Dear R users,
I have a seasonal rainfall time series x.
acf(x) shows correlation at lags 4, 8 and 12, but
frequency(x) is 1.
I would have expected frequency equal to 4.
Moreover,
acf(diff(aso,4,1)) shows a correlation only at lag 4, while
acf(diff(aso,4,2)) shows a correlation at lags 4 and 8
(an
On Sun, 27 Oct 2013, Imran Akbar wrote:
Hi,
I've got a data set with a control group and a number of experimental
groups, that have unequal sample sizes, and am measuring the number of
people in each that respond yes or no. I'd like to use a dunnett test in
R, where the syntax is supposed to
On 10/28/2013 04:53 PM, Hansol Yu wrote:
When my data has 50 rows, 100 columns and class column. How can I plot this
data and show classes? Do I have to draw 100 lines?
Hi Hansol,
I doubt that anyone on the R help list really knows the answer to your
question unless your lecturer is one of us.
When my data has 50 rows, 100 columns and class column. How can I plot this
data and show classes? Do I have to draw 100 lines?
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On Sun, 27 Oct 2013 14:37:27 -0700 (PDT)
Peter Maclean wrote:
It's not fully clear what you need, but, as I very vaguely recall, the
code book in SPSS provided labels for what are called levels in
"factors" in R, which are categorical variables.
Try: "??categorical" at the prompt for starters.
anord zooekol.lu.se> writes:
>
> Dear all,
> I'm trying to fit a model on ecological data in which I have measured a few
> biotic and abiotic factors over the course of a few days in several
> individuals. Specifically, I'm interested in modelling y ~ x1, with x2, x3,
> and 'factor' as independ
No data came through (I don't think "CSV" is one of the approved file types.)
You probably have some odd characters somewhere in the data. Try adding the
argument stringsAsFactors=FALSE to the read.csv call before converting the
troublesome column.. Converting factors to numeric converts the int
On 10/28/13 00:10, Hansol Yu wrote:
data(Boston, package='MASS')
y <- Boston$nox
x <- Boston$dis
nls(y~ A + B * exp(C * x), start=list(A=1, B=1, C=1))
Error in nls(y ~ A + B * exp(C * x), start = list(A = 1, B = 1, C = 1), :
step factor 0.000488281 reduced below 'minFactor' of 0.000976562
I
Re: Heteroscedasticity and mgcv. (Collin Lynch)
The GAMLSS package can model heterogeneity in the scale parameter (e.g.
standard deviastion) [and also heterogeity in skewness and kurtosis
parameters].of the response variable distribution.
For parametric models a generalized likelihood ratio test
data(Boston, package='MASS')
y <- Boston$nox
x <- Boston$dis
nls(y~ A + B * exp(C * x), start=list(A=1, B=1, C=1))
Error in nls(y ~ A + B * exp(C * x), start = list(A = 1, B = 1, C = 1), :
step factor 0.000488281 reduced below 'minFactor' of 0.000976562
I don't know how to fix this error. I th
Hello.
trying to do one of the simplest actions -read in data into R.
I don't know why the FBfollowers column is being read as a factor and also
if I use as.numeric on it, it looks really strange and actually complety
alters the data.
I am attaching the data set here called ddd.csv
I used
data=read
Hi,
Thank You for the reply of my previous question.
I have another doubt regarding Hclust. In Hierarchical clustering how can i
find that what are the members at each clustering level?
Please send me a reply soon.
Thank You.
On Sat, Oct 26, 2013 at 9:56 PM, wrote:
> Hi,
> I need some answer
Hi,
I've got a data set with a control group and a number of experimental
groups, that have unequal sample sizes, and am measuring the number of
people in each that respond yes or no. I'd like to use a dunnett test in
R, where the syntax is supposed to be like:
library(multcomp)
test.dunnett=
I am trying again. I do not have SPSS and I would like to create a code book in
a data frame format using R. I am reading the SPSS file using "memisc package".
The script is:
#Data for 2012 available at http://www.ark.ac.uk/nilt/datasets/
#Also attached
ibrary(memisc)
## change the working direct
Dear all,
i am a bit stuck with a problem right now. Specifically, I have a correlation
matrix, and a dataframe on which I want to project the values. However, I am
not sure how I can do this.
Here the calculations I made, I wanted to get a matrix that shows the values
for each of the combina
Hi,
DF$Col2
# [1] a e b b a b c e b a c c e e a c d c c e
#Levels: a b c d e
"b" is not found in any of the "Grs". Also Gr3 is not presnt in DF$Col2
So, I am not sure whether this works for you.
indx <- 1+ 2*DF$Col2 %in% Gr1 + 4*DF$Col2 %in% Gr2 + 8*DF$Col2 %in% Gr3
indx <- indx[indx>1]
spli
Dear all,
I would like to ask you how I can avoid this warning I am getting when I am
writing some results in a text file
5: In write.table(x = cor(t(collectMean_UL), t(collectMean_DL)), ... :
appending column names to file
the code that saves to the file look like:
write(x="TEMPERATURE",f
Hi again,
Let say I have following DF:
DF <- structure(list(Col1 = 1:20, Col2 = structure(c(1L, 5L, 2L, 2L,
1L, 2L, 3L, 5L, 2L, 1L, 3L, 3L, 5L, 5L, 1L, 3L, 4L, 3L, 3L, 5L
), .Label = c("a", "b", "c", "d", "e"), class = "factor")), .Names =
c("Col1",
"Col2"), row.names = c(NA, -20L), class = "data
not homework, but thanks for the hint!
Andras
On Sunday, October 27, 2013 7:51 AM, Patrick Burns
wrote:
Homework? A hint is:
?diff
Pat
On 27/10/2013 11:37, Andras Farkas wrote:
> Dear All,
>
> please help with the following problem:
>
> I have
>
>
> t <-seq(0,24,by=6)
> a <-600
> g <-0
Homework? A hint is:
?diff
Pat
On 27/10/2013 11:37, Andras Farkas wrote:
Dear All,
please help with the following problem:
I have
t <-seq(0,24,by=6)
a <-600
g <-0.05
b <-a*exp(-g*t)
I would like to establish a vector called z (for example) based on b where the
results are calculated as
Here is a link to a plot that illustrates the question:
bio.lmu.de/~pavlidis/pg1.pdf
the question is how to evaluate whether the blue points fit the curve well
enough. The curve has been produced from the black points
best
pavlos
On Sun, Oct 27, 2013 at 1:30 PM, Pavlos Pavlidis wrote:
> Hi all
Dear All,
please help with the following problem:
I have
t <-seq(0,24,by=6)
a <-600
g <-0.05
b <-a*exp(-g*t)
I would like to establish a vector called z (for example) based on b where the
results are calculated as :
z <-c(a-b[1],b[1]-b[2],b[2]-b[3],b[3]-b[4],b[4]-b[5])
so the results are:
Hi all,
I have fitted polynomial models to a bunch of data (time-course analysis).
The experiment is "the expression value of gene A under condition K over
time". The data points that have been used to fit the model are about 200
(dataset A). Furthermore I have a few data (dataset B; about 10 point
On 10/27/2013 08:39 AM, Alaios wrote:
Hi Jim and thanks for your answer... I might be too tired with my new
born or just exhausted.
I am attaching for everyone a small data snipset that you can load
load("DataToPlotAsImage.Rdata")
require(plotrix)
browser()
test<-data
# this transforms the val
Hello,
Both questions are answered in the help page for kmeans(). At an R
prompt type
?kmeans
and read the section Value. The membership is given by 'cluster' and the
centers by 'centers'. See also the very first example.
Hope this helps,
Rui Barradas
Em 27-10-2013 01:56, pragya.pancha..
On Sat, Oct 26, 2013 at 9:37 PM, Peter Maclean wrote:
> I do not have SPSS and I would like to create a code book in a data frame
> format using R.
> #How could I extract a codebook (without Summary statistics for printing)?
This isn't that clear because I don't think 'codebook' is something
w
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