On Jul 8, 2012, at 23:39 , ycyi121 wrote:
> Hi,
>
> I have great difficulty in simulation the a dataset based in a loading
> matrix [c(1,1,1,2,3,3,3,4,4,3,2,2,1,1), 7, 2) and an error covariance matrix
> is 2*I. I have to simulate a dataset with 7 variables and 50 rows. I search
> a lot and did
Spencer:
Just for fun, may I hazard a guess: It would be messy to retain time zones
if your were concatenating objects with more than one time zone among them.
"Normalizing" everything to a single zone probably also makes subsequent
operations on the results much easier.
Not that it couldn't be
Hello:
What is the recommended method for retaining the tzone attributes
when concatonating POSIXct objects?
(d1 <- ISOdate(1970,1,1)) # Sets the tzone attribute = GMT
[1] "1970-01-01 12:00:00 GMT"
(d1.2 <- c(d1, d1)) # c(..) strips the tzone attribute, displays in
the time zone of
Hi,
I want using zero-inflated negative binomial regression model to
classify data(a vector of data), that is I want know each observed value is
more likely belong to the "zero" or "count" distribution(better with
relative probability). My data is some like:
count site samp
1290911
Dear useRs
I need to do graphs with dates in different languages on Ubuntu.
In Windows the following will plot the date axis labels in Spanish:
random.dates <- as.Date("2001/1/1") + 70*sort(stats::runif(100))
>language <- "Spanish"
>Sys.setlocale("LC_TIME", language)
>plot(random.dates, 1:100, x
Since you did not provide an example of the file, I will take a guess
at the content and show to to extract the values and take the mean of
all of them since you did not say if you want the mean of each file,
or a single means.
myData <- do.call(c, lapply(1:65, function(.file){
x <- read.c
Hello,
I'm coming straight to the point:
I have 65 .txt-Files named "XYZ_1.txt" to "XYZ_65.txt" (each number
represents a test subject).
I have to open them in Microsoft Excel to see the exact structure.
In each of those .txt-files there are reaction time values (in milliseconds)
from line 15,
Thank you very much Professor. David L Carlson .. This method saves my time!!
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___
Hi,
I have great difficulty in simulation the a dataset based in a loading
matrix [c(1,1,1,2,3,3,3,4,4,3,2,2,1,1), 7, 2) and an error covariance matrix
is 2*I. I have to simulate a dataset with 7 variables and 50 rows. I search
a lot and did find some information on this, for example, using rmvnor
Hi Petr,
I think sprintf and formatC are identical as it can round >22 decimal places as
opposed to print and signif
print(pi,digits=35)
Error in print.default(pi, digits = 35) : invalid 'digits' argument
signif(pi,digits=22)
[1] 3.141593
a<-sprintf("%.35f",pi)
a
[1] "3.1415926535897931159979634
Hi,
As the error says, the replacements should have equal number of rows.
You can either do it adding NAs,
df$V1<-c(NA,rollapply(df$V1,3,mean),NA)
df
V1
1 NA
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
10 NA
#or,
#use any of these
#as Michael suggested
df2<-rollapply(df,3,mean,fill=NA)
On Fri, 6 Jul 2012 21:13:32 +0530
umesh khatri wrote:
> Dear everyone
>
> I'm dealing with a problem related to Poisson Ridge Regression. If
> anyone can help me in this regard by telling if any changes in the
> source code of "glm.fit" may help
>
>
You've posted this problem twice under diff
The message concerning readline is common in compiling console mode
programs. If you search on readline, you'll learn what it does. Since
you are compiling source, the header files for the appropriate
libraries need to available in the path. You need to install the
readline and readline.h files
On 12-07-08 3:23 PM, Erin Hodgess wrote:
Dear R People:
I'm starting to think that I should just install from the binary, but
here is my latest effort to install from source on a Windows 7 64 bit:
It looks as though your path is messed up. You shouldn't have mingw32
tools on it.
The entrie
Should this not be attributed to DescaRtes?
Ted.
On 08-Jul-2012 18:41:17 Achim Zeileis wrote:
> On Sun, 8 Jul 2012, Spencer Graves wrote:
>
>> Hello, All:
>>
>> "I think therefore I R", according to the header on several R-Tutorials
>> by William B. King, PhD, Coastal Carolina University
>
On Sun, Jul 8, 2012 at 2:32 AM, Diana Marcela Martinez Ruiz
wrote:
> Hello,
>
> I would like to know how to test the assumption of proportional odds or
> parallel lines or slopes for an ordinal logistic regression with svyolr
I wouldn't, but if someone finds a clear reference I'd be prepared to
On Sat, Jul 07, 2012 at 11:52:35AM +0300, Martin Ivanov wrote:
> Dear R users,
>
> I need a function that gets a number and returns its number of actual decimal
> places.
> For example f(3.14) should return 2, f(3.142) should return 3, f(3.1400)
> should also return 2
> and so on. Is such funct
On Sun, Jul 08, 2012 at 11:39:22AM -0700, arun wrote:
> Hi Petr,
>
> I think sprintf and formatC are identical as it can round >22 decimal places
> as opposed to print and signif
> print(pi,digits=35)
Hi Arun:
Thank you for pointing this out. Funtion formatC()
is easier to use and uses the same
Dear R People:
I'm starting to think that I should just install from the binary, but
here is my latest effort to install from source on a Windows 7 64 bit:
c:\R64\R-patched>cd src
cd src
c:\R64\R-patched\src>cd gnuwin32/
cd gnuwin32/
c:\R64\R-patched\src\gnuwin32>set TMPDIR=c:\temp
set TMPDIR=c
On Sun, 8 Jul 2012, Spencer Graves wrote:
Hello, All:
"I think therefore I R", according to the header on several R-Tutorials
by William B. King, PhD, Coastal Carolina University
(http://ww2.coastal.edu/kingw/statistics/R-tutorials).
Might this be appropriate for "fortunes"?
N
On Sat, Jul 07, 2012 at 01:12:34PM +0100, Ted Harding wrote:
> I had thought of also (as well as my numerical routing) suggesting
> a "gsub()" type solution like Joshua's below, but held back because
> the result could depend on how the number arose (keyboard input,
> file input, or from computatio
Hello, All:
"I think therefore I R", according to the header on several
R-Tutorials by William B. King, PhD, Coastal Carolina University
(http://ww2.coastal.edu/kingw/statistics/R-tutorials).
Might this be appropriate for "fortunes"?
Spencer
--
Spencer Graves, PE, PhD
Your
On Sun, Jul 8, 2012 at 12:22 PM, Stathis Kamperis wrote:
> 2012/7/8 Michael Weylandt :
>>
>>
>> On Jul 8, 2012, at 9:31 AM, Stathis Kamperis wrote:
>>
>>> Hello everyone,
>>>
>>> I have a dataframe with 1 column and I'd like to replace that column
>>> with a moving average.
>>> Example:
>>>
On 2012-07-08 06:57, fabiano wrote:
Thanks Peter.
We had a look at both Hab and habitat. These are integers representing
habitat types.
habitat <- read.csv("Ungulate_vegetation.csv")
habitat <- habitat[,3]
habitat
[1] 3 3 4 3 3 3 4 4 3 3 3 3 3 4 2 3 2 3 2 3
Hab <- cbind(seq(1,20),habitat)
Hab
On Jul 8, 2012, at 16:52 , John C Nash wrote:
> This looks like a homework trap set up to catch those trying to use
> facilities like Rhelp.
>
> f = exp(x^2-y+z^(-1))= exp(x^2) * exp(1/z)/exp(y)
>
> To maximize clearly needs biggest x (37), smallest y (2) and a z that
> makes exp(1/z) big -- 0
On Jul 8, 2012, at 9:31 AM, Stathis Kamperis wrote:
> Hello everyone,
>
> I have a dataframe with 1 column and I'd like to replace that column
> with a moving average.
> Example:
>
>> library('zoo')
>> mydat <- seq_len(10)
>> mydat
> [1] 1 2 3 4 5 6 7 8 9 10
>> df <- data.frame("V1"
Hello everyone,
I have a dataframe with 1 column and I'd like to replace that column
with a moving average.
Example:
> library('zoo')
> mydat <- seq_len(10)
> mydat
[1] 1 2 3 4 5 6 7 8 9 10
> df <- data.frame("V1" = mydat)
> df
V1
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
In general, you should try to keep your version of R current rather than
lagging behind. If you would just search the Web yourself for keywords like
install R Ubuntu 11.04
you would find many discussions of this topic. A key file to read is [1]
[1] http://cran.r-project.org/bin/linux/ubuntu/RE
On Jul 8, 2012, at 7:55 AM, SKrishna wrote:
Hi, Thanks for the reply.
Sex[120:144]<-factor(TG) #Renaming some males to transgender, to
create 3 groups, male, female and transgender
Sorry, that should have been
Sex[120:144]<-factor('TG')
The original line did not have the quotes.
I show
On 08.07.2012 16:51, R Heberto Ghezzo, Dr wrote:
Hello, I am running Win XP in a notebook IEEE, I have R-2-15.0 and R-2.15.1. In
a subdirectory Cran I
have the packages I downloaded from CRAN (all), after last update when I type
library()
Error in .readRDS(pfile) : unknown input format
Hmm
On 08.07.2012 13:02, deeksha.malhan wrote:
Hi
I am working on co-expression analysis of rice dataset with the help of
wgcna and R but now I am at one point which is showing error as shown below
:
dissTOM = 1-TOMsimilarityFromExpr(datExpr, power = 8);
Error: cannot allocate vector of size 2
On 08.07.2012 14:08, hanansela wrote:
Hello
I am an Ubuntu 11.04 and R version 2.12 user. I am using Rkward as a GUI
for R . Some of the packages I need were build on 2.14. Therefore i need to
upgrade to 2.14. Rkward needs version 2.14 or less. but the version name
cant be with suffix like
This looks like a homework trap set up to catch those trying to use facilities
like Rhelp.
f = exp(x^2-y+z^(-1))= exp(x^2) * exp(1/z)/exp(y)
To maximize clearly needs biggest x (37), smallest y (2) and a z that
makes exp(1/z) big -- 0. Except that you'll get Inf etc.
Actually, several of the op
Hello, I am running Win XP in a notebook IEEE, I have R-2-15.0 and R-2.15.1. In
a subdirectory Cran I
have the packages I downloaded from CRAN (all), after last update when I type
> library()
Error in .readRDS(pfile) : unknown input format
>
a very old R-2.4.0 sitting in a corner and not used for
Thanks Peter.
We had a look at both Hab and habitat. These are integers representing
habitat types.
habitat <- read.csv("Ungulate_vegetation.csv")
habitat <- habitat[,3]
habitat
[1] 3 3 4 3 3 3 4 4 3 3 3 3 3 4 2 3 2 3 2 3
Hab <- cbind(seq(1,20),habitat)
Hab
habitat
[1,] 1 3
[2
Below is R code that successfully reads the first line of a JSON file
(attached).
However, it is supposed to read 5 lines of the file, not just one. What is the
wrong?
>library("rjson")
>json_file <- "/Users/smcintyremobile/Google Drive/AAShelby/CORRESP/Services
>Rese
Hello
I am an Ubuntu 11.04 and R version 2.12 user. I am using Rkward as a GUI
for R . Some of the packages I need were build on 2.14. Therefore i need to
upgrade to 2.14. Rkward needs version 2.14 or less. but the version name
cant be with suffix like "natty" (as far as I understand). Is ther
hi all,
Prior to this post I asked a question how to deal with binary clustered data
when the crosstab by variables shows an empty cell. I figured out later that
such an empty cell corresponds to what is called "separation". Fortunately,
R package "logistf" is developed to handle such a problem u
Hi, Thanks for the reply.
> Sex[120:144]<-factor(TG) #Renaming some males to transgender, to
> create 3 groups, male, female and transgender
Sorry, that should have been
Sex[120:144]<-factor('TG')
The original line did not have the quotes.
>I'm getting the sense that this is homework. You
I would like to thank all of you for spending your precious time in ordrer to
help me out.
I really appreciate the fact that experienced R users replied to my
"newbie" post.
Regards,
Spiros Gkolfinopoulos
--
View this message in context:
http://r.789695.n4.nabble.com/Tables-extraction-in-R-tp46
Hi
I am working on co-expression analysis of rice dataset with the help of
wgcna and R but now I am at one point which is showing error as shown below
:
dissTOM = 1-TOMsimilarityFromExpr(datExpr, power = 8);
Error: cannot allocate vector of size 2.8 Gb
In addition: Warning messages:
1: In matr
It's all documented in ?regexp. "." is a regex metacharacter.
Metacharacters have to be escaped via "\\".
In particular, note:
"The fundamental building blocks are the regular expressions that match a
single character. Most characters, including all letters and digits, are
regular expressions th
Works perfectly. Thank you very much indeed.
John Kane
Kingston ON Canada
> -Original Message-
> From: dwinsem...@comcast.net
> Sent: Sat, 7 Jul 2012 21:45:58 -0400
> To: jrkrid...@inbox.com
> Subject: Re: [R] Splitting a character vector.
>
>
> On Jul 7, 2012, at 5:37 PM, John Kane wr
On 08/07/2012 14:35, Uwe Ligges wrote:
On 08.07.2012 14:47, syrvn wrote:
Hello,
when I use list.files with recursive = TRUE and all.files = TRUE, R
returns
a list of strings/paths.
From all those strings I want to keep only the ones starting with a .
I tried using grep to achieve that. Howe
On 08.07.2012 14:47, syrvn wrote:
Hello,
when I use list.files with recursive = TRUE and all.files = TRUE, R returns
a list of strings/paths.
From all those strings I want to keep only the ones starting with a .
I tried using grep to achieve that. However, the problem is that because of
the
Hello,
when I use list.files with recursive = TRUE and all.files = TRUE, R returns
a list of strings/paths.
>From all those strings I want to keep only the ones starting with a .
I tried using grep to achieve that. However, the problem is that because of
the recursive list.files parameter,
for som
On Jul 8, 2012, at 4:11 AM, Suresh Krishna wrote:
Hi,
I am a very occasional user of R, and will be grateful for some
help in constructing a regression across groups.
Here is an example:
library(MASS)
attach(cats)
Sex[120:144]<-factor(TG) #Renaming some males to transgender, to
create
Good day R list
I want to transform an autoregressive distributed lag (ARDL) to a
long-run equation
(reparametrization of the (ARDL). How could i do that?
This equation is displayed in this link
https://docs.google.com/file/d/0B4dAkTAHpGBDSjA4RmlnbkxoLVU/edit
Many thanks in advance
Hello,
There are several optimization functions in R. There's even a group
dedicated to the field. See the CRAN Task View: Optimization and
Mathematical Programming.
To use optim(), you could do something like
f <- function(x, y, z) (x^2 - y - z^2/2) # I've changed the function
negf <- funct
Hello,
You don't need an optimzation routine to know that the maximum of this
function is +Inf. It's attained at z = 0+ (when z converges to zero by
positive values).
This breaks the R function optim(), by the way. It
" needs finite values of 'fn' "
Hope this helps,
Rui Barradas
Em 08-07-
Hello,
Em 08-07-2012 03:00, Peter Ehlers escreveu:
On 2012-07-07 14:56, YTP wrote:
Hi Rui,
Thanks for responding. I did not write "raw=raw", and I'm not sure why R
would return such a misleading error message. Indeed, the same error
message
comes up when I run the 2nd part of your code:
m <
guRus!
I have a function f = exp(x^2-y+(1/z))
Also, x can take values from 1 to 37, y from 2 to 20 and Z from -13 to 51.
How can I find the maximum of f using any of the optimization functions
please?
Is there a way to store the possible values of x, y and Z in a single
variable like in a List
Hi,
I am a very occasional user of R, and will be grateful for some help in
constructing a regression across groups.
Here is an example:
library(MASS)
attach(cats)
Sex[120:144]<-factor(TG) #Renaming some males to transgender, to create 3
groups, male, female and transgender
out<-lm(Bwt
Hi,
Try this:
dat1<-data.frame(var1=15:25)
dat1$var2<-NA
dat1$var2[2:11]<-dat1$var1[1:10]
dat1
var1 var2
1 15 NA
2 16 15
3 17 16
4 18 17
5 19 18
6 20 19
7 21 20
8 22 21
9 23 22
10 24 23
11 25 24
You can also do the same within the sin
On 07/07/2012 03:23 AM, Greeknovice wrote:
Hi,
I 'm a novice user of R statistics and my hands-on experience with it is
minimal.
I want to create a table for my MBA course assignment that looks like the
ones that SPSS and MS Excel produces ,the data that the table has to include
are the following
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