Sorry that didnt work for me, any ideas?
- Original Message -
From: ilai ke...@math.montana.edu
To: David Lyon david_ly...@yahoo.com
Cc: r-help@r-project.org r-help@r-project.org
Sent: Tuesday, April 3, 2012 10:43 PM
Subject: Re: [R] image.plot adding x-axis labels. Please Help
On Tue,
Here is the data I'm working with:
http://r.789695.n4.nabble.com/file/n4530888/new.txt new.txt
http://r.789695.n4.nabble.com/file/n4530888/old.txt old.txt
My code is here:
http://pastebin.com/9jjs6Ahr
I'm looking for away to simply attach the new.txt to the bottom of old.txt
through R, else
Here's a case where it doesn't work. Again, the problem is that when I use
the rbind or concatenate functions, the 2012 data set seems to go ahead of
the 2010 and 2011 portions of the data set. The problem seems dependent on
the text files I read in:
On 04-04-2012, at 07:15, Ashish Agarwal wrote:
Yes. I was missing the DROP argument.
But now the problem is splitting is causing some weird ordering of groups.
Why weird?
See below:
DF - read.table(text=
Houseid,Personid,Tripid,taz
1,1,1,4
1,1,2,7
2,1,1,96
2,1,2,4
2,1,3,2
2,2,1,58
Hello.
I have yet to receive a response to my previous post, so I may have
done a poor job asking the question. So, here is the general question:
how can I run a run a multivariate (more than one non-independent,
response variables) ordered probit regression model? I've had success
doing this in
Thanks a ton!
It was weird because according to me ordering should have by default.
Anyways, your workaround along with Weidong's method are both good
solutions.
On Wed, Apr 4, 2012 at 12:10 PM, Berend Hasselman b...@xs4all.nl wrote:
On 04-04-2012, at 07:15, Ashish Agarwal wrote:
Yes. I was
Michael,
First of all, thank you very much for your answer.
I've read your 2 answers, but I'm not really sure that they corresponds
to
my problem of NAs.
You shall read answers more carefully
x-rnorm(20)
x[3:4]-NA
x[12:19]-NA
x
[1] -0.30754528 0.07597988 NA NA
Hi
Can you please be more specific? Based on this input, what do you want as
a result?
set.seed(111)
dates = as.Date(sort(rnorm(10,3000,100)), origin = 2000-1-1)
dates
[1] 2007-08-01 2007-10-21 2007-12-08 2007-12-15 2008-01-29
2008-02-14 2008-02-16 2008-03-01
[9] 2008-04-02 2008-04-11
Wow, thank you for all your answers.
You were completely right michael. Well, it's my fault. I didn't understood
your 2nd reply, when you were talking about arguments for larger gaps. I
thought it was for deleting big gaps too. I apologize.
It was too easy in fact. I also didn't noticed the
It is unclear what the problem is. Does following code solve your append
problem?
fmt = %m/%d/%Y %H:%M
fname - new.txt
#records = 2904
newfile - read.csv(fname, header = TRUE, sep = ,, skip=0,
colClasses = c(rep(character,2), rep(numeric, 16))
)
newfile.comb - cbind(newfile[2], newfile[3])
fname
Dear all,
A new package 'IC2' is now available. IC2 computes some indices of inequality
and concentration (SGini, Atkinson, GEI). For each index, it provides
decomposition between subgroups. Plotting of Lorenz and concentration curves
are also available. Sampling weights can be used.
Regards,
Dear Petr,
thanks for taking your time.
For this input, the first element should be selected since there are more than
3 more dates within one year (basically, all other dates are within one year)
and at least one of them is more than 3 month later.
In the meantime, I came up with some code
Hi everyone,
I'd appreciate if someone could help me to understand what is happening.
I'm attempting to connect R to the broker platform using tcp on localhost
5333.
Just to learn how use make.socket, write.socket, ..functions I wrote simple
code:
#prepare string command to subscribe ask and
Dear David,
thanks for your suggestion.
However, when applied to
dates = as.Date(c(2001-1-1, 2001-1-3, 2001-1-12, 2001-1-13,
2001-4-20))
it doesn't behave like i want...
which( dates[4:(length(dates))] -dates[1:(length(dates)-3)] 365
dates[3:(length(dates)-1)]
On 12-04-03 4:35 PM, dnewbold wrote:
Hi, Im doing a simple non parametric regression using two variables(ie
regressing one on the the other), how would I counstruct my persp plot for
it with there only be two variables in total, . Any help would be much
appreciated.
You can't. persp() plots
On 04/04/12 15:54, John Kohr wrote:
Hello,
I have several functions in an .R file. I try to load them with load() command
but it seems is not working..
if .R is in /home/user/myfunctions.R
how can i load it? is there any other way?
Don't assume that you know what load means on the basis of
Rolf:
Google on load functions into R.
A post referencing source() (from Henrik Bengtsson is the first hit.
-- Bert
On Wed, Apr 4, 2012 at 3:23 AM, Rolf Turner rolf.tur...@xtra.co.nz wrote:
On 04/04/12 15:54, John Kohr wrote:
Hello,
I have several functions in an .R file. I try to load
Hi, Vinod,
Hope this will help you:
library(RJDBC)
#specify your mysql driver
drv - JDBC(com.vertica.Driver, ../vertica_3.5_jdk_5.jar)
# specify your connection string
conn - dbConnect(drv, jdbc:postgres://IP:port/dbname, login,
password)
#list tables
dbListTables(conn)
#get your distances
On Apr 3, 2012, at 11:16 PM, David Lyon wrote:
Sorry that didnt work for me, any ideas?
You _could_ indicate which package the image.plot function comes from.
You _could_ include dput on a sufficient segment of `data1` to offer a
reproducible test case. You _could_ indicate in what
On 12-04-03 12:25 PM, Marc Girondot wrote:
Indeed I get this error message when I install the library using R CMD
INSTALL but not within the GUI (in MacOsX). Good to know that R CMD
INSTALL is more verbose and permits to track bug.
I followed up in R-sig-mac, and it turns out the reason you
Hi
Dear Petr,
thanks for taking your time.
For this input, the first element should be selected since there are
more
than 3 more dates within one year (basically, all other dates are within
one year) and at least one of them is more than 3 month later.
In the meantime, I came
On Apr 3, 2012, at 9:25 PM, Melrose2012 wrote:
I am trying to plot the logistic regression of a dataset (# of
living flies
vs days the flies are alive) and then fit a best-fit line to this
data.
Here is my code:
plot(fflies$living~fflies$day,xlab=Number of Days,ylab=Number of
Fruit
Dear Danielle,
At least in industrial toxicology (my original background) the recent
tendency has been to use benchmark dose (BSD) approach instead of NOEL
or NOAEL approach due to various problems with the definition and
estimation of NO(A)EL. In R this can be achieved using the packages
drc and
Hello,
I want to do a cluster analysis with my data. The problem is, that the
variables dont't consist of single value but the entries are pairs of
values.
That lokks like this:
Variable 1:Variable2: Variable3: ...
(1,2) (1,5) (4,2)
(7,8) (3,88)
Make that
bmd(fit, 0.01)
in my previous post.
Jarno
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
No problem -- best of luck with it: the zoo package is one of the best
documentation-wise and I'd advise you to look at the available
vignettes when you have time.
Vignettes are extended documentation included in some packages that
give a more systematic presentation than can be given in the help
On Wed, Apr 4, 2012 at 1:47 AM, knavero knav...@gmail.com wrote:
Here's a case where it doesn't work. Again, the problem is that when I use
the rbind or concatenate functions, the 2012 data set seems to go ahead of
the 2010 and 2011 portions of the data set. The problem seems dependent on
the
Hi there,
do you know if there is a package that fits spatio temporal autoregressive
models in R?
thanks
vasilis
--
View this message in context:
http://r.789695.n4.nabble.com/STAR-Spatio-Temporal-AutoRegressive-models-tp4531793p4531793.html
Sent from the R help mailing list archive at
Found solution.
I've changed the library and functions to open and read sockets.
Using base package I wrote:
msg3-function=subscribe|item=MI.EQCON.1|schema=last_price;ask;bid
msg4-function=unsubscribe
#open socket connection
socketPointer-socketConnection('localhost', port=5333, server=FALSE)
On Apr 4, 2012, at 8:19 AM, Petr PIKAL wrote:
Hi
Dear Petr,
thanks for taking your time.
For this input, the first element should be selected since there are
more
than 3 more dates within one year (basically, all other dates are
within
one year) and at least one of them is more than
Dear all,
I have a large dataset of randomly generated weighed sample for which I
wish to compute a kernel density estimate.
I have used the np package successfully for smaller datasets, however
for the larger ones, they take too long when
using the cross validation options for bandwidth
I would like to plat some spaghetti plots from my data , ma data is as
follows
ak[1:3,]
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
[,8] [,9]
[1,] 0.3211745 0.4132568 0.5649930 0.6920562 0.7760113 0.8118568 0.8609301
0.9088819 0.9326736
[2,] 0.3159234
On Wed, Apr 4, 2012 at 4:22 PM, uday uday_143...@hotmail.com wrote:
I would like to plat some spaghetti plots from my data , ma data is as
See:
require(sos)
findFn('spaghetti')
Liviu
follows
ak[1:3,]
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
[,8] [,9]
I have a huge list (returned by fromJSON) with elements like this:
$`zz/3260`
$`zz/3260`$name
[1] myname
$`zz/3260`$status
[1] active
$`zz/3260`$vectors
$`zz/3260`$vectors$`vector/241`
$`zz/3260`$vectors$`vector/241`$channel
[1] channel/300
$`zz/3260`$vectors$`vector/241`$targets
I am sure a common need is to plot a scatterplot with some fitted
line(s) and maybe save to a file.
I have this:
plot.glm - function (x, y, file = NULL, xlab = deparse(substitute(x)),
ylab = deparse(substitute(y)), main = NULL) {
m - glm(y ~ x)
if (!is.null(file))
Please first search yourself before posting.
Google on R convert list to data frame.
-- Bert
On Wed, Apr 4, 2012 at 8:11 AM, Sam Steingold s...@gnu.org wrote:
I have a huge list (returned by fromJSON) with elements like this:
$`zz/3260`
$`zz/3260`$name
[1] myname
$`zz/3260`$status
[1]
I'm not sure what your definition of easier would be, but there are some style
things you might want to be aware of:
I) the name is likely to hit up against the S3 generic plot() when applied to a
glm object. This might lead to strange bugs at some point.
II) you can test !is.null once and use
I'd like to make the distinction between the purpose of factors, i.e.,
what they are intended for, and how that purpose is accomplished.
Their purpose is for use in statistical models. The simplest example is
analysis of variance, where predictors are commonly referred to as
factors. Factors in R
On Apr 4, 2012, at 11:30 AM, R. Michael Weylandt michael.weyla...@gmail.com
wrote:
I'm not sure what your definition of easier would be, but there are
some style things you might want to be aware of:
I) the name is likely to hit up against the S3 generic plot() when
applied to a glm
Hi Liviu ,
thanks for post , but I could not find findFn('spaghetti') , I can see the
following functions in sos package
Extract.findFn
findFn
grepFn
hits
installPackages
PackageSum2
PackageSummary
print.findFn
sortFindFn
summary.findFn
unionFindFn
writeFindFn2xls
--
View this
On Wed, Apr 4, 2012 at 5:04 PM, uday uday_143...@hotmail.com wrote:
Hi Liviu ,
thanks for post , but I could not find findFn('spaghetti') , I can see the
following functions in sos package
Extract.findFn
findFn
After installing 'sos', use the 'findFn()' function. For example, run
You can create distance matrices for each Variable, square them, sum them,
and take the square root. As for getting the data into a data frame, the
simplest would be to enter the three variables into six columns like the
following:
data
[,1] [,2] [,3] [,4] [,5] [,6]
[1,]1215
Try
A[[1]] - NA
(It is of course up to you to do the tests, presumably using if(), to
decide when to assign NA to the list element.)
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 3/31/12 7:53 PM, michaelyb
On Tue, Apr 3, 2012 at 6:22 PM, Peter Ehlers ehl...@ucalgary.ca wrote:
On 2012-04-03 15:49, ilai wrote:
Try to plot the points first followed by vis.gam(...,type='contour',
color='bw', add=T) instead of vis.gam followed by points.
HTH
Or, if vis.gam gives you default scales that you wish
On Wed, Apr 04, 2012 at 01:32:10PM +0200, paladini wrote:
Hello,
I want to do a cluster analysis with my data. The problem is, that the
variables dont't consist of single value but the entries are pairs of
values.
That lokks like this:
Variable 1:Variable2: Variable3: ..
Carl Witthoft c...@witthoft.com writes:
Hi,
While playing with quantile-quantile plots, I wrote up some code which
plots something strangely different. Here's the pseudocode:
testhist - hist(sample_data)
refhist - hist(rnorm(n, mean=0,sd=1)) # for some large-ish n
cumtest -
Dear Sir,
I saw a question from a member in 2007 asking for regime switching model
and I am looking for the same kind of model.
I also saw a project named RSNL but I don't know if this one is
available and if we can have access to the code to change things if
needed... actually I used to build
On Wed, Apr 4, 2012 at 6:05 AM, David Winsemius dwinsem...@comcast.net wrote:
On Apr 3, 2012, at 11:16 PM, David Lyon wrote:
Sorry that didnt work for me, any ideas?
You _could_ indicate which package the image.plot function comes from. You
_could_ include dput on a sufficient segment of
How are you calculating the correlations? That may be part of the
problem, when you categorize a continuous variable you get a factor
whose internal representation is a set of integers. If you try to get
a correlation with that variable it will not be the polychoric
correlation.
Also do you
sorry, google does give a good start.
Google on R convert list to data frame.
as.data.frame(do.call(rbind,a))
returns an object which I don't understand.
summary(f)
name.Length name.Class name.Modestatus
1 -none- characterLength:4445
1
On Wed, Apr 4, 2012 at 10:12 AM, Petr Savicky savi...@cs.cas.cz wrote:
On Wed, Apr 04, 2012 at 01:32:10PM +0200, paladini wrote:
Var1 - c((1,2), (7,8), (4,7))
Var2 - c((1,5), (3,88), (12,4))
Var3 - c((4,2), (6,5), (4,4))
DF - data.frame(Var1, Var2, Var3, stringsAsFactors=FALSE)
If you
??? What is a?
?str
str(a)
?do.call
On Wed, Apr 4, 2012 at 9:34 AM, Sam Steingold s...@gnu.org wrote:
sorry, google does give a good start.
Google on R convert list to data frame.
as.data.frame(do.call(rbind,a))
returns an object which I don't understand.
summary(f)
name.Length
On 03.04.2012 19:43, Drew Tyre wrote:
A final followup. I have identified a rather extreme workaround. The
problem arises when the function utils:::unpackPkgZip uses file.rename(...)
to move the unzipped binary package from the temporary directory that it
was unpacked into into the proper
On 2012-04-03 20:03, Rmh wrote:
yes. See ?glht in the multcomp package, and the examples using glht in ?MMC in
the HH package.
Sent from my iPhone
Thank you very much for the clues. However, I can't figure out how to
construct the linfct in glht.
I also tried to inverse the computation
My $.01 contribution without having read the complete thread:
Some other process/service is locking your file/directory. There are
a few Windows tools out there helping your to narrow down exactly
which, e.g.
http://www.guidingtech.com/10175/tools-to-delete-locked-files-in-windows/
/Henrik
Bob O'Hara rni.boh at gmail.com writes:
On 4 April 2012 05:35, Jack Tanner ihok at hotmail.com wrote:
samplesBgr(beta) # crash
samplesBgr(beta, plot=FALSE) # also crash
Have you plotted your histories? I haven't used samplesBgr() much, so I
don't know how stable it is (although I do
Hi,
I am using power.law.fit to get an mle-class object in tmp and print
summary(tmp), coef(tmp) and logLik(tmp). I wanted to print the std. error for
alpha separately as I want to show these values concisely in a graph legend.
coef(summary(tmp)) displays the alpha and std. error jointly,
Hi,
First, thank you to Duncan Mackay for getting me started processing dates
with R. Unfortunately, I need to do a little more than I initially expected.
I have 5K lines of data that look like this:
ID AREA DATE
0001 Center 2010-10-15
0002 Center 2010-01-02
0003
Hi Liviu ,
now I can see that function but the problem is that its only applicable for
single data frame. as I wrote in my first post that I got 2 different matrix
with same dimensions ( 3x 12 here in example) , so if I plot normal plot
using plot function
plot(ak[1,],pre[1,],type=l)
Okay, will do. Thanks for all the handy advice Gabor. Ugh, it's such a stupid
bug once I actually know what is going on. I need to go over my Unix
date/time format specifiers, and I'll probably use the rep function to
simplify and reducing the amount of code. A lot of that is definitely new to
me.
Hello,
uday wrote
Hi Liviu ,
now I can see that function but the problem is that its only applicable
for single data frame. as I wrote in my first post that I got 2 different
matrix with same dimensions ( 3x 12 here in example) , so if I plot normal
plot using plot function
Greetings,
I wish to conduct a meta-analysis for which the outcome is a continuous
variable measured on the same individuals before and after an intervention.
Hence, the comparison is not made between two groups, but within groups, at
diffrent times.
Each study reports the mean outcome and
Can't you just combine your matrices into a single matrix: rbind() or
cbind() should do the job.
Michael
On Wed, Apr 4, 2012 at 12:24 PM, uday uday_143...@hotmail.com wrote:
Hi Liviu ,
now I can see that function but the problem is that its only applicable for
single data frame. as I wrote in
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Saruman
I dont see how this answered the original question of the poster.
He was quite clear: the value of the predictions coming out
of RF do not
match what comes out of the predict function using
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Sam Steingold
plot.glm - function (x, y, file = NULL, xlab =
deparse(substitute(x)),
ylab = deparse(substitute(y)), main = NULL) {
m - glm(y ~ x)
Thanks everyone for the advice, you raise interesting points. Maybe the
best thing for me to do is do an ANOVA in R with binomial data (if
possible) and find the lowest dose that gives a significant difference from
the controls.
On Mon, Apr 2, 2012 at 2:45 PM, Danielle Duncan
Thanks for your reply!
1. the strings I replaced with and are very long; I wish I
could replace them in the object all, not just in text
2. `all` is the result of
as.data.frame(do.call(rbind,l),stringsAsFactors = FALSE)
3. I get my data frame as
fr - data.frame(audience =
I suppose I'll just report a LC10 using the dose.p function in the package
MASS using my glm fitted logistic regression on binomial data. Thanks
everyone for ideas input! The LOEC seems to be a flawed
calculation...I'll research it. Again, thanks all!
On Mon, Apr 2, 2012 at 2:45 PM, Danielle
Hello Folks,
When I run the document below through sweave, rgui.exe/rsession.exe
leaves a file handle open to the sweave-001.pdf graphic (as verified by
process explorer). Pdflatex.exe then crashes (with a Permission Denied
error) because the graphic file is locked.
This only seems to happen
Hi all,
I am constructing a likelihood involving the following
lbeta(j + a, k - j + b)
where j,k are constants and a and b are parameters (0).
While doing the optimization, the error sometimes occurs,
In lbeta(j + a, k - j + b) : underflow occurred in 'lgammacor'
Is there a way to avoid it?
See ?closeAllConnections
Suggestion to the maintainer of Sweave: atomify the figure
generation, e.g. use { pdf(); on.exit(dev.off()); {...}; } or similar,
instead of { pdf(); {...}; dev.off(); } possibly by leaving a copy of
the fault figure file for troubleshooting.
/Henrik
On Wed, Apr 4, 2012
Thanks for the reply, Henrik. Process Explorer still shows the file
handle as being open, but R only shows the following:
showConnections(all=TRUE)
description class mode text isopen can read can write
0 stdin terminal r text opened yesno
1 stdoutterminal w text opened
Herik's suggestion is an absolutely good practice which guarantees the
device is always closed. That is what I did in the knitr package, so
you can probably take a look at http://yihui.name/knitr/
Regards,
Yihui
--
Yihui Xie xieyi...@gmail.com
Phone: 515-294-2465 Web: http://yihui.name
Department
DEADLINE FAST APPROACHING – 8th Annual International R User Conference
useR! 2012, Nashville, Tennessee USA
Registration Deadlines:
Early Registration: Passed
Regular Registration: Mar 1- May 12
Late Registration: May 13 – June 4
On-Site Registration: June 12 – June 15
Please note: Nashville is
Hello,
I am relatively new to R, and I am trying to select the last
observation within a group, where the group is defined by two
variables. One of the variables is a date.
In the below example, C3 varies within C2, which varies within C1. I
need to select the last observation in C3 for 4
Hello everyone,
I want to do a meta-analysis of case-control studies on which an OR was
computed based on a continuous exposure. I have found several several
packages (metafor, rmeta, meta) but unless I misunderstood their main
functions, it seems to me that they focus on two-group comparisons
Tena koe Naomi
There are lots of ways to do this. Here are a couple (note I've made a minor
modification to your example):
naomi
C1 C2 C3
1 1 x 1
2 1 x 2
3 1 y 1
4 1 y 2
5 2 x 1
6 2 x 2
7 2 x 3
8 2 y 1
9 2 y 2
tapply(naomi[,3], naomi[,1:2], function(x)
Since R has the same namespace for functions and variables,
c - 1
kills the global function, which can be restored by
c - get(c,mode=function)
Is there a way to prevent R from overriding globals
or at least warning when I do that
or at least warning when I replace a functional value with
* Sam Steingold f...@tah.bet [2012-04-04 14:58:15 -0400]:
1. the strings I replaced with and are very long; I wish I
could replace them in the object all, not just in text
i.e., I have a long list with elements with long names.
how do I replace all these long names with something
On 12-04-04 4:52 PM, Sam Steingold wrote:
Since R has the same namespace for functions and variables,
c- 1
kills the global function, which can be restored by
c- get(c,mode=function)
Is there a way to prevent R from overriding globals
or at least warning when I do that
or at least warning
HI,
I would like to extract data in a specific way. For example, the rainfall data
0,0,1.5,0,0, 3,1,2.5,0,0,0,0, 2.3,0,0,0, 2.1,1.4,0,0,0, 3,2,1,0,0,0...
data_1: 1.5, 2.3 ( a single nonzero data between zeros data)
data_2: 3.1, 2.5, 2.1,1.4 ( two nonzero data between zeros
HI,
I would like to extract data in a specific way. For example, the rainfall data
0,0,1.5,0,0, 3,1,2.5,0,0,0,0, 2.3,0,0,0, 2.1,1.4,0,0,0, 3,2,1,0,0,0...
data_1: 1.5, 2.3 ( a single nonzero data between zeros data)
data_2: 3.1, 2.5, 2.1,1.4 ( two nonzero data between
* Duncan Murdoch zheqbpu.qha...@tznvy.pbz [2012-04-04 17:00:32 -0400]:
There's no warning when you mask a function with a non-function at top
level, and little need for one, because R does the right search based on
the fact that you're making a function call:
c
[1] 1
c(1,2)
[1] 1 2
why
* Duncan Murdoch zheqbpu.qha...@tznvy.pbz [2012-04-04 17:00:32 -0400]:
There's no warning when you mask a function with a non-function at top
level, and little need for one, because R does the right search based on
the fact that you're making a function call:
c
[1] 1
c(1,2)
[1] 1 2
why
On Thu, Apr 5, 2012 at 8:24 AM, Marie-Pierre Sylvestre
mp.sylves...@gmail.com wrote:
Hello everyone,
I want to do a meta-analysis of case-control studies on which an OR was
computed based on a continuous exposure. I have found several several
packages (metafor, rmeta, meta) but unless I
On Apr 4, 2012, at 4:54 PM, Sam Steingold wrote:
* Sam Steingold f...@tah.bet [2012-04-04 14:58:15 -0400]:
1. the strings I replaced with and are very long; I wish I
could replace them in the object all, not just in text
i.e., I have a long list with elements with long names.
how
Hi Peter,
Thanks! This was very helpful and worked perfectly.
Naomi
On Apr 4, 2012, at 4:52 PM, Peter Alspach wrote:
Tena koe Naomi
There are lots of ways to do this. Here are a couple (note I've
made a minor modification to your example):
naomi
C1 C2 C3
1 1 x 1
2 1 x 2
3 1 y
you need to subtract the length of gap in y-axis.
Good luck!
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Hello,
The by function does not seem to allow two variables in the Indices
argument:
Yes it does, but you must use a list of variables.
(Read the help for 'by': INDICESa factor or a list of factors, each of
length nrow(data).)
mydata - read.table(text=
C1 C2 C3
1 x 1
1 x 2
1 y 1
json_dir is a list of JSON lists mapping lat/long route points between
locations using CloudMade's API.
post_url is the URL of the HTTP request
for (n in json_dir) {
i = i + 1
if (typeof(json_dir[[i]]) != NULL) {
if (i == 1) {
dat_add
I am new to R and have been spinning my wheels on the following.
*Issue:* I have a membership to a website, and I want to grab data from
the website using download.file().
download.file(url, destfile, method, quiet = T, mode = w, cacheOK = TRUE)
The R Documentation is helpful. However, I have
Have you looked at plyr?
Generally, ldply works well for this sort of thing.
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Hello,
Roslina Zakaria wrote
HI,
I would like to extract data in a specific way. For example, the rainfall
data
0,0,1.5,0,0, 3,1,2.5,0,0,0,0, 2.3,0,0,0, 2.1,1.4,0,0,0, 3,2,1,0,0,0...
data_1: 1.5, 2.3 ( a single nonzero data between zeros data)
data_2:
On 04/04/12 22:32, Bert Gunter wrote:
Rolf:
Google on load functions into R.
A post referencing source() (from Henrik Bengtsson is the first hit.
Tried that just now. The only hits I got were to *your* post; no hits
on any post from Henrik Bengtsson.
These things are never as easy and
Greetings!
I want to have the coefficients that R uses in shapiro.test()
for the Shapiro-Wilk test for a prticular sample size, i.e.
the a[i] in
W = Sum(a[i]*x[i])/(Sum(x[i] - mean(x))^2)
(where the x[i] are sorted). Two questions:
Q1:
Is there a readymade R function from which I can extract
I just tried it, because I'm curious that way.
If I search for
load functions into R
I get only this thread.
If I search for
load functions into R
(no quotes), I get the referenced discussion from Henrik Bengtsson:
ttps://stat.ethz.ch/pipermail/r-help/2008-September/173606.html
As in so many
On 05/04/12 10:10, Sarah Goslee wrote:
I just tried it, because I'm curious that way.
If I search for
load functions into R
I get only this thread.
If I search for
load functions into R
(no quotes), I get the referenced discussion from Henrik Bengtsson:
Are you aware that the summary function normally returns a data value that you
can extract values from and format to your hearts desire?
try
str(coef(summary(tmp)))
and read ?mle-class
(and try to provide a reproducible example next time)
On Apr 4, 2012, at 6:10 PM, Sarah Goslee wrote:
I just tried it, because I'm curious that way.
If I search for
load functions into R
I get only this thread.
If I search for
load functions into R
(no quotes), I get the referenced discussion from Henrik Bengtsson:
Having problems with the write.table function. I can write a tab delimited
file just fine, but for each line in my matrix its inputs a carriage return
when i dont want it to.
For example my matrix might be:
ID V1 V2 V3
FARY1004 1 2 3
FARY2067 2 3 1
FARY4587 2 2 2
And I want the written File to
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