Hi, Please help! I need to plot a degree distribution.
so far (see below) i have the following but the problem: i'm plotting the
graph. instead I need to plot the degree distribution.
library(igraph)
dat- read.graph(file=tf.net, format=pajek)
dat- as.undirected(dat, mode = c(each))
I just started using the colorspace package, and converting between RGB and
HLS is not working as I expect. In particular, converting RGB(0,0,0) to HLS
then back to RGB seems broken:
# as(as(RGB(0, 0, 0), HLS), RGB)
R G B
[1,] 1 1 0
That is, converting black to HLS then back
I am making my first submission to Plos One and am trying to install the
extrafonts package to obtain Arial for the figures. extrafonts was archived
at the end of last month so I downloaded first the extrafont_0.16.tar.gz file
and then the older extrafont_0.15.tar.gz file.
I selected Install
Hi,
I cannot reproduce your result:
R as(as(RGB(0, 0, 0), HLS), RGB)
R G B
[1,] 0 0 0
You probably should provide the output of sessionInfo().
Regards,
Pascal
On Thu, Mar 13, 2014 at 7:41 AM, Michael Gauland mikely...@amuri.net wrote:
I just started using the colorspace package, and
On Wed, 12 Mar 2014, Michael Gauland wrote:
I just started using the colorspace package, and converting between RGB and
HLS is not working as I expect. In particular, converting RGB(0,0,0) to HLS
then back to RGB seems broken:
# as(as(RGB(0, 0, 0), HLS), RGB)
R G B
[1,] 1 1 0
Hi,
Is there any optimization package in R recommended for general purposes
(constrained, unconstrained, etc)?
Has anyone used the function in NAGFWrapper package
http://www.nag.co.uk/numeric/R/r-package
Are the optimization functions therein available for free?
Thanks,
Miao
On 13/03/2014 04:31, robin.thom...@csiro.au wrote:
I am making my first submission to Plos One and am trying to install the extrafonts
package to obtain Arial for the figures. extrafonts was archived at the end
of last month so I downloaded first the extrafont_0.16.tar.gz file and then the
Dear all,
Consider the simpel RMarkdown file below. I've saved it as test.md with UTF-8
encoding. Notice that I have embedded a custom pandoc variable 'test' in the
file. This variable holds an UTF-8 character ©.
%My title
%The authorslist
!--pandoc
format: latex
V: test:Copyright notice. ©
On 13-03-2014, at 09:50, jpm miao miao...@gmail.com wrote:
Hi,
Is there any optimization package in R recommended for general purposes
(constrained, unconstrained, etc)?
See CRAN Task Views, Optimization. http://cran.r-project.org/web/views/
Has anyone used the function in
And what did the maintainer say? (See the posting guide.)
On 13/03/2014 09:11, ONKELINX, Thierry wrote:
Dear all,
Consider the simpel RMarkdown file below. I've saved it as test.md with UTF-8
encoding. Notice that I have embedded a custom pandoc variable 'test' in the
file. This variable
Dear all!
Is there a possibility to replace all duplicates values in data frame with
0?
Thank you very much!
--
---
Catalin-Constantin ROIBU
Lecturer PhD, Forestry engineer
Forestry Faculty of Suceava
Str. Universitatii no. 13, Suceava, 720229, Romania
office phone +4 0230 52 29 78, ext.
Hello,
Dis you at least search?
?duplicated
Regards,
Pascal
On Thu, Mar 13, 2014 at 9:35 PM, catalin roibu catalinro...@gmail.com wrote:
Dear all!
Is there a possibility to replace all duplicates values in data frame with
0?
Thank you very much!
--
---
Catalin-Constantin ROIBU
Hello,
See ?duplicated
Something like
dat1[duplicated(dat1), ] - 0
Hope this helps,
Rui Barradas
Em 13-03-2014 12:35, catalin roibu escreveu:
Dear all!
Is there a possibility to replace all duplicates values in data frame with
0?
Thank you very much!
Hi Catalin,
The following should give you some ideas:
set.seed(123)
x - rpois(50, 2)
x
idx - duplicated(x)
x[idx] - 0
x
Best,
Jorge.-
On Thu, Mar 13, 2014 at 11:35 PM, catalin roibu catalinro...@gmail.comwrote:
Dear all!
Is there a possibility to replace all duplicates values in data
Hi all,
I have downloaded the file 5.R.RData and I am trying to load it into R using
load(5.R.RData)
But it doesn't work.What's wrong,
Many thanks
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Do you really think we can answer this? Ok, the file is not a valid RData file,
or was corrupted in the file transfer. Was that helpful? If not, try being
specific (what URL did this file come from? Which version of R? What was the
output of session in sessionInfo()?) and posting in plain text
Hi List,
while running a script on a set of matrices I came into a case I would not
have guessed to arrive.
Below is a small toy example to illustrate the case.
Of course there is a simple workaround (using a simple test), but why does
this occur, and shouldnt it be corrected ?
More probably I
Dear all!
I have a new problem with the date format in a data frame. I have rainfall
records extracted from an automatic meteo station. In the same data frame
(with 1 records) the date is in 2 formats like that:
4/15/11 11:49 AM
5.6.11 2:51 PM
My question is how to modify date format for all
Hi,
Your basic problem seems to be that you expect R to take
TM2[0, ]
as meaning not to subset anything, rather than to take only row 0,
which doesn't exist:
R TM2[0,]
[,1] [,2] [,3]
There's a hint in
?[
which says:
An index value of 'NULL' is treated as if it were
Dear list users,
I have two data frames df1 and df2, where the columns of df1 are
Sensor_RM Place_RM Station_RM Y_init_RM M_init_RM D_init_RM Y_fin_RM M_fin_RM
D_fin_RM
and the columns of df2 are
Sensor_RM Station_RM Place_RM Province_RM Region_RM Net_init_RM
GaussBoaga_EST_RM
I would use gsub() to change instances like 5.6.11 to 5/6/11.
Hopefully, both versions have month and day in the same order.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 3/13/14 6:57 AM, catalin roibu
You have duplicates after merging because, although you know they are the
same, the R merge() function does not. And the people who wrote that
function knew that sometimes two columns with the same name are not
identical.
Since you know that the columns are identical, drop the column from one of
Dear useR's,
I have several biological data sets from laboratory experiments
where a few experiments failed completely due to bacterial
contamination. Such cases can easily be seen by eye as outliers.
Fitting a Michaelis-Menten kinetics works well with robust nonlinear
regression from
On Mar 13, 2014, at 10:19 AM, Stefano Sofia stefano.so...@regione.marche.it
wrote:
Dear list users,
I have two data frames df1 and df2, where the columns of df1 are
Sensor_RM Place_RM Station_RM Y_init_RM M_init_RM D_init_RM Y_fin_RM M_fin_RM
D_fin_RM
and the columns of df2 are
I am creating variables representing intraindividual means and standard
deviations for longitudinal data with the following code:
data$TraitHAPPYmean - with(data, ave(Happy, ID, FUN=function(x) mean(x,
na.rm=TRUE) ) )
data$TraitHAPPYsd - with(data, ave(Happy, ID, FUN=function(x) sd(x,
Hi,
I've been trying to figure out the code to estimate the LA/AIDS model
with the inverse mills ratio from the Heckman-2 step to correct for
zero consumption in R with no luck. Could someone please direct me on
how to do this in R?
Thanks,
Belinda A.
Try:
vec1 - c(4/15/11 11:49 AM, 6/12/12 2:30 PM, 5.6.11 2:51 PM)
vec2 - gsub([.],/,vec1)
A.K.
On Thursday, March 13, 2014 9:57 AM, catalin roibu catalinro...@gmail.com
wrote:
Dear all!
I have a new problem with the date format in a data frame. I have rainfall
records extracted from an
Hi,
You could use:
TM2[!margin.Rows =thresh,!margin.Cols =thresh]
# [,1] [,2]
#[1,] 1 1
#[2,] 1 1
#[3,] 1 1
#For the first case:
TM1[!margin.Rows =thresh,!margin.Cols =thresh]
# [,1] [,2]
#[1,] 1 1
#[2,] 1 1
A.K.
On Thursday, March 13, 2014 10:02
Hi,
Try:
set.seed(42)
dat1 - data.frame(Happy=sample(c(NA,1:25),40,replace=TRUE),ID=rep(1:5,each=8))
with(dat1,ave(Happy,ID,FUN=function(x) sum(!is.na(x
#or
library(plyr)
ddply(dat1,.(ID),mutate,mean=mean(Happy,na.rm=TRUE),SD=sd(Happy,na.rm=TRUE),n=sum(!is.na(Happy)))
#or you could
Hi,
Try:
Either
tab - read.table(text=pop Freq
1 1 30
2 2 25
3 3 30
4 4 30
5 5 30
6 6 30
7 7 30,sep=,header=TRUE)
indx - rep(1:nrow(tab),tab$Freq)
tab1 - transform(tab[indx,],ind=ave(seq_along(indx),indx,FUN=seq_along))[,-2]
#or
tab2 -
Thank you Sarah,
But no, I was not expecting this. For me integer(0) is not 0.
That's why I finally tested length(unused.rows), which is 0 when
unused.rows is integer(0).
Olivier
-Message d'origine-
De : Sarah Goslee [mailto:sarah.gos...@gmail.com]
Envoyé : jeudi 13 mars 2014 16:12
À :
On Thu, Mar 13, 2014 at 11:51 AM, Olivier ETERRADOSSI
olivier.eterrado...@mines-ales.fr wrote:
Thank you Sarah,
But no, I was not expecting this. For me integer(0) is not 0.
That's why I finally tested length(unused.rows), which is 0 when
unused.rows is integer(0).
Also from
?[
i, j, ...:
Hello,
Although lm() gives a way to get the adjusted R squared by
adjr2 - summary(mdl)$adj.r.squared
I cannot find a way to extract the adjusted R squared from gls(), any hint?
Thanks,
Rebecca
--
This message, and any
Thank you, Arun and Sarah
I was not trying to take row 0 that does not exist, rather trying not to
take (I wrote TM[- unused.rows,]) something that does not exist.
So what I understand from Arun's answer is that I was badly using MINUS with
a vector instead of NOT with a logical.
Olivier
Yes, that's usually what I'm doing...
Here I didn't guess that the answer was in [ !
I already noticed that it's sometimes easier to locate something very
technical or statistically smart than obvious things (because we think we
know, or think we have already read 10 times the basics...) ;-)
O.
Hello all,
I would like to install R from source on a SL 6.5 box. I have everything I
need except for inconsolata.sty and zi4.sty not found. I am thinking of
installing latex 2013 from https://www.tug.org/texlive/.
The tex binary will be installed in a different folder.
1. How do I tell
dear all,
I have tried to create a dataframe using the structure() function, but it
did not really work. In column 1 i have the row number, in column 2 and 3
factors (8 and 4 levels respectively) and in column 4 the actual data.
any clue on what went wrong?
best regards
luigi
Hello R users,
I am trying to make a baricentric diagram like the ternary plot, but with 4
edges. I want to know how to calculate the centroid of the diamond. The 4
edges are A, B, C, D. If value of A=B=C=D, then the point should be at the
centre of the diamond. If AB and B=C=D=0, Then the point
Dear All,
I have updated my OS - Windows 7, and I found a situation where R stops working
with reported error R for Windows GUI front-end has stopped working. My
script worked before (on windows XP).
The error occured when I perform this:
coxph(Surv(time,event)~F11_rs2036914+frailty(n),
I have tried to create a dataframe using the structure() function,
Why do you want to do this?
but it did not really work.
Use str() or dput() to compare this to a data.frame made in the usual
way. You have .Names and class being arguments to list() instead of
to structure() and you didn't
Hello,
You're misplacing one close parenthesis. See the commented lines below.
structure(list(
column_1 = 1:32,
column_2 = structure(c(1, 2, 3, 4, 5, 6, 7, 8,
1, 2, 3, 4, 5, 6, 7, 8,
1, 2, 3, 4, 5, 6, 7, 8,
1, 2, 3, 4, 5, 6, 7, 8),
.Label =
c(Unstimulated, ESAT6, CFP10, Rv3615c, Rv2654,
CASTELLI christel christel.CASTELLI at chu-nimes.fr writes:
Dear All,
I have updated my OS - Windows 7, and I found a
situation where R stops working
with reported error R for Windows GUI front-end has
stopped working. My script worked before (on windows XP).
The error occured when
Less coding with plyr:
tab - read.table(text=pop Freq
1 1 30
2 2 25
3 3 30
4 4 30
5 5 30
6 6 30
7 7 30,sep=,header=TRUE)
# Function to do the work on each row
f - function(pop, Freq) data.frame(ind = seq_len(Freq))
library(plyr)
u -
I think this'll be way simpler and also faster:
ans - data.frame(pop = rep.int(tab$pop, tab$Freq), ind=sequence(tab$Freq))
Arun
From:Â Dennis Murphy djmu...@gmail.com
Reply:Â Dennis Murphy djmu...@gmail.com
Date:Â March 13, 2014 at 9:57:20 PM
To:Â arun smartpink...@yahoo.com
Cc:Â R help
Well if I had it and you asked nicely, then I would be happy to give
it to you. Oh, you mean the gls function, not GLS as my initials (my
parents are OLS and WLS, perhaps I was destined to regress), sorry.
The gls function in the nlme package (is that the one that you are
asking about? or is
Or use sequence() and rep(), as in
u1 - with(tab, data.frame(pop=rep(pop,Freq), ind=sequence(Freq)))
I think that u1 is the same as your u.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
I think we're down to counting the number of characters in each
solution! Arun's 3 two-line versus your two-line solution (not
counting loading plyr). How about three short lines?
pop - rep(1:nrow(tab), tab$Freq)
ind - unlist(sapply(tab$Freq, seq_len))
tab2 - data.frame(pop, ind)
Your question makes absolutely no sense at all. See inline below.
On 14/03/14 08:03, al Vel wrote:
Hello R users,
I am trying to make a baricentric diagram like the ternary plot, but with 4
edges. I want to know how to calculate the centroid of the diamond.
Which centroid? A diamond
Hi,
Try:
my.data - structure(list(column_1 = 1:32,
column_2 = structure(c(1, 2, 3, 4, 5, 6, 7, 8,
1, 2, 3, 4, 5, 6, 7, 8,
1, 2, 3, 4, 5, 6, 7, 8,
1, 2, 3, 4, 5, 6, 7, 8), .Label = c(Unstimulated, ESAT6, CFP10,
Rv3615c, Rv2654, Rv3879,
Rv3873, PHA), class = factor),
column_3= structure(c(1, 1,
Dear R-users,
I want to plot boxplots of a single variable collected a few times during
almost one year and I would like the x-axis to recognize the date-class of the
variable.
I found some topics in the archive but:
- some questions were poorly posed
Dear all,
I want to create a boxplot with whiskers. I want to compare several
studies. For each study I have
1. mean
2. standard deviation (sd)
3. name
4. number of observations (n)
How can i do this in R ?
normally I would type
bxp
or
boxplot
but this is not allowed when I only
Hi,
I am working with hurdle models in the pscl package to model zero inflated
overdispersed count data and want to incorporate censored observations into
the equation. 33% of the observed positive count data is right censored,
i.e. subject lost to follow up during the duration of the study. Can
On 14/03/14 08:52, Frederik Borup wrote:
Dear all,
I want to create a boxplot with whiskers. I want to compare several
studies. For each study I have
1. mean
2. standard deviation (sd)
3. name
4. number of observations (n)
How can i do this in R ?
normally I would type
bxp
Dear R-list,
I am wondering whether anyone could explain what'd be the difference between
running a 'generalized additive regression' versus 'generalized linear
regression' with splines.
Are they same models theoretically? My apologies if this is a silly question.
Any comments or direction
Achim Zeileis Achim.Zeileis at uibk.ac.at writes:
Maybe you are using an old version of colorspace? For version 1.1-1
(from two years ago, version 1.2-4 is current) the NEWS file says:
...
That was it--thanks!
As a developer, I should know enough to check the release notes...
--Mike
On 03/14/2014 06:03 AM, al Vel wrote:
Hello R users,
I am trying to make a baricentric diagram like the ternary plot, but with 4
edges. I want to know how to calculate the centroid of the diamond. The 4
edges are A, B, C, D. If value of A=B=C=D, then the point should be at the
centre of the
On 03/14/2014 06:52 AM, Frederik Borup wrote:
Dear all,
I want to create a boxplot with whiskers. I want to compare several
studies. For each study I have
1. mean
2. standard deviation (sd)
3. name
4. number of observations (n)
How can i do this in R ?
normally I would type
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