I have a function that makes use of the ode() function from the
deSolve package. I am trying to find a way of getting it to put out a
progress report every t.int time units (by progress report I just
mean reporting what time it's got up to).
I thought to put code something like the
Dear Charles,
see the help file and the examples at
http://cran.r-project.org/web/packages/fGarch/fGarch.pdf
or use ?garchFit
in the examples you will see for example:
garchFit(~ garch(1,1), data = x.vec, trace = FALSE)
Try something like that. Make sure you provide the package of the function
Hello together,
i have a little problem, maybe anyone can help me.
I have 2 data.frame, one look like this one:
FS_ID ABNR
9327 33688812
11391 33688812
11392 33688812
11388 33688812
11390 33688812
12028 33688812
12029 33688812
the other data.frame looks like as follows:
On Tue, 25 Feb 2014, Rolf Turner r.tur...@auckland.ac.nz writes:
I have a function that makes use of the ode() function from the
deSolve package. I am trying to find a way of getting it to put out
a progress report every t.int time units (by progress report I
just mean reporting what time
On 14-02-25 3:08 AM, Rolf Turner wrote:
I have a function that makes use of the ode() function from the
deSolve package. I am trying to find a way of getting it to put out a
progress report every t.int time units (by progress report I just
mean reporting what time it's got up to).
I thought
Dear All,
Please consider the snippet at the end of the email.
It is representative of the problems I am experiencing.
I am trying to use glm (without using the formula interface because the
original data is quite large) to model the response in a case where the
predictors are a mix of
Regarding : ... I don't know
what the 4th to last page would be called (could add another ante-, or
in R just use tail(book,4))...
According to wordsmith.org (sign up it's free, note I have no affiliation to
that site) the word is preantepenultimate.
Check it out:
Hi,
How do we limit the Theta range plotted? In the current format, R plots
the
whole 2Pi range, however I want a plot between 0 and pi/2.
I do not see any parameter in polar.plot to do the same, am I missing
something very obvious?
Hi Avaneesh,
Use the radial.pos argument to provide
Hello,
I have to install R 3.0.2 on a computing center ressources for some of
our users and I encounter a compilation error. I take some times to
search on the Internet but I find nothing relevant so I send an email to
this list. If this is not the right one, please tell me which is more
Hello,
I get the following error when running the example in the MatchIt package,
demo(analysis)
ate.all - c(s.out1$qi$att.ev, -s.out2$qi$att.ev)Error in -s.out2$qi$att.ev :
invalid argument to unary operatorIn addition: Warning messages:1: In
setx.default(z.out1, data = match.data(m.out1,
I am trying to use restricted cubic spline to examine the association
between an independent variable and outcome. When I plot the relationship
between HR and the independent variable, I found the HR is not equal to 1
for the specified reference value. For example:
dat - read.table(mydata.csv)
It appears that average treatment effects are not calculated in the
version of Zelig currently on CRAN. Note that this is a Zelig issue,
not a MatchIt issue. See the missing features section of
http://cran.r-project.org/web/packages/Zelig/NEWS.
Best,
Ista
On Mon, Feb 24, 2014 at 9:09 AM, Marwan
On 02/25/2014 05:00 AM, r-help-requ...@r-project.org wrote:
Hi,
I have some measurements and their uncertainties. I'm using an
uncensored subset of the data for a weighted fit (for now---I'll do a
fit to the full, censored, dataset when I understand the results).
survreg() reports a much
I have a Y variable with many values less than 50, and many fewer
between 50 and 250.I'd like to plot those Y's against an X, with two
scales on the Y axis---maybe 60% of the axis height for 0-50 and the top
40% for 50-250.(I can't use log(Y) because there are many zeroes, and
that is the most
Since ... hmmm.. May 2012, I've had a cron-initiated script running
monthly to extract some data and generate some numeric tables and
plots (in PNG format).
In its normal mode, the script automagically sends its results
to a small handful of managers on the first of each month. Out of
Dear R community
I'm new to R and I'd like to ask for hints how to approach the following
problem:
I have two vectors of count data 'observed_S' and 'observed_A'. Whereas
'observed_S' follows a neg. binomial distribution but 'observed_A' is a
mixture of an unknown variable 'A' (also from a
Yes!!..many thanks for your help - seems the problem is still pending!
Here it is,
Average Treatment Effect quantities of interest are not being included in
zelig models temporarily. Simulation of these qi's will return pending a
minor update to the 'setx' function.
regards Marwan
On
I am encountering a problem using *geom_polygon(., fill=.)* with a dataframe
created using fortify(map) *if the polygon has holes*.
It appears that fill=. ignores the holes - -eg. fills them as if they are not
present. geom_path(.) on the other hand does
recognize the boundaries of the holes.
Hi,
You could also do:
mat1 - matrix(NA,ncol=max(n),nrow=length(n))
mat1[cbind(rep(seq_along(n),n),seq_len(sum(n))-
rep(cumsum(c(0L,n[-length(n)])),n))] - y
mat1
A.K.
On Tuesday, February 25, 2014 10:34 AM, arun smartpink...@yahoo.com wrote:
Hi,
One way would be:
res -
In mcreg, there's the following snippet for bootstrap CI method of BCa
(and a very similar one for quantile):
else if (method.bootstrap.ci == BCa) {
bootB0 - mc.calc.bca(Xboot = B0, Xjack = B0jack,
xhat = glob.coef[1], alpha)
bootB1 - mc.calc.bca(Xboot =
Hi,
May be this helps:
dat1 - read.table(text=FS_ID ABNR
9327 33688812
11391 33688812
11392 33688812
11388 33688812
11390 33688812
12028 33688812
12029 33688812,sep=,header=TRUE)
dat2 - read.table(text=FS_ID DATE POST
11390 2012-12-13 28
12029 2013-01-17
One option is the gap.plot function in the plotrix package.
On Tue, Feb 25, 2014 at 10:18 AM, David Parkhurst parkh...@imap.iu.edu wrote:
I have a Y variable with many values less than 50, and many fewer
between 50 and 250.I'd like to plot those Y's against an X, with two
scales on the Y
Hi,
One way would be:
res - t(sapply(split(y,rep(seq_along(n),n)),function(x) {if(length(x)
max(n)) c(x,rep(NA,max(n)-length(x))) else x}))
A.K.
Dear all,
my question regards how to subset an existing vector in
subvectors of different lengths and then create a matrix. See example
below.
Hi David,
Did you see https://stat.ethz.ch/pipermail/r-help/2010-March/231778.html
? What does capabilities() tell you?
Best,
Ista
On Tue, Feb 25, 2014 at 1:36 PM, David Wolfskill r...@catwhisker.org wrote:
Since ... hmmm.. May 2012, I've had a cron-initiated script running
monthly to extract
I discovered the 'mlogit'-package for multinomial logit models in search of
estimating a multinomial mixed logit model. After reading the excellent
vignette I discovered that I could not apply my data on any of the
described examples.
I now write in hope of help with my problem and created a
Please be a good netizen and post plain text on the list.
Jim can probably point you to some plotrix function that will do what you ask,
but I would encourage you to plot the data twice rather than confusing the
audience with nonlinear (discontinuous) scales in a single plot.
Hi,
You can try to use cairo instead of png.
IT doesn’t require X.
try putting this line in a Rprofile file :
options(bitmapType=cairo)
Massimo.
On Feb 25, 2014, at 1:36 PM, David Wolfskill r...@catwhisker.org wrote:
Since ... hmmm.. May 2012, I've had a cron-initiated script
R Experts,
I had a problem when trying to install package tm. The install looked
successful (Package 'tm' successfully unpacked and MD5 sums checked) but I
could not load it through
library(tm). It kept complaining that tm package was not installed.
So it was through this problem that I
This is really not new... Google is your friend... http://bit.ly/1fCUnQH... or
read FAQ 7.19. The fact that this changed for you seems more like something
changed on your end... did your admin remove X11 from your system?
On Tue, Feb 25, 2014 at 01:45:40PM -0500, epi wrote:
Hi,
You can try to use cairo instead of png.
IT doesn?t require X.
try putting this line in a Rprofile file :
options(bitmapType=cairo)
..
Thank you for the suggestion.
Early in the first function my script invokes, I have:
Hello,
I am branching out to xyplot for the first time, and I want to layer
several complex xyplots. I have tried using panel functions, but so far I
lose all complexity from the scatterplot. I would like to have the
following things in the plot:
1) A plot of observation vs. modeled individual
Hi,
Check the ?str() of testxls. I guess the two columns studya and studyb,
would be character().
I don't have package xlsx installed. So, I read the file using
library(XLConnect). Had the same problem. You can use ?setMissingValue in
XLConnect.
library(XLConnect)
library(reshape2)
wb -
Hello,
I have two questions about one sided ks.test.
First, is there any function in R to find _the critical value_ for this
test? I looked at the Z. W. Birnbaum and Fred H. Tingey (1951) paper
and I found the formula sqrt(-1/(2n)log(/a/)) but when I use the
p-value from ks.test and this
On 26/02/14 01:40, Lorenzo Isella wrote:
Dear All,
Please consider the snippet at the end of the email.
It is representative of the problems I am experiencing.
I am trying to use glm (without using the formula interface because the
original data is quite large) to model the response in a case
On Tue, Feb 25, 2014 at 10:50 AM, Therneau, Terry M., Ph.D.
thern...@mayo.edu wrote:
On 02/25/2014 05:00 AM, r-help-requ...@r-project.org wrote:
Hi,
I have some measurements and their uncertainties. I'm using an
uncensored subset of the data for a weighted fit (for now---I'll do a
fit
Survreg treats weights as case weights, and lm treats them as sampling
weights.
Here is a simple example. Data set test2 has two copies of every obs in data
set test.
test - data.frame(x=1:6, y=c(1,3,2,4,6,5))
test2 - test[c(1:6, 1:6),]
summary(lm( y ~ x, data=test))$coef
I think both of your questions can be answered using simulations.
If you simulate a bunch of datasets where the null hypothesis is true
(data comes from the candidate distribution or 2 sets come from the
same distribution) and compute the KS statistic for each (you can use
the ks.test function
I¹ve used twang to get ATE propensity scores.
I¹ve done multivariable, case weighted Cox PH models in survey using
svycoxph and in rms using cph with id(cluster) set to get robust estimates.
The model language is identical.
The point estimates are identical, but the CIs are considerably wider
Hello Lib,
I think what you're trying to do is very easy using ggplot2 -- easy, that
is, once you got your hear around ggplot2 in the first place. The layering
you mention is the core feature of ggplot2. Fortunately it is
well-documented including a thin, overpriced book from Springer (which I
On Tue, Feb 25, 2014 at 11:10:12AM -0800, Jeff Newmiller wrote:
This is really not new... Google is your friend... http://bit.ly/1fCUnQH...
or read FAQ 7.19. The fact that this changed for you seems more like
something changed on your end... did your admin remove X11 from your system?
...
I
Hi Arun,
Yes, I figured that, thanks a lot for your help.
Howver, when I test res1 for symmetricity I get:
isSymmetric(unname(res1))[1] FALSE
I need the final matrix to be symmetric.
Any idea?
E.
On Tue, Feb 25, 2014 at 10:14 PM, arun smartpink...@yahoo.com wrote:
Hi,
Sorry, a typo:
Please see at end.
On 26/02/14 01:13, Duncan Murdoch wrote:
On 14-02-25 3:08 AM, Rolf Turner wrote:
I have a function that makes use of the ode() function from the
deSolve package. I am trying to find a way of getting it to put out a
progress report every t.int time units (by progress
Hi Arun,
Great, many thanks again and sorry for the confusion, Since this is going
to the forum, I also found a way to merge symmetric matrices (just two,
hence the question on multiple symmetric matrix merge), I can post it here
for future reference by other users:
ix -
On Tue, Feb 25, 2014 at 2:51 PM, Nathan Pace n.l.p...@utah.edu wrote:
I¹ve used twang to get ATE propensity scores.
I¹ve done multivariable, case weighted Cox PH models in survey using
svycoxph and in rms using cph with id(cluster) set to get robust estimates.
The model language is
On 26/02/14 00:56, Enrico Schumann wrote:
SNIP
I did not follow your example, neither do I use the deSolve package; but
why not pass an environment as an argument?
## some iterative function that takes another fun as argument
outer - function(fun, ...) {
for (i in 1:20)
On 14-02-25 4:43 PM, Rolf Turner wrote:
Please see at end.
On 26/02/14 01:13, Duncan Murdoch wrote:
On 14-02-25 3:08 AM, Rolf Turner wrote:
I have a function that makes use of the ode() function from the
deSolve package. I am trying to find a way of getting it to put out a
progress report
On Tue, Feb 25, 2014 at 10:36:29AM -0800, David Wolfskill wrote:
...
This morning, I found a message in my mailbox from such a preview run:
| Error in .External2(C_X11, paste(png::, filename, sep = ), g$width, :
| unable to start device PNG
| Calls: gen_build_histogram - png
| In
Hi,
I have realized a multiple linear regression.
To know how well my model does in terms of prediction, I can compute prediction
intervals bands and decide if they are narrow enough to be of use. If they are
too wide, then they probably are not useful.
So what I am trying to do is :
Hi,
I am not sure about your final result. In your initial post, you mentioned
but with row names that need to be matched. Anyway, this gives me symmetric
matrix
##rownames are the same as colnames for each matrix, so:
uNrownames - unique(as.vector(sapply(lst2,rownames)))
res -
HI Elio,
Not sure whether this helps:
length(list.files(pattern=.txt))
#[1] 22
lst1 - lapply(list.files(pattern=.txt),function(x)
read.table(x,header=TRUE,stringsAsFactors=FALSE))
sapply(lst1,dim)
sapply(lst1,function(x) all(apply(rbind(colnames(x),rownames(x)),2,function(y)
y[1]==y[2])))
Thank you Arun!
Le mail ti raggiungono ovunque con BlackBerry® from Vodafone!
-Original Message-
From: arun kirshna [via R] ml-node+s789695n4685806...@n4.nabble.com
Date: Tue, 25 Feb 2014 10:54:10
To: bexelisabetta.petra...@gmail.com
Subject: Re: how to extract consecutive subvetors of
Hi,
Sorry, a typo:
res1[rownames(mat1),] - res[rownames(mat1),] + mat1
###should be:
res1[rownames(mat1),] - res1[rownames(mat1),] + mat1
A.K.
On Tuesday, February 25, 2014 4:03 PM, arun smartpink...@yahoo.com wrote:
HI Elio,
Not sure whether this helps:
Hi All,
I am using lattice::bwplot to plot the results of a subgroup analysis for
different simulation scenarios. I have 4 subgroups, 5 methods of estimating
treatment effect in subgroups, and 4 scenarios. I am plotting the subgroup
effect and its upper and lower CI.
I have 2 issues that I
On Tue, Feb 25, 2014 at 4:49 PM, Ravi Varadhan ravi.varad...@jhu.edu wrote:
Hi All,
I am using lattice::bwplot to plot the results of a subgroup analysis for
different simulation scenarios. I have 4 subgroups, 5 methods of estimating
treatment effect in subgroups, and 4 scenarios. I am
Hi
Once you want to do extra things from the basic you may have to go into the
panel function
xyplot(Observation,IPrediction,
groups=TreatmentArm,
col = c(1,2,3),
cex=0.7,
panel = function(x,y,...){
Hi Ravi
str(estimates)
'data.frame': 240 obs. of 4 variables:
$ Tx.effect: num -0.2321 -0.1097 0.0409 0.0546 0.1069 ...
$ method : chr Bayes-DS Bayes-DS Bayes-DS Bayes-DS ...
$ name : chr X0=0, scenario1 X0=1, scenario1 X1=0, scenario1
X1=1, scenario1 ...
$ type : chr Point
Here are the model outputs.
Nathan
Survey package
ca.ATE.design - svydesign(ids = ~ id, weights = ~ get.weights(ca.ATE.ps,
stop.method = 'ks.mean'), data = ca.dt)
Independent Sampling design (with replacement)
svydesign(ids = ~id, weights = ~get.weights(ca.ATE.ps, stop.method =
ks.mean),
On 26/02/14 11:57, varin sacha wrote:
Hi,
I have realized a multiple linear regression.
To know how well my model does in terms of prediction, I can compute prediction
intervals bands and decide if they are narrow enough to be of use. If they are
too wide, then they probably are not useful.
Rolf Turner wrote:
Somehow I managed *not* to cc to R-help the message that I just sent to
you. I thought I'd clicked on Reply All but apparently not. And in
thrashing around trying to recover, I managed not to get a copy kept in
my Sent Mail!!!
Could I please prevail upon you to pass that
When I run my script, the progress bar is always minimized, and I have to
manually click on it to be visible. Does anyone know how to put an R
progress bar on top once it is created?
--
View this message in context:
http://r.789695.n4.nabble.com/R-Progress-Bar-tp4685847.html
Sent from the R
Hi Felipe,
Pasting the code from your second email with ?which.max()
#changed 'test' to `hw` as
hw2 - ddply(hw,id,summarise,
subSiteName=unique(subSiteName),nReleased=unique(nReleased),
I have a Y variable with many values less than 50, and many fewer
between 50 and 250.I'd like to plot those Y's against an X, with two
scales on the Y axis---maybe 60% of the axis height for 0-50 and the top
40% for 50-250.(I can't use log(Y) because there are many zeroes, and
that is the
Another suggestion - would a square-root scale work for you?
Peter Alspach
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Jim Lemon
Sent: Wednesday, 26 February 2014 3:00 p.m.
To: David Parkhurst
Cc: r-help@r-project.org
Subject:
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