You need to read ?Sys.setlocale (surely part of the homework the R posting
guide asked of you).
I have read that. And I have used the standard way of changing locale
to fa_IR.utf8 (i.e. using
Sys.setlocale(category=LC_ALL,locale=fa_IR.utf8). Also
The subject says it all really.
Question 1.
Here is some code created to illustrate my problem, can anyone spot where I'm
going wrong?
Question 2.
The reason I'm following a manual specification of models relates to the fact
that in reality I am using mgcv::gam, and I'm not aware that dredge
Dnieper 2012-01-17 10:51, Dunbar, Michael J. piste:
The subject says it all really.
Question 1.
Here is some code created to illustrate my problem, can anyone spot where I'm
going wrong?
Question 2.
The reason I'm following a manual specification of models relates to the fact
that in
Hello everyone,
I have got the same problem, with the same error message.
Using R 2.14.1, plyr 1.7.1, R.Studio 0.94.110, Windows XP
The plyr mailing list does not provide any help until now.
require(plyr)
c(sample(c(1:100), 50, replace=TRUE))-V1
c(rep( 1:5, 10))-f1 #variable to group V1
I have a text file with states and numbers. I would like to display each
number that corresponds to a state on a map.
I am trying to use the maps package, but it doesn't show Alaska or Hawaii. Do
you have suggestions on how to do this?
Jeffrey
Thank you all for your help. It's working now. I chose to use the sqldf
method and fn$ in the gsubfn package. I used fn$ so that I could put
variables into the sqldf statement. This helped me to increase or decrease
the window size in the Gene dataframe if I wanted to include values in the
At 12:15 16/01/2012, Ricc wrote:
Hello,
I used the default parameters:
- envelope: default is TRUE
- level: the default is to take the value from the object (I do not
understand this very well)
When you specified your original model to rma.uni you either
specified the level or let it default
On 1/11/2012 11:07 PM, Paul Miller wrote:
Hello Everyone,
I have a question about how best to check dates for entry errors.
Try using regular expression matching and the functions grep, strsplit,
regexpr etc.
If you are not familiar with regex: bit a bumpy road of getting into it
but in the
@ Micheal: thanks I understand now.
@ Wolfgang: apparently, using the DL-estimator solved my issue and
leaded to a result with only a slight difference with metawin. thanks
!
2012/1/17 Michael Dewey i...@aghmed.fsnet.co.uk:
At 12:15 16/01/2012, Ricc wrote:
Hello,
I used the default
Hi, I use the lda function from the MASS package to classify some
samples according to some chemical properties. If I run lda without
cross validation all is ok but, if I run lda with cross validation,
the R consol say:
resLDA - ldaRedOx - lda(Activity ~ TRedOx[,1:6], CV=TRUE,
Hi,
I have the simulation results of the following structure:
run par measured
1 1012
2 1014
1 2020
2 2026
Where run is the simulation run number, par is the parameter of
the simulation, and measured is the value measured in the
simulation. This is only a simple
df-data.frame(
group=rep(c(a,b), c(7,6)),
sales=c(3,4,6,5,1,30,8,4,6,9,10,27,9),
turn_over=c(1.5, 2.9, 1.9,20.5, 2.3, 1.65, 0.06, 3.4, 3.5, 2.23, 0.1,
9.8,1.4)
)
Hello all,
In this data set ı need to replace the outliers with 1.5IQR for each group
and for each variable so the final data set
Dear all,
I have a question about the knowing for which row I have the max value of
one of my variables.
I calculated the Rsquared for different columns and made a list to gather
them. I unlisted this list to create a vector with this values. I want to
know for which column I have the max value of
hello,
i want a visualization of the k-mean clustering.which one method
will be best for visualization??
thnkx
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Dear Members,
I required to score probability of survival before specified time using
fitted cox model on scoring dataset.
On the training sample data I am able to get the probability of a survival
before time point(t), but on the scoring dataset, which will have only
predictor information I am
Dear Hélène Genet,
Re:
Dear all,
I need to do the same procedure on several files. But I don't know how to
refer to the file name.
Here is an example of what I am trying to do.
List of files: file1(A,B,C, D1...Dn), file2(A,B,C,E1,...,En),
file3(A,B,C,F1,...,Fn)
Procedure I want
On 16.01.2012 18:00, chaps31 wrote:
Hi
The log file (not as .odc and as .txt file) is in R'd tempdir() after
WinBUGS returns to R.
Was this my statement?
I actually meant to write *both* rather than not above.
Best,
Uwe
Is there any way to save the .odc file?
Ruth
--
View this
Thanks for the reply. I think more the issue is whether it can be applied
to cross-sectional data. This I'm not sure. This method is heavily cited
in the New England Journal of Medicine, but thus far I've only seen it
used with longitudinal data.
On 1/16/12 10:23 PM, Kevin E. Thorpe
Hello all,
It might be a simple question, but I cannot find the solution, as I do not
know which subjects I should search on. So, much thanks for he/she we can
help me.
I am creating a function and would like to place a formula in the function,
without it being executed immediately. Like saving
I'm setting up an Ubuntu virtual machine that will use 4-Intel Xeon CPU x5650.
I'd like to compile R with a BLAS but the question is whcih one. Seems
like the only free ones are GotoBLAS which I'm not sure is being maintained
for newer CPUs and OpenBLAS for Loongson CPUs. I saw a favorable
Hi!
I want to plot the probability density function and the cumulative
distribution function for the gamma, lognormal, exponential and Pareto
distribution. I want to vary the parameters and and have a plot with 2-3
different parameters in the same figure. It should look like this (example
weibull
On 17.01.2012 12:31, Irek Szczesniak wrote:
Hi,
I have the simulation results of the following structure:
run par measured
1 1012
2 1014
1 2020
2 2026
Where run is the simulation run number, par is the parameter of
the simulation, and measured is the value measured
On 17.01.2012 14:54, Riccardo Romoli wrote:
Hi, I use the lda function from the MASS package to classify some
samples according to some chemical properties. If I run lda without
cross validation all is ok but, if I run lda with cross validation, the
R consol say:
resLDA - ldaRedOx -
On 17/01/2012 5:35 AM, Nerak wrote:
Dear all,
I have a question about the knowing for which row I have the max value of
one of my variables.
I calculated the Rsquared for different columns and made a list to gather
them. I unlisted this list to create a vector with this values. I want to
know
On 17-01-2012, at 11:35, Nerak wrote:
Dear all,
I have a question about the knowing for which row I have the max value of
one of my variables.
I calculated the Rsquared for different columns and made a list to gather
them. I unlisted this list to create a vector with this values. I want to
On 17-01-2012, at 13:36, Julia Burggraaf wrote:
Hello all,
It might be a simple question, but I cannot find the solution, as I do not
know which subjects I should search on. So, much thanks for he/she we can
help me.
I am creating a function and would like to place a formula in the
Hi
Hello all,
It might be a simple question, but I cannot find the solution, as I do
not
know which subjects I should search on. So, much thanks for he/she we
can
help me.
I am creating a function and would like to place a formula in the
function,
without it being executed
On Jan 17, 2012, at 5:37 AM, Jeffrey Joh wrote:
I have a text file with states and numbers. I would like to display
each number that corresponds to a state on a map.
I am trying to use the maps package, but it doesn't show Alaska or
Hawaii. Do you have suggestions on how to do this?
Hi
Hi,
I am creating a function and ran into the problem of selecting a column
from a dataset. It seems as though the $ function (as in
data$columnname)
does not apply in the function. In simplified version:
This works:
testf2-function(data,columnnumber){print(data[,columnnumber])}
On Jan 17, 2012, at 8:02 AM, Thomas Mang wrote:
On 1/11/2012 11:07 PM, Paul Miller wrote:
Hello Everyone,
I have a question about how best to check dates for entry errors.
Try using regular expression matching and the functions grep,
strsplit, regexpr etc.
If you are not familiar with
On Tue, Jan 17, 2012 at 6:06 AM, Scott Raynaud scott.rayn...@yahoo.com wrote:
I'm setting up an Ubuntu virtual machine that will use 4-Intel Xeon CPU x5650.
I'd like to compile R with a BLAS but the question is whcih one. Seems
like the only free ones are GotoBLAS which I'm not sure is being
On Mon, Jan 16, 2012 at 6:05 PM, Mary Kindall mary.kind...@gmail.com wrote:
Thanks for reply
I wanted to have legend name with spaces. Right now I am using the
following code but it produce two legends. I have to use Gimp to cut the
redundant legend.
Your basic problem is that you're using
Will depend heavily on the structure of your data (you haven't even told use te
number of dimensions or the metric in question), but I'd suggest something like
a scatterplot color coded by cluster with an additional marker for cluster
means.
Michael Weylandt
On Jan 17, 2012, at 3:48 AM,
Perhaps I misunderstand you, but it sounds like all you need to do is change
weibull to the name of another distribution
Michael
On Jan 17, 2012, at 8:11 AM, chrisr34000 cr...@wolke7.net wrote:
Hi!
I want to plot the probability density function and the cumulative
distribution function
You mean the process of clustering (the algorithm)? Have you looked at
kmeans.ani() in the animation package?
Regards,
Yihui
--
Yihui Xie xieyi...@gmail.com
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State University
2215 Snedecor Hall, Ames, IA
On Tue, Jan 17,
Em 16/1/2012 08:07, David martin escreveu:
Hi,
I haven't found in R a possibility to draw a boxplot with a diamond
shape (means and CI).
David,
Perhaps, even prejudicially, as I cannot see any advantage on the
diamond shape for displaying just two dimensions, I would recommend you
check if
Inline:
Michael
On Jan 16, 2012, at 10:26 PM, Hélène Genet hge...@alaska.edu wrote:
Dear all,
I need to do the same procedure on several files. But I don't know how to
refer to the file name.
Here is an example of what I am trying to do.
List of files: file1(A,B,C, D1...Dn),
Dear R team, dear Prof. Therneau,
library(survival)
data(colon)
?colon
gives me only a very rudimentary source (only a name). Is there a
possibility to get a reference to the clinical trial these data
are taken from?
Many thanks in advance. With best wishes,
Matthias Gondan
--
Dear Forum,
I have been wracking my head over this problem for the past few days. I have
a dataset of (x,y). I have been able to obtain a nonlinear regression line
using nls. However, we would like to do some statistical analysis. I would
like to obtain a confidence interval for the curve. We
Hi, Julian-
I'm not sure if this will be what you want but you could start by taking a look
at:
?predict.nls
Ken
On 01/17/12, crimsonengineer87 julianjonre...@gmail.com wrote:
Dear Forum,
I have been wracking my head over this problem for the past few days. I have
a dataset of (x,y). I
Sorry, that wasn't to helpful...I see that the intervals and se.fit argument
are currently ignored.
On 01/17/12, crimsonengineer87 julianjonre...@gmail.com wrote:
Dear Forum,
I have been wracking my head over this problem for the past few days. I have
a dataset of (x,y). I have been able
On Jan 17, 2012, at 10:22 AM, csrabak wrote:
Em 16/1/2012 08:07, David martin escreveu:
Hi,
I haven't found in R a possibility to draw a boxplot with a diamond
shape (means and CI).
David,
Perhaps, even prejudicially, as I cannot see any advantage on the
diamond shape for displaying just
Hi !
I am new to R and I am using Rstudio on Linux.
Have I missed some library() ?
and if so does anyone have the time to write which?
I am trying to create some PostqreSQL tables from comma separated files.
I am a bit surpriced that character is a problem. The missing value
could be NULL.
On Jan 17, 2012, at 10:48 AM, Matthias Gondan wrote:
Dear R team, dear Prof. Therneau,
library(survival)
data(colon)
?colon
gives me only a very rudimentary source (only a name). Is there a
possibility to get a reference to the clinical trial these data
are taken from?
Wouldn't this seem
Hi Ken,
Thx for that advice. I took a brief look at it. I already have my curve by
just using the curve() function using the parameters a and b given by the
nls. Would se.fit and interval have computed the CI?
Maybe where I'm confused is at how I can break up my curve into pieces of
linear
I am working on predicitng the scores for a days worth of matches of team
sports. I have already collected data for the teams for the season we are
concentrating on.
I have been fitting poisson models for football games and have worked out
what model is best and which predictor variables are
I am having problems using the /lme /command to fit mixed models. I have
a data set similar to longitudinal data, except the hypothesised
correlation is between observations taken from different individuals in
the same family rather than from the same individual at different times.
As soon as
On Tue, Jan 17, 2012 at 8:06 AM, Kenneth Frost kfr...@wisc.edu wrote:
Sorry, that wasn't to helpful...I see that the intervals and se.fit argument
are currently ignored.
Yes, because the fitted values are nonlinear in the parameters, which
makes finding exact confidence regions impossible. I
On Jan 17, 2012, at 10:55 AM, kerry1912 wrote:
I am working on predicitng the scores for a days worth of matches of
team
sports. I have already collected data for the teams for the season
we are
concentrating on.
I have been fitting poisson models for football games and have
worked out
Robin Lock at St Lawrence has done this for hockey, see
http://it.stlawu.edu/~chodr/faq.html
As I recall, he has a poisson regression model with parameters for
offense and defense, and perhaps home 'field' advantage.
I confess I am skeptical that this is the right approach for football
-
On Mon, Jan 16, 2012 at 1:13 AM, Paul p...@paulhurley.co.uk wrote:
On 16/01/12 02:08, J Toll wrote:
Hi,
I'm trying to create a stacked bar plot using ggplot2. Rather than
plotting the count of each of the 13 Bar factors on the Y axis, I
would like to represent the sum of the Values
On 01/17/2012 07:16 AM, Essers, Jonah wrote:
Thanks for the reply. I think more the issue is whether it can be applied
to cross-sectional data. This I'm not sure. This method is heavily cited
in the New England Journal of Medicine, but thus far I've only seen it
used with longitudinal data.
As
Actually, I don't think I made myself clear and I wrote this late last
nightSorry. More the issue is that the raw model predictions (from 0
to 1) have no inherent clinical value to them. I.e. They aren't risk of
disease or risk of outcome. They are raw scores that are specific to
each model
R offers a bewildering array of options when it comes to representing
dates and times (e.g, as.Date, chron, strptime, zoo, etc). Can anybody
recommend a document that compares the relative merit of each method? I'm
not looking for help with any one method, but rather a guide that
describes
On 01/17/2012 11:55 AM, Essers, Jonah wrote:
Actually, I don't think I made myself clear and I wrote this late last
nightSorry. More the issue is that the raw model predictions (from 0
to 1) have no inherent clinical value to them. I.e. They aren't risk of
disease or risk of outcome. They
Replying to old messages without including context (particularly old ones)
is rather bad netiquette.
Thank you for at least providing a reproducible example. Now if you can
figure out how to read the documentation we will really make some
progress.
Further responses below.
On Tue, 17 Jan
Dear all,
I am trying to apply the aggregate() function to calculate correlations for
subsets of a dataframe. My argument x is supposed to consist of 2 numerical
vectors, which represent x and y for the cor() function.
The following error results when calling the aggregate function: Error in
On 17/01/2012 12:14 PM, Jake Beaulieu wrote:
R offers a bewildering array of options when it comes to representing
dates and times (e.g, as.Date, chron, strptime, zoo, etc). Can anybody
recommend a document that compares the relative merit of each method? I'm
not looking for help with any one
R offers a bewildering array of options when it comes to representing
dates and times
Yes no: read www.r-project.org/doc/Rnews/Rnews_2004-1.pdf (the help
desk section)
Brief summary: 3 major ways to deal with dates/times in R:
i ) the Date class from the base distribution -- no time support,
Searched archives and found some old email threads on the topic. But mot
exactly what I think I need. Suppose I have a datafile such as tmp.
tmp - data.frame(var1 = c(rnorm(1000), rnorm(1000, 1, 1)), var2 = gl(2, 1000))
I'd like a plot similar to the one below, but with an abline of v=0 in the
Note that although ddply does a lot for you, it doesn't reproduce all of
your calculations on all of the data columns like summaryBy does... you have
to explicitly create every calculated column in your function.
Well, ddply doesn't, but colwise will.
Hadley
--
Assistant Professor /
?panel.number
This tells you what panel you're in and you can use that to determine
which line to draw.
-- Bert
On Tue, Jan 17, 2012 at 9:59 AM, Doran, Harold hdo...@air.org wrote:
Searched archives and found some old email threads on the topic. But mot
exactly what I think I need. Suppose I
On Tue, 17 Jan 2012, crimsonengineer87 wrote:
Dear Forum,
I have been wracking my head over this problem for the past few days. I have
a dataset of (x,y). I have been able to obtain a nonlinear regression line
using nls. However, we would like to do some statistical analysis. I would
like to
On 17.01.2012 18:10, RNoob wrote:
Dear all,
I am trying to apply the aggregate() function to calculate correlations for
subsets of a dataframe. My argument x is supposed to consist of 2 numerical
vectors, which represent x and y for the cor() function.
The following error results when
On Tue, 17 Jan 2012, Bert Gunter wrote:
On Tue, Jan 17, 2012 at 8:06 AM, Kenneth Frost kfr...@wisc.edu wrote:
Sorry, that wasn't to helpful...I see that the intervals and se.fit argument
are currently ignored.
Yes, because the fitted values are nonlinear in the parameters, which
makes
Thank you, Bert. The help page doesn't have a usage example and I can't seem to
find one via google. Do you, or anyone else, have sample code?
-Original Message-
From: Bert Gunter [mailto:gunter.ber...@gene.com]
Sent: Tuesday, January 17, 2012 1:07 PM
To: Doran, Harold
Cc:
Sarah Jervis sj414 at medschl.cam.ac.uk writes:
I am having problems using the /lme /command to fit mixed models. I have
a data set similar to longitudinal data, except the hypothesised
correlation is between observations taken from different individuals in
the same family rather than
Dear all,
I am writing an R code to fit a Bayesian mixed logit (BML) via MCMC / MH
algorithms following Train (2009, ch. 12).
Unfortunately, after many draws the covariance matrix of the correlated random
parameters tend to become a matrix with almost perfect correlation, so I think
there is
On Jan 17, 2012, at 1:34 PM, Doran, Harold wrote:
Thank you, Bert. The help page doesn't have a usage example and I
can't seem to find one via google. Do you, or anyone else, have
sample code?
It did not seem particularly daring or complex when I tried this
(which does appear to produce
It does indeed produce what I'm expecting. The input to panel.number seems to
require a character string, but here the function is called with no argument. I
am not entirely clear _why_ it works, but it does seem to.
-Original Message-
From: David Winsemius
On Jan 17, 2012, at 1:52 PM, Doran, Harold wrote:
It does indeed produce what I'm expecting. The input to panel.number
seems to require a character string, but here the function is called
with no argument. I am not entirely clear _why_ it works, but it
does seem to.
?panel.numer
Says
Hello, R-List,
I'm getting error messages when adding geom_density2d() [package ggplot2]:
Fehler in pretty(range(data$z), 10) :
NA/NaN/Inf in externem Funktionsaufruf (arg 1)
Zusätzlich: Warnmeldungen:
1: Removed 1
I have a question on generating multivariate time series surrogates
using the surrogates function in the RTisean library.
The surrogate data matrices are always much shorter than the input matrices.
FYI, I'm using R version 2.12.2 on Windows XP
RTisean library v 3.0.14
Tisean algorithms v
David:
That doesn't quite answer the question about Alaska and Hawaii.
Jeffrey:
help(state, maps)
states This database produces a map of the states of the United States
mainland ...
so you have to use:
map(world, USA)
map(state, add=T)
to get the whole lot (which I am willing to bet is not
Thanks! Both solutions work well for the problem that I described,
although I failed to mention that there are also pre-abbreviated names
in the list that I'm working with, and the second solution returns NA's
for these (but there are plenty of ways around this). Sample data might
be:
I think the amount of people on this list who understand your question
is roughly zero. We cannot see how the subject is related to the body of
your function nor do we see any incidence that ou followed the posting
guide.
Uwe Ligges
On 17.01.2012 17:06, Poul Kristensen wrote:
Hi !
I am
Hello,
RNoob wrote
Dear all,
I am trying to apply the aggregate() function to calculate correlations
for subsets of a dataframe. My argument x is supposed to consist of 2
numerical vectors, which represent x and y for the cor() function.
The following error results when calling the
2012/1/17 Uwe Ligges lig...@statistik.tu-dortmund.de:
I think the amount of people on this list who understand your question is
roughly zero.
A Fortunes candidate?
Cheers,
Bert
We cannot see how the subject is related to the body of your
function nor do we see any incidence that you
Hi everyone,
I have the following:
sqldf(select Premie,count(tpounds) N,avg(tpounds) Avg_Weight,
stddev_samp(tpounds) StdDev
from children
group by Premie
having !is.na(Premie))
sqldf() does not like the !is.na(Premie) specification. How does one
exclude a missing group in an aggregated
Did you try a where statement?
where Premie is not null
On Tue, Jan 17, 2012 at 3:03 PM, Dan Abner dan.abne...@gmail.com wrote:
Hi everyone,
I have the following:
sqldf(select Premie,count(tpounds) N,avg(tpounds) Avg_Weight,
stddev_samp(tpounds) StdDev
from children
group by Premie
(As a noob to R, this is my first posting - yes yes, groans all around...)
I'm trying to extract certain rows from a data frame. I used the following to
import data from a CSV txt file.
data - read.table(file=data.txt, header=TRUE)
when I do this, my attempt to extract the data rows
Dan -
Try using having Premie not null instead of
having !is.na(Premie) .
- Phil Spector
Statistical Computing Facility
Department of Statistics
mukul purva wrote on 01/16/2012 01:35:00 AM:
hello,
i hav a prob in R lang. i want to do correlation of data frame
22810(gene) rows and 1436 colums(experiment) when i covert this file
in csv or xls format it reads only 1024 cloumns. n when i do
correlation of data mean 22810 *22810
On Jan 17, 2012, at 2:21 PM, Ray Brownrigg wrote:
David:
That doesn't quite answer the question about Alaska and Hawaii.
Agreed. I misinterpreted the text of help(map) example to mean that HI
and AK boundaries could be found in unemp. However, it was also
advice to Jeffrey that
Read the help file on how to extract from a data frame:
?[.data.frame
Then, try adding a comma inside the brackets.
data.station1 - data[data$Station==1, ]
Before the comma, the data$Station==1 identifies what rows to select.
After the comma, the lack of specification indicates that all columns
Carlo Fezzi (ENV C.Fezzi at uea.ac.uk writes:
Dear all,
I am writing an R code to fit a Bayesian mixed logit (BML) via MCMC / MH
algorithms following Train (2009, ch. 12).
Unfortunately, after many draws the covariance matrix
of the correlated random parameters tend to become
a matrix
Thank you, Uwe, for your help! I have more measurements (m1, m2) and
more parameters (par1, par2). I can calculate the means of m1 and m2
this way:
aggregate(cbind(m1, m2) ~ par1 + par2, dat, mean)
However, I also need to calculate the standard error of the mean, and
the variance for the
Thanks for the comments everyone. I was hoping to not have to find someone in
the stats department ... well, we'll see.
So in response to Z's comment ... I have tried breakpoints(Na ~ yield) and I
did expect to get something continuous. The idea was to get two or three
linear functions making up
On Jan 17, 2012, at 4:56 PM, Jean V Adams wrote:
Read the help file on how to extract from a data frame:
?[.data.frame
Then, try adding a comma inside the brackets.
data.station1 - data[data$Station==1, ]
Before the comma, the data$Station==1 identifies what rows to select.
After the comma,
Try using the function in the plyr package. E.g.,
z - data.frame( # your toy dataset
run = c(1, 2, 1, 2),
par = c(10, 10, 20, 20),
measured = c(12, 14, 20, 26))
library(plyr)
ddply(z, .(par), summarize, meanMeasured=mean(measured),
sdMeasured=sd(measured))
par
This request is related to the following post from last year:
https://stat.ethz.ch/pipermail/r-help/2011-June/279752.html
After reading the thread, the idea is still not clear. I have fitted a model
using HURDLE from the PSCL package. I am trying to get marginal effects /
slopes by multiplying
Hi, I recently got a bizarre message when running arules. It just said
Killed and quit. Anyone know why this might have happened? I am running R
on an AWS quad xl ubuntu instance.
Here is some information, including dataset size and the parameters:
parameter specification:
confidence minval
Thanks Hadley for your input.
The following code works fine now.
Thanks again
con = textConnection(inputs var1 var2 var3
100 10 5 2
1000 20 10 4
5000 30 15 8
1 40 20 16
3 50 25 32)
data = read.table(con, header=TRUE)
data
data = melt(data, id=inputs)
g - ggplot(data,aes(x=inputs,
Look at Hadley Wickham's devtools package. It is designed with this
sort of thing. That said, it really is not too difficult to install
as long as you have a working tool chain (which you will need to test
it anyway).
I cound not find it with google and found no devtools on this page
I don't believe you can. However, you need not install it into a system-wide
library directory... your personal library (e.g.
/home/jonas/R/x86_64-pc-linux-gnu-library/2.14) should be sufficient.
Finally i created a new testuser to install the library locally as you wrote.
It works. Thank
http://cran.r-project.org/web/packages/devtools/index.html
Michael
On Tue, Jan 17, 2012 at 6:51 PM, Jonas Stein n...@jonasstein.de wrote:
Look at Hadley Wickham's devtools package. It is designed with this
sort of thing. That said, it really is not too difficult to install
as long as you
In respect of fitting piecewise linear regressions, have you looked at
the segmented package?
cheers,
Rolf Turner
On 18/01/12 04:30, crimsonengineer87 wrote:
Dear Forum,
I have been wracking my head over this problem for the past few days. I have
a dataset of (x,y). I have been
Hi,
i create two constants kilo and milli in [1]. These should be available
after loading
library(sitools)
How should i export them and what have i done wrong?
(Other suggestions for improving the package are welcome too)
The ready to use .tar.gz and the source can be found on github [2,3]
Try adding
LazyData: yes
to the DESCRIPTION file.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Jonas Stein
Sent: Tuesday, January 17, 2012 4:41 PM
To:
Just install the updated library over the old one and start a new R session.
Devtools can be helpful for some things, but when I last looked at it I was
having more difficulty with getting documentation right than debugging code,
which I can do using normal function development processes, so I
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