Hello everybody,
I am a new R user..(still;;;). I have a simple sapply function example for
calculating mean and sd of splited data scale. My data contains half hourly
wind speed with direction. I want to know daily weibull distribution for my
study for 13 years. That is why my dataset is
dear Daniel,
yet another package performing growth modelling is quantregGrowth. It
uses quantile regressions with B-splines and quadratic penalties to
ensure flexible estimation with additional noncrossing and monotonicity
(optional) constraints.
The paper underlying the package is here:
This is the solution fpr the problem.
Its not the cleanest one i guess but it works just the way i wanted.
If anybody has better performing or cleaner code, please send it to me.
best regards
Uwe
type-sample(c(-1,1) , 20, replace = TRUE )
weight-sample(c(20:50),20,
Gundala Viswanath gunda...@gmail.com
on Sun, 8 Dec 2013 16:11:12 +0900 writes:
Hi, According to daisy function from cluster
documentation, it can compute dissimilarity when NA
(missing) value(s) is present.
I'm also curious how to use glmnet with survfit -- specifically, for use
with interval regression (which, under the hood, is implemented using
survfit). Can you show how you converted your Surv object formula to a
design matrix for use with glmnet?
Thanks,
-Aaron
On Sun, Dec 8, 2013 at 12:45
Hello list,
I have the following data on dm table
dm
Group.1 V1 V2 V3V4 V5 V6 V7 V8
1 C/L NA 15.5 732179 875270.6 -143091.46 1107270 1088300 18964.40
2 C/S NA 15.5 803926 850352.1 -46426.03 1395710 1312310 83403.30
3 D/D NA 15.5
Hi everybody,
I am dealing with a time series of eeg data and I need to filter them
with a notch filter. However, I could only find the function notch() in
the RTisean package. Unfortunately, this function is not implemented
yet. Is there another package/function in R which performs such a
Dear Soeren Groettrup,
Re:
I am dealing with a time series of eeg data and I need to filter them with a
notch filter. However, I could only find the function notch() in the RTisean
package. Unfortunately, this function is not implemented yet. Is there
another package/function in R which
Start here
dm - read.table(text=
Group.1 V1 V2 V3V4 V5 V6 V7 V8
1 C/L NA 15.5 732179 875270.6 -143091.46 1107270 1088300 18964.40
2 C/S NA 15.5 803926 850352.1 -46426.03 1395710 1312310 83403.30
3 D/D NA 15.5 751660 857828.2
Hi
You probably missed this
Instead of those tricky ifs (uff uff) you can use either of these
df[df[,2]==2,2]-3
df$C-as.numeric(as.character(factor(df$C, labels=c(0,2,3
df
A B C
1 0 3 3
2 0 1 2
3 0 3 2
4 1 0 3
5 1 0 3
6 2 3 2
7 1 3 2
8 2 3 3
9 1 1 0
10 0 0 3
And here I am lost
There is a no-homework policy on this mailing list (see the Posting Guide
mentioned at the bottom of every email). If this is not assigned homework then
at the very least you need to understand R and your problem well enough to
provide a reproducible example [1] before we can communicate about
Hi
you are still rather cryptic. If you said you want to extract prevalent choices
in each row it would save me (and you) a lot of time.
Import data and make necessary chnages
survey.results - read.csv(SamplePairedComparisonData.csv)
survey.results[survey.results[,3]==2,3]-3 # Convert column
Hi Gundala,
This question isn't about a Bioconductor package, so should be asked on
R-help instead.
Best,
Jim
On Sunday, December 08, 2013 2:11:12 AM, Gundala Viswanath wrote:
Hi,
According to daisy function from cluster documentation, it can compute
dissimilarity when NA (missing)
it's a pity, but thanks anyway!
--
View this message in context:
http://r.789695.n4.nabble.com/GAM-Assumption-Tests-tp4681670p4681857.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
I am trying to plot vertical bar plots over a map. I went through examples
online but somehow not being able to.
My data is currently in this format:
University| Count | Category | lat | long
Here is the code that I am trying execute:
Petr,
Thank you for your assistance; however, your code does not produce the
correct results in the following two cases;
ID,Q1,Q2,Q3
17,Option 1, Option 3, Option 2
24,Option 2, Option 3, Option 1
In both cases it chooses a preference of Option 1, when the correct
answer is None
# The data
Dear Daniel,
There are several papers which use gamlss for centile estimation.
See www.gamlss.org/ and click MORE ON GAMLSS, Books Articles.
In particular Rigby and Stasinopoulos (2004, 2005, 2006, 2013)
and Stasinopoulos and Rigby (2007).
m3 - gamlss(BMI~age, family=BCT,
Dear All,
I have fitted the exponential and gamma model to my univariate data and
obtained the MLE estimates using the R package fitdistr, now I'm trying to do
model selection based on leave-one-out cross validation, are there any readily
avaliable R package to do this.
Thanks!
check this one
http://stackoverflow.com/questions/16299891/estimating-many-interaction-terms-in-glmnet
On Mon, Dec 9, 2013 at 5:39 AM, Aaron Mackey ajmac...@gmail.com wrote:
I'm also curious how to use glmnet with survfit -- specifically, for use
with interval regression (which, under the
Hello,
I want to fit linear mixed model for non-normal observation. Which
package is appropriate?
Thanks
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
Hi, I am unable to install roxygen2 on R3.0.2. Any idea why?
install.packages(roxygen2)
Installing package into
/home/lefebvr3/R/x86_64-unknown-linux-gnu-library/3.0
(as lib is unspecified)
Warning message:
package roxygen2 is not available (for R version 3.0.1)
sessionInfo()
R version
dataorder.csv http://r.789695.n4.nabble.com/file/n4681879/dataorder.csv I
have a set of data as attached.Like (181,246,378).(180,228,378)And I
want to use test for trend in proportions using (400,500,600) as denominator
and get 119 p-valuesSo I use the code as
Unfortunately roxygen2 3.0.0 now requires R 3.0.2. See
https://github.com/klutometis/roxygen/issues/163 for some discussion
as to why.
Hadley
On Mon, Dec 9, 2013 at 12:28 PM, François Lefebvre lefeb...@gmail.com wrote:
Hi, I am unable to install roxygen2 on R3.0.2. Any idea why?
A more complete description of non-normal would be helpful. You might
start with lme4 and MCMCglmm. See:
http://www.rseek.org/?cx=010923144343702598753%3Aboaz1reyxd4newwindow=1q=mixed%20model%20nonnormalsa=Searchcof=FORID%3A11
Kevin
On Mon, Dec 9, 2013 at 11:58 AM, Elham Shaarbaf
Revolution Analytics staff write about R every weekday at the Revolutions blog:
http://blog.revolutionanalytics.com
and every month I post a summary of articles from the previous month
of particular interest to readers of r-help.
In case you missed them, here are some articles related to R from
The package specifies it. Either because the package author has used some
feature that is only available in that version, or he did not test it in any
earlier version. You can contact the maintainer (?maintainer) or try modifying
the package dependencies and finding out yourself if it is a real
Dear All
please help with the following:
I have:
a -seq(0,10,by=1)
b -c(10:20)
d -cbind(a,b)
f -16
I would like to select the value in column a based on a value in column b,
where the value in column b is the 1st value that is smaller then f. Thus I
should end up with the number 5 because
On Dec 8, 2013, at 7:45 AM, Dániel Kehl wrote:
Dear Community,
I am struggling with a growth curve estimation problem. It is a classic BMI
change with age calculation. I am not an expert of this field but have some
statistical experience in other fields.
Of course I started reading
Karen,
Thank you for your reply. That approach makes the code for determining
preference much clearer. Unfortunately, it appears I am still needing
to use a for loop to process each row.
For any who find these posts and may have similar questions, I am
including my current code and sample
Thank you for providing a reproducible example. I tweaked it a little
bit to make it actually a data frame problem.
There are lots of ways to do this; here's one approach.
On second thought, this looks a lot like homework, so perhaps instead
I'll just suggest using subset() with more than one
Though your second question, restating this, has already been
answered, it might be worth you taking another look at your code in
this one as well.
In particular note that NA and NA are NOT the same thing.
data(mtcars)
str(mtcars)
# from your code
mtcars[2,2] - NA
mtcars[6,7] - NA
str(mtcars)
If it's not homework, then I'm happy to provide more help:
a -seq(0,10,by=1)
b -c(10:20)
d -data.frame(a=a,b=b)
f -16
subset(d, b f b == max(b[b f]))$a
# I'd turn it into a function
getVal - function(d, f) {
subset(d, b f b == max(b[b f]))$a
}
Sarah
On Mon, Dec 9, 2013 at 3:50
I have a humongous csv file containing census data, far too big to read into
RAM. I have been trying to extract individual columns from this file using
the colbycol package. This works for certain subsets of the columns, but not
for others. I have not yet been able to precisely identify the
On Dec 9, 2013, at 9:46 AM, celebrex wrote:
dataorder.csv http://r.789695.n4.nabble.com/file/n4681879/dataorder.csv
I have a set of data as attached.Like (181,246,378).(180,228,378). And I
want to use test for trend in proportions using (400,500,600) as denominator
and get 119
The etiquette of this email list is to stay on the list.
I am returning this email to the entire list.
The line I sent earlier prints one Figure, with a different set of 4
bars in each panel.
Here are three more options (and I repeat the first as well).
Basic documentation for barchart is in
Hello,
I am having difficulty obtaining the correct colors in my R charts.
colors()[c(552, 254, 26)]
[1] red green blue
But, if I specify col=552 in my barplot, I get gray bars. Likewise,
col=254 gives bright pink, and col=26 is a red-orange. I get accurate
results when I spell out the
Dear R-list,
I've been trying to produce a sort of an interaction plot wherein colored
stripplots and boxplots are superposed. In particular, I want the colors
of the (transparently) filled boxes to be the same as the colors of the
box borders (rectangle) and their whiskers (umbrella). Below
Hi,
col=552 isn't the same as colors()[552] - I think the former is drawn
from your current palette, with recycling of indices. The default
color palette has only eight colors.
You need instead
col=colors()[552]
It's very difficult to get 20-30 readily distinguishable colors. You
might try the
I have a mortality data over many years and I wish to plot the data and also
add some smoother to clearly highlight the trend. How could I do that in R with
base graphics or ggplot? I have the following sample data: require(lubridate)
mdate-seq(ymd('2000-01-01'),ymd('2010-12-31'), by = '1
For example, I have a numeric vector named d (without any attributes) and
I want to coerce it to character vector d. Is there any such functions? I
need it to make a function which applies other functions to objects,
something like this:
do-function(x,fun, ...) {
Hi Andras,
here is an other solution which also works if b contains missing values:
a -seq(0,10,by=1)
b -c(NA, 11:20)
f -16
#
a[which.max(b[bf])]
#
However, your question seems a bit artificial. Maybe you converted your
original question to a suboptimal problem.
HTH,
Denes
If it's not
Hello,
I am having difficulty obtaining the correct colors in my R charts.
colors()[c(552, 254, 26)]
[1] red green blue
But, if I specify col=552 in my barplot, I get gray bars. Likewise,
col=254 gives bright pink, and col=26 is a red-orange. I get accurate
results when I spell out the
Thank you very much Wolfgang and Michael for your help and information.
Now I know how to get the predicted values.
For information, my mean is the effect size for the one-sample-case.
Obviously I used misleading labels, but I calculated the same with CMA and
getting the same results, so it
The full details on the col= argument can be found in the
section titled Color Specification on the help page for par -
?par.
Basically, col= accepts color names, hexadecimal RGB, or an
integer designating a position on the current palette. You can
get the current palette using
palette()
[1]
Gerrit,
Thank you for the opportunity to illustrate this. I solved this
problem last week
and it will be included in the next version of the HH package (about a
month away).
panel.bwplot.constantColor - function(..., col, fill, cex, pch) {
## to be included in next version of the HH package
Those numbers that you pass to col = ... correspond to the current
sessions palette, not to the names of colors() that R knows about. You
can either set up your own palette:
## see current palette
palette()
[1] black red green3 bluecyanmagenta yellow
[8] gray
## set up new
On Mon, Dec 9, 2013 at 2:08 PM, Katharine Miller - NOAA Federal
katharine.mil...@noaa.gov wrote:
Hello,
I am having difficulty obtaining the correct colors in my R charts.
colors()[c(552, 254, 26)]
[1] red green blue
But, if I specify col=552 in my barplot, I get gray bars. Likewise,
Thanks everyone! You've been a big help. I've only ever worked with a few
colors before, so this is something new!
On Mon, Dec 9, 2013 at 1:46 PM, David Carlson dcarl...@tamu.edu wrote:
The full details on the col= argument can be found in the
section titled Color Specification on the help
Not reading the documentation for color specification? Integers do not specify
offsets in the colors() table.
?par
If you do want offsets into the colors table, perhaps you should do just that?
..., col=colors()[ c( 552, 254, 26 )], ...
On 12/10/2013 01:19 AM, Adel ESSAFI wrote:
Hello list,
I have the following data on dm table
dm
Group.1 V1 V2 V3V4 V5 V6 V7 V8
1 C/L NA 15.5 732179 875270.6 -143091.46 1107270 1088300 18964.40
2 C/S NA 15.5 803926 850352.1
Not tested, but I think you may want this:
do - function(x,fun, ...) {
fun - match.fun(fun)
obj.name - deparse(substitute(x))
assign(obj.name,fun(x, ...))
}
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On
On 12/10/2013 07:53 AM, Norbi Gurracho wrote:
I have a mortality data over many years and I wish to plot the data and also add some
smoother to clearly highlight the trend. How could I do that in R with base graphics or
ggplot? I have the following sample data: require(lubridate)
Can anyone recommend a good way to add tables?
Ideally I would like
t1 - table(x1)
t2 - table(x2)
t1+t2
It t1 and t2 have the same levels this works fine, but I need something
that will work even if they differ, e.g.,
t1
1 2 4 5
2 1 1 1
t2 - table(c(10, 11, 12, 13))
t1+t2 # apparently
Answering myself...
On Mon, 2013-12-09 at 15:59 -0800, Ross Boylan wrote:
Can anyone recommend a good way to add tables?
For count data, which were my main concern, it looks as if tabulate with
nbins will work. I'm not sure how this works with a cross-classifying
factor, which I will also need.
Is this what you are after?
http://www.statmethods.net/management/merging.html
-Roy
On Dec 9, 2013, at 4:09 PM, Ross Boylan r...@biostat.ucsf.edu wrote:
Answering myself...
On Mon, 2013-12-09 at 15:59 -0800, Ross Boylan wrote:
Can anyone recommend a good way to add tables?
For count data,
On Mon, 2013-12-09 at 16:20 -0800, Roy Mendelssohn wrote:
Is this what you are after?
http://www.statmethods.net/management/merging.html
Not directly. Something could probably be fashioned using it and
as.data.frame on the result of table(), but merge doesn't sum values.
Ross
-Roy
On Dec
Dear R users,
I'm using the ineq package to calculate the values ââof Gini and Lorenz
coefficients and to and plot Lorenz graph.
I want to plot on the same diagram, curves from two different populations,
that have different n.
How can I do this?
Â
Best regards,
Â
Patricia
Don:
I defer to your judgment as to whether this was what the OP wanted,
but I think you would agree that the idiom of assign()ing to the
global workspace from within a function is almost always a bad idea in
R. Unfortunately, a better alternative, which frequently involves
building up a list
On Dec 9, 2013, at 3:59 PM, Ross Boylan wrote:
Can anyone recommend a good way to add tables?
Ideally I would like
t1 - table(x1)
t2 - table(x2)
t1+t2
It t1 and t2 have the same levels this works fine, but I need something
that will work even if they differ, e.g.,
t1
1 2 4 5
2 1 1
On Mon, 2013-12-09 at 16:09 -0800, Ross Boylan wrote:
Answering myself...
On Mon, 2013-12-09 at 15:59 -0800, Ross Boylan wrote:
Can anyone recommend a good way to add tables?
For count data, which were my main concern, it looks as if tabulate with
nbins will work. I'm not sure how this
Hello,
Please read:
library(fortune)
fortune('TFM')
Then:
?plot.Lc
HTH,
Pascal
On 10 December 2013 09:19, Patricia Costa patcost...@yahoo.com.br wrote:
Dear R users,
I'm using the ineq package to calculate the values of Gini and Lorenz
coefficients and to and plot Lorenz graph.
I
HI,
May be this helps:
t2 - table(c(10,11,12,13))
t1 -table(c(1,1,2,4,5))
t - c(t1,t2)
tapply(t,sort(as.numeric(names(t))),sum)
A.K.
On Monday, December 9, 2013 7:01 PM, Ross Boylan r...@biostat.ucsf.edu wrote:
Can anyone recommend a good way to add tables?
Ideally I would like
t1 -
Hi, I am quite new to R so I know that this probably is very basic , but how
can I split a sequence of number into multiple parts with equal length?
For example I have a vector
X=c(1:12)
I simply need to split it into sub-vectors with the same length N . Say N=3
then I need the output to be like
Hi,
Try:
split(X,as.numeric(gl(length(X),3,length(X
A.K.
Hi, I am quite new to R so I know that this probably is very basic , but how
can I split a sequence of number into multiple parts with equal
length?
For example I have a vector
X=c(1:12)
I simply need to split it into sub-vectors
On Mon, 09 Dec 2013, andrewH ahoer...@rprogress.org writes:
I have a humongous csv file containing census data, far too big to read into
RAM. I have been trying to extract individual columns from this file using
the colbycol package. This works for certain subsets of the columns, but not
for
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