On Mon, 10 Jun 2013, Bhupendrasinh Thakre vickytha...@gmail.com writes:
Thanks Rex for the help. So it seems that I might have to use Python or Perl
to perform the action.
On Windows, you may want to look at Blat ( http://www.blat.net/ ). You
can easily use it from R scripts via 'system'.
Hi Guys
I am trying to cast a data frame but not aggregate the rows for the
same variable.
here is a contrived example.
**input**
temp_df -
data.frame(names=c('foo','foo','foo'),variable=c('w','w','w'),value=c(34,65,12))
temp_df
names variable value
1 foow34
2 foow
On 10/06/2013 03:17, Pascal Oettli wrote:
Hello,
I am not sure whether it helps you, but I was able to install it.
OpenSUSE 12.3
R version 3.0.1 Patched (2013-06-09 r62918)
pbdMPI version 0.1-6
gcc version 4.7.2
OpenMPI version 1.6.3
I didn't try with the most recent version of ompi (1.6.4).
Hello,
I am working my way through A (not so) Short introduction to S4
I created a class
setClass(Class = Trajectories,
representation = representation(times = numeric,traj = matrix))
and tried to build a method using
setMethod(
f = plot,
signature = Trajectories,
You can try this:
library(inflection)
#you have to instsall package inflection first
a-findiplist(cbind(year),cbind(piproute),1)
a
The answer:
[,1] [,2] [,3]
[1,]5 35 1986.0
[2,]5 30 1983.5
shows that the total inflection point is between 1983 and 1986, if we treat
Hi,
I am trying to build a package with package.skeleton function.
I already have the function quadprod2.R in the current folder. After
running the program,
library(frontier)
source(quadprod2.R)
package.skeleton(name=sfa_ext)
package.skeleton(name=sfa_ext)
Creating directories ...
On Jun 9, 2013, at 11:37 PM, andreas betz wrote:
Hello,
I am working my way through A (not so) Short introduction to S4
I created a class
setClass(Class = Trajectories,
representation = representation(times = numeric,traj = matrix))
and tried to build a method using
Hello,
Please quote context.
The message you get means that package foreign is installed on your
computer, you need to load it in the R session:
library(foreign)
Hope this helps,
Rui Barradas
Em 09-06-2013 23:07, Court escreveu:
Hi,
I think that they are loaded. Here is the response
Your question makes no sense at all. The grid expansion
has 9 rows. In case you hadn't noticed, 9 is an odd number
(i.e. not divisible by 2). There are no halves.
Do not expect the list to read your mind. Instead, ask a
meaningful question.
cheers,
Rolf Turner
On 10/06/13
On 06/09/2013 11:14 PM, Calum Polwart wrote:
...
What we are trying to do is determine the most appropriate number to
make the capsules. (Our dosing is more complex but lets stick to
something simple. I can safely assure you that vritually no-one actually
needs 250 or 500mg as a dose of
Hi,
I have a data.frame that contains a variable act which records the duration (in
seconds) of two states (wet-dry) for several individuals (identified by Ring)
over a period of time. Since I want to work with daytime (i.e. from sunrise
till sunset) and night time (i.e. from sunset till next
Dear all,
I have to create a model which is a mixture of a normal and log-normal
distribution. To create it, I need to estimate the 2 covariance matrixes and
the mixing parameter (total =7 parameters) by maximizing the log-likelihood
function. This maximization has to be performed by the nlm
On 10-06-2013, at 11:49, Santiago Guallar sgual...@yahoo.com wrote:
Hi,
I have a data.frame that contains a variable act which records the duration
(in seconds) of two states (wet-dry) for several individuals (identified by
Ring) over a period of time. Since I want to work with daytime
Thank you, I will try contact the developper.
Antoine Migeon
Université de Bourgogne
Centre de Calcul et Messagerie
Direction des Systèmes d'Information
tel : 03 80 39 52 70
Site du CCUB : http://www.u-bourgogne.fr/dsi-ccub
Le 10/06/2013 08:19, Prof Brian Ripley a écrit :
On 10/06/2013 03:17,
Hugo Varet vareth...@gmail.com
on Sun, 9 Jun 2013 11:43:32 +0200 writes:
Dear R users,
I discovered something strange using the function agnes() of the cluster
package on R 3.0.1 and on R 2.14.1. Indeed, the clusterings obtained are
different whereas I ran exactly the
Abhi,
In the example you give, you don't really need to reshape the data ... just
rename the column value to w.
Here's a different example with more than one category ...
tempdf - expand.grid(names=c(foo, bar), variable=letters[1:3])
tempdf$value - rnorm(dim(tempdf)[1])
tempdf
library(reshape)
Unless I completely misunderstand what you are doing you don't need to
aggregate, just drop the one column and rename things
newtemp - temp_df[, c(1,3)]
names(newtemp) - c(names, w)
newtemp
John Kane
Kingston ON Canada
-Original Message-
From: abhishek@gmail.com
Sent: Sun,
No image. The R-help list tends to strip out a lot of files. A pdf or txt
usually gets through. In any case I understand what you want this may do it.
library(ggplot2)
dat1 - data.frame( v = rnorm(13),
w = rnorm(13),
x = rnorm(13),
y = rnorm(13),
z = rnorm(13))
plotmatrix(dat1)
John Kane
Hi,If your dataset is similar to the one below:
set.seed(24)
temp1_df-
data.frame(names=rep(c('foo','foo1'),each=6),variable=rep(c('w','x'),times=6),value=sample(25:40,12,replace=TRUE),stringsAsFactors=FALSE)
library(reshape2)
Hi,
Try this:
which(duplicated(res10Percent))
# [1] 117 125 157 189 213 235 267 275 278 293 301 327 331 335 339 367 369 371
379
#[20] 413 415 417 441 459 461 477 479 505
res10PercentSub1-subset(res10Percent[which(duplicated(res10Percent)),],dummy==1)
#most of the duplicated are dummy==1
Thanks, guys.
On Sat, Jun 8, 2013 at 2:17 PM, Neal Fultz nfu...@gmail.com wrote:
rowSums and Reduce will have the same problems with bad data you alluded
to earlier, eg
cg = 1, hs = 0
But that's something to check for with crosstabs anyway.
This wrong data thing is a distraction here. I
If you can explain why those particular six combinations out of the
complete set of nine, then perhaps someone can tell you how.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 6/9/13 10:25 PM, Gundala Viswanath
Hello,
I plotted a graph on R showing how salinity (in ‰, y-axis) changes with time(in
years, x-axis). However, right from the beginning on the Excel spreadsheet the v
alues for salinity appeared as, for example, 35000‰ instead of 35‰, which I gues
sed must have been a typing error for the
Dear all,
I am using Epi package to calculate Odds ratio in my bivariate analysis.
How can I make *twoby2 *in variables that have 3 or more levels.
For example:
I have 4 level var (Age)
m=matrix(c(290, 100,232, 201, 136, 99, 182, 240), nrow=4, ncol=2)
twoby2(m)
R gives me only
Comparing : Row 1
Wenn man ihn mal braucht ist er tot. folgende Fehlermeldung ereilt mich seit
heute beim starten des R Commander auf dem Mac:
library(Rcmdr)
Lade nötiges Paket: car
Lade nötiges Paket: MASS
Lade nötiges Paket: nnet
Error : .onAttach in attachNamespace() für 'Rcmdr' fehlgeschlagen, Details:
Sounds like you have made no effort to learn R, e.g. by reading the
Intro to R tutorial packaged with R or other online tutorial (there
are many).
Don't you think you need to do some homework first?
-- Bert
On Mon, Jun 10, 2013 at 7:26 AM, diddle1...@fastwebnet.it wrote:
Hello,
I plotted a
Just calculate a new sequence if those percentages are in an orderly sequence.
See ?seq
v - seq(25, 200, by = 10)
or perhaps the values are actually text
?substr
x - substr(v, 1,2)
John Kane
Kingston ON Canada
-Original Message-
From: diddle1...@fastwebnet.it
Sent: Mon, 10
I did look into tutorials but I could not find the exact request I am looking
for. I just started using R so I am still a beginner. If you then know
where I can find it, can you please redirect me to it
--
View this message in context:
Dear Bastian,
I'm afraid that I don't read German, but (as near as I can tell) since you say
that you're using the most recent version of R and have X11 installed, you
should have the software you need. Just in case, you might check the Rcmdr
installation notes for Mac users at
Dear all,
I am using Epi package to calculate Odds ratio in my bivariate analysis.
How can I make *twoby2 *in variables that have 3 or more levels.
For example:
I have 4 level var (Age)
m=matrix(c(290, 100,232, 201, 136, 99, 182, 240), nrow=4, ncol=2)
library (Epi)
twoby2(m)
R gives me only
Hi Emanuela,
Welcome to R
It can be hard finding even relatively simple things when you are just
starting. You might want to have a look at
http://www.unt.edu/rss/class/Jon/R_SC/ or
http://www.burns-stat.com/documents/tutorials/impatient-r/ if ou have not
already seen them. Patrick Burn's
Perhaps the OP wants the unique combinations of V1 and V2, as in
R d - expand.grid(V1=c(x,y,z),V2=c(x,y,z))
R d[ as.numeric(d$V1) = as.numeric(d$V2), ]
V1 V2
1 x x
4 x y
5 y y
7 x z
8 y z
9 z z
or
R V - letters[24:26]
R rbind(t(combn(V,m=2)), cbind(V,V))
Hi,
I was trying to make a density plot with 13 samples. To distinguish each
sample, it would be good if each color is as different as possible from the
other colors. I could use the built in function, but that does not do more
than 8 colors and then goes back to recycling the cols. If I use a
here are some small benchmarks on an i7-2600k with an SSD:
input file: 104,126 rows with 76 columns. all numeric.
linux time bzcat bzfile.csv.bz2 /dev/null -- 1.8 seconds
R d - read.csv( pipe( bzfile ) ) -- 6.3 seconds
R d - read.csv( pipe( bzfile ), colClasses=numeric) -- 4.2 seconds
R
On Jun 10, 2013, at 9:27 AM, Vlatka Matkovic Puljic wrote:
Dear all,
I am using Epi package to calculate Odds ratio in my bivariate analysis.
How can I make *twoby2 *in variables that have 3 or more levels.
I hope looking at that again you will see how odd it sounds to be requesting
Hey all
I am trying to use where in clause in sql query in R
here is my code:
sql.select-paste(select PERSON_NAME from UNITS where UNIT_ID in
(',cathree,'),sep=)
where cathree is 1 variable with 16 observations as follows
UNIT_ID
1 205
2 209
3 213
4 217
5 228
6 232
7 236
8 240
9 245
10 249
11
You may want to consider a cumulative logit model which effectively
bifurcates an ordinal variable by utilizing the odds of being in a given
level or below (depending on your coding).
On Mon, Jun 10, 2013 at 12:27 PM, Vlatka Matkovic Puljic vlatk...@gmail.com
wrote:
Dear all,
I am using Epi
Do this
cat(sql.select,'\n')
and then decide whether the query is what it should be according to
standard SQL syntax.
(If it is not, then fix it.)
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 6/10/13 11:47 AM,
It will be hard to come up with 20 clearly distinguishable colors. Check
out the website http://colorbrewer2.org/ and the R package RColorBrewer.
It does not have a 20-color palette, but it does have some 8- to 12-color
palettes that are very nice.
library(RColorBrewer)
Thanks everyone for your quick reply. I think my contrived example hid
the complexity I wanted to show by using only one variable.
@Arun: I think your example is exactly what I was looking for. Very
cool trick with 'ave' and 'seq_along'...just dint occur to me.
Best,
-Abh
On Mon, Jun 10, 2013
Dear all,
I have to create a model which is a mixture of a normal and log-normal
distribution. To create it, I need to estimate the 2 covariance matrixes and
the mixing parameter (total =7 parameters) by maximizing the log-likelihood
function. This maximization has to be performed by the nlm
Hi,
On Jun 10, 2013, at 3:46 PM, Adams, Jean wrote:
It will be hard to come up with 20 clearly distinguishable colors. Check
out the website http://colorbrewer2.org/ and the R package RColorBrewer.
It does not have a 20-color palette, but it does have some 8- to 12-color
palettes that are
Any response please? Was my question not clear to the list? Please let me
know.
Thanks and regards,
-- Forwarded message --
From: Christofer Bogaso bogaso.christo...@gmail.com
Date: Sat, Jun 8, 2013 at 9:39 PM
Subject: Re: Problem with ODBC connection
To: r-help
I have run a PCA on one data set. I need the standard deviation of the first
two bands for my analysis. I now want to apply the same PCA rotation I used
in the first one to all my other data sets. Is there any way to do this in
r? Thanks.
--
View this message in context:
I have a For loop that is quite slow and am wondering if there is a faster
option:
df - data.frame(TreeID=rep(1:500,each=20), Age=rep(seq(1,20,1),500))
df$Height - exp(-0.1 + 0.2*df$Age)
df$HeightGrowth - NA #intialize with NA
for (i in 2:nrow(df))
{if(df$TreeID[i]==df$TreeID[i-1])
Hello R community,
I am trying to combine two CSV files that look like this:
File A
Row_ID_CR, Data1,Data2,Data3
1, aa, bb, cc
2, dd, ee, ff
File B
Row_ID_N, Src_Row_ID, DataN1
1a, 1,
It works, Arun. Thanks!
(FYI, a couple a the matrices I am dealing with have 1000+ rows, so I had
to do in on a supercomputer at work. For the curious, I am trying to find
all possible scores in a model f language mixing described in:
Title: Structured Variation in Codeswitching: Towards an
Hi,
Try this:
res10Percent- fun1(final3New,0.1,200)
res10PercentSub1-subset(res10Percent[duplicated(res10Percent)|duplicated(res10Percent,fromLast=TRUE),],dummy==1)
indx1-as.numeric(row.names(res10PercentSub1))
res10PercentSub2-res10PercentSub1[order(res10PercentSub1$dimension),]
Hello,
One way to speed it up is to use a matrix instead of a data.frame. Since
data.frames can hold data of all classes, the access to their elements
is slow. And your data is all numeric so it can be hold in a matrix. The
second way below gave me a speed up by a factor of 50.
try this:
fileA - read.csv(text = Row_ID_CR, Data1,Data2,Data3
+ 1, aa, bb, cc
+ 2, dd, ee, ff, as.is = TRUE)
fileB - read.csv(text = Row_ID_N, Src_Row_ID, DataN1
+ 1a, 1, This
How about
for (ir in unique(df$TreeID)) {
in.ir - df$TreeID == ir
df$HeightGrowth[in.ir] - cumsum(df$Height[in.ir])
}
Seemed fast enough to me.
In R, it is generally good to look for ways to operate on entire vectors
or arrays, rather than element by element within them. The cumsum()
Sorry, I forgot to paste some lines and change the names:
res10Percent- fun1(final3New,0.1,200)
res10PercentSub1-subset(res10Percent[duplicated(res10Percent)|duplicated(res10Percent,fromLast=TRUE),],dummy==1)
indx1-as.numeric(row.names(res10PercentSub1))
mansor nad nadsim88 at hotmail.com writes:
i need HELPPP!! how do i calculate the RMSE value for two GEV
models?first GEV is where the three parameters are constant.2nd GEV
model a 4 parameter model with the location parameter is allowed to
vary linearly with respect to time while holding
On Jun 10, 2013, at 10:28 AM, Trevor Walker wrote:
I have a For loop that is quite slow and am wondering if there is a faster
option:
df - data.frame(TreeID=rep(1:500,each=20), Age=rep(seq(1,20,1),500))
df$Height - exp(-0.1 + 0.2*df$Age)
df$HeightGrowth - NA #intialize with NA
for (i
Sorry, it looks like I was hasty.
Absent another dumb mistake, the following should do it.
The request was for differences, i.e., the amount of growth from one
period to the next, separately for each tree.
for (ir in unique(df$TreeID)) {
in.ir - df$TreeID == ir
df$HeightGrowth[in.ir] - c(NA,
Hi,
Try this:
dat1-read.table(text=
Row_ID_CR, Data1, Data2, Data3
1, aa, bb, cc
2, dd, ee, ff
,sep=,,header=TRUE,stringsAsFactors=FALSE)
dat2-read.table(text=
Row_ID_N, Src_Row_ID, DataN1
1a, 1,
Well, speaking of hasty...
This will also do it, provided that each tree's initial height is less
than the previous tree's final height. In principle, not a safe
assumption, but might be ok depending on where the data came from.
df$delta - c(NA,diff(df$Height))
df$delta[df$delta 0] - NA
-Don
Hi,
Some speed comparisons:
df - data.frame(TreeID=rep(1:6000,each=20), Age=rep(seq(1,20,1),6000))
df$Height - exp(-0.1 + 0.2*df$Age)
df1- df
df3-df
library(data.table)
dt1- data.table(df)
df$HeightGrowth - NA
system.time({ #Rui's 2nd function
df2 - data.matrix(df)
for(i in
Short answer: Yes.
Long answer: Your question does not provide specific information;
therefore, I cannot provide a specific answer.
On Mon, Jun 10, 2013 at 1:23 PM, edelance delanceye...@gmail.com wrote:
I have run a PCA on one data set. I need the standard deviation of the
first
two bands
HI,
I am not sure about your DataN1 column. If there is any identifier to
differentiate the comments (in this case 1,2,3), then it will easier to place
that in the correct column.
My previous solution is not helpful in situations like these:
dat2-read.table(text=
Row_ID_N, Src_Row_ID,
Dear list
Getting very frustrated with this simple-looking problem
m1 - lm(x~y, data=mydata)
outliers - abs(stdres(m1))2
plot(x~y, data=mydata)
I would like to plot a simple x,y scatter plot with labels giving custom
information displayed for the outliers only, i.e. I would like to define a
I am downloading time series data from FRED. I have a working download, but I
do not want to write out the download for all 50 states likes this:
IDRGSP -
read.table('http://research.stlouisfed.org/fred2/data/IDRGSP.txt', skip=11,
header=TRUE)
IDRGSP$DATE - as.Date(IDRGSP$DATE, '%Y-%m-%d')
Try adding the argument
na.action = na.exclude
to your call to lm(). See help(na.exclude) for details.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf
Of Rob Forsyth
This should do it for you:
base - http://research.stlouisfed.org/fred2/data/;
files - lapply(state.abb, function(.state){
+ cat(.state, \n)
+ input - read.table(paste0(base, .state, RGSP.txt)
+ , skip = 11
+ , header = TRUE
+ , as.is =
On 06/11/2013 12:26 AM, diddle1...@fastwebnet.it wrote:
Hello,
I plotted a graph on R showing how salinity (in ‰, y-axis) changes with time(in
years, x-axis). However, right from the beginning on the Excel spreadsheet the v
alues for salinity appeared as, for example, 35000‰ instead of 35‰,
Given the resounding silence, I would venture to guess that no-one here is
interested in troubleshooting ODBC connections to Excel. The problem is most
likely in the ODBC driver for Excel (not in R or RODBC), and Excel is NOT a
database (so any data format problem is unlikely to be detected).
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Jeff Newmiller
Sent: Monday, June 10, 2013 9:45 PM
To: Christofer Bogaso; r-help
Subject: Re: [R] Fwd: Problem with ODBC connection
Given the resounding silence, I would
On Tue, 11 Jun 2013 02:19:14 +0545
Christofer Bogaso bogaso.christo...@gmail.com wrote:
Any real answer would be contingent on a reader being provided a
reproducible example. Since you don't provide that, there's not a lot
of point to an answer. However, to tilt at a windmill, depending on the
Hi,
I have a structure, which is the result of a function
How can I access the elements in the gradient?
dput(test1)
structure(-1.17782911684913, gradient = structure(c(-0.0571065371783791,
-0.144708170683529), .Dim = 1:2, .Dimnames = list(NULL, c(x1,
x2
test1[[1]]
[1] -1.177829
test1
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