think that I need to do
On Tue, 2011-10-04 at 08:45 +, Ashley Houlden wrote:
Hi,
forgive me if someone has already posted about this but I have had a
look and cannot find the answer, also I am very new to R and been
getting the grips with this.
I have been trying to use Adonis to find out if there are
On Tue, 2011-10-04 at 08:45 +, Ashley Houlden wrote:
Hi,
snip /
#distance matrix of samples using bray curtis
d= bcdist(mydata, rmzero=FALSE)
In addition, you don't necessarily need ecodist for the bray curtis
distance. vegdist() in vegan will compute this for you.
Not that there is
On 5/10/2011 7:25 a.m., Charles McClure wrote:
I am new to R and have recently tried Tinn-R with very mixed and unexpected
results. Can you point me to a Tinn-R tutorial on the web or a decent
reference book?
Thank you for your help;
Charles McClure
cmccl...@atrcorp.com
cfmccl...@verizon.net
On Tue, Oct 4, 2011 at 4:41 PM, Gavin Simpson gavin.simp...@ucl.ac.uk wrote:
On Tue, 2011-10-04 at 08:45 +, Ashley Houlden wrote:
Hi,
snip /
#distance matrix of samples using bray curtis
d= bcdist(mydata, rmzero=FALSE)
In addition, you don't necessarily need ecodist for the bray curtis
Hi,
I wanted to change the default colors appearing in boxplot. For example, the
following code (from the package/documentation):
===
library(ggplot2)
p - ggplot(mtcars, aes(factor(cyl), mpg))
p + geom_boxplot(aes(fill = factor(am)))
===
Gives the default colors. What do I
Dear Michael,
Thanks very much.
Jiang
On Tue, Oct 4, 2011 at 2:39 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
On Mon, Oct 3, 2011 at 10:08 PM, chunjiang he camel...@gmail.com wrote:
Hi,
I have two questions want to ask.
1. If I have a matrix like this, and I want to
I'm going to put on my fire suit and wade in (see inline)
On 10/4/2011 8:11 AM, Bert Gunter wrote:
On Tue, Oct 4, 2011 at 7:42 AM, Jeanne M. Spicerxn8spi...@gmail.comwrote:
I'm not sure how returning an incorrect result is ever a 'positive' feature
It is **not** incorrect; perhaps
1 - 100 of 127 matches
Mail list logo
