I have used acf() and pacf() in R to get the acf and pacf values at
max/lag=20
but the output did not show the values associated with lag numbers. lag
numbers is shown in decimals.
--
Rashid Ameer
View my recent publication at
*
On 30/12/2012 07:47, Rashid Ameer wrote:
I have used acf() and pacf() in R to get the acf and pacf values at
max/lag=20
but the output did not show the values associated with lag numbers. lag
numbers is shown in decimals.
What 'lag numbers'?
Lags in time series are in time units: most likely
On Thu, 27 Dec 2012 22:01:22 -0500
Steve Powers power...@nd.edu wrote:
Two points:
1) You don't define crash. Did the script simply hang, did R
abruptly cease to run and exit to the OS, did the display freeze, did
the OS and machine stop working? Crashing is not explanatory, nor is
it
On Sat, 2012-12-29 at 20:40 +, Laura Martínez Suz wrote:
Hello there,
I'm trying to plot vectors with p0.1 in a NMDS ordination plot using p.max.
Below the scripts I'm using. I guess I'm missing something! could you please
give me a hand?
Dear useRs,
while working in XLConnect, i noticed a strange error
Error: IllegalArgumentException (Java): Sheet index (-2147483648) is out of
range (0..15)
there is not much help available about it online. Can anyone please help?
elisa
[[alternative
On 30/12/2012 14:34, eliza botto wrote:
Dear useRs,
while working in XLConnect, i noticed a strange error
Error: IllegalArgumentException (Java): Sheet index (-2147483648) is out of range
(0..15)
there is not much help available about it online. Can anyone please help?
That's the value of
thankyou prof. ripley
elisa
Date: Sun, 30 Dec 2012 14:47:29 +
From: rip...@stats.ox.ac.uk
To: r-help@r-project.org
Subject: Re: [R] Sheet index (-2147483648) is out of range (0..15)
On 30/12/2012 14:34, eliza botto wrote:
Dear useRs,
while working in XLConnect, i noticed a
I have two questions;
Do you know how to take out axes in a levelplot? Me doesn't work axes =
FALSE
And I would like to fix the values range of colorkey or legend from my
rainbow col.regions, dou you know how can I fix this values independent
of values database?
Thanks and happy new year!
I have installed R on my machine.
Can anyone now suggest to me the best book/e-book from where I can learn
the R language most efficiently?
Thanks in advance
--
Siddhant Gupta
III Year
Department of Biotechnology
IIT Roorkee
India
[[alternative HTML version deleted]]
hi all:
Here's a dataframe(dat) and a vector(z):
dat:
x1 x2x3
0.2 1.2 2.5
0.5 2 5
0.8 3 6.2
z
[1] 10 100 100
I wanna do the following:
10*x1,100*x2,1000*x3
My solution is using the loop for z and dat(since the length of z is the same
as ncol of dat),which is
On 30 Dec 2012, at 12:22 , Siddhant Gupta wrote:
I have installed R on my machine.
Can anyone now suggest to me the best book/e-book from where I can learn
the R language most efficiently?
Thanks in advance
--
Siddhant Gupta
III Year
Department of Biotechnology
IIT Roorkee
India
At Sun, 30 Dec 2012 18:26:45 +0800 (CST),
meng wrote:
hi all:
Here's a dataframe(dat) and a vector(z):
dat:
x1 x2x3
0.2 1.2 2.5
0.5 2 5
0.8 3 6.2
z
[1] 10 100 100
I wanna do the following:
10*x1,100*x2,1000*x3
My solution is using the loop for
Efficiency of learning materials depends on your background and learning style.
If you have any background at all in using software, the Introduction to R
document that is supplied with R is quite good. There is also a very useful
document on getting data in and out of R. There is a list of R
Please read the Posting Guide mentioned at the bottom of any message on this
list (and follow the recommendations there).
You may find the suggestions offered here useful:
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
On 30-12-2012, at 11:26, meng laomen...@163.com wrote:
hi all:
Here's a dataframe(dat) and a vector(z):
dat:
x1 x2x3
0.2 1.2 2.5
0.5 2 5
0.8 3 6.2
z
[1] 10 100 100
I wanna do the following:
10*x1,100*x2,1000*x3
My solution is using the loop for z
At Sun, 30 Dec 2012 16:28:44 +,
Andrius Druzinis wrote:
Hi Neal,
Notice that c(2, 3) gets replicated into c(2, 3, 2, 3, 2, 3) and then
multiplied by column. This is not the same as multiplying each column by
the respective element in vector c(2, 3).
I think you mean multiplied by
https://www.coursera.org/course/stats1
or
https://www.coursera.org/course/compdata
On Sun, Dec 30, 2012 at 1:22 PM, Siddhant Gupta sid.2311...@gmail.comwrote:
I have installed R on my machine.
Can anyone now suggest to me the best book/e-book from where I can learn
the R language most
It is very dependent on your background and what you are planning to do.
Because R is a tool that seems to be used by everyone from linguists to
biochemists and everyone has their special interest it is often best to just
google for what you are looking for.
Here aresome sources that I
On 2012-12-30 06:25, Janue Miret, Jofre wrote:
I have two questions;
Do you know how to take out axes in a levelplot? Me doesn't work axes =
FALSE
levelplot() is a lattice function, not base graphics; it has no 'axes'
argument. Read about the 'scales' argument in ?xyplot and use
Took some googling, but it was worth it! :)
Best,
Simone
Sent from my iPhone. Please excuse brevity and odd typos
Il giorno 30/dic/2012, alle ore 19:44, Bert Gunter gunter.ber...@gene.com ha
scritto:
Are you learning the ropes or on the ropes?
__
On 29 December 2012 20:35, arun smartpink...@yahoo.com wrote:
Is it possible to obtain the same result as X without converting X to R?
What do you mean by the same result? There is a relationship between X and R.
If you express this relationship algebraically, you can get X directly using
Y and
A (late) update to this question:
On Fri Aug 17 07:33:29, Henrik Singmann wrote:
Hi Diego,
I am struggeling with this question also for some time and there does
not seem to be an easy and general solution to this problem. At least
I
haven't found one.
However, if you have just one
Hi Meng,
A one-liner would be
dat*rep(z, each=nrow(dat))
Cheers,
Andrius
2012/12/30 meng laomen...@163.com
hi all:
Here's a dataframe(dat) and a vector(z):
dat:
x1 x2x3
0.2 1.2 2.5
0.5 2 5
0.8 3 6.2
z
[1] 10 100 100
I wanna do the following:
Hi Neal,
Notice that c(2, 3) gets replicated into c(2, 3, 2, 3, 2, 3) and then
multiplied by column. This is not the same as multiplying each column by
the respective element in vector c(2, 3).
Andrius
2012/12/30 Neal H. Walfield n...@walfield.org
At Sun, 30 Dec 2012 18:26:45 +0800 (CST),
HI,
Its not clear esp
I wanna do the following:
10*x1,100*x2,1000*x3
Did you mean 10* dat[,1], 100*dat[,2], 1000*dat[,3]?
dat-read.table(text=
x1 x2 x3
0.2 1.2 2.5
0.5 2 5
0.8 3 6.2
,sep=,header=TRUE)
z-c(10,100,1000) # 3rd element in your z is 100, which is confusing.
HI Usha,
I tried the codes on the full dataset. This is what I get:
BP_2b-read.csv(BP_2b.csv,sep=\t)
#head(BP_2b,2)
# CODEA Sex MaternalAge Education Birthplace AggScore IntScore Obese14
#1 1 NA 3 4 1 NA NA NA
#2 3 2 3 3
Is there packaged code to convert geographical coordinates (e.g.,
longitude, latitude, elevation) to Cartesian coordinates in 3-space?
I can see how to do this using
1. a spherical-to-Cartesian conversion like pracma::sph2cart(tpr)
http://cran.r-project.org/web/packages/pracma/
2. a
Hi Andrius:
Thanks for your reply.
Your answer: dat*rep(z,each=nrow(dat)) works well.
But a strange thing happened:
dat-data.frame(x1=1:3,x2=4:6,x3=7:9)
z-c(0.1,10,100)
#I wanna 0.1*x1,10*x2,100*x3
I type:
dat*rep(z,rach=nrow(dat))
rach is each indeed,but I type rach mistakenly.
What's strange
Hi Neal,
Thanks for your reply.
dat-data.frame(x1=1:3,x2=4:6,x3=7:9)
z-c(0.1,10,100)
#I wanna 0.1*x1,10*x2,100*x3
According to your answer:
as.matrix(dat)*z
x1x2x3
[1,] 0.1 0.4 0.7
[2,] 20.0 50.0 80.0
[3,] 300.0 600.0 900.0
The above is not what I want.
What I want is:
Hi Berend:
Thanks for your reply.
dat-data.frame(x1=1:3,x2=4:6,x3=7:9)
z-c(0.1,10,100)
#I wanna 0.1*x1,10*x2,100*x3
Option2 is similar as dat*rep(z,each=length(z)),and the latter is simpler
than Option2 in expression.
At 2012-12-31 00:31:42,Berend Hasselman b...@xs4all.nl wrote:
On
The following is also work:
data.frame(t(t(dat)*z))
At 2012-12-31 00:40:24,Neal H. Walfield n...@walfield.org wrote:
At Sun, 30 Dec 2012 16:28:44 +,
Andrius Druzinis wrote:
Hi Neal,
Notice that c(2, 3) gets replicated into c(2, 3, 2, 3, 2, 3) and then
multiplied by column.
HI Meng,
NO problem.
#In fact,
sweep(dat,2,z,*) #will be data.frame
# x1 x2 x3
#1 2 120 2500
#2 5 200 5000
#3 8 300 6200
str(sweep(dat,2,z,*))
#'data.frame': 3 obs. of 3 variables:
# $ x1: num 2 5 8
# $ x2: num 120 200 300
# $ x3: num 2500 5000 6200
A.K.
Hi,arun:
Yes,your answer is what I want.
A little different is :
data.frame(t(t(dat)*z))
Because I wanna get the data frametype, not matrix.
Thanks for your reply.
At 2012-12-31 00:59:43,arun smartpink...@yahoo.com wrote:
HI,
Its not clear esp
I wanna do the following:
Many thanks arun!
Your answer is the best one :)
At 2012-12-31 10:51:35,arun smartpink...@yahoo.com wrote:
HI Meng,
NO problem.
#In fact,
sweep(dat,2,z,*) #will be data.frame
# x1 x2 x3
#1 2 120 2500
#2 5 200 5000
#3 8 300 6200
str(sweep(dat,2,z,*))
#'data.frame':3 obs. of
Have you checked the spatial stats task view on CRAN?
http://cran.r-project.org/web/views/Spatial.html
-- Bert
On Sun, Dec 30, 2012 at 6:49 PM, Tom Roche tom_ro...@pobox.com wrote:
Is there packaged code to convert geographical coordinates (e.g.,
longitude, latitude, elevation) to Cartesian
https://stat.ethz.ch/pipermail/r-help/2012-December/332658.html
Is there packaged code to convert geographical coordinates (e.g.,
longitude, latitude, elevation) to Cartesian coordinates in 3-space?
...
Net: the task seems straightforward enough, but there's certainly
scope for error, so I'd
Hi Jean, thank-you again.
Both the assignment of names and the indices of the successful locations
worked perfectly.
Irucka Embry
-Original Message-
From: Adams, Jean [jvad...@usgs.gov]
Sent: 12/28/2012 1:28:29 PM
To: iruc...@mail2world.com
Cc: r-help@r-project.org
Subject: Re: [R]
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