WR == Worik R wor...@gmail.com
on Tue, 11 Dec 2012 19:59:58 +1300 writes:
WR On Tue, Dec 11, 2012 at 7:49 PM, Jeff Newmiller
jdnew...@dcn.davis.ca.uswrote:
What about putting your objects in a list, which does not have the search
through parents semantics?
Thank you for that Pascal.
I changed this bit to the following:
result - vector(list, (length(test1)-1))
for(i in 1:(length(test1)-1))
{
for(j in i+1:length(test1))
{
result[[i]][j-i] - agrep(test1[i], test1[j], ignore.case = TRUE, value =
TRUE, max.distance = 0.1)
}
}
And now I get the
On Mon, Dec 10, 2012 at 11:46:40PM -0500, David Kulp wrote:
I'd like to write unicode strings using the \u escape syntax. According to
the documentation, print.default or encodeString will escape unicode using
the \u convention. In practice, I can't make it work.
b=Unicode character:
Hello,
Probably because 'result' doesn't have the expected size/number of
dimension. How do you create it?
Regards,
Pascal
Le 11/12/2012 19:46, surekha nagabhushan a écrit :
Thank you for that Pascal.
I changed this bit to the following:
result - vector(list, (length(test1)-1))
for(i in
Hi,
I've got a dataframe having a code as column name.
Addtionally I have another dataframe with a two columns (and lots of
rows), the first
containing the code and the second some Text (real name).
Now I'd like to use the information (pairs of code and name) of the
second dataframe to rename
Hello,
And another error in line 2. It should be
for(j in (i+1):length(test1))
Hope this helps,
Rui Barradas
Em 11-12-2012 07:54, Pascal Oettli escreveu:
Hi,
There is a mistake in the first line. It should be:
for(i in 1:(length(test1)-1))
Regards,
Pascal
Le 11/12/2012 16:01, surekha
Le mardi 11 décembre 2012 à 01:10 +0100, Richard Zijdeman a écrit :
Dear all,
I have imported a dataset from Stata using the foreign package. The
original data contain French characters such as and .
After importing, string variables containing names of French
departments have changed.
Dear all,
I have a big file containing latitude points(-10 to 80) and
corresponding values.
Example data
Lat=c(69.48134, 69.49439, 69.50736, 69.52026, 69.52438, 69.53308,
69.53746, 69.54365, 69.54582, 69.6884, 69.69272, 69.998, 70.00055,
70.00106, 70.00295, 70.00308, 70.00363, 70.00427,
Pascal,
result_vector - vector()
result - vector(list, (length(test1)-1))
for(i in 1:(length(test1)-1))
{
for(j in (i+1):length(test1))
{
result_vector[j-i] - agrep(test1[i], test1[j], ignore.case = TRUE, value
= TRUE, max.distance = 0.1)
}
result[[i]]- result_vector
}
I'm not sure
Hello,
Right, I didn't notice. Apologies.
Pascal
Le 11/12/2012 19:55, Rui Barradas a écrit :
Hello,
And another error in line 2. It should be
for(j in (i+1):length(test1))
Hope this helps,
Rui Barradas
Em 11-12-2012 07:54, Pascal Oettli escreveu:
Hi,
There is a mistake in the first
Hello,
See if this is it. You must reinitialize 'result_vector' just before the
loop that constructs it.
test1 - c(Vashi, Vashi,navi Mumbai, Thane, Vashi,new Mumbai,
Thana, Surekha, Thane(w), surekhaN)
result - vector(list, (length(test1)-1))
for(i in 1:(length(test1)-1)){
df - data.frame(A=(1:10),B=(1:10),C=(1:10))
# my changes to show that order doesn't matter
df_names - data.frame(code=c(C,A,D,E,B),name=c(Col C,Col
A,Col D,Col E,Col B))
names( df ) - df_names[ match( names( df ) , df_names[ , 'code' ] ) ,
'name' ]
for more detail see
?match
On Tue, Dec 11,
Rui,
I have initialized it...doesn't seem to help...
result_vector - vector()
result - vector(list, (length(test1)-1))
for(i in 1:(length(test1)-1))
{
for(j in (i+1):length(test1))
{
result_vector[j-i] - agrep(test1[i], test1[j], ignore.case = TRUE, value
= TRUE, max.distance = 0.1)
}
On 12-12-10 8:46 PM, Worik R wrote:
On Tue, Dec 11, 2012 at 2:27 PM, Duncan Murdoch
murdoch.dun...@gmail.com mailto:murdoch.dun...@gmail.com wrote:
On 12-12-10 7:33 PM, Worik R wrote:
Let me restate my question.
Is there a straightforward way of ensuring I can use the
On 12-12-11 12:42 AM, Worik R wrote:
You may find it more reliable to define an environment in which you
will be storing your data (perhaps globalenv(), perhaps something created
by new.env()) and then testing for existence of a dataset by a given name
in that environment.
I did that.
On 12-12-11 5:49 AM, Jan T Kim wrote: On Mon, Dec 10, 2012 at
11:46:40PM -0500, David Kulp wrote:
I'd like to write unicode strings using the \u escape syntax.
According to the documentation, print.default or encodeString will
escape unicode using the \u convention. In practice, I can't make
Thomas,
Thanks for enlighting me about using pnorm.The reason I was going to
use the double integral was for the cumulative distribution fuction F(X)
in the formula. I just tried your method, and it worked which saved me a
lot of time.
Thanks.
Kyong
On Thu, Dec 6, 2012 at 3:41 PM, Thomas
Hello,
Inline.
Em 11-12-2012 12:04, surekha nagabhushan escreveu:
Rui,
I have initialized it...doesn't seem to help...
result_vector - vector()
No! This must be just before the loop in 'j'
result - vector(list, (length(test1)-1))
for(i in 1:(length(test1)-1))
{
for(j in
I represent a graph as an adjacency matrix of class dgCMatrix (from the
Matrix package).
xx
5 x 5 sparse Matrix of class dgCMatrix
a b c d e
a . 1 1 . .
b 1 . 1 . .
c 1 1 . 1 1
d . . 1 . 1
e . . 1 1 .
To check if the matrix defines and undirected graph, I have made the following
Hi,
thank you so much, that works perfectly. I used
the first suggestion by Anthony (names( df ) - df_names[ match(
names( df ) , df_names[ , 'code' ] ) , 'name' ]).
Thank you for the hint about ?match... that was the function I was
looking for, makes comparing vectors very easy.
best,
/Johannes
Thanks, Jan. Unfortunately I have huge streams of data to transmit and it
should be mostly human readable, too, so escape encoding the entire string
isn't an option.
A workaround is that I found I can use the rjson package as in
cat(toJSON(fromJSON(\Unicode char: \ufffd\)))
Unicode char:
Dear all:
I have 10 response matrices with missing data.
I used difMH to detect DIF items.
syntax as:
n-10
difMH-list()
for (i in 1:10){
difMH[[i]]-difMH(respM[[i]], group=group, focal.name=1 , MHstat=MHChisq,
correct=TRUE, exact=FALSE, alpha=0.05, purify=FALSE,
nrIter=10,
Hi all,
I have been away from R for far too many months and have two questions.
One is likely simple, but not found under help or in many of the
available R ref., books.
1. How does one save the results of an analysis from the main console
to a file without the need to copy and paste?
2.
Hi,
On Tue, Dec 11, 2012 at 9:23 AM, Neotropical bat risk assessments
neotropical.b...@gmail.com wrote:
Hi all,
I have been away from R for far too many months and have two questions.
One is likely simple, but not found under help or in many of the available R
ref., books.
1. How does one
Dear useRs,
i have certain commands for some operations in R. They are good if you have a
small dataset but my dataset, apart from what i used in the recent past, is
prety large. I want to convert these massive sets of commands into a simple
loop.
Your help is required on it
thanks in advance
Does this solve your problem:
fakedata - matrix(runif(100), ncol=10)
fakedata.dist - apply(fakedata, 2, function(x)as.vector(dist(x,
upper=TRUE, diag=TRUE)))
The columns of the resulting matrix contain the distance vectors.
Sarah
On Tue, Dec 11, 2012 at 9:45 AM, eliza botto
In January I will be visiting Sarasota. The directory of user groups
http://blog.revolutionanalytics.com/local-r-groups.html
doesn't show any groups in Florida. Contact me off-list if interested in
an informal get-together. It might help start another RUG.
JN
Dear Sarah,
thankyou very much it worked...
what if i want traditional distance matrices instead of distance column
vectors??
i hope i'm not bothering you...
thanks in advance
eliza
Date: Tue, 11 Dec 2012 09:57:37 -0500
Subject: Re: [R] converting manual command to loop command
From:
Given the same artificial data I provided, this will store all the
dist objects in a list:
fakedata.dlist - lapply(1:ncol(fakedata),
function(x)dist(fakedata[,x], upper=TRUE, diag=TRUE))
Sarah
On Tue, Dec 11, 2012 at 10:15 AM, eliza botto eliza_bo...@hotmail.com wrote:
Dear Sarah,
thankyou
Hello,
Try the following.
tapply(Value, floor(Lat), FUN = mean)
6970
0.1805381 0.1617072
Hope this helps,
Rui Barradas
Em 11-12-2012 11:17, Swagath Navin escreveu:
Dear all,
I have a big file containing latitude points(-10 to 80) and
corresponding values.
Example data
On 12/11/2012 01:46 PM, Søren Højsgaard wrote:
I represent a graph as an adjacency matrix of class dgCMatrix (from the
Matrix package).
xx
5 x 5 sparse Matrix of class dgCMatrix
a b c d e
a . 1 1 . .
b 1 . 1 . .
c 1 1 . 1 1
d . . 1 . 1
e . . 1 1 .
To check if the matrix defines and
Hello, again.
Another possibility is
aggregate(Value, by = list(floor(Lat)), FUN = mean)
Rui Barradas
Em 11-12-2012 11:17, Swagath Navin escreveu:
Dear all,
I have a big file containing latitude points(-10 to 80) and
corresponding values.
Example data
Lat=c(69.48134, 69.49439, 69.50736,
Dear Milan,
thank you for kind suggestion. Converting the characters using:
iconv(department, ISO-8859-15, UTF-8)
indeed improves the situation in that now all values (names of departments) are
displayed in the plot, although the specific special characters are
unfortunately appearing as empty
HI,
Try this:
names(df)-df_names$name[df_names$code%in%names(df)]
head(df,2)
# Col A Col B Col C
#1 1 1 1
#2 2 2 2
A.K.
- Original Message -
From: Johannes Radinger johannesradin...@gmail.com
To: r-help@r-project.org
Cc:
Sent: Tuesday, December 11, 2012 5:55
HI,
You can also try this:
df - data.frame(A=(1:10),B=(1:10),C=(1:10))
df_names - data.frame(code=c(A,B,D,E,C),name=c(Col A,Col B,Col
D,Col E,Col C))
names(df)-df_names$name[match(names(df),df_names$code)]
A.K.
- Original Message -
From: Johannes Radinger johannesradin...@gmail.com
I have a simple R script which uses the psych package to calculate cohens
kappa (weighted) from a csv file. The csv file has 2 columns of ordinal data
- one ranked by an experienced observer and the other by a novice who is
undergoing training. What I would like to do is measure kappa for subsets
All,
I have the attached dataset which I read from SPSS and transformed a little
bit using the attached script. I am trying to run a logistic regression
using glm() on a subset of my data. When I run the logistic regression on
the whle dataset, it runs OK. As soon as I try to run on the subset, I
Hi:
I am trying to search PubMed abstracts which contains BOTH two terms:
COL4A1 AND Ocular. I am using the following code:
url= http://eutils.ncbi.nlm.nih.gov/entrez/eutils/esearch.fcgi?;
search = paste(url,
db=pubmedterm=COL4A1+AND+Ocular[abstract]retmax=300, sep=)
docId -
I'm attempting to use function varimpAUC in the Party package but get a not
found message. It was reportedly added September 26th to party_1.0-3, so I
wonder if it was not included in the Windows binary that I downloaded. Can
anyone please tell me how to access this function? Thanks in advance!
Greetings! I'm trying to use function varimpAUC in the party package
(party_1.0-3 released September 26th of this year). Unfortunately, I get the
following error message:
data.cforest.varimp - varimpAUC(data.cforest, conditional = TRUE)
Error: could not find function varimpAUC
Was this
Le mardi 11 décembre 2012 à 16:41 +0100, Richard Zijdeman a écrit :
Dear Milan,
thank you for kind suggestion. Converting the characters using:
iconv(department, ISO-8859-15, UTF-8)
indeed improves the situation in that now all values (names of
departments) are displayed in the plot,
Hello everyone,
I'm trying to install the tools to build packages under Fedora (17), and
have little luck finding anything useful using Google. I wanted to ask if
there is any documentation associated with this issue; a link will be very
useful.
Thank you very much.
[[alternative HTML
Le mardi 11 décembre 2012 à 15:09 +0100, Virgile Capo-Chichi a écrit :
All,
I have the attached dataset which I read from SPSS and transformed a little
bit using the attached script. I am trying to run a logistic regression
using glm() on a subset of my data. When I run the logistic regression
Le mardi 11 décembre 2012 à 17:18 +0100, Virgile Capo-Chichi a écrit :
Hello all,
I have the attached dataset which I read from SPSS and transformed a
little bit using the script below. I am trying to run a logistic
regression using glm() on a subset of my data. When I run the logistic
Trying again with a smaller data file. V
Hello all,
I have the attached dataset which I read from SPSS and transformed a little
bit using the script below. I am trying to run a logistic regression using
glm() on a subset of my data. When I run the logistic regression on the
whle dataset, it
Le mardi 11 décembre 2012 à 10:59 -0500, Tony Paredes a écrit :
Hello everyone,
I'm trying to install the tools to build packages under Fedora (17), and
have little luck finding anything useful using Google. I wanted to ask if
there is any documentation associated with this issue; a link
On Dec 11, 2012, at 9:59 AM, Tony Paredes tgal...@gmail.com wrote:
Hello everyone,
I'm trying to install the tools to build packages under Fedora (17), and
have little luck finding anything useful using Google. I wanted to ask if
there is any documentation associated with this issue; a link
By 'testing for existence in a given environment' I meant to use
exists(dataName, env=theEnvironment, inherits=FALSE)
E.g.,
rm(t)
exists(t, envir=globalenv())
[1] TRUE
exists(t, envir=globalenv(), inherits=FALSE)
[1] FALSE
Look at help(exists) for details.
Bill Dunlap
Hello,
I need to calculate all eigenvectors of network adjacency matrix.
to do this, I called evcent function such as following
p2=evcent(g, options=list(nev=2)) where g is my graph and nev is number of
required eigenvector
but it only calculated first eigenvector and p2$options$nev was
Hello all,
I have the attached dataset which I read from SPSS and transformed a little
bit using the script below. I am trying to run a logistic regression using
glm() on a subset of my data. When I run the logistic regression on the
whle dataset, it runs OK. As soon as I try to run on the
Hi,
In addition, you can also use:
?trunc(), ?substr() etc.
aggregate(Value, by = list(floor(Lat)), FUN = function(x) signif(mean(x),2))
# Group.1 x
#1 69 0.18
#2 70 0.16
aggregate(Value, by = list(substr(Lat,1,2)), FUN = function(x)
signif(mean(x),2))
# Group.1 x
#1
On Dec 11, 2012, at 3:17 AM, Swagath Navin wrote:
Dear all,
I have a big file containing latitude points(-10 to 80) and
corresponding values.
Example data
Lat=c(69.48134, 69.49439, 69.50736, 69.52026, 69.52438, 69.53308,
69.53746, 69.54365, 69.54582, 69.6884, 69.69272, 69.998, 70.00055,
All -
I have a column of SiteNames:
SiteName
OYS-PIA2-FL-1
OYS-PIA2-LA-1
OYS-PI-LA-BB-1
OYS-PIA2-LA-10
...
[truncated]
and I want to include only the last few digits into a new column.
I tried
substr(data$SiteName, 13, 20)
but because some SiteName values are of a different length, the final
On Dec 11, 2012, at 6:42 AM, email wrote:
Hi:
I am trying to search PubMed abstracts which contains BOTH two terms:
COL4A1 AND Ocular. I am using the following code:
url= http://eutils.ncbi.nlm.nih.gov/entrez/eutils/esearch.fcgi?;
search = paste(url,
It may be overkill, but you can specify the model pieces using the offset
function in the model, then the predictions work out (at least for my
simple trial case). Something like:
fit - glm( y ~ 0+offset(-1 + 2*x), family=binomial, data=data.frame(y=0,
x=0) )
predict( fit,
try this:
x
[1] OYS-PIA2-FL-1 OYS-PIA2-LA-1 OYS-PI-LA-BB-1 OYS-PIA2-LA-10
sub(^.*?([0-9]+)$, \\1, x)
[1] 1 1 1 10
On Tue, Dec 11, 2012 at 12:46 PM, Steven Ranney steven.ran...@gmail.com wrote:
OYS-PIA2-FL-1
OYS-PIA2-LA-1
OYS-PI-LA-BB-1
OYS-PIA2-LA-10
--
Jim Holtman
Data Munger
Dear R experts,
recently I tried to debug a R function with an internal lapply call.
When debugging I seem not to be able to use the n command to debug the
inner function called by lapply.
How could I achieve this?
*For example:*
test - function( ) {
lapply( 1:3, function( x ) x + 1 )
}
debug(
On Dec 11, 2012, at 10:10 AM, jim holtman wrote:
try this:
x
[1] OYS-PIA2-FL-1 OYS-PIA2-LA-1 OYS-PI-LA-BB-1 OYS-PIA2-
LA-10
sub(^.*?([0-9]+)$, \\1, x)
[1] 1 1 1 10
Steve;
jim holtman is one of the jewels of the rhelp world. I generally
assume that his answers are going to
Typically when I am debugging an 'lapply', I put a browser call inside
the lapply function that is being called and then make sure I 'source'
in the code instead of copy/paste -- the copy/paste will use any
trailing statements after the lapply call as commands to the browser
function.
Here is the
Hi,
I'd like to be able to generate a splom plot in R and then use my mouse to
click on one of the sub-panels (panel.pairs, specifically) and have R return
either the coordinates of that sub-panel, or even better, the names of the
corresponding variables plotted in that sub-panel.
Here's an
David and Jim -
Thanks for your help. Your suggestions worked just fine. Now my task
is to learn why the random-looking string of characters in the first
part of Jim's sub() statement aren't really so random.
Thanks again -
SR
Steven H. Ranney
On Tue, Dec 11, 2012 at 11:37 AM, David
Hello.
I'm running a generalized linear model and am interested in using the
random effects that are output for further analysis. My random effect is
interacting with two different fixed effects (which which are factors with
two levels each). When I retrieve the random effects I get something like
HI,
You could also use:
x - c(OYS-PIA2-FL-1, OYS-PIA2-LA-1, OYS-PI-LA-BB-1, OYS-PIA2-LA-10)
gsub(.*\\-(\\d+)$,\\1,x)
#[1] 1 1 1 10
#or
gsub([A-Z2-],,x) #in this case
#[1] 1 1 1 10
- Original Message -
From: Steven Ranney steven.ran...@gmail.com
To: r-help@r-project.org
Cc:
I am trying to get a function written in R that calls a cascade of functions
from the graphics package, and I want to eventually call replacements to
functions in the graphics package instead of the originals. Specifically, I
have a function that calls qqnorm in stats, which calls
On 11/12/2012 1:17 PM, Asis Hallab wrote:
Dear R experts,
recently I tried to debug a R function with an internal lapply call.
When debugging I seem not to be able to use the n command to debug the
inner function called by lapply.
How could I achieve this?
Jim gave you one solution. Another
On Tue, Dec 11, 2012 at 12:46 PM, Steven Ranney steven.ran...@gmail.com wrote:
All -
I have a column of SiteNames:
SiteName
OYS-PIA2-FL-1
OYS-PIA2-LA-1
OYS-PI-LA-BB-1
OYS-PIA2-LA-10
...
[truncated]
and I want to include only the last few digits into a new column.
I tried
You could try
require(grid)
trellis.focus()
names(iris)[round(unlist(grid.locator()))]
trellis.unfocus()
cheers
On Tue, Dec 11, 2012 at 11:59 AM, Eric Stone eric.st...@temple.edu wrote:
Hi,
I'd like to be able to generate a splom plot in R and then use my mouse to
click on one of the
On Dec 11, 2012, at 11:14 AM, Steven Ranney wrote:
David and Jim -
Thanks for your help. Your suggestions worked just fine. Now my task
is to learn why the random-looking string of characters in the first
part of Jim's sub() statement aren't really so random.
Jim's solution can be
Dear:
I am having trouble solving simultaneous nonlinear equations by R. I have
been using BBsolve (BB) to do so. Though the function is very strong, still
the program doesn't converge. I have tried all (according to my small
knowledge) the options described in the help file.
Now I am trying to
Ginnie D Morrison ginn at utexas.edu writes:
I'm running a generalized linear model
Note that this is a generalized linear *mixed* model, which
complicates the situation somewhat (otherwise you wouldn't
be dealing with random effects). Presumably you are using
glmer from the lme4 package,
On 11-12-2012, at 21:10, Rajibul Mian wrote:
Dear:
I am having trouble solving simultaneous nonlinear equations by R. I have
been using BBsolve (BB) to do so. Though the function is very strong, still
the program doesn't converge. I have tried all (according to my small
knowledge) the
Thank you very much for all those solutions.
On 11-12-12, David Winsemius dwinsem...@comcast.net wrote:
On Dec 11, 2012, at 3:17 AM, Swagath Navin wrote:
Dear all,
I have a big file containing latitude points(-10 to 80) and corresponding
values.
Example data
Lat=c(69.48134,
Dear Milan, please see my results inline
On 11 Dec 2012, at 16:58, Milan Bouchet-Valat nalimi...@club.fr wrote:
Le mardi 11 décembre 2012 à 16:41 +0100, Richard Zijdeman a écrit :
Dear Milan,
thank you for kind suggestion. Converting the characters using:
iconv(department, ISO-8859-15,
I'm trying to use Rprof() to identify bottlenecks and speed up a particullary
slow section of code which reads in a portion of a tif file and compares
each of the values to values of predictors used for model fitting. I've
written up an example that anyone can run. Generally temp would be a
On 12-12-10 7:10 PM, Richard Zijdeman wrote:
Dear all,
I have imported a dataset from Stata using the foreign package. The original
data contain French characters such as è and ç .
After importing, string variables containing names of French departments have
changed. E.g. Ardèche became
Hi All,
I'm having trouble with the colors on my screen getting translated to
the colors in the outputted .pdf document.
Here is a caricature of my problem:
par(mfrow=c(1,1))
x1 = rnorm(1000)
x2 = rnorm(1000)+10
y1 = rnorm(1000)+10
y2 = rnorm(1000)+10
palette(rainbow(6))
Hi,
Try this:
pdf(broke.pdf)
palette(rainbow(6))
plot(x=x1,y=y1,col=y1,xlim=c(-10,20))
palette(heat.colors(6))
points(x=x2,y=y2,col=y2)
dev.off()
A.K.
- Original Message -
From: Andrew Crane-Droesch andre...@gmail.com
To: R help r-help@r-project.org
Cc:
Sent: Tuesday, December
Thanks a lot! This works, provided I run my version first. For
posterity, the following does what is wanted:
par(mfrow=c(1,1))
x1 = rnorm(1000)
x2 = rnorm(1000)+10
y1 = rnorm(1000)+10
y2 = rnorm(1000)+10
palette(rainbow(6))
plot(x=x1,y=y1,col=y1,xlim=c(-10,20))
palette(heat.colors(6))
I think the error is because the other functions are expecting the plot.new
function to do some specific things to set up the graphics device for a new
plot, but your function did not do those things.
You might consider the trace function as an alternative to what you are
trying. It can be used
Dear members:
Could you please tell me the package for Bayesian haplotype estimation in R.
Currently PHASE is available for such purpose but I need a similar R package.
Best regards,
Keramat Nourijelyani, PhD
Associate Professorof Biostatistics
Tehran
Hello,
I've got a lattice plot and need to add text into the bottom margin of the
plotting area (below the bottom legend).
This seems to work in principle using grid.arrange, yet the text to be added is
rather long. As a consequence, it gets clipped:
require(lattice)
require(grid)
myplot -
Hello
You can insert \n in your text.
mytext - textGrob(This is such a very very long text\n that it goes on
forever and therefore needs to be wrapped in order\n for someone to be
able to read it properly.)
HTH
Pascal
Le 12/12/2012 16:22, knallg...@gmx.com a écrit :
Hello,
I've got a
Readers,
For a data set 'a':
1
2
3
4
Please what is the syntax to remove the last row and create a new object 'b':
1
2
3
Thanks.
--
R2151
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Hi,
I have a transition matrix T for which I want to find the steady state matrix
for. This could be approximated by taking T^n , for large n.
T= [ 0.8797 0.0382 0.0527 0.0008
0.02120.8002 0.0041 0.0143
0.09810.0273 0.8802 0.0527
0.00100.1343
Thanks a million!
- Original Message -
From: Pascal Oettli
Sent: 12/12/12 09:37 AM
To: knallg...@gmx.com
Subject: Re: [R] long margin text below lattice plot - how to wrap lines?
Hello
You can insert \n in your text.
mytext - textGrob(This is such a very very long text\n
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of e-letter
Sent: Tuesday, December 11, 2012 11:45 PM
To: r-help@r-project.org
Subject: [R] remove last row of a data frame
Readers,
For a data set 'a':
1
2
3
4
Please
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