Hi all,
I thought I read somewhere that the reviewing process of the Journal of Statistical Software was
quite fast (arround 3 month). Is that correct?
--
Christophe Genolini
Maître de conférences en bio-statistique
Vice président Communication interne et animation du campus
Université Paris
Christophe:
I thought I read somewhere that the reviewing process of the Journal of
Statistical Software was quite fast (arround 3 month). Is that correct?
I'm not sure whether this is the right place to ask about this...
In any case, the JSS web page publishes the submit/accept/publication
R throws out this event due to the missing time-dependent covariate at day
6. Is there a way I can keep this event without filling in a covariate
value at day 6?
No.
The Cox model assesses the risk associated with each covariate by comparing, at each event
time, the values of the subject who
Hi,
I have 25 questions divided into 3 modules. I'm building tables of DISCIPLINE
with each of the questions (Q1, Q2, Q3, ..., Q25).
Each table, of course, has a different title.
In the first module (questions Q1, Q2, ..., Q7) I donât have problems with
the titles of tables.
DISCIPLINA -
Hi all,
Â
I have a data set, named âdata1.longâ,
which has 180 subjects with two variables, âtimeâ and âpatientâ. The
âtimeâ
variable takes 9 values, i.e., 1, 2, 3,â¦,9, and the âpatientâ variable
takes
two values, 0 and 1. There are 10 subjects for each combination of
Your assignment of NAs is fine.
When you extract, you have to remember to specify whether you want to
include or exclude those NA values.
Try this:
data1.long[data1.long$time==9 !is.na(data1.long$time), time]
Jean
On Tue, Jan 14, 2014 at 7:22 AM, Chia-Chieh Lin
Hello :)
I'm Solip Park in Barcelona :)
I have one question about linear model in R.
I used generalized linear model (glm) in R with three variables (A,B, and
C).
So I made a model like this;
glm.model = glm (Freq ~ A * B * C, family = poisson)
and then,
anova (glm.model, test = Chisq).
It
I am not sure what you mean by expected table, but perhaps
?predict.glm
is what you are looking for. If not, hopefully someone else will help.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is
If you use the formula method for plot then you can use the subset
argument, for example:
plot(Sepal.Width ~ Sepal.Length, data=iris)
plot(Sepal.Width ~ Sepal.Length, data=iris, subset=Species=='setosa')
On Mon, Jan 13, 2014 at 5:39 PM, Janet Choate jsc@gmail.com wrote:
Hi R community,
i
Solip:
You should usually cc R-help on your responses to increase the chance
that others can help or to correct bad advice.
To respond to your explanation: Read ?glm and ?family to read about
how to construct glm models and family functions for them. glm models
are by default fit by iterated
Hi,
Can you help me. I need to fit Bivariate Binary model with conditional
synchrony measures (CSM) and Odds Ratio (OR) as measures of association.
Can you give some hint code?
Regards
Adelino
[[alternative HTML version deleted]]
Dear R helpers!,
I have a question on how to run a regression with many indices.
To give you a practical example, let y_{itabp} be an dependent variable
(representing prices) indexed by
i=country, t=time, a=area, b=brand and p=package size.
In particular, we collected prices on a
Hello list
I have the following data in file in attachment.
in want to draw bars for every value of V5 in finction of V3
grouped by V2*V1. however, each unique value
of V4, V2 and V1 I want to draw a bar.
This example is very close to want I want to do. but
here, for each value of V3, barchart
Dear R Users,
I'm searching for a Self Start function for Weibull function (3 parameters).
Somebody can help?
Cheers,
Vasco Cadavez
On 14/01/14 11:00, r-help-requ...@r-project.org wrote:
Send R-help mailing list submissions to
r-help@r-project.org
To subscribe or unsubscribe
I'm running the following to get what I would expect is a subset of
countries that are not equal to US AND COUNTRY is not in one of my
validcountries values.
non_us - subset(mydf, (COUNTRY %in% validcountries) COUNTRY != US,
select = COUNTRY, na.rm=TRUE)
however, when I then do table(non_us) I
I've noticed that I get different output when running a linear model on my Mac
versus on my PC. Same effect, but the Mac assumes the predictor as a 0 level
whereas the PC uses the first category (alphabetically).
So for example (using Bodo Winter's example from his online linear models
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
No data. The list strips off most files. If you want to send data give the
file a .txt suffix but it is much better to supply the output of dput() .
John Kane
Kingston ON Canada
-Original
Hi,
Try:
table(as.character(non_us[,COUNTRY]))
A.K.
On Tuesday, January 14, 2014 3:17 PM, Jeff Johnson mrjeffto...@gmail.com
wrote:
I'm running the following to get what I would expect is a subset of
countries that are not equal to US AND COUNTRY is not in one of my
validcountries values.
On Jan 14, 2014, at 1:38 PM, Jeff Johnson mrjeffto...@gmail.com wrote:
I'm running the following to get what I would expect is a subset of
countries that are not equal to US AND COUNTRY is not in one of my
validcountries values.
non_us - subset(mydf, (COUNTRY %in% validcountries) COUNTRY
I am not sure that I got the data correctly--it is much better to supply sample
data using dput(). See ?dput for more information but I think something like
this will work
dat1 / - structure(list(cty = structure(1:70, .Label = c(AE, AN, AR,
AT, AU, BB, BD, BE, BH, BM, BN, BO, BR, BS,
CA, CH,
On Jan 14, 2014, at 2:23 PM, CASENHISER, DEVIN M de...@uthsc.edu wrote:
I've noticed that I get different output when running a linear model on my
Mac versus on my PC. Same effect, but the Mac assumes the predictor as a 0
level whereas the PC uses the first category (alphabetically).
So
Here is a reproducible example of your problem where you do not
want to see a table entry for Medium.
tmp_df - data.frame(Size=factor(rep(c(Small,Medium,Large),1:3),
levels=c(Small,Medium,Large)))
non_medium - subset(tmp_df, Size != Medium, select=Size)
table(non_medium)
non_medium
I would suggest running the code:
options('contrasts')
on both machines to see if there is a difference. Having the default
contrasts set differently would be one explanation.
On Tue, Jan 14, 2014 at 2:28 PM, Marc Schwartz marc_schwa...@me.com wrote:
On Jan 14, 2014, at 2:23 PM, CASENHISER,
I think this is a case of using dput to make sure that the datasets are the
same.
I was bitten once by this and now dput between machines.
Regards
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
Armidale NSW 2351
Email: home: mac...@northnet.com.au
Ok,
I put here the data exported with dput().
structure(list(V1 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L,
0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L,
0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
Good catch Greg.
The Mac output observed can result from either:
options(contrasts = c(contr.helmert, contr.poly))
or
options(contrasts = c(contr.sum, contr.poly))
being run first, before calling the model code.
I checked the referenced tutorial and did not see any steps pertaining to
Hello,
Maybe function ?SSweibull in package stats.
Hope this helps,
Rui Barradas
Em 14-01-2014 18:29, Vasco Cadavez escreveu:
Dear R Users,
I'm searching for a Self Start function for Weibull function (3
parameters).
Somebody can help?
Cheers,
Vasco Cadavez
On 14/01/14 11:00,
Thanks John (and everyone else as well). John's example got it very close.
I can tweak from here. Thanks!
On Tue, Jan 14, 2014 at 1:22 PM, John Kane jrkrid...@inbox.com wrote:
I am not sure that I got the data correctly--it is much better to supply
sample data using dput(). See ?dput for more
Thanks so much Marc and for those that responded. Mark's suggestion with
droplevels gave me the desired result.
I'm new to figuring out how to post reproducible code. I'll try using the
set.seed and rnorm functions next time and hope that does the trick.
Thanks everyone!
On Tue, Jan 14, 2014
Hi All,
I have R 64bit and R-32 bit installed in my windows 7.
For 64 bit, the version info is
R.Version()
$platform
[1] x86_64-w64-mingw32
$arch
[1] x86_64
$os
[1] mingw32
$system
[1] x86_64, mingw32
$status
[1]
$major
[1] 3
$minor
[1] 0.2
$year
[1] 2013
$month
[1] 09
$day
[1] 25
X is a 5000 x 5 matrix (numerical variables)
k = 6
My desktop machine is a Xeon-processor Dell Precision T3500.
[Ubuntu 12.04.4 LTS (GNU/Linux 3.2.0-58-generic x86_64) with 24 GB RAM]
[R version 3.0.2 (2013-09-25) -- Frisbee Sailing
Copyright (C) 2013 The R Foundation for Statistical Computing
On Jan 14, 2014, at 10:29 AM, Vasco Cadavez wrote:
Dear R Users,
I'm searching for a Self Start function for Weibull function (3 parameters).
Have you looked at:
?selfStart # be sure to look at the links in the See Also section
--
David
Somebody can help?
Cheers,
Vasco
Post plain text per the posting guide?
Install the 64bit version of the Java Runtime?
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#.
I am using R3.02 on WIndows 7 64bit.
How can I test for trend across ordered groups. I am using
`prop.trend.test` but it doesn't order into groups and doesn't give
the expected output of `sum of ranks` , `z value`...
I have this data set and am doing
`prop.trend.test (birthweight2$lbw2
Now, if I were to move the data over from an excel doc would that change
anything. I do understand that that I would have to change it to a csv
document and create a variable for it. Just to give you a more visual
understanding of what I am doing I attached a picture of the head of the
data. So
Hi,
I don't want to cheat for Assignment Week 1 I calculated the answers using
microsoft excel.
Please help me with extracting data, counting missing values in R software
will really be grateful. Don't want to be a liar.
--
Dorcas Nduati
PHPT Dept.
Room 111
UoN
Office:0202453621 Ext 27107
Hi all,
I am having some trouble running GLMM's and using model averaging with
QAICc.
Let me know if you need more detail here:
I am trying to run GLMM's on count data in the package glmmADMB with a
negative binomial distribution due to overdispersion. The dispersion
parameter has now reduced to
show us some of your effort? what have you tried? did u went through the
video lectures in the site?
On Wed, Jan 15, 2014 at 3:11 AM, Dorcas Nduati dndu...@gmail.com wrote:
Hi,
I don't want to cheat for Assignment Week 1 I calculated the answers using
microsoft excel.
Please help me with
Hi
It seems to me that you would do yourself a favor if you go through R-Intro.
See in line.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Norman McBride
Sent: Tuesday, January 14, 2014 11:56 PM
To: r-help@r-project.org
Hi Dorcas Nduati,
Better place to discuss and ask for help about home work is discussion
forum of that site.
It is one of recommendations is that: you should not post your
homework on Rhelp or stackOverflow.
On Wed, Jan 15, 2014 at 12:56 PM, arun smartpink...@yahoo.com wrote:
Hi,May be this
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